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# JEE Advanced 2014 Paper -2 with Solutions

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## 60 Questions MCQ Test JEE Main & Advanced Mock Test Series | JEE Advanced 2014 Paper -2 with Solutions

JEE Advanced 2014 Paper -2 with Solutions for JEE 2022 is part of JEE Main & Advanced Mock Test Series preparation. The JEE Advanced 2014 Paper -2 with Solutions questions and answers have been prepared according to the JEE exam syllabus.The JEE Advanced 2014 Paper -2 with Solutions MCQs are made for JEE 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Advanced 2014 Paper -2 with Solutions below.
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JEE Advanced 2014 Paper -2 with Solutions - Question 1

### A glass capillary tube is of the shape of truncated cone with an apex angle α so that its two ends have cross sections of different radii. When dipped in water vertically, water rises in it to a height h, where the radius of its cross section is b. If the surface tension of water is S, its density is ρ, and its contact angle with glass is θ, the value of h will be (g is the acceleration due to gravity)

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 1

If R be the meniscus radius
R cos (θ + α/2) = b
Excess pressure on concave side of meniscus = 2S/R

JEE Advanced 2014 Paper -2 with Solutions - Question 2

### If λcu is the wavelength of Kα X-ray line of copper (atomic number 29) and λMo is the wavelength of the K? X-ray line of molybdenum (atomic number 42), then the ratio λcu/λMo is close to

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 2

JEE Advanced 2014 Paper -2 with Solutions - Question 3

### A planet of radius R = 1/10 x (radius of Earth) has the same mass density as Earth. Scientists dig a well of depth R/5 on it and lower a wire of the same length and of linear mass density 10-3 kgm-1 into it. If the wire is not touching anywhere, the force applied at the top of the wire by a person holding it in place is (take the radius of Earth = 6 x 106 m and the acceleration due to gravity of Earth is 10 ms-2)

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 3

JEE Advanced 2014 Paper -2 with Solutions - Question 4

A tennis ball is dropped on a horizontal smooth surface. It bounces back to its original position after hitting
the surface. The force on the ball during the collision is proportional to the length of compression of the
ball. Which one of the following sketches describes the variation of its kinetic energy K with time t most
appropriately? The figures are only illustrative and not to the scale.

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 4

JEE Advanced 2014 Paper -2 with Solutions - Question 5

A metal surface is illuminated by light of two different wavelengths 248 nm and 310 nm. The maximum
speeds of the photoelectrons corresponding to these wavelengths are u1 and u2, respectively. If the ratio
u1 : u2 = 2 : 1 and hc = 1240 eV nm, the work function of the metal is nearly

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 5

JEE Advanced 2014 Paper -2 with Solutions - Question 6

A wire, which passes through the hole in a small bead, is bent in the form of quarter of a circle. The wire is
fixed vertically on ground as shown in the figure. The bead is released from near the top of the wire and it
slides along the wire without friction. As the bead moves from A to B, the force it applies on the wire is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 6

During motion at an instant, N = 0, after that N will act radially outward.

JEE Advanced 2014 Paper -2 with Solutions - Question 7

During an experiment with a metre bridge, the galvanometer shows a null point when the jockey is pressed
at 40.0 cm using a standard resistance of 90 , as shown in the figure. The least count of the scale used in
the metre bridge is 1 mm. The unknown resistance is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 7

JEE Advanced 2014 Paper -2 with Solutions - Question 8

Parallel rays of light of intensity I = 912 Wm–2 are incident on a spherical black body kept in surroundings
of temperature 300 K. Take Stefan-Boltzmann constant σ = 5.7×10–8 Wm–2 K–4 and assume that the energy
exchange with the surroundings is only through radiation. The final steady state temperature of the black
body is close to

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 8

Rate of radiation energy lost by the sphere
= Rate of radiation energy incident on it

JEE Advanced 2014 Paper -2 with Solutions - Question 9

A point source S is placed at the bottom of a transparent block of height 10 mm and refractive index 2.72. It is immersed in a lower refractive index liquid as shown in the figure. It is found that the light emerging from the block to the liquid forms a circular bright spot of diameter 11.54 mm on the top of the block. The refractive index of the liquid is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 9

JEE Advanced 2014 Paper -2 with Solutions - Question 10

Q.No. 11 - 16 carry 3 marks each

This section contains 3 paragraphs, each describing theory, experiments, data etc. Six questions relate to the three paragraphs with two questions on each paragraph. Each question has only one correct answer among the four given options (A), (B), (C) and (D).

Paragraph For Questions 11 & 12

The figure shows a circular loop of radius a with two long parallel wires (numbered 1 and 2) all in the plane of the paper. The distance of each wire from the centre of the loop is d. The loop and the wires are carrying the same current I. The current in the loop is in the counterclockwise direction if seen from above.

Q.

When d ≈ a but wires are not touching the loop, it is found that the net magnetic field on the axis of the
loop is zero at a height h above the loop. In that case

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 10

The direction of magnetic field at the given  Point due to the loop is normally out of the plane. Therefore,
the net magnetic field due the both wires should be into the plane. For this current in wire I should be along
PQ and that in wire RS should be along SR.

JEE Advanced 2014 Paper -2 with Solutions - Question 11

Paragraph

The figure shows a circular loop of radius a with two long parallel wires (numbered 1 and 2) all in the plane of the paper. The distance of each wire from the centre of the loop is d. The loop and the wires are carrying the same current I. The current in the loop is in the counterclockwise direction if seen from above.

Q.

Consider d >> a, and the loop is rotated about its diameter parallel to the wires by 30° from the position
shown in the figure. If the currents in the wires are in the opposite directions, the torque on the loop at its
new position will be (assume that the net field due to the wires is constant over the loop)

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 11

JEE Advanced 2014 Paper -2 with Solutions - Question 12

Paragraph for Questions 13 & 14

In the figure a container is shown to have a movable (without friction) piston on top. The container and
the piston are all made of perfectly insulating material allowing no heat transfer between outside and
inside the container. The container is divided into two compartments by a rigid partition made of a
thermally conducting material that allows slow transfer of heat. The lower compartment of the container
is filled with 2 moles of an ideal monatomic gas at 700 K and the upper compartment is filled with 2
moles of an ideal diatomic gas at 400 K. The heat capacities per mole of an ideal monatomic gas are  and those for an ideal diatomic gas are

Q.

Consider the partition to be rigidly fixed so that it does not move. When equilibrium is achieved, the final
temperature of the gases will be

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 12

Heat given by lower compartment =

Heat obtained by upper compartment =

equating (i) and (ii)
3 (700 – T) = 7 (T – 400)
2100 – 3T = 7 T – 2800
4900 = 10 T T = 490 K

JEE Advanced 2014 Paper -2 with Solutions - Question 13

In the figure a container is shown to have a movable (without friction) piston on top. The container and
the piston are all made of perfectly insulating material allowing no heat transfer between outside and
inside the container. The container is divided into two compartments by a rigid partition made of a
thermally conducting material that allows slow transfer of heat. The lower compartment of the container is filled with 2 moles of an ideal monatomic gas at 700 K and the upper compartment is filled with 2 moles of an ideal diatomic gas at 400 K. The heat capacities per mole of an ideal monatomic gas are
and those for an ideal diatomic gas are

Q.

Now consider the partition to be free to move without friction so that the pressure of gases in both
compartments is the same. Then total work done by the gases till the time they achieve equilibrium will be

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 13

Heat given by lower compartment =

Heat obtained by upper compartment =

By equating (i) and (ii)
5(700 -T) = 7(T - 400)
3000 – 5T = 7T– 2800
6300 = 12 T
T = 525K
Work done by lower gas = nRΔT = – 350 R
Work done by upper gas = nRΔT = +250 R
Net work done - 100 R

JEE Advanced 2014 Paper -2 with Solutions - Question 14

Paragraph for Questions 15 & 16

A spray gun is shown in the figure where a piston pushes air out of a nozzle. A thin tube of uniform cross section is connected to the nozzle. The other end of the tube is in a small liquid container. As the piston
pushes air through the nozzle, the liquid from the container rises into the nozzle and is sprayed out. For the spray gun shown, the radii of the piston and the nozzle are 20 mm and 1 mm respectively. The upper end of the container is open to the atmosphere.

Q.

If the piston is pushed at a speed of 5 mms–1, the air comes out of the nozzle with a speed of

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 14

JEE Advanced 2014 Paper -2 with Solutions - Question 15

If the density of air is ρa and that of the liquid ρl , then for a given piston speed the rate (volume per unit
time) at which the liquid is sprayed will be proportional to

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 15

JEE Advanced 2014 Paper -2 with Solutions - Question 16

Q. no 17-21 cary 3 marks each.

Each queation having two matching lists. Choices for the correct combination of elements from List-I and List-II are given as option (A), (B), (C) and (D) out of which one is correct.

Q.

A person in a lift is holding a water jar, which has a small hole at the lower end of its side. When the lift is at rest, the water jet coming out of the hole hits the floor of the lift at a distance d of 1.2 m from the person. In the following, state of the lift’s motion is given in List I and the distance where the water jet hits the floor of the lift is given in List II. Match the statements from List I with those in List II and select the correct answer using the code given below the lists.

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 16

In P, Q, R no horizontal velocity is imparted to falling water, so d remains same.
In S, since its free fall, aeff = 0
Liquid won’t fall with respect to lift.

JEE Advanced 2014 Paper -2 with Solutions - Question 17

Four charges Q1, Q2, Q3 and Q4 of same magnitude are fixed along the x axis at x = -2a, -a, +a and +2a,
respectively. A positive charge q is placed on the positive y axis at a distance b > 0. Four options of the
signs of these charges are given in List I. The direction of the forces on the charge q is given in List II.
Match List I with List II and select the correct answer using the code given below the lists.

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 17

P: By Q1 and Q4, Q3 and Q2 F is in +y
Q: By Q1 and Q4, Q2 and Q3 F is in +ve x.
R: By Q1 and Q4, F is in +ve y
By Q2 and Q3, F is in –ve y
But later has more magnitude, since its closer to
(0, b). Therefore net force is in – y
S: By Q1 and Q4, F is in +ve x and by Q2 and Q3, F is
in –x, but later is more in magnitude, since its
closer to (0, b). Therefore net force is in –ve x.

JEE Advanced 2014 Paper -2 with Solutions - Question 18

Four combinations of two thin lenses are given in List I. The radius of curvature of all curved surfaces is r
and the refractive index of all the lenses is 1.5. Match lens combinations in List I with their focal length in
List II and select the correct answer using the code given below the lists.

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 18

JEE Advanced 2014 Paper -2 with Solutions - Question 19

A block of mass m1 = 1 kg another mass m2 = 2kg, are placed together (see figure) on an inclined plane
with angle of inclination θ. Various values of θ are given in List I. The coefficient of friction between the
block m1 and the plane is always zero. The coefficient of static and dynamic friction between the block m2
and the plane are equal to μ = 0.3. In List II expressions for the friction on the block m2 are given. Match
the correct expression of the friction in List II with the angles given in List I, and choose the correct option.
The acceleration due to gravity is denoted by g.
[Useful information: tan (5.5o) ≈ 0.1; tan (11.5o) ≈ 0.2; tan (16.5o) ≈ 0.3]

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 19

JEE Advanced 2014 Paper -2 with Solutions - Question 20

Inst.

Q. No 1- 10 carry 3 marks each and 1 as negative marking for incorrect answer

Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE option is correct.

Q.

Charges Q, 2Q and 4Q are uniformly distributed in three dielectric solid spheres 1, 2 and 3 of radii R/2, R
and 2R respectively, as shown in figure. If magnitudes of the electric fields at point P at a distance R from
the centre of spheres 1, 2 and 3 are E1, E2 and E3 respectively, then

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 20

JEE Advanced 2014 Paper -2 with Solutions - Question 21

Q. No 21- 40 carry 3 marks each and 1 as negative marking for incorrect answer

Q.

Assuming 2s – 2p mixing is NOT operative, the paramagnetic species among the following is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 21

JEE Advanced 2014 Paper -2 with Solutions - Question 22

For the process

at T = 100oC and 1 atmosphere pressure, the correct choice is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 22

At 1000C and 1 atmosphere pressure  is at equilibrium. For equilibrium ΔStotal = 0

JEE Advanced 2014 Paper -2 with Solutions - Question 23

For the elementary reaction M → N, the rate of disappearance of M increases by a factor of 8 upon
doubling the concentration of M. The order of the reaction with respect to M is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 23

JEE Advanced 2014 Paper -2 with Solutions - Question 24

For the identification of β-naphthol using dye test, it is necessary to use

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 24

JEE Advanced 2014 Paper -2 with Solutions - Question 25

Isomers of hexane, based on their branching, can be divided into three distinct classes as shown in the
figure.

The correct order of their boiling point is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 25

III > II > I
More the branching in an alkane, lesser will be the surface area, lesser will be the boiling point

JEE Advanced 2014 Paper -2 with Solutions - Question 26

The major product in the following reaction is

[Figure

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 26

JEE Advanced 2014 Paper -2 with Solutions - Question 27

Under ambient conditions, the total number of gases released as products in the final step of the reaction
scheme shown below is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 27

JEE Advanced 2014 Paper -2 with Solutions - Question 28

The product formed in the reaction of SOCl2 with white phosphorous is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 28

JEE Advanced 2014 Paper -2 with Solutions - Question 29

Hydrogen peroxide in its reaction with KIO4 and NH2OH respectively, is acting as a

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 29

JEE Advanced 2014 Paper -2 with Solutions - Question 30

The acidic hydrolysis of ether (X) shown below is fastest when

Figure

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 30

When two phenyl groups are replaced by two para methoxy group, carbocation formed will be more stable

JEE Advanced 2014 Paper -2 with Solutions - Question 31

Q. No 31- 36 carry 3 marks each and 1 as negative marking for incorrect answer

Paragraph For Questions 31 and 32

X and Y are two volatile liquids with molar weights of 10 g mol-1 and 40 g mol-1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is first observed at a distance d cm from the plug soaked in X.Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.

Q.

The value of d in cm (shown in the figure), as estimated from Graham’s law, is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 31

JEE Advanced 2014 Paper -2 with Solutions - Question 32

X and Y are two volatile liquids with molar weights of 10 g mol-1 and 40 g mol-1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is first observed at a distance d cm from the plug soaked in X.Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.

Q.

The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is
due to

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 32

As the collision frequency increases then molecular speed decreases than the expected.

JEE Advanced 2014 Paper -2 with Solutions - Question 33

Paragraph For Questions 33 and 34

Schemes 1 and 2 describe sequential transformation of alkynes M and N. Consider only the major products formed in each step for both schemes

Q.

The product X is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 33

JEE Advanced 2014 Paper -2 with Solutions - Question 34

Schemes 1 and 2 describe sequential transformation of alkynes M and N. Consider only the major products formed in each step for both schemes

Q.

The correct statement with respect to product Y is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 34

JEE Advanced 2014 Paper -2 with Solutions - Question 35

Paragraph For Questions 35 and 36

An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarized in the scheme given below.

Q.

M1, Q and R, respectively are

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 35

JEE Advanced 2014 Paper -2 with Solutions - Question 36

An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarized in the scheme given below.

Q.

Reagent S is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 36

JEE Advanced 2014 Paper -2 with Solutions - Question 37

Q. No 37- 40 carry 3 marks each and 1 as negative marking for incorrect answer

This section contains four questions, each having two matching lists. Choices for the correct combination of elements from List-I and List-II are given as options (A), (B), (C) and (D), out of which one is correct.

Q.

Match each coordination compound in List-I with an appropriate pair of characteristics from List-II and
select the correct answer using the code given below the lists
{en = H2NCH2CH2NH2; atomic numbers: Ti = 22, Cr = 24; Co= 27; Pt = 78)

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 37

(P) [Cr(NH3)4Cl2]Cl → Paramagnetic and exhibits cis-trans isomerism
(Q) [Ti(H2O)5Cl](NO3)2 → Paramagnetic and exhibits ionization isomerism
(R) [Pt(en)(NH3)Cl]NO3 → Diamagnetic and exhibits ionization isomerism
(S) [Co(NH3)4(NO3)2]NO3 → Diamagnetic and exhibits cis-trans isomerism

JEE Advanced 2014 Paper -2 with Solutions - Question 38

Match the orbital overlap figures shown in List-I with the description given in List-II and select the correct
answer using the code given below the lists.

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 38

JEE Advanced 2014 Paper -2 with Solutions - Question 39

Different possible thermal decomposition pathways for peroxyesters are shown below. Match each
pathway from List I with an appropriate structure from List II and select the correct answer using the code
given below the lists.

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 39

JEE Advanced 2014 Paper -2 with Solutions - Question 40

Match the four starting materials (P, Q, R, S) given in List I with the corresponding reaction schemes
(I, II, III, IV) provided in List II and select the correct answer using the code given below the lists.

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 40

JEE Advanced 2014 Paper -2 with Solutions - Question 41

Q. No 41- 50 carry 3 marks each and 1 as negative marking for incorrect answer

This section contains 10 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE option is correct.

Q.

Three boys and two girls stand in a queue. The probability, that the number of boys ahead of every girl is at
least one more than the number of girls ahead of her, is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 41

Either a girl will start the sequence or will be at second position and will not acquire the last position as
well.

JEE Advanced 2014 Paper -2 with Solutions - Question 42

In a triangle the sum of two sides is x and the product of the same two sides is y. If x2 - c2 = y, where c is
the third side of the triangle, then the ratio of the in-radius to the circum-radius of the triangle is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 42

JEE Advanced 2014 Paper -2 with Solutions - Question 43

Six cards and six envelopes are numbered 1, 2, 3, 4, 5, 6 and cards are to be placed in envelopes so that
each envelope contains exactly one card and no card is placed in the envelope bearing the same number and
moreover the card numbered 1 is always placed in envelope numbered 2. Then the number of ways it can
be done is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 43

JEE Advanced 2014 Paper -2 with Solutions - Question 44

The common tangents to the circle x2 + y2 = 2 and the parabola y2 = 8x touch the circle at the points P, Q
and the parabola at the points R, S. Then the area of the quadrilateral PQRS is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 44

JEE Advanced 2014 Paper -2 with Solutions - Question 45

The quadratic equation p(x) = 0 with real coefficients has purely imaginary roots. Then the equation
p(p(x)) = 0 has

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 45

Hence real or purely imaginary number can not satisfy P(P(x)) = 0.

JEE Advanced 2014 Paper -2 with Solutions - Question 46

The following integral  is equal to

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 46

JEE Advanced 2014 Paper -2 with Solutions - Question 47

The function y = f (x) is the solution of the differential equation  satisfying

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 47

JEE Advanced 2014 Paper -2 with Solutions - Question 48

Let f : [0, 2] → R be a function which is continuous on [0, 2] and is differentiable on (0, 2) with f(0) = 1.

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 48

JEE Advanced 2014 Paper -2 with Solutions - Question 49

Coefficient of x11 in the expansion of (1 + x2)4 (1 + x3)7 (1 + x4)12 is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 49

2x1 + 3x2 + 4x3 = 11
Possibilities are (0, 1, 2); (1, 3, 0); (2, 1, 1); (4, 1, 0).
Required coefficients

JEE Advanced 2014 Paper -2 with Solutions - Question 50

For   the equation sinx + 2sin2x - sin3x = 3 has

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 50

which is not possible at same time
Hence, no solution

JEE Advanced 2014 Paper -2 with Solutions - Question 51

SECTION – 2 : Comprehension Type (Only One Option Correct)

Q. No 51- 56 carry 3 marks each and 1 as negative marking for incorrect answer

This section contains 3 paragraph, each describing theory, experiments, data etc. Six questions relate to the three paragraphs with two questions on each paragraph. Each question has only one correct answer among the four given options (A), (B), (C) and (D).

Paragraph For Questions 51 and 52

Box 1 contains three cards bearing numbers 1, 2, 3 ; box 2 contains five cards bearing numbers 1, 2, 3, 4, 5 ; and box 3 contains seven cards bearing numbers 1, 2, 3, 4, 5, 6, 7. A card is drawn from each of the boxes. Let xi be the number on the card drawn from the ith box, i = 1, 2, 3.

Q.

The probability that x1 + x2 + x3 is odd, is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 51

Case I : One odd, 2 even
Total number of ways = 2 x 2 x 3 + 1 x 3 x 3 + 1 x 2 x 4 = 29.
Case II: All 3 odd
Number of ways = 2 x 3 x 4 = 24
Favourable ways = 53

JEE Advanced 2014 Paper -2 with Solutions - Question 52

Box 1 contains three cards bearing numbers 1, 2, 3 ; box 2 contains five cards bearing numbers 1, 2, 3, 4, 5 ; and box 3 contains seven cards bearing numbers 1, 2, 3, 4, 5, 6, 7. A card is drawn from each of the boxes. Let xi be the number on the card drawn from the ith box, i = 1, 2, 3.

Q.

The probability that x1 , x2 , x3 are in an arithmetic progression, is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 52

Here 2x2 = x1 + x3
x1 + x3 = even
Hence number of favourable ways =

JEE Advanced 2014 Paper -2 with Solutions - Question 53

Paragraph For Questions 53 and 54

Let a, r, s, t be non-zero real numbers. Let P(at2, 2at), Q, R(ar2, 2ar) and S(as2, 2as) be distinct points on the parabola y2 = 4ax. Suppose that PQ is the focal chord and lines QR and PK are parallel, where K is the point (2a, 0).

Q.

The value of r is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 53

JEE Advanced 2014 Paper -2 with Solutions - Question 54

Let a, r, s, t be non-zero real numbers. Let P(at2, 2at), Q, R(ar2, 2ar) and S(as2, 2as) be distinct points on the parabola y2 = 4ax. Suppose that PQ is the focal chord and lines QR and PK are parallel, where K is the point (2a, 0).

Q.

If st = 1, then the tangent at P and the normal at S to the parabola meet at a point whose ordinate is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 54

JEE Advanced 2014 Paper -2 with Solutions - Question 55

Paragraph For Questions 55 and 56

Given that for each  exists. Let this limit be g(a). In addition, it is given that the function g(a) is differentiable on (0, 1)

Q.

The value of g(1/2) is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 55

JEE Advanced 2014 Paper -2 with Solutions - Question 56

Given that for each  exists. Let this limit be g(a). In addition, it is given that the function g(a) is differentiable on (0, 1)

Q.

The value of g'(1/2) is

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 56

We have g (a) = g (1 - a) and g is differentiable
Hence g'(1/2) =0

JEE Advanced 2014 Paper -2 with Solutions - Question 57

SECTION – 3 : Matching List Type (Only One Option Correct)

Q. No 57- 60 carry 3 marks each and 1 as negative marking for incorrect answer

This section contains four questions, each having two matching list. Choices for the correct combination of elements from List-I and List-II are given as options (A), (B), (C) and (D), out of which ONE is correct.

Q.

Match the following

A

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 57

JEE Advanced 2014 Paper -2 with Solutions - Question 58

Match the following:

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 58

JEE Advanced 2014 Paper -2 with Solutions - Question 59

Let  be defined by

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 59

JEE Advanced 2014 Paper -2 with Solutions - Question 60

Let

Detailed Solution for JEE Advanced 2014 Paper -2 with Solutions - Question 60

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