JEE Main Maths Test- 5 - JEE MCQ

# JEE Main Maths Test- 5 - JEE MCQ

Test Description

## 25 Questions MCQ Test Mock Tests for JEE Main and Advanced 2024 - JEE Main Maths Test- 5

JEE Main Maths Test- 5 for JEE 2024 is part of Mock Tests for JEE Main and Advanced 2024 preparation. The JEE Main Maths Test- 5 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Maths Test- 5 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Maths Test- 5 below.
Solutions of JEE Main Maths Test- 5 questions in English are available as part of our Mock Tests for JEE Main and Advanced 2024 for JEE & JEE Main Maths Test- 5 solutions in Hindi for Mock Tests for JEE Main and Advanced 2024 course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt JEE Main Maths Test- 5 | 25 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study Mock Tests for JEE Main and Advanced 2024 for JEE Exam | Download free PDF with solutions
 1 Crore+ students have signed up on EduRev. Have you?
JEE Main Maths Test- 5 - Question 1

### The differential equation of all circles which pass through the origin and whose centres lie on y-axis is

Detailed Solution for JEE Main Maths Test- 5 - Question 1
Toolbox:
Equation of a family of circles in (x−h)^2+(y−k)^2=a^2 where (h,k) are the centers and a is the radius.
If the given equation has 'n' arbitary constants, then the given equation will be of h order

We are asked to form the differential equations of all circles which pass through the orgin and whose centers lies on y-axis
Since it is given that the center lies on the y-axis, the sketch of the circle is as shown

JEE Main Maths Test- 5 - Question 2

### If  , then solution of above equation is

JEE Main Maths Test- 5 - Question 3

### Order and degree of differential equation  are

JEE Main Maths Test- 5 - Question 4

Differential equation for y = A cos αx + B sin αx where A and B are arbitrary constants is

JEE Main Maths Test- 5 - Question 5
The solution of the differential equation   is
JEE Main Maths Test- 5 - Question 6

The integrating factor of the different equation dy/dx ( x log x ) + y = 2 log x is given by:

JEE Main Maths Test- 5 - Question 7

Solution of   is

Detailed Solution for JEE Main Maths Test- 5 - Question 7

JEE Main Maths Test- 5 - Question 8

The solution   is

JEE Main Maths Test- 5 - Question 9

Solution of differential equation xdy – ydx = 0 represents

JEE Main Maths Test- 5 - Question 10

Integration factor of   is

JEE Main Maths Test- 5 - Question 11

A continuously differentiable function  y = f(x) ∈ (0,π ) satisfying  y = 1 + y, y (0) = 0 = y(π)is

JEE Main Maths Test- 5 - Question 12

The solution of   is

JEE Main Maths Test- 5 - Question 13
A primitive of sin x cos x is
JEE Main Maths Test- 5 - Question 14
JEE Main Maths Test- 5 - Question 15
If   then
JEE Main Maths Test- 5 - Question 16

JEE Main Maths Test- 5 - Question 17
JEE Main Maths Test- 5 - Question 18

The primitive of | x |, when x < 0 is

JEE Main Maths Test- 5 - Question 19
JEE Main Maths Test- 5 - Question 20
*Answer can only contain numeric values
JEE Main Maths Test- 5 - Question 21

If  is differentiable at x = 1, then the value of (A + 4B) is

Detailed Solution for JEE Main Maths Test- 5 - Question 21

ƒ(x) is continuous  A + B = A + 3 – B
⇒ B = 3/2
ƒ(x) is differentiable 2B = 6 + A
⇒ A = –3

*Answer can only contain numeric values
JEE Main Maths Test- 5 - Question 22

A function y = ƒ(x) satisfies the differential equation  The value of |ƒ"(1)| is

Detailed Solution for JEE Main Maths Test- 5 - Question 22

ƒ'(x) + x2ƒ(x) = –2x, ƒ(1) = 1
⇒    ƒ'(1) + 1 = –2     ⇒    ƒ'(1) = –3
ƒ''(x) + 2xƒ(x) + x2ƒ'(x) = –2
ƒ''(1) + 2ƒ(1) + ƒ'(1) = –2
ƒ''(1) = 3 – 4 = –1  ⇒ |ƒ''(1)| = 1

*Answer can only contain numeric values
JEE Main Maths Test- 5 - Question 23

If the foci of the ellipse  and the hyperbola  coincide, then the value of b2 is :-

*Answer can only contain numeric values
JEE Main Maths Test- 5 - Question 24

Let f(x) = min.  for all x ≤ 1. Then the area bounded by y = f(x) and the x-axis is :-

Detailed Solution for JEE Main Maths Test- 5 - Question 24

*Answer can only contain numeric values
JEE Main Maths Test- 5 - Question 25

The area bounded by the loop of the curve 4y2 = x2 (4 – x2) is :-

Detailed Solution for JEE Main Maths Test- 5 - Question 25

## Mock Tests for JEE Main and Advanced 2024

357 docs|148 tests
Information about JEE Main Maths Test- 5 Page
In this test you can find the Exam questions for JEE Main Maths Test- 5 solved & explained in the simplest way possible. Besides giving Questions and answers for JEE Main Maths Test- 5, EduRev gives you an ample number of Online tests for practice

### Up next

 Test | 25 ques
 Test | 25 ques
 Test | 25 ques
 Test | 25 ques
 Test | 25 ques

## Mock Tests for JEE Main and Advanced 2024

357 docs|148 tests

### Up next

 Test | 25 ques
 Test | 25 ques
 Test | 25 ques
 Test | 25 ques
 Test | 25 ques