JEE Main Physics Test- 7 - JEE MCQ

# JEE Main Physics Test- 7 - JEE MCQ

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## 25 Questions MCQ Test Mock Tests for JEE Main and Advanced 2025 - JEE Main Physics Test- 7

JEE Main Physics Test- 7 for JEE 2024 is part of Mock Tests for JEE Main and Advanced 2025 preparation. The JEE Main Physics Test- 7 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Physics Test- 7 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Physics Test- 7 below.
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JEE Main Physics Test- 7 - Question 1

### The sun subtends an angle of half a degree at the pole of a concave mirror which has a radius of curvature of 15 metres. Then the size (disameter) of the image of the sun formed by the concave mirror is

Detailed Solution for JEE Main Physics Test- 7 - Question 1
See , in this case ,
u = ∞ , Let x be the diameter ,
using mirror formula ,
1/u + 1/v = 1/f
v = f ,
let ∆ be the angle ,
∆ = x/f
x = ∆f ,
Multiply these two u will get diameter , or u can change your angle to radian.
JEE Main Physics Test- 7 - Question 2

### A convex lens of focal length 24 cms is placed 12 cms in front of a convex mirror. It is found that when a pin is placed 36 cms in front of the lens, it coincides with its own inverted image formed by the lens and the mirror.Then the focal length of the mirror is

Detailed Solution for JEE Main Physics Test- 7 - Question 2
A convex lens of focal length 24 cm is placed 12 cm in front of a convex mirror. It is found that when a pin is placed 36 cm in front of the lens, it coincides with its own inverted image formed by the lens and the mirror. Then the focal length of the mirror is 30 cm.
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JEE Main Physics Test- 7 - Question 3

### A ray of light makes an angles of with the horizontal and strikes a plane mirror which is inclinedat an angle to the horizontal.The angle  for which the reflected ray becomes vertical, is

Detailed Solution for JEE Main Physics Test- 7 - Question 3
Draw a ray-diagram,
Angle between the reflected and incident ray = 80degree (Final ray is vertical and incidence is 10 wrt horizontal)
Angle of incidence = angle of reflected ray = 40degree
Angle of reflected ray with mirror = 90degree – 40degree = 50degree
So, angle with horizontal = 90degree – 50degree = 40degree
JEE Main Physics Test- 7 - Question 4

The refractive index of a given piece of transparent quartz if greatest for

Detailed Solution for JEE Main Physics Test- 7 - Question 4
CORRECT OPTION IS (B).
JEE Main Physics Test- 7 - Question 5

If the critical angle for total internal reflection from a medium to vacuum is the velocity of light in
the medium is

Detailed Solution for JEE Main Physics Test- 7 - Question 5
We should know Snell's law
n1 sin I = n2 sin r
for critical angle the value of r becomes 90 degree
n1 / n2 = sin 90 / sin 30 = 2
also
n1/n2 = v2/v1
2 = 3 * 10^8 / velocity in medium
v= 1.5 * 10^8
JEE Main Physics Test- 7 - Question 6
Two immiscible liquids are in a cylindrical vessel of depths of 8.4 cm and 7.8 cm, their refractive indices being 1.2 and 1.3 respectively. An object O at the bottom isseen from vertically
above the liquids. The upward displacement in cm in its apparant position is

JEE Main Physics Test- 7 - Question 7

X is a small angled prism of angle made of a material of refractive index 1.5. A ray of light is made incident as shown in figure. M is a plane mirror.The angle of deviation for the ray reflected from the mirror. M with respect to incident ray is

JEE Main Physics Test- 7 - Question 8
The face AC of a prism ABC of refracting angle is silvered. A ray is incident on face AB at an angle of as shown in figure. The refracted ray undergoes reflection on face AC and retraces its path. The refractive index of the prisms is

Detailed Solution for JEE Main Physics Test- 7 - Question 8
Use triangle property180 - (90 + 30 ) = 60r = (90 - 60) = 30sin i/sin r = Refractive Index (R I)R I = sin 45/sin 30 = √2
JEE Main Physics Test- 7 - Question 9
If half the body of a lens is covered with black paper the image produced by the lens will
JEE Main Physics Test- 7 - Question 10
The distance between the object and the screen is D (greater than 4 times the focal length of a convex lens). Real images of the object are obtained on the screen for two positions of the lens that are separated by distance d apart. The ratio of size of the images in the two positions of the lens are
JEE Main Physics Test- 7 - Question 11
An object 20 cm high produces using a lens a real image of 80cm.When an object is shifted by 5 cm a real image 40 cm high is produced.The power of the lens is
JEE Main Physics Test- 7 - Question 12
When the object is at a distance x1 and x2, a real and a virtual image of the same size are formed
respectively. The focal length of the convex lens is
JEE Main Physics Test- 7 - Question 13
An isotropic source of 2 candela  produces a light flux equal to
JEE Main Physics Test- 7 - Question 14
A lamp is hanging at a height 40 cm from the center of a table. If its height is increased by 10 cm, the illuminance on the table will decrease by
JEE Main Physics Test- 7 - Question 15
The intensity of light at a distance r from the axis of a long cylindrical source is proportional to
JEE Main Physics Test- 7 - Question 16
Rainbows are produced when sunlight
JEE Main Physics Test- 7 - Question 17
The magnifying power of telescope can be increased by
JEE Main Physics Test- 7 - Question 18
A movie projector projects an image of length 3.5 m of a 35 mm. movie film on a screen. Neglecting
absorption of light by the film and the air, the ratio of the illumination on the screen is
JEE Main Physics Test- 7 - Question 19
The focal length of a simple convex lens used as a magnifier is 10 cm. For the image to be formed at a distance of distinct vision (D = 25 cm), the object
must be placed away from the lens at a distance of
Detailed Solution for JEE Main Physics Test- 7 - Question 19
JEE Main Physics Test- 7 - Question 20
A person can see objects only at distance greater than 40 cm. He is advised to use lens of power
Detailed Solution for JEE Main Physics Test- 7 - Question 20
*Answer can only contain numeric values
JEE Main Physics Test- 7 - Question 21

A compound microscope has an eyepiece of focal length 10 cm and an objective of focal length 4 cm. Calculate the magnification, if an object is kept at a distance of 5 cm from the objective so that final image is formed at the least distance of distinct vision (20 cm) :-

*Answer can only contain numeric values
JEE Main Physics Test- 7 - Question 22

An object is placed on the axis of a convex lens. Its image is formed 80 cm from the object. The magnification is 3. The focal length of the lens (in cm) is:-

*Answer can only contain numeric values
JEE Main Physics Test- 7 - Question 23

A linear aperture whose width is 0.02 cm is placed immediately in front of a lens of focal length 60 cm. The aperture is illuminated normally by a parallel beam of wavelength 5 × 10–5 cm. The distance of the first dark band of the diffraction pattern from the centre of the screen is :-

Detailed Solution for JEE Main Physics Test- 7 - Question 23

f = D = 60 cm
For first minima,

*Answer can only contain numeric values
JEE Main Physics Test- 7 - Question 24

Young's double slit experment is first performed in air and then in a medium other than air. It is found that 8th bright fringe in the medium lies where 5th dark fringe lies in air. The refractive index of the medium is nearly :-

Detailed Solution for JEE Main Physics Test- 7 - Question 24

*Answer can only contain numeric values
JEE Main Physics Test- 7 - Question 25

Find the ratio of refractive index of transmitted medium with that of incident medium when the Brewster angle is 60 degree.

Detailed Solution for JEE Main Physics Test- 7 - Question 25

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