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Test: Classification of Elements & Periodicity in Properties - 1 - NEET MCQ


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25 Questions MCQ Test Chemistry Class 11 - Test: Classification of Elements & Periodicity in Properties - 1

Test: Classification of Elements & Periodicity in Properties - 1 for NEET 2024 is part of Chemistry Class 11 preparation. The Test: Classification of Elements & Periodicity in Properties - 1 questions and answers have been prepared according to the NEET exam syllabus.The Test: Classification of Elements & Periodicity in Properties - 1 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Classification of Elements & Periodicity in Properties - 1 below.
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Test: Classification of Elements & Periodicity in Properties - 1 - Question 1

f block of the Periodic Table consists of

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 1

Lanthanides, Ce(Z = 58) ñ Lu(Z = 71) and Actinoids comprises of f block elements.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 2

The elements charecterised by the filling of 4 f-orbitals, are:

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 2

Elements characterized by the filling of 4f orbitals are lanthanides.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 3

14 elements after actinium is called

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 3

The correct answer is Option B.

14 elements after actinium is called Actinides.
 

Test: Classification of Elements & Periodicity in Properties - 1 - Question 4

An element belongs to Group 15 and third period of the periodic table. Its electronic configuration will be

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 4

group is 15 so total valence electrons will be 5 while period is 3rd so n value of valence shell will be 3.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 5

It is now recognized that the ‘Modern Periodic Law’ is essentially the consequence of the

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 5

Modern periodic law is essentially the result of periodic variation and electronic configuration.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 6

Metalloids show the properties of

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 6

Metalloids shows both the properties of metals as well as non metals.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 7

One of the following options is not used for explaining atomic radius

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 7

coordinate radius is not used for explaining atomic radius.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 8

Among the alkali metals cesium is the most reactive because

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 8

Among the alkali metals cesium is the most reactive because the outermost electron is more loosely bound than the outermost electron of the other alkali metals.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 9

In which one of the given formulae of xenon compounds there are five α−bonds and three π-bonds in it?

 

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 9

Test: Classification of Elements & Periodicity in Properties - 1 - Question 10

In the modern periodic table

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 10

Horizontal rows are periods while vertical column are groups.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 11

Which of the following statements is false?

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 11

Alkali metals always form ionic bonds.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 12

The order of Decreasing radius is

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 12

vanderwaal radius > Metallic radius > Covalent radius.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 13

For alkali metals, which one of the following trends is INCORRECT?

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 13

Density: Li < Na < K < Rb.
The density of K is lower than that of Na. Thus, option D is incorrect. The correct trend is
Li < K < Na < Rb

Test: Classification of Elements & Periodicity in Properties - 1 - Question 14

Dmitri Mendeleev (1834-1907) and the German chemist, Lothar Meyer (1830-1895) proposed arranging elements in

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 14

They arranged elements in increasing order of atomic weights.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 15

According to the recommendation of International Union of Pure and Applied Chemistry (IUPAC), the groups in the modern periodic table are numbered from

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 15

they are numbered from 1 to 18 1 is alkali metal group and 18 is noble gases.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 16

Ionization enthalpy increases across a period because

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 16

as we move from left to right in a period atomic radii decreases and due to effective nuclear charge outermost electrons are held more closely to the nucleus.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 17

Choose one of the following in th increasing order of bond length

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 17

As the size increases bond length also increases.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 18

For the four successive transition elements (Cr, Mn, Fe and Co), the stability of + 2 oxidation state will be there in which of the following order? (At. nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 18

Mn has most stable +2 stable because Mn+2 had d5 configuration which is most stable.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 19

A transition metal ion exists in its highest oxidation state. It is expected to behave as

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 19

When a transition metal ion is in highest oxidation state it tends to lower its oxidation state by gaining electrons. thus it itself reduces and oxidizes the substance from which it accepts electron. So, it acts as oxidising agent. 

Test: Classification of Elements & Periodicity in Properties - 1 - Question 20

The sequence of ionic mobility in aqueous solution is 

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 20

Smaller the size of cation, higher will be the hydration and its effective size will increase and hence mobility in aqueous solution will decrease. Larger size ions have more ionic mobility due to less hydration. Thus the degree of hydration of M+ ions decreases from Li+ to Cs+. Consequently the radii of the hydrated ion decreases from Li+ to Cs+. Hence the ionic conductance of these hydrated ions increases from Li+ to Cs+ 

Test: Classification of Elements & Periodicity in Properties - 1 - Question 21

In the periodic table Electronegativity generally

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 21

electronegativity increases on moving from left to right while decreases as we move down the group.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 22

Al(3+)<Mg(2+)<Na+<F−<O(2−)<N(3−) The above can be aptly described as

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 22

They are isoelectronic species with same number of electrons. Higher is the atomic number, higher will be the effective nuclear charge, lower will be the size.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 23

Generally, the first ionization energy increases along a period. But there are some exceptions. One which is NOT an exception is ______.

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 23

Na and Mg are not an exception.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 24

Which of the following will have the most negative electron gain enthalpy and which one the least negative? P, S, Cl, F.

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 24

Cl just need one more electrons to get fully filled electronic configuration so it has most negative electron gain enthalpy while P has d3 configuration which is already stable so it cannot accept one electron extra easily so have large positive electron gain enthalpy.

Test: Classification of Elements & Periodicity in Properties - 1 - Question 25

For Atomic numbers greater than 100 IUPAC has made recommendation that until a new element ‘s discovery is proved, and its name is officially recognized, a systematic nomenclature be derived directly from the atomic number of the element using the numerical roots for 0 and numbers 1-9. The name 'sept' in this scheme corresponds to the digit

Detailed Solution for Test: Classification of Elements & Periodicity in Properties - 1 - Question 25

sept is for 7.

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