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Test: Geometrical Isomerism - 2 - NEET MCQ


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30 Questions MCQ Test Chemistry Class 11 - Test: Geometrical Isomerism - 2

Test: Geometrical Isomerism - 2 for NEET 2024 is part of Chemistry Class 11 preparation. The Test: Geometrical Isomerism - 2 questions and answers have been prepared according to the NEET exam syllabus.The Test: Geometrical Isomerism - 2 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Geometrical Isomerism - 2 below.
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Test: Geometrical Isomerism - 2 - Question 1

Direction (Q. Nos. 1-10) This section contains 10 multiple choice questions. Each question has four
 choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

 

Q.

How many different stereoisomers exist for the compound shown?

Test: Geometrical Isomerism - 2 - Question 2

Which compound below has four stereoisomers ? 

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 2

Since in compound a, b and d we have symmetry in the molecule, so both double bonds are identical. THerefore, stereoisomerism is counted from only one bond. This will give us 2 isomers.
In compound c, both double bonds are different, so both will involve GI. N has a lone pair which will also be counted. So, we have 4 isomers in all.

Test: Geometrical Isomerism - 2 - Question 3

Which compound below is capable of showing geometrical isomerism ?

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 3

The correct answer is option B
CH3 – CH = C = C = CH – CH3 will show geometrical isomerism because it is odd cumulene (3 pie bond) and odd cumulene always shows geometrical isomerism 

Test: Geometrical Isomerism - 2 - Question 4

consider the following reaction.

How many different isomers of X satisfy the above condition ?

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 4

The correct answer is Option C.
If C6H3Cl has 4 positional isomers then it’s structure can be;
So, X can be

Test: Geometrical Isomerism - 2 - Question 5

Which isomer below has a stable intramolecular H-bond?

Test: Geometrical Isomerism - 2 - Question 6

A ketone with molar mass of 100 g, has only one positional isomer. How many different enol isomers exist for this ketone? 

Test: Geometrical Isomerism - 2 - Question 7

Carbonyl compound condenses with ammonia as 

How many diffrent dilimines would be obtained on condensation of 2,4- pentanedlone with excess of ammonia ?

Test: Geometrical Isomerism - 2 - Question 8

How many cyclic Isomers (structural and geometrical only) exist for C5H10

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 8

5 isomers are possible. C5H10(CnH2n). Molecules having the CnH2n  formula are most likely to be cyclic alkanes. The five isomers are:

Test: Geometrical Isomerism - 2 - Question 9

How many geometrical isomers exist for the molecule shown below ?

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 9

The correct answer is option B
 
Threegeometrical isomers exits of the molecule given cis-cis, tran-trans and cis-trans.

Test: Geometrical Isomerism - 2 - Question 10

If chlorocyclohexane is subjected to further chlorination, how many different isomers (geometrical plus structural only) of dichiorocyclohexane would be produced? 

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 10

The correct answer is option D
There will be three constitutional isomers i.e. 1,2 dichloro cyclohexane,1,3 dichloro cyclohexane and1,4 dichloro cyclohexane.Each constitutional isomer will have cis and trans configuration thereby making six isomers in all.Also there will be two optically active isomers.
You can understand it better through these infographics
1,2 dichloro cyclohexane

*Multiple options can be correct
Test: Geometrical Isomerism - 2 - Question 11

Direction (Q. Nos. 11-18) This section contains 8 multiple choice questions. Each question has four
choices (a), (b), (c) and (d), out of which ONE or  MORE THANT ONE  is correct.

 

Q.

Choose the correct statement(s) regarding isomers of C2H2C12.

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 11

The correct answers are Option B,C and D.
C2H2C12 => 3 isomers possible.

  1.  1,2-dichloroethane ---> cis
  2.  1,1-dichloroethane ---> trans

(1)
Net dipole moment=0
So, no polar isomer.
(2)

*Multiple options can be correct
Test: Geometrical Isomerism - 2 - Question 12

Dibromo derivative of a hydrocarbon has molar mass of 200 g (Br = 80) and none of the isomers have any ring structure. Which is/are the correct deduction regarding isomers?

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 12

The correct answers are option B & C.
Compound is dibromoethene, it can have 3 isomers (two geometrical isomers (cis & trans) of 1,2 dibromoethene and one is 1,1 dibromoethene).

*Multiple options can be correct
Test: Geometrical Isomerism - 2 - Question 13

Which of the following carbonyls have four enol isomers?

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 13

The correct answers are Options C and D.
 
Enolization involves the α-carbon atom. The ketone 2,4-dimethyl-3-pentanone gives a single enol, since the two α carbons are equivalent. An enol is not a resonance form of a carbonyl compound; the two are constitutional isomers of each other.
 

*Multiple options can be correct
Test: Geometrical Isomerism - 2 - Question 14

Pick up the correct statements regarding isomers of C2FCIBrt

*Multiple options can be correct
Test: Geometrical Isomerism - 2 - Question 15

Enol isomer of which of the following forms six membered stable ring through intramolecular H-bonding?

*Multiple options can be correct
Test: Geometrical Isomerism - 2 - Question 16

Which is/are true regarding pair of geometrical isomers?

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 16

a) Geometric isomerism occurs when two structures with the same connectivity are not inconvertible.
b) The boiling points of the isomers might be different enough that you can separate them by fractional distillation. The affinities for the stationary phase may be different enough that they can be separated by gas chromatography.
c) Geometric isomers are diastereomers, i.e. they are stereoisomers that are not enantiomers. The prefixes cis and trans refer to the relative dispositions of the substituents attached to the doubly bonded carbon atoms. In the cis diastereomer the hydrogen atom attached to one carbon is on the same side of the double bond as the hydrogen attached to the other carbon. In the trans stereoisomer they are on opposite sides.
 

*Multiple options can be correct
Test: Geometrical Isomerism - 2 - Question 17

Which of the following compounds have more than one pairs of stereoisomers?

*Multiple options can be correct
Test: Geometrical Isomerism - 2 - Question 18

A hydrocarbon X (M = 140 g/mol) on catalytic hydrogenation gives C10H22 (Y). Y on chlorination gives only two positional isomers with molecular formula C10H21C1. Which is/are correct about X and Y?

Test: Geometrical Isomerism - 2 - Question 19

Direction (Q. Nos. 19 and 20) Choice the correct combination of elements and column I and coloumn II  are given as option (a), (b), (c) and (d), out of which ONE option is correct.

Q.

Match the quantity from Column I with the types of isomerism from Column II

Codes 

    

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 19

The correct answer is option c

Pentene has two positional isomers, two geometrical isomers and more than four cyclic isomers

1-methoxypropene has two geometrical isomers and more than four cyclic isomers

Dichlorocyclopropane has two positional isomers and two geometrical isomers

2,4,6-octatriene has six geometrical isomers and more than four cyclic isomers

1. Pentene has two positional isomers, two geometrical isomers, and more than four
cyclic isomers.
Pentene (C5H10) is an unsaturated hydrocarbon with the formula C5H10.It has two positional isomers: 1-pentene and 2-pentene. It has two geometrical isomers due to the presence of a double bond. For cyclic isomers, we can have a cyclopentane ring, so the statement is correct.

2.1-methoxypropene has two geometrical isomers and more than four cyclic isomers.
• 1-methoxypropene (CH3O-CH= CH-CH2CH3) has two geometrical isomers due to the presence of a double bond. For cyclic isomers, it can form a cyclic structure by including the oxygen atom, so the statement is correct.
3. Dichlorocyclopropane has two positional isomers and two geometrical isomers.
• Dichlorocyclopropane (C3H4Cl2) has two positional isomers: 1,2- dichlorocyclopropane and 1,3-dichlorocyclopropane. It has two geometrical isomers due to the cis-trans isomerism in the cyclopropane ring. So the statement is correct.

4. 2,4,6-octatriene has six geometrical isomers and more than four cyclic isomers.
• 2,4,6-octatriene (CH3-CH = CH- CH2 - CH=CH- CH2-CH = CH2) has six geometrical isomers because of the three double bonds. For cyclic isomers, it can form various cyclic structures, so the statement is correct.

Test: Geometrical Isomerism - 2 - Question 20

Match the systems in Column I with their corresponding characterstics from Column II

Codes 

    

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 20

The correct answer is option A

Butanone has three tautomers other than the mentioned compound itself and acts as a H-bond acceptor3-pentanone has two tautomers other than the mentioned compound itself and acts as a H-bond acceptorMethanamide has two tautomers other than the mentioned compound itself, forms intermolecular H-bonds with its own molecules and acts as a H-bond acceptor Ethane nitrile  has two tautomers other than the mentioned compound itself and acts as a H-bond acceptor

1. Butanone has three tautomers other than the mentioned compound itself and acts as an H-bond acceptor.
• Butanone (CH3- CO - CH2CH3) can exist in different tautomeric forms. The keto form is the most stable, but it can also undergo keto-enol tautomerism. However, saying it has three tautomers may be misleading. It primarily exists as the keto form with a minor contribution from the enol form. Also, ketones like butanone can act as H-bond acceptors due to the oxygen atom in the carbonyl group. So the statement is correct.
2. 3-pentanone has two tautomers other than the mentioned compound itself and acts as an H-bond acceptor.
• 3-pentanone (CH3- CO - CH2CH2- CH3) can undergo keto-enol tautomerism, so it has an enol form as a tautomer. Also, ketones can act as H-bond acceptors. So the statement is correct.
3. Methanamide has two tautomers other than the mentioned compound itself, forms intermolecular H-bonds with its own molecules, and acts as an H-bond acceptor.
• Methanamide (HCONH2) can exist in different tautomeric forms due to the possibility of hydrogen migration. It can form intermolecular H-bonds with its own molecules, and as an amide, it acts as an H-bond acceptor. So the statement is correct.
4. Ethane nitrile has two tautomers other than the mentioned compound itself and acts as an H-bond acceptor.
• Ethane nitrile (CH3CH2- CN) can undergo tautomerism involving the movement of a hydrogen atom. Also, nitriles like ethane nitrile can act as H-bond acceptors due to the electronegative nitrogen atom. So the statement is correct

Test: Geometrical Isomerism - 2 - Question 21

Direction (Q. Nos. 21-26) This section contains 2 paragraph, wach describing  theory, experiments, data etc. three Questions related to paragraph have been  given.Each question have only one correct answer among the four given  ptions  (a),(b),(c),(d)

Passage I

A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane. 

Q. 

How many structural isomers of the starting hydrocarbon, on catalytic hydrogenation can give the mentioned alkane? 

Test: Geometrical Isomerism - 2 - Question 22

Passage I

A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane. 
Q. 
How many of the above unsaturated hydrocarbons are capable of exhibiting geometrical isomerism? 

Test: Geometrical Isomerism - 2 - Question 23

Passage I

A number of unsaturated hydrocarbons have the same molecular formula C11H22. All of these hydrocarbons on catalytic hydrogenation gives the same 3,4,6-trimethyloctane. 
Q.

If the product alkane is 3,6-dimethyloctane, how many different isomers. (structural plus geometrical only) of alkenes can give this product? 

Test: Geometrical Isomerism - 2 - Question 24

Passage II

Consider the dollowing molecules to answer the next three questions.

Q.

How many stereoisomers exist for this molecule ?

Detailed Solution for Test: Geometrical Isomerism - 2 - Question 24

the number of stereogenic centres which comprises of optically active carbon and the carbon showing geometrical isomerism. In the above picture, there is only one geometric isomer and chiral carbon. So there is 2 stereogenic centre.
stereoisomers = 2n
=22
= 4

Test: Geometrical Isomerism - 2 - Question 25

Passage II

Consier the following molecules to answer the next three questions.

Q.

Treatment of halogenated hydrocarbon with NaBH4 reduces secondary and tertiary halides but olefinic bonds are not affected. If the above mentioned compound is reduced with NaBH4, how many different isomers would be produced? 
 

Test: Geometrical Isomerism - 2 - Question 26

Passage II

Consider the following molecules to answer the next three questions.

Q.

If the given compound is carefully reduced so that only double bond is reduced, leaving halide bonds intact, how many different stereoisomers would be produced? 

*Answer can only contain numeric values
Test: Geometrical Isomerism - 2 - Question 27

Direction (Q. Nos. 27-30) This section contains 4 questions. when worked out will result in an integer from 0 to 9 (both inclusive)

Q.

For hydrocarbon with molecular formula C5H8, how many acyclic isomers without consecutive pi-bonds are possible? 


Detailed Solution for Test: Geometrical Isomerism - 2 - Question 27

C5H8 has the following three isomers :

CH3CH2CH2C≡CH

CH3CH2C≡CCH3

(CH3)2CH−C≡CH

*Answer can only contain numeric values
Test: Geometrical Isomerism - 2 - Question 28

How many different isomers of alkene with molecular formula C7H14, on catalytic hydrogenation, can give 3-methyl hexane? 


Detailed Solution for Test: Geometrical Isomerism - 2 - Question 28

The correct answer is 9

*Answer can only contain numeric values
Test: Geometrical Isomerism - 2 - Question 29

How many geometrical isomers exist in 1,2,4-trichlorocyclopentane? 


*Answer can only contain numeric values
Test: Geometrical Isomerism - 2 - Question 30

How many geometrical isomers exist for 1-bromo-2-chloro-3-fluorocyclopropane? 


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