Test: Area Of Triangles

Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. If area (ΔAOD) = 37sq cm, then area (ΔBOC) =

ABCD is a parallelogram whose diagonals intersect at O. A line through O intersects AB at P and DC at Q. Then

The area of a right triangle is 30 sq cm. If the base is 5 cm, then the hypotenuse must be

AE is a median to side BC of triangle ABC. If area(ΔABC) = 24 cm, then area(ΔABE) =

D is the mid point of side BC of ABC and E is the mid point of BD. If O is the mid point of AE, then

In the figure, ∠PQR = 90°, PS = RS, QP = 12 cm and QS = 6.5 cm. The area of ΔPQR is

​

In the given figure, if parallelogram ABCD and rectangle ABEF are of equal area then:

In ΔABC, if L and M are points on AB and AC respectively such that LM BC then ar (LMC) is equal to

In a parallelogram ABCD, P is a point in interior of parallelogram ABCD. If ar (||gm ABCD) = 18 cm² then [arΔAPD) + ar(ΔCPB)] is :​

Diagonals AC and BD of a trapezium ABCD with AB ll DC intersect each other at O. If area (ΔAOD)=37sq cm, then area (ΔBOC) = ?

In ΔPQR, if D and E are points on PQ and PR respectively such that DE || QR, then ar (PQE) is equal to

ABC is a triangle in which D is the mid point of BC and E is the mid point of AD. Then area (ΔBED) is equal to

In a parallelogram ABCD, E and F are any two points on the sides AB and BC respectively. If ar (ΔDCE) is 12 cm², then ar(ΔADF) is

​

AD is one of the medians of a Δ ABC. X is any point on AD. Then, the area of ΔABX is equal to

ABC and BDE are two equilateral triangles such that D is the mid point of BC. AE intersects BC in F. Then ar (BDE) is equal to

In figure P, Q are points on sides AB, AC respectively of ΔABC such that ar (BCQ) = ar (BCP). Then,

In ΔABC, E is the mid-point of median AD. Area(ΔBED) =