Chemistry Exam  >  Chemistry Tests  >  Inorganic Chemistry  >  Test: Chemical Bonding- 2 - Chemistry MCQ

Test: Chemical Bonding- 2 - Chemistry MCQ


Test Description

30 Questions MCQ Test Inorganic Chemistry - Test: Chemical Bonding- 2

Test: Chemical Bonding- 2 for Chemistry 2024 is part of Inorganic Chemistry preparation. The Test: Chemical Bonding- 2 questions and answers have been prepared according to the Chemistry exam syllabus.The Test: Chemical Bonding- 2 MCQs are made for Chemistry 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Chemical Bonding- 2 below.
Solutions of Test: Chemical Bonding- 2 questions in English are available as part of our Inorganic Chemistry for Chemistry & Test: Chemical Bonding- 2 solutions in Hindi for Inorganic Chemistry course. Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free. Attempt Test: Chemical Bonding- 2 | 30 questions in 90 minutes | Mock test for Chemistry preparation | Free important questions MCQ to study Inorganic Chemistry for Chemistry Exam | Download free PDF with solutions
Test: Chemical Bonding- 2 - Question 1

Which is having different shape among:

Test: Chemical Bonding- 2 - Question 2

Among the following pairs in which the two species are not isostructural is:

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Chemical Bonding- 2 - Question 3

Which of the following set of ions/ molecules is isoelectric and structural?

Detailed Solution for Test: Chemical Bonding- 2 - Question 3

Isoelectronic species are those have same number of electrons.

 

Test: Chemical Bonding- 2 - Question 4

In allene (C3H4), the type(s) of hybridisation of the carbon atoms is (are) 

Test: Chemical Bonding- 2 - Question 5

The atom that form discrete polyatomic molecule in its elemental state are:

Detailed Solution for Test: Chemical Bonding- 2 - Question 5

Sulfur forms discrete polyatomic molecule as in S8

Carbon forms discrete polyatomic molecules as in diamond, etc.

Test: Chemical Bonding- 2 - Question 6

Which one of the following pairs is isoelectronic?

Test: Chemical Bonding- 2 - Question 7

The structure of XeF4 is:

Detailed Solution for Test: Chemical Bonding- 2 - Question 7

The correct answer is Square Planar. The structure of XeF4 is Square Planar. This is because XeF4 follows the VSEPR theory, and the two lone pairs of electrons in XeF4 are placed in a plane that is perpendicular inside an octahedral setting. They face opposite to each other, which is at a distance of 180°. This is the sole reason for the square planar shape of xenon tetrafluoride.

Test: Chemical Bonding- 2 - Question 8

Which of the following species has two non bonded electron pairs on the central atom:

Detailed Solution for Test: Chemical Bonding- 2 - Question 8

In TeCl4 out of 6 electrons:bonded electrons are 4,non-bonded electron pair is 1.
In ClF3 out of 7 electrons:bonded electrons are 3,non-bonded electron pairs are 2.
In PCl3 out of 5 electrons:bonded electrons are 3,non-bonded electron pair is 1.
In ICl2− out of (7+1=8) electrons:bonded electrons are 2,non-bonded electron pairs are 3.

Test: Chemical Bonding- 2 - Question 9

The shape and expected hybridization of BrO3- and HOCl are:

Test: Chemical Bonding- 2 - Question 10

I3- ion is linear having the hybridization:

Test: Chemical Bonding- 2 - Question 11

The hybridization of atomic orbital of nitrogen in NO2+, NO3- and NH4+ are:

Detailed Solution for Test: Chemical Bonding- 2 - Question 11

Test: Chemical Bonding- 2 - Question 12

pπ – dπ bonding is present in which molecule

Detailed Solution for Test: Chemical Bonding- 2 - Question 12


Test: Chemical Bonding- 2 - Question 13

The ion which is iso-electronic with CO is —————

Detailed Solution for Test: Chemical Bonding- 2 - Question 13

Both CO (6 + 8=14) and CN (6 + 7+1= 14) have the same electrons. so they are iso-electronic with each other.

Test: Chemical Bonding- 2 - Question 14

Angles in XeO3F2 are equal with which molecule:

Test: Chemical Bonding- 2 - Question 15

Covalent-molecules are usually held in a crystal structure by

Detailed Solution for Test: Chemical Bonding- 2 - Question 15

The atoms in molecular covalent molecules are held together by strong covalent bonds. Although these bonds are strong, there are only weak forces of attraction between molecules. These weak attractive forces are called van der Waal’s forces and can be broken with little energy.

Test: Chemical Bonding- 2 - Question 16

Hybridization on anionic carbon in allyl anion is:

Test: Chemical Bonding- 2 - Question 17

Hybridization and shape of N(SiH3)3 is:

Test: Chemical Bonding- 2 - Question 18

Hybridization in carbon atoms of

Test: Chemical Bonding- 2 - Question 19

Hybridization in (C6H5)3C (on negative carbon) is:

Detailed Solution for Test: Chemical Bonding- 2 - Question 19

Test: Chemical Bonding- 2 - Question 20

Hybridization of carbon C3O2 and CO2 are:

Test: Chemical Bonding- 2 - Question 21

Hybridization on central atom in SOF4 is:

Test: Chemical Bonding- 2 - Question 22

Hybridization on central atom in Be2C is:

Test: Chemical Bonding- 2 - Question 23

Hybridization in N2 is:

Detailed Solution for Test: Chemical Bonding- 2 - Question 23

Pi bond electrons don’t contribute when we calculate the hybridization. So due to one sigma bond and one lone pair hybridization will be “sp”.

Hence D is correct.

Test: Chemical Bonding- 2 - Question 24

Hybridization on the central atom in H3Ois:

Test: Chemical Bonding- 2 - Question 25

Hybridization in Si in Si4O116– is:

Test: Chemical Bonding- 2 - Question 26

In octahedral structure the pair of ‘d’ orbitals invo lved is:

Test: Chemical Bonding- 2 - Question 27

The ONO angle is maximum is:

Test: Chemical Bonding- 2 - Question 28

Hybridization state of boron and oxygen in boric acid is:

Detailed Solution for Test: Chemical Bonding- 2 - Question 28

The state of hybridization of boron and oxygen atom in boric acid (H3​BO3​) is sp2,sp3  respectively.

Boric acid ; has a network structure in which boron is trigonal having sp2 and each oxygen atom is tetrahedral having sp3-hybridization with two lone pair of electrons on oxygen.

Test: Chemical Bonding- 2 - Question 29

Which is correct order of bond angle:

Test: Chemical Bonding- 2 - Question 30

Which of These is Pyramidal in Shape? 

Detailed Solution for Test: Chemical Bonding- 2 - Question 30

PCl3 has sp3-hybridised phosphorus, with one lone pair. Therefore, molecule has pyramidal shape like ammonia.

48 videos|92 docs|41 tests
Information about Test: Chemical Bonding- 2 Page
In this test you can find the Exam questions for Test: Chemical Bonding- 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Chemical Bonding- 2, EduRev gives you an ample number of Online tests for practice
48 videos|92 docs|41 tests
Download as PDF