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Test: Elimination Reaction - Chemistry MCQ


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15 Questions MCQ Test Organic Chemistry - Test: Elimination Reaction

Test: Elimination Reaction for Chemistry 2024 is part of Organic Chemistry preparation. The Test: Elimination Reaction questions and answers have been prepared according to the Chemistry exam syllabus.The Test: Elimination Reaction MCQs are made for Chemistry 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Elimination Reaction below.
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Test: Elimination Reaction - Question 1

Which of the following is incorrect statement for the giver reaction?
Formation of III involves E1 reaction in given reaction

Detailed Solution for Test: Elimination Reaction - Question 1

Rate of formation of II and IV similar because H & D are approximately of same size.
C–H & C–D bond breaking is the part of RDS hence rate in I is slower than III
It undergo E2 not via E1 because carbocation is not stable.

Test: Elimination Reaction - Question 2

Which of the following order is incorrect for the rate of E2 reaction?

Detailed Solution for Test: Elimination Reaction - Question 2

For 5-Bromocycloheptene > 4-Bromocycloheptene, more stable product leads to faster rate of reaction. Product formed by E2 of 4-Bromocycloheptene is more stable than 5-Bromocycloheptene. So, rate of reaction 4-Bromocycloheptene is fater than 5-Bromocycloheptene. So option 5-Bromocycloheptene > 4-Bromocycloheptene is incorrect.
Find the following order is incorrect / not for the rate of E2 reaction
For 2-Bromo- I -phenylbutane > 3-Bromo- I-phenylbutane, it is true rate of reaction for 2-Bromo- I -phenylbutane is more than 3-Bromo- I-phenylbutane as product formed in former is more stable due to resonance.
5-Bromocycloheptene greater 4-Bromocycloheptene is incorrect for the rate of E2 reaction
For 3-Bromocyclohexene > Bromocyclohexane, it is true rate of reaction for 3-Bromocyclohexeneis more than Bromocyclohexane as product formed in former is more stable.
Bromo-I-phenylbutane as product formed in former is more stable due to resonance
For 3-Bromo-2-methylpentane > 2-Bromo-4-methylpentane, it is true rate of reaction for 3-Bromo-2-methylpentane more stable than 2-Bromo-4-methylpentane as product formed in former is more stable.
2-Bromo-4-methylpentane as product formed in former is more stable

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Test: Elimination Reaction - Question 3

Which of the following statement (s) is/are true about the following eliminations?
Find the following statement (s) is/are true about the following eliminations
(1) Hoffmann product is major product in I (2) Saytzeff product is major product in I (3) Hoffmann product is major product in II (4) Saytzeffproduct is major product in II

Detailed Solution for Test: Elimination Reaction - Question 3

Here correct is statement 1 and 4 are true. Due to steric hinderence tert-Butyl alcohol anion will attack less substituted C-H bond.
Ethanol anion will attack more substituted C-H bond to form more stable alkene.
Ethanol anion will attack more substituted C-H bond to form more stable alkene

Test: Elimination Reaction - Question 4

Detailed Solution for Test: Elimination Reaction - Question 4




Test: Elimination Reaction - Question 5

Which of the following reaction will not show addition elimination mechanism?

Detailed Solution for Test: Elimination Reaction - Question 5

Compounds a, b and c will follow Addition- Elimination mechanism.
Compounds a, b & c will follow Addition-Elimination mechanism
Compound will follow elimination -addition mechanism, as shown in below reaction. NH anion first attack on the ring which lead to formation of benzyne ring and further addition of -NH2 will take place.
Compound will follow elimination-addition mechanism NH–anion first attack on the ring

Test: Elimination Reaction - Question 6

Assuming both the reactions as E1, where will the expected ratio between KH/KD lies between?
Find the expected ratio between KH/KD that lies between for the reactions as E1

Detailed Solution for Test: Elimination Reaction - Question 6

In E1 elimination RDS is the formation of carbocation from halide hence C – H and C – D are not the part of RDS there KH/KD is approx. 1.
E1 elimination RDS is the formation of carbocation from halide hence C – H & C – D

Test: Elimination Reaction - Question 7

When the all-cis isomer of C6H6Cl6 (2, 3, 4, 5, 6-Hexachlorocyclohexane) is heated with alc.KOH, what will be the most probable product?

Detailed Solution for Test: Elimination Reaction - Question 7

Here three times Elimination(E2) occurs and three pie bond will be formed and three water molecule will be removed as shown below.
3 times Elimination occurs & three pie bond will be formed & three water molecule removed

Test: Elimination Reaction - Question 8

Which of the following statement is correct?

Detailed Solution for Test: Elimination Reaction - Question 8

E2 is a concerted reaction in which bonds break and new bonds form at the same time in a single step. Order of reactivity of alkyl halides towards E2 dehydrohalogenation is found to be 3o > 2o > 1o. In E2 reaction both hydrogen and leaving group should be antiperiplanar and that’s why In E2 elimination different stereoisomer (diastereomer) converts into different stereo product.

Test: Elimination Reaction - Question 9

 In which reaction product formation takes place by hoffmann rule?
Find the type of product formation takes place by hoffmann rule

Detailed Solution for Test: Elimination Reaction - Question 9

All of the above molecules will form product by hoffmann rule that is less substituted C-H bond will be attacked because more stable product will be formed via this in all cases.
I.
The molecules will form product by hoffmann rule that is less substituted C-H bond
II.
The leaving group are F & NH2 type to produce hoffmann product
When leaving group are F & NH2 type then they give hoffmann product.

 

III.
The more stable product will be formed via this in all cases in given reaction
IV.The product formation takes place by hoffmann rule is I, II, III & IV

Test: Elimination Reaction - Question 10

Which of the following are incorrect statement?
Br is better leaving group so formation of removal of leaving group is incorrect

Detailed Solution for Test: Elimination Reaction - Question 10

Due to inductive effect of halogen it stabilize the negative charge on adjacent to carbon atom, as X will withdraw the electron towards itself.

Test: Elimination Reaction - Question 11

Predict the product for the following elimination reaction.
Find the product for the following elimination reaction

Detailed Solution for Test: Elimination Reaction - Question 11

Iodine is a better leaving group than chlorine, so attach will be at iodine site.
Iodine is a better leaving group than chlorine in given diagram

Test: Elimination Reaction - Question 12

Which of the following statements is correct for alkyl halide?

Detailed Solution for Test: Elimination Reaction - Question 12

In most unimolecular reactions of alkyl halide SN1 reaction is favoured over E1 reaction. E1 mechanism is favoured as compared to SN1 mechanism by branching at carbon increases, as more steric hinderence at the attacking site will leads to E1 mechanism.

Test: Elimination Reaction - Question 13

Which of the following statement is correct regarding the following reaction?
Find the following statement is correct regarding the following reaction

Detailed Solution for Test: Elimination Reaction - Question 13

Exocyclic alkene are more stable than endo beacuse of but due to “steric hindrance” the less substituted alkene is formed.
Major product is exocyclic alkene formed according to Hoffmann in given diagram

Test: Elimination Reaction - Question 14

Which incorrect about alkyl bromide having molecular formula C5H11Br?

Detailed Solution for Test: Elimination Reaction - Question 14

From the following isomers of C5H11Br, except IX all are capable of E2 elimination.
The following isomers of C5H11Br, except IX all are capable of E2 elimination

Test: Elimination Reaction - Question 15

Which of the following is not the examples of E1CB reaction?

Detailed Solution for Test: Elimination Reaction - Question 15

Compound d will give E2 reaction, CL is a better leaving group so formation of carboanion and removal of leaving group occurs simultaneously. But E1CB reaction shown by poor leaving group like in compounds a, b and c.
E1CB reaction shown by poor leaving group like in compounds a, b & c

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