Practice Test: Probability - Class 10 MCQ

# Practice Test: Probability - Class 10 MCQ

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## 25 Questions MCQ Test Mathematics (Maths) Class 10 - Practice Test: Probability

Practice Test: Probability for Class 10 2024 is part of Mathematics (Maths) Class 10 preparation. The Practice Test: Probability questions and answers have been prepared according to the Class 10 exam syllabus.The Practice Test: Probability MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Practice Test: Probability below.
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Practice Test: Probability - Question 1

### If A be the event such that P(A) = 2/5, then P(not A) is equal to

Detailed Solution for Practice Test: Probability - Question 1

We know Probability law which is law of  complement
Which is P(not A)=1-P(A)
Where P(A)=⅖
P(not A)=1-⅖=3/5

Practice Test: Probability - Question 2

### What are the chances that no two boys are sitting together for a photograph if there are 5 girls and 2 boys?

Detailed Solution for Practice Test: Probability - Question 2

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Practice Test: Probability - Question 3

### In a single throw of a die, the probability of getting a multiple of 3 is

Detailed Solution for Practice Test: Probability - Question 3

Given : A die is thrown once .

A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.

If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6

Number of possible outcomes are = 6

Let E = Event of getting a getting a multiple of 3

Multiples of 3 are = 3, 6

Number of outcome favourable to E = 2

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 2/6  = 1/3

Hence, the probability of getting a  multiple of 3, P(E) = 1/3

Practice Test: Probability - Question 4

Find the probability of getting a number greater than 2 when a die is thrown

Detailed Solution for Practice Test: Probability - Question 4

Probability of getting a number greater than 2 is
number greater than 2 = 4
total outcomes = 6
so, 4/6
=2/3

Practice Test: Probability - Question 5

If a die is rolled, the probability of getting a number between 1 and 6 is

Detailed Solution for Practice Test: Probability - Question 5

Between 1 and 6, meaning not 1 or 6, then we have four favorable choices (2, 3, 4, 5) out of six possible outcomes (1, 2, 3, 4, 5, 6). Therefore your probability is 4/6 = 2/3.

Practice Test: Probability - Question 6

What are the chances that no two boys are sitting together for a photograph if there are 5 girls and 2 boys?

Detailed Solution for Practice Test: Probability - Question 6

Practice Test: Probability - Question 7

What is the probability of getting one head and one tail when a coin is tossed 2 times?

Detailed Solution for Practice Test: Probability - Question 7

Assume that is an equal chance of the coin landing on heads or tail (the coin is fair, not biased).

Probability of coin landing on head and then on tails=1/2 x 1/2=1/4

Probability of coin landing on tails and then on heads= 1/2 x 1/2 =1/4

Therefore, probability of getting one head and one tail in two coin tosses=1/4+1/4=1/2

Practice Test: Probability - Question 8

What is the probability of getting two heads when a coin is tossed twice?

Practice Test: Probability - Question 9

What is the probability of getting no head when two coins are tossed?

Detailed Solution for Practice Test: Probability - Question 9

Two coins are tossed simultaneously, so there are four possible outcomes ie, HH,HT,TT,TH
Total number of outcomes=4
Probability of getting no head=no. of favourable outcomes/ total no. of outcomes
=1/4

Practice Test: Probability - Question 10

In a simultaneous throw of two coins the probability of getting at least one head is

Detailed Solution for Practice Test: Probability - Question 10

Two coins are simultaneously tossed.
So sample space={HH,HT,TH,TT}
No. of favourable outcomes=getting at least one head={HH,HT,TH}
=3
Total number of outcomes=4
Probability of getting at least one head=No. of favourable outcomes/Total number of outcomes
=3/4

Practice Test: Probability - Question 11

The probability of getting a jack card is

Detailed Solution for Practice Test: Probability - Question 11

Total number of outcomes = 52
Favourable outcomes = four cards are of Jack.
Total number of favourable outcomes = 4

Probability = Number of favourable outcomes/ Total number of outcomes.

Required probability = P(jack) = 4/52= 1/13.

Hence, the probability of getting Jack is 1/13.

Practice Test: Probability - Question 12

The probability of getting a face card is

Detailed Solution for Practice Test: Probability - Question 12

Total Cards: 52

Total Face cards: 12 (4 Jacks, 4 Queens, 4 Kings)

P(Choosing a Face card) =12/52= 3/13

Practice Test: Probability - Question 13

One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the card drawn is :

The probability of getting a '10' of black suit is

Detailed Solution for Practice Test: Probability - Question 13

Let G be the favourable outcomes of getting 10 of black suit then

⇒ n(G) = 2

Therefore,  P(G)

Practice Test: Probability - Question 14

One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the card drawn is :

The probability of getting a red and a king card is

Detailed Solution for Practice Test: Probability - Question 14

Let D be the favourable outcomes of getting red and a king, then n(D)=2 Therefore,

Practice Test: Probability - Question 15

A bag contains 4 red balls and 3 green balls. A ball is drawn at random. The probability of drawing a green ball is

Detailed Solution for Practice Test: Probability - Question 15

Total number of outcomes=7
No. of favourable outcomes=3 (no. Of green balls)
Probability of getting a green ball=No. Of favourable outcomes/Total no. of outcomes=3/7

Practice Test: Probability - Question 16

P(E) + P(E)¯ is equal to

Practice Test: Probability - Question 17

Which one of the following cannot be the probability of an event

Practice Test: Probability - Question 18

Which one of the following cannot be the probability of an event

Detailed Solution for Practice Test: Probability - Question 18

The probability of an event cannot be negative in any case, thus −1.5 cannot be the probability of an event. The probability of happening of an event always lies between 0 to 1, i.e., 0≤P(E)≤1.

Practice Test: Probability - Question 19

Probability of an impossible event is equal to

Practice Test: Probability - Question 20

If P(E1) = 1/6, P (E2) = 1/3 , P (E3) = 1/6 , where E1, E2, E3 and E4 are elementary events of a random experiment, then P (E4) is equal to

Practice Test: Probability - Question 21

Cards each marked with one of the numbers 4, 5, 6,...., 20 are placed in a box and mixed thoroughly. One card is drawn at random from the box. Then, the probability of getting an even prime number is

Detailed Solution for Practice Test: Probability - Question 21

We have one and only even prime number which is 2. So no. of favourable outcomes= 0  and total no. of outcomes=17
Probability of getting 2 =0 this means that 2 cannot occur .

Practice Test: Probability - Question 22

A bag contains 5 red and 4 black balls. A ball is drawn at random from the bag. Then, the probability of getting a black ball is

Practice Test: Probability - Question 23

Find the probability of getting a head in a throw of a coin.

Practice Test: Probability - Question 24

Two fair coins are tossed simultaneously. Find the probability of Getting only one head

Detailed Solution for Practice Test: Probability - Question 24

When two coins are tossed, the sample space of possible outcomes would be the set

S = {HH, HT, TH, TT}

where H: the outcome is a “Head” and T: the outcome is a “Tail” and the probabilities associated with each of these outcomes are equal assuming the coins are fair.

When we say at most 1 “Head” outcome, it means that only 1 of the two coins show up a head or that the no “Head” outcome shows up.

If A is the event obtaining only 1 “Head” outcome, then the set of outcomes that makes up event A is

A = {(HT), (TH)}

Hence, the probability of event A is

P(A) = 2/4

Practice Test: Probability - Question 25

Two fair coins are tossed simultaneously. Find the probability of Getting atleast one head

Detailed Solution for Practice Test: Probability - Question 25

When two coins are tossed simultaneously then the possible outcomes obtained are {HH, HT, TH, and TT}.

Here H denotes head and T denotes tail.

Therefore, a total of 4 outcomes obtained on tossing two coins simultaneously.

Consider the event of obtaining at the most one head. At most one head is obtained means either no head is obtained or one head is obtained.

The outcome(s) favourable to no head obtained is {TT}

The outcome(s) favourable to one head obtained is {HT, TH}

Therefore, the event of obtaining at most one head has 3 favourable outcomes. These are TT, HT and TH.

Therefore, the probability of obtaining at most one head = 3/4.

## Mathematics (Maths) Class 10

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## Mathematics (Maths) Class 10

116 videos|420 docs|77 tests