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This mock test of CAT LRDI MCQ for CAT helps you for every CAT entrance exam.
This contains 32 Multiple Choice Questions for CAT CAT LRDI MCQ (mcq) to study with solutions a complete question bank.
The solved questions answers in this CAT LRDI MCQ quiz give you a good mix of easy questions and tough questions. CAT
students definitely take this CAT LRDI MCQ exercise for a better result in the exam. You can find other CAT LRDI MCQ extra questions,
long questions & short questions for CAT on EduRev as well by searching above.

*Answer can only contain numeric values

QUESTION: 1

Group Question

Answer the following question based on the information given below.

The table below shows the series of activities that are required to complete a particular project. The dependent activities can start only when the activity/activities on which they are dependent on is/are completed.

If the project has to be completed in the minimum possible duration, then how many hours 3 would be required to complete the project assuming 8 working hours in a day?

Solution:

All the activities are plotted in the Gantt chart shown above.

The number written beside each activity represents the number of man power required for that activity.

Calculation of man power requirement on any given day is done as follows:

Consider as an example Day 6; the activities which would be in progress on Day 6 would be B, C, F and N. Hence, the total man power required for Day 6 would be 15.

The minimum time that would be required to execute the project completely is 24 days, as is evident from graph above.

Total hours required would be 24 x 8 = 192 hours

Answer: 192

*Answer can only contain numeric values

QUESTION: 2

The table below shows the series of activities that are required to complete a particular project. The dependent activities can start only when the activity/activities on which they are dependent on is/are completed.

At the end of the 13 ^{th} day, what can be the maximum number of scheduled activities that can be completed?

Solution:

At the end of the 13^{ttl} day, the following activities can be completed are A, B, C, D, E, F, G, H, N and J; i.e. a total of 10 activities.

Answer: 10

*Answer can only contain numeric values

QUESTION: 3

The table below shows the series of activities that are required to complete a particular project. The dependent activities can start only when the activity/activities on which they are dependent on is/are completed.

On any given day, what can be the maximum number of men working simultaneously?

Solution:

The Maximum number of men that could be working simultaneously is 20 (on Day 14 and 15).

Answer: 20

*Answer can only contain numeric values

QUESTION: 4

The workers who have been working continuously right from day 1 to the last day of the project are to be awarded a special recognition award. What can be the maximum number of workers are eligible for the award?

Solution:

The activity that ends on last day is O and this activity required only 2 workers.

••• There could be maximum 2 workers who could be eligible for this special award.

Answer: 2

QUESTION: 5

Group Question

Answer the following question based on the information given below.

The following table gives the ranking of 10 countries in various parameters.

A lower numerical value represents a better ranking. The overall ranking of a country is better than others if it has a higher ranking in at least 3 of the 5 parameters.

Which country has an overall ranking of 9?

Solution:

Italy has rank 10 in two parameters and 9 in GDP. So, every country other than Spain must definitely have better overall ranking. Comparing ranks of Spain and Italy, we conclude that overall ranking of Italy and Spain must be 10 and 9 respectively.

Hence, option 4.

Note: Russia also has rank 10 in two parameters. But Russia is not given as an option it can be ignored.

QUESTION: 6

The following table gives the ranking of 10 countries in various parameters.

A lower numerical value represents a better ranking. The overall ranking of a country is better than others if it has a higher ranking in at least 3 of the 5 parameters.

Which of this country has a better overall ranking than India?

Solution:

As seen earlier, overall ranking of Italy and Spain must be 10 and 9 respectively.

Now comparing ranks of Russia and Spain, Russia has better overall ranking and hence Russia's rank must be 8.

By observation, USA and China have lower numerical ranks. Comparing the ranks, USA will be ranked 1 and China will be ranked 2.

Among the remaining countries, India has better rank in Population, GDP and Nuclear Power. So, India must be ranked 3^{rd}.

Among the remaining countries, Japan has better rank in Population, GDP and Nuclear Power. So, Japan must be ranked 4^{th}.

Continuing likewise, overall ranks of Argentina, Canada and Australia are 7, 5 and 6 respectively.

Hence, option 4.

QUESTION: 7

The following table gives the ranking of 10 countries in various parameters.

A lower numerical value represents a better ranking. The overall ranking of a country is better than others if it has a higher ranking in at least 3 of the 5 parameters.

How many countries have an overall rank higher than Japan, but have a lower ranking in ‘Nuclear Power’?

Solution:

Overall rank of only three countries ( USA, China and India) is higher than Japan.

But their nuclear rank also is higher.

Hence, option 1.

QUESTION: 8

The following table gives the ranking of 10 countries in various parameters.

How many countries have an overall numerical rank between the overall ranks of Russia and Argentina?

Solution:

As seen earlier, overall ranks of Argentina and Russia are 7 and 8. Thus, there is no country between them.

Hence, option 1.

QUESTION: 9

The following table gives the ranking of 10 countries in various parameters.

Which country has an overall rank 5?

Solution:

From the previous solutions, we know that Canada has an overall rank 5.

Hence, option 2.

QUESTION: 10

Study the following information carefully and answer the questions that follow.

A jailor instructed all inmates from Cell 1 to 8 to stand in a row. The jailor was very strict and since he didn’t mention the direction, the inmates stood in a straight row facing either north or south without asking him any further question. They stood in such a manner that no three consecutive inmates faced the same direction. The jailor then asked each of them to shout out loud the number of inmates he can see ahead of him. The following table gives the number reported by each inmate:

Further, it is also given that the number of inmates facing south was not more than four.

**How many different arrangements are possible?**

Solution:

Let’s first number the places as shown in the figure-

We can see that inmate 5 sees 0 people in front of him. So, he must be standing at the extreme and facing the same direction i.e. north when standing in front or south when standing at last.

Similarly, inmate 6 sees 7 people. So, he must stand at P facing south or at W facing north.

Now, there are 2 people who see 6 people in front of them. So, they must be facing opposite direction (i.e. one who stands at Q faces south and one who stands at V faces north) and stand at one place among Q and V.

Also, inmate 2 sees 2 people ahead of him while inmate 7 sees 5 people. So, they must be facing the same direction standing at one position among R and U.

Similarly, 3 and 4 must be standing at one position among S and T facing the same direction.

So, positions of the 8 inmates can be concluded as:

Let us now decide on the directions for each of them:

The person from Q must definitely be facing south. Apart from this, the person facing south will increase by 2. Since the number of inmates facing south was not more than four, the number of person facing south has to be 3. If positions P and W are facing south, all others will have to face north which is not possible as no three consecutive inmates faced the same direction. So, person on P and W must be facing north. So, one of the pair of R-U or S-T must be facing south. But when person on U faces north, three consecutive people i.e. U, V, and W must be facing north which is not possible. Thus, pair S-T must be facing south. In this way, we can figure out the whole arrangement-

QUESTION: 11

Study the following information carefully and answer the questions that follow.

A jailor instructed all inmates from Cell 1 to 8 to stand in a row. The jailor was very strict and since he didn’t mention the direction, the inmates stood in a straight row facing either north or south without asking him any further question. They stood in such a manner that no three consecutive inmates faced the same direction. The jailor then asked each of them to shout out loud the number of inmates he can see ahead of him. The following table gives the number reported by each inmate:

Further, it is also given that the number of inmates facing south was not more than four.

**Who among the following is definitely facing South?**

Solution:

Let’s first number the places as shown in the figure-

We can see that inmate 5 sees 0 people in front of him. So, he must be standing at the extreme and facing the same direction i.e. north when standing in front or south when standing at last.

Similarly, inmate 6 sees 7 people. So, he must stand at P facing south or at W facing north.

Now, there are 2 people who see 6 people in front of them. So, they must be facing opposite direction (i.e. one who stands at Q faces south and one who stands at V faces north) and stand at one place among Q and V.

Also, inmate 2 sees 2 people ahead of him while inmate 7 sees 5 people. So, they must be facing the same direction standing at one position among R and U.

Similarly, 3 and 4 must be standing at one position among S and T facing the same direction.

So, positions of the 8 inmates can be concluded as:

Let us now decide on the directions for each of them:

The person from Q must definitely be facing south. Apart from this, the person facing south will increase by 2. Since the number of inmates facing south was not more than four, the number of person facing south has to be 3. If positions P and W are facing south, all others will have to face north which is not possible as no three consecutive inmates faced the same direction. So, person on P and W must be facing north. So, one of the pair of R-U or S-T must be facing south. But when person on U faces north, three consecutive people i.e. U, V, and W must be facing north which is not possible. Thus, pair S-T must be facing south. In this way, we can figure out the whole arrangement-

We can see that inmate from cell 7 definitely faces south.

QUESTION: 12

Study the following information carefully and answer the questions that follow.

A jailor instructed all inmates from Cell 1 to 8 to stand in a row. The jailor was very strict and since he didn’t mention the direction, the inmates stood in a straight row facing either north or south without asking him any further question. They stood in such a manner that no three consecutive inmates faced the same direction. The jailor then asked each of them to shout out loud the number of inmates he can see ahead of him. The following table gives the number reported by each inmate:

Further, it is also given that the number of inmates facing south was not more than four.

**Between inmate from cell 5 and inmate from cell 2 (both excluded), how many inmates are facing North?**

Solution:

Let’s first number the places as shown in the figure-

We can see that inmate 5 sees 0 people in front of him. So, he must be standing at the extreme and facing the same direction i.e. north when standing in front or south when standing at last.

Similarly, inmate 6 sees 7 people. So, he must stand at P facing south or at W facing north.

Now, there are 2 people who see 6 people in front of them. So, they must be facing opposite direction (i.e. one who stands at Q faces south and one who stands at V faces north) and stand at one place among Q and V.

Also, inmate 2 sees 2 people ahead of him while inmate 7 sees 5 people. So, they must be facing the same direction standing at one position among R and U.

Similarly, 3 and 4 must be standing at one position among S and T facing the same direction.

So, positions of the 8 inmates can be concluded as:

Let us now decide on the directions for each of them:

The person from Q must definitely be facing south. Apart from this, the person facing south will increase by 2. Since the number of inmates facing south was not more than four, the number of person facing south has to be 3. If positions P and W are facing south, all others will have to face north which is not possible as no three consecutive inmates faced the same direction. So, person on P and W must be facing north. So, one of the pair of R-U or S-T must be facing south. But when person on U faces north, three consecutive people i.e. U, V, and W must be facing north which is not possible. Thus, pair S-T must be facing south. In this way, we can figure out the whole arrangement-

We can see that among the positions, Q, R, S, and T, 2 are facing north. Thus, ‘2’ is the correct answer.

QUESTION: 13

The following table shows the income of different divisions Manufacturing, Retail, Logistics and IT of a company XYZ Corporation in four different cities of India in the years 2014 and 2015.

**What is the number of divisions of XYZ Corporation where, for at least two cities, there was no increase in income from 2014 to 2015?**

Solution:

Manufacturing division did not show any increase from 2014 to 2015 in Delhi and Chennai.

Retail division did not show any increase from 2014 to 2015 in Mumbai and Delhi.

Logistics division did not show any increase from 2014 to 2015 in Delhi, Kolkata and Chennai.

These 3 divisions comply with the criterion given in the question.

QUESTION: 14

Group Question

Answer the following question based on the information given below.

The bar graph, the line graph and the pie chart represent the total rice production in India (from 2008 to 2013), the total rice exported from India (from 2008 to 2013) and the statewise breakup of the production for the year 2010.

In how many years was there a greater than 5% increase in the percentage of rice exported as compared to the previous year?

Solution:

The rice exported as a percentage of the total rice produced; and the percentage increase in the export percentage of the rice can be calculated as shown in the table above.

It is clearly seen from the table that the percentage increase in the export percentage was more than 5% in 3 years - 2009, 2010 and 2011.

Hence, option 3.

QUESTION: 15

The bar graph, the line graph and the pie chart represent the total rice production in India (from 2008 to 2013), the total rice exported from India (from 2008 to 2013) and the statewise breakup of the production for the year 2010.

If the state-wise composition of production remained the same for all 6 years and it was decided that the production from no more than 3 states would be utilized to meet the export requirements, then in how many years would India have exported less than the required quantity? For this question, assume that the quantities actually exported are the required quantities. Also, for any state considered for rice export, all the rice produced in a certain year is exported in that year itself.

Solution:

Consider the solution to the previous question.

The maximum amount of rice ever exported in a single year was 74.747% of the rice produced in that year (2011). So, the maximum export requirement in any given year is 74.747% of production.

Now, the statewise composition of the rice production remains constant throughout the years.

Since a maximum of 3 states can be used to meet the export requirements, we consider the three states that contribute the most each year.

Punjab (35%), Haryana (20%) and Maharashtra (20%) are the top-3 contributors to the rice production each year, and their total contribution is 75% of the total production.

Since all the rice that is produced in these three states is exported, the exports in each year always exceed the export requirements for that year.

Hence, there is no year in the given period where India has exported less than the required quantity.

Hence, option 4.

QUESTION: 16

The bar graph, the line graph and the pie chart represent the total rice production in India (from 2008 to 2013), the total rice exported from India (from 2008 to 2013) and the statewise breakup of the production for the year 2010.

If in the previous question, the percentage share of Punjab has continuously kept decreasing by 500 basis points (100 basis points = 1%) since 2008 and correspondingly the percentage share of UP has continuously kept increasing by 500 basis points, then in how many years would India have exported less than the required quantity? Again, rice could be exported from not more than 3 states.

Solution:

Consider the solution to both the previous questions.

The year-wise export requirements are as given in the first table above.

Also, keeping in mind the chnage in the contribution of Punjab and UP each year, the year-wise and state-wise compositions are:

Now we can observe that the requirements for the respective years can be met as follows:

2008 => Punjab alone

2009=> Punjab + Maharashtra (or Haryana) + any other state

2010 => Punjab + Maharashtra + Haryana

2011 => Punjab + Any 2 from Maharashtra, Haryana and UP + MP

2012 => Punjab + UP + Any one from Maharashtra and Haryana + MP

2013 => UP + Any 2 from Punjab, Maharashtra and Haryana + MP

Thus, India was able to export more than the export requirement in only 3 years (2008 to 2010) when not more than 3 states were considered.

Hence, option 3.

QUESTION: 17

The figures for the year 2014 are projected as follows:

The production in million tones of each of the 5 states has increased, but the % increase is not constant. It is as follows:

It is also given that the projected exports are 10% higher than those of year 2013. In how many years was the % change in the % of rice exported with respect to the previous year lesser than that for 2014? Assume data from previous question, if required.

Solution:

••• The total projected production in million tones in 2014 = 190.374 Projected exports in 2014 = 10% more than those in 2013 =>132 x l.l = 145.2 million tones

••• Projected % of exports in 2014 = (145.2/190.37) x 100 = 76.27%

••• In two years the % change over previous year was lesser than that in 2014.

Hence, option 4.

*Answer can only contain numeric values

QUESTION: 18

Group Question

Answer the following question based on the information given below.

Three friends Pradeep, Dinesh and Manish started a business of manufacturing soaps, shampoos and deodorants. For the first month, they contributed in the ratio of 5 : 6 : 7. On each day of that month, they manufactured soaps and shampoos such that the cost incurred due to total soap production was thrice of that of the total cost of shampoos production. Also, the production cost of seven units of soap was equal to nine units of shampoos. The combined selling price of a unit of soap and shampoo was Rs. 30. In the next month, they started with the production of deodorants as well whose cost of production per day was thrice the combined cost of production of soaps and shampoos per day. For the second month, the number of deodorants was l/6th of the total number of soaps and shampoos manufactured per day. There are 30 days in the 1st month of the production when they manufactured only soaps and shampoos. And further, the production happened on all the days of the month.

If the selling price of one unit of soap is Rs. 10 and the total sales in the first month is Rs. 4,44,600, then what is the difference in the number of units of soaps and shampoos sold in a day assuming that the entire production has been sold off?

Solution:

Let production cost of a soap, a shampoo and a deodorant be a, b, and c respectively.

Let number of units of soaps, shampoos and deodorants produced per day be x, y and z respectively.

By the given conditions,

1) c = 3 {xa +yb)

2) xa = 3yb and 7a = 9b

x : y = 21 : 9

So, x = 21 k and y = 9k, for some constant k

As selling price of soap is Rs. 10, selling price of shampoo is Rs. 20.

Total sales for the first month = 30(21 k x 10 + 9k x 20) = 30 x 390k 30 x 390& = 444600

So, k=38

Difference in the number of units of soaps and shampoos = 12k= 12 x 38 = 456

Answer: 456

*Answer can only contain numeric values

QUESTION: 19

Three friends Pradeep, Dinesh and Manish started a business of manufacturing soaps, shampoos and deodorants. For the first month, they contributed in the ratio of 5 : 6 : 7. On each day of that month, they manufactured soaps and shampoos such that the cost incurred due to total soap production was thrice of that of the total cost of shampoos production. Also, the production cost of seven units of soap was equal to nine units of shampoos. The combined selling price of a unit of soap and shampoo was Rs. 30. In the next month, they started with the production of deodorants as well whose cost of production per day was thrice the combined cost of production of soaps and shampoos per day. For the second month, the number of deodorants was l/6th of the total number of soaps and shampoos manufactured per day. There are 30 days in the 1st month of the production when they manufactured only soaps and shampoos. And further, the production happened on all the days of the month.

If the total amount invested by Pradeep in the first month was Rs. 35,000 and the number of units of soap manufactured was 6330, then what was the cost price of each unit of shampoo? [Round off your answer upto two decimal places.]

Solution:

Since the amount invested by Pradeep is Rs. 35,000, it implies that the total investment by three friends put together would be (35000/5) x (5 + 6 + 7) = 7000 x 18 = 126000

Hence the investment per day would be Rs. 4,200.

The production cost of soaps per day = 3/4 x 4200 = Rs. 3,150 The production cost of shampoos per day = Rs. 1,050 Number of units of shampoo manufactured = 9/21 x 6330

The cost per unit of shampoo would be (1050 x 21)/(9 x 6330) = 0.39

QUESTION: 20

Three friends Pradeep, Dinesh and Manish started a business of manufacturing soaps, shampoos and deodorants. For the first month, they contributed in the ratio of 5 : 6 : 7. On each day of that month, they manufactured soaps and shampoos such that the cost incurred due to total soap production was thrice of that of the total cost of shampoos production. Also, the production cost of seven units of soap was equal to nine units of shampoos. The combined selling price of a unit of soap and shampoo was Rs. 30. In the next month, they started with the production of deodorants as well whose cost of production per day was thrice the combined cost of production of soaps and shampoos per day. For the second month, the number of deodorants was l/6th of the total number of soaps and shampoos manufactured per day. There are 30 days in the 1st month of the production when they manufactured only soaps and shampoos. And further, the production happened on all the days of the month.

On a day in next month, 2000 units of deodorant were manufactured and the cost of production of soaps was Rs. 15,000. What would be the cost of production of a set of a soap, a shampoo and a deodorant? [Round off your answer to the nearest integer.]

Solution:

Since 2000 units of Deodorants are manufactured it implies that the number of units of soap manufactured is 2000/5 x 21 = 8400 and the number of units of shampoos manufactured is 2000/5 x 9 = 3600

The production cost of soaps is Rs. 15,000, implies that the production cost of shampoo is 15000/3 = Rs. 5,000

And the production cost of deodorants is 3(15000 + 5000) = Rs. 60,000.

The cost of a single unit of soap would be 15000/8400 ~ Rs. 1.8

Cost of a single unit of shampoo would be 5000/3600 ~ Rs. 1.4

And cost of single unit of Deodorant would be 60000/2000 = Rs. 30

Hence the cost of a single set of soap, shampoo and a deodorant would be 1.8 + 1.4 + 30 = Rs. 33.20

Answer: 33

*Answer can only contain numeric values

QUESTION: 21

If the total number of items manufactured on a day in second month is 2100 and the total cost of production on that day is Rs. 8,400, then what is the approximate profit Marks (in Rs.) on that day when the selling price of a unit of soap, shampoo and a deodorant is Rs. 5, Rs. 8 and Rs. 10 respectively?

Solution:

Production of soaps = (21/35) x 2100 = 1260 Production of shampoos = (9/35) x 2100 = 540

Production of deodorants = (5/35) x 2100 = 300 The total production cost = Rs. 8400 Total sales would be (1260 x 5) + (540 x 8) + (300 x 10) = 13620 ••• The total profit for the day would be (13620 - 8400) = Rs. 5220

Answer: 5220

QUESTION: 22

Group Question

Answer the following question based on the information given below.

Each of the six men - Abhinav, Jagan, Saket, Shishir, Shreshth and Vinit got married to six different women among Debika, Ekta, Ishita, Kriti, Nikita and Smita. Their marriages took place in six different months - January, February, March, April, May and June and at six different places - Bhilai, Dehradun, Delhi, Moradabad, Mumbai and Jalandhar,not necessarily in that order. It is also known that:

i. Marriage of Jagan and Ishita took place in the month of February and that of Debika in the month of April.

ii. Nikita’s marriage took place in Delhi after Saket’s marriage but not in the month of June.

iii. Ekta’s marriage took place in Jalandhar and she is not married to Saket. She got married before Shreshth but not in the month of January.

iv. Kriti and Shishir got married in Bhilai. The marriage didn’t take place in January.

v. Smita got married to either Abhinav or Shreshth.

vi. Neither Ishita’s nor Debika’s marriage took place in Mumbai.

Who got married to Nikita?

Solution:

Marriage of Jagan and Ishita took place in the month of February and that of Debika in the month of April. As Saket was not married to Nikita, Ekta, Kriti, Smita and Ishita, he must have married to Debika.in the month of April. Now as Nikita’s marriage took place after Saket but not in June, she must have got married in the month of May. As Ekta didn’t get married in January and she got married before Shreshth, she must have got married in March. This leaves Kriti and Shishir to be married in June and Smita to be married in January. As Shreshth is married after Ekta, he has to be married to Nikita in May which leaves Abhinav to be married to Smita and Vinit to Ekta.

Hence, we can draw the following table:

Shreshth got married to Nikita.

Hence, option 3.

QUESTION: 23

Each of the six men - Abhinav, Jagan, Saket, Shishir, Shreshth and Vinit got married to six different women among Debika, Ekta, Ishita, Kriti, Nikita and Smita. Their marriages took place in six different months - January, February, March, April, May and June and at six different places - Bhilai, Dehradun, Delhi, Moradabad, Mumbai and Jalandhar,not necessarily in that order. It is also known that:

i. Marriage of Jagan and Ishita took place in the month of February and that of Debika in the month of April.

ii. Nikita’s marriage took place in Delhi after Saket’s marriage but not in the month of June.

iii. Ekta’s marriage took place in Jalandhar and she is not married to Saket. She got married before Shreshth but not in the month of January.

iv. Kriti and Shishir got married in Bhilai. The marriage didn’t take place in January.

v. Smita got married to either Abhinav or Shreshth.

vi. Neither Ishita’s nor Debika’s marriage took place in Mumbai.

Which of the following is a correct combination of person and his month of marriage?

Solution:

According to the solution given in the first question of the set, Saket - April is the correct combination.

Hence, option 2.

QUESTION: 24

Each of the six men - Abhinav, Jagan, Saket, Shishir, Shreshth and Vinit got married to six different women among Debika, Ekta, Ishita, Kriti, Nikita and Smita. Their marriages took place in six different months - January, February, March, April, May and June and at six different places - Bhilai, Dehradun, Delhi, Moradabad, Mumbai and Jalandhar,not necessarily in that order. It is also known that:

i. Marriage of Jagan and Ishita took place in the month of February and that of Debika in the month of April.

ii. Nikita’s marriage took place in Delhi after Saket’s marriage but not in the month of June.

iii. Ekta’s marriage took place in Jalandhar and she is not married to Saket. She got married before Shreshth but not in the month of January.

iv. Kriti and Shishir got married in Bhilai. The marriage didn’t take place in January.

v. Smita got married to either Abhinav or Shreshth.

vi. Neither Ishita’s nor Debika’s marriage took place in Mumbai.

Where did the marriage that happened in the month of January take place?

Solution:

According to the solution given in the first question of the set, Abhinav and Smita got married in January in Mumbai.

Hence, option 1.

QUESTION: 25

Group Question

Answer the following question based on the information given below.

There are six Parking slots available in a building. The design of the Parking plot is as shown below:

There are six cars, namely A, B, C, D, E and F and all cars are parked facing the corridor. The following things are known about the cars that are parked.

Parking slots for cars A and E are not situated at the comers.

Cars F and C are in opposite rows.

Cars B and F are facing each other.

Car D is parked on the right hand side of car A.

Car C occupies a slot to the right of the corridor as one enters the parking plot.

Car F is parked in___________

Solution:

From statement 5, car C is in slot P4, P5 or P6.

From 2, car F is in slot PI, P2 or P3.

From 3, car B is in slot P4, P5 or P6.

From 4, as car D is on the right hand side of A, and we know that B and C are in slots P4, P5 and P6, we can say that A and D are in slot PI, P2 and P3.

Also, as A and E are not at comers, A is in slot P2, E is in slot P5.

••• D is in slot PI, F is in slot P3, C is in slot P4 and B is in slot P6.

Thus we have the following:

Car F is parked in slot P3.

Hence, option 2.

QUESTION: 26

There are six Parking slots available in a building. The design of the Parking plot is as shown below:

There are six cars, namely A, B, C, D, E and F and all cars are parked facing the corridor. The following things are known about the cars that are parked.

Parking slots for cars A and E are not situated at the comers.

Cars F and C are in opposite rows.

Cars B and F are facing each other.

Car D is parked on the right hand side of car A.

Car C occupies a slot to the right of the corridor as one enters the parking plot.

Which car is to the left of car C?

Solution:

From the arrangement given in the solution of the first question of the set, we can see that car C is in slot P4, which does not have any slot to its left.

Hence, option 4.

QUESTION: 27

There are six Parking slots available in a building. The design of the Parking plot is as shown below:

There are six cars, namely A, B, C, D, E and F and all cars are parked facing the corridor. The following things are known about the cars that are parked.

Parking slots for cars A and E are not situated at the comers.

Cars F and C are in opposite rows.

Cars B and F are facing each other.

Car D is parked on the right hand side of car A.

Car C occupies a slot to the right of the corridor as one enters the parking plot.

If car A is parked in the parking slot of car B, then which car will be diagonally opposite car A?

Solution:

From the arrangement given in the solution to the first question, it is clear that car D is diagonally opposite car B.

Thus, if car A and car B interchange positions, car D will be diagonally opposite car A.

Hence, option 1.

QUESTION: 28

Parking slots for cars A and E are not situated at the comers.

Cars F and C are in opposite rows.

Cars B and F are facing each other.

Car D is parked on the right hand side of car A.

Car C occupies a slot to the right of the corridor as one enters the parking plot.

Which two cars are in the same row?

Solution:

As per the arrangement given in the solution of the first question of the set, none of the options gives two cars that are in the same row

Hence, option 4.

QUESTION: 29

Group Question

Answer the following question based on the information given below.

The security personnel of a leading employment organization insisted on developing a new system of allotting the unique ID numbers to its employees to prevent the tampering of ID numbers by any of the unscrupulous members. They insisted that the 10 digit number must include all the numbers from 0-9 exactly once. Further, all the ID numbers should also be exactly divisible by all the numbers from 1-9.

What could be the smallest ID number that could be generated using this system?

Solution:

Any number using all the digits will be divisible by both 3 and 9. Since the numbers have to be divisible by both 2 and 5, they must end in 0.

Any number divisible by 3 and 2 will be divisible by 6. And, if a number is divisible by 8, then it will be divisible by 4.

So, if the number ends in 0, we only need to find whether it is divisible by 7 and 8. Any number whose last three digits are divisible by 8 will be divisible by 8.

Furthermore, since the numbers end in 0, for the last three digits to be divisible by 8, the two-digit number formed by the hundreds and tens digits (in that order) must be divisible by 4.

For a number to be the smallest, the digits on the left must be smallest possible. So, consider 123456***0.

The missing digits are 7, 8 and 9. But, no two-digit numbers formed by 7, 8 and 9 are divisible by 4. So, choose a slightly larger number, swapping the 7 for the 6: 123457***0.

Now, missing digits are 6, 8 and 9, which yield two two-digit numbers divisible by 4: 68 and 96.

So, we can test 1234579680 and 1234578960 for divisibility by 7.

Continuing in this manner, choosing slightly larger number each time, we get to the solution: 1234759680.

Hence, option 3.

QUESTION: 30

The security personnel of a leading employment organization insisted on developing a new system of allotting the unique ID numbers to its employees to prevent the tampering of ID numbers by any of the unscrupulous members. They insisted that the 10 digit number must include all the numbers from 0-9 exactly once. Further, all the ID numbers should also be exactly divisible by all the numbers from 1-9.

The largest ID number that could be generated using this system is: 3

Solution:

To find the largest ID number, start with 987654***0.

The largest possible ID number is 9876351240.

Hence, option 2.

QUESTION: 31

The security personnel of a leading employment organization insisted on developing a new system of allotting the unique ID numbers to its employees to prevent the tampering of ID numbers by any of the unscrupulous members. They insisted that the 10 digit number must include all the numbers from 0-9 exactly once. Further, all the ID numbers should also be exactly divisible by all the numbers from 1-9.

What would be the sum of last four digits of the smallest ID number generated?

Solution:

As seen in the solution to the first question of the set, the smallest ID number generated is: 1234759680.

The required sum = 23

Hence, option 1.

QUESTION: 32

What would be the sum of first four digits of the largest ID number generated?

Solution:

Hence, option 2.

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