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SSC Selection Post Mock Test - 2 - SSC Selection Post MCQ


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30 Questions MCQ Test SSC Selection Post Exam Mock Test Series 2024 - SSC Selection Post Mock Test - 2

SSC Selection Post Mock Test - 2 for SSC Selection Post 2024 is part of SSC Selection Post Exam Mock Test Series 2024 preparation. The SSC Selection Post Mock Test - 2 questions and answers have been prepared according to the SSC Selection Post exam syllabus.The SSC Selection Post Mock Test - 2 MCQs are made for SSC Selection Post 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for SSC Selection Post Mock Test - 2 below.
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SSC Selection Post Mock Test - 2 - Question 1

Find the missing term in the series.

7, 10, 15, 22, ?, 42, 55

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 1

Given: 7, 10, 15, 22, ?, 42, 55
The logic follows here is:

Hence, the correct answer is "31".

SSC Selection Post Mock Test - 2 - Question 2

Select the correct combination of mathematical symbols that can sequentially replace the @ symbols and balance the given equation.

(15 @ 5 @ 25) @ 20 @ (25 @ 6) @ - 26

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 2

Using BODMAS rule as follows:

Checking options one by one:
1. ×, +, =, +, ÷, -
After replacing the symbol @ by the symbols given in option 1 we get:
(15 × 5 + 25) = 20 + (25 ÷  6) - (- 26)
⇒ 75 + 25 = 20 + 4.167 + 26
⇒ 100 ≠ 50.167 (Incorrect)
2. ×, +, =, ÷, -, +
After replacing the symbol @ by the symbols given in option 2 we get:
(15 × 5 + 25) = 20 ÷ (25 - 6) + (- 26)
75 + 25 = 20 ÷ 21 - 26
75 + 25 = 0.952 - 26
100 ≠ - 25.048 (Incorrect)
3. +, ÷, ×, +, =, -
After replacing the symbol @ by the symbols given in option 3 we get:
(15 + 5 ÷ 25) × 20 + 25 = 6 - (- 26)
(15 + 0.2) × 20 + 25 = 6 + 26
15.2 × 20 + 25 = 32 
304 + 25 = 32
329 ≠ 32 (Incorrect)
4. ×, +, ÷, -,+, =
After replacing the symbol @ by the symbols given in option 4 we get:
(15 × 5 + 25) ÷ 20 - (25 + 6) = (- 26)
100 ÷ 20 - 31 = (-26)
5 - 31 = (-26)
(-26) = (-26) (Correct)
Hence, the correct answer is "×, +, ÷, -,+, =".

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SSC Selection Post Mock Test - 2 - Question 3

Select the option that should replace the question mark (?) and complete the figure series given below.

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 3

The square shape moves two times clockwise. The central shape remains the same:

In the next step, i.e. third figure, the no. of sides increases in the corner element and it becomes a pentagon.

In the next step, the pentagon moves two steps ahead in the clockwise direction and takes up the top left position and the central element remains unchanged as shown:

Hence, the correct answer is "Option (1)".

SSC Selection Post Mock Test - 2 - Question 4

The second number in the given number pairs is obtained by performing certain mathematical operation(s) on the first number. The same operation(s) are followed in all the number pairs, except one. Find that odd number pair.

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 4

The logic here is:
Logic: (First number)2 + 5 = Second number.
So, we will check the options one by one: 
1) 6 : 41 ⇒ (6)2 + 5 = 36 + 5 = 41
2) 4 : 21 ⇒ (4)2 + 5 = 16 + 5 = 21
3) 8 : 70 ⇒ (8)2 + 5 = 69 ≠ 70
4) 7 : 54 ⇒ (7)2 + 5 = 49 + 5 = 54
Hence, the number pair '8 : 70' is the odd one out.

SSC Selection Post Mock Test - 2 - Question 5

Which one of the given responses would be a meaningful order of the following?

  1. Login
  2. Set Password
  3. Logout
  4. Sign up
  5. Enter details
Detailed Solution for SSC Selection Post Mock Test - 2 - Question 5

In order to open an account on any website, we first enter our details and set a password to signup, after that we login to our account and then we logout.
So, the correct order is ‘5, 2, 4, 1, 3’.

SSC Selection Post Mock Test - 2 - Question 6

G, H, I, J, T and L are six members of a family. G and H are married couple. H is daughter-in-law of L. J is the only son of I. T is sister of J. I is G's brother.

Q. How is T related to I?

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 6

Preparing the family tree using the following symbols,

Given:
1) G and H are married couple.
2) H is daughter-in-law of L.
3) I is G's brother.
4) J is the only son of I.
5) T is sister of J.

Hence, T is the "Daughter" of I.

SSC Selection Post Mock Test - 2 - Question 7

Select the option figure which is embedded in the figure (X) given below (rotation is NOT allowed)

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 7

The image embedded in given figure is as shown below :

∴ Here, Option figure 3 is not embedded in given figure (X).
Hence, the correct answer is "Option-(3)".

SSC Selection Post Mock Test - 2 - Question 8

Which of the following numbers will replace the question mark (?) in the given series?

822, 817, 807, 787, ?

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 8

The pattern followed here is:

Hence, "752" is the correct answer.

SSC Selection Post Mock Test - 2 - Question 9

Select the option that is related to the third letter-cluster in the same way as the second letter-cluster is related to the first letter-cluster.

GKNR : SOLH :: MNGB : ?

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 9


The logic followed here is :-
In the given word the letters alphabet positional value opposite -1.
GKNR : SOLH

Similarly,
MNGB : ? 

Hence, the correct answer is "MLSX".

SSC Selection Post Mock Test - 2 - Question 10

Which two signs need to be interchanged to make the following equation correct?

198 ÷ 9 – 27 + 3 × 14 = 81 

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 10

By checking all the options and substituting accordingly:
1) × and + 
⇒ 198 ÷ 9 – 27 × 3 + 14 = 81
⇒ 22 - 81 + 14 = 81
⇒ -45 ≠ 81
2) × and – 
⇒ 198 ÷ 9 × 27 + 3 – 14 = 81
⇒ 22 × 27 + 3 - 14 = 81
⇒ 594 + 3 - 14 = 81
⇒ 583 ≠ 81
3) ÷ and – 
⇒ 198 – 9 ÷ 27 + 3 × 14 = 81
⇒ 198 - (1/3) + 42 = 81
⇒ 239.66 ≠ 81
4) ÷ and +
⇒ 198 + 9 – 27 ÷ 3 × 14 = 81
⇒ 198 + 9 - 9 × 14 = 81
⇒ 198 + 9 - 126 = 81
⇒ 81 = 81
Hence, the correct answer is "option 4".

SSC Selection Post Mock Test - 2 - Question 11

Select the figure that will come in place of the question mark (?) in the following figure series.

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 11

Logic followed here is:
When we move in series from left to right than we find circular ball and both straight lines are decreases simultaneously.

Therefore, the next image will be

Hence, the correct answer is "Option (4)".

SSC Selection Post Mock Test - 2 - Question 12

Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.

KRA, IQZ, ?, EOX, CNW

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 12


The logic followed here is:

So, 'GPY' will replace the question mark in the given series.
Hence, the correct answer is "Option 2".

SSC Selection Post Mock Test - 2 - Question 13

In the question below are given some statements followed by some conclusions based on those statements. Take the given statements to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements.
Statement:
I. All P are Q.
II. Some Q are T.
III. All T are D.
Conclusion:
I. Some Q are D.
II. Some D are P
III. Some P is T.

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 13

Statement:
I. All P are Q.
II. Some Q are T.
III. All T are D.
The least possible diagram for the given statements is as follows:

Conclusion:
I. Some Q are D → True (Because 'Some Q are T' and 'All T are D', so 'Q' that are 'T' are also 'D', so it is definitely true)
II. Some D are P → False (Because there is no direct relation between 'D' and 'P' so it is possible but not definite, so it is false)
III. Some P is T → False (Because there is no direct relation between 'P' and 'T' so it is possible but not definite, so it is false)
Hence, the correct answer is "Only conclusion I follows".

SSC Selection Post Mock Test - 2 - Question 14

How many rectangles are there in the given figure?

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 14

We can Calculate the number of rectangles as follows:

The required rectangles in the given figure are as follows:
ABHJ, JHFI, BCDG, GDEF, ABFI, BCEF, and ACEI.
So, the number of rectangles are 7.
Hence, the correct answer is 7.

SSC Selection Post Mock Test - 2 - Question 15

From the given answer figures, select the one in which the question figure is hidden/embedded.

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 15

The given pattern should definitely overlap with any one of the answers.
In option (A), (C) and (D), we can observe that the required figure is not hidden. 
In option (B), we can observe that the required figure is hidden which is shown below:

SSC Selection Post Mock Test - 2 - Question 16

If a mirror is placed on the line AB, then which of the answer figures is the right image of the given figure?

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 16

When the mirror is placed at the right-hand side of the figure, then the top and bottom part of the image remains the same, while the left and right side of the image will be interchanged in the mirror image i.e the image will flip horizontally.
Hence, the correct answer is:

SSC Selection Post Mock Test - 2 - Question 17

If ‘P’ means '÷', 'Q' means '+', 'R' means ‘×' and 'S' means '−-', then 
54 R 11 P 99 Q 23 S 14 = ?

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 17

We are given the following information in the problem:

54 R 11 P 99 Q 23 S 14
= 54 × 11 ÷ 99 + 23 −14
= 54 × (1/9)  + 23 −14  
= 6 + 23 −14
= 15

SSC Selection Post Mock Test - 2 - Question 18

Arrange the given words in the sequence in which they occur in the dictionary.

1. Locker 2. Lamp 3. Lost 4. Longer 5. Listed

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 18

In dictionary words are written according to the alphabet series.
All letters are starting with ‘’L’’, so we will check the second letter of each word and try to write the words in the sequence.
2. Lamp
5. Listed
1. Locker
4. Longer
3. Lost
Thus, the correct order will be 25143.

SSC Selection Post Mock Test - 2 - Question 19

A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.

AZ, BY, CX, DW, ?

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 19

According to the given condition, the opposite letter pairs are arranged to form a series.
The pairs of letters whose sum of the place value is 27 are opposite to each other.
For example, the place value of A is 1 and place value of Z is 26.
So, 1+26 = 27.
Similarly,
BY, CX, and DW are pairs of opposite letters. 
So, the next pair will be EV.
Hence, the correct answer is EV.

SSC Selection Post Mock Test - 2 - Question 20

In the following question, select the odd number pair from the given alternatives. 

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 20

42 = 16
52 = 25
62 = 36
72 = 49
We can observe that second number of each group is square of the first number but in second group we can observe the difference. Thus, the odd pair is (5−24).

SSC Selection Post Mock Test - 2 - Question 21

Identify the diagram that best represents the relationship among the given classes.

Spoon, Fork, Utensils

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 21

According to the given condition, we have to determine the relationship between Spoon, Fork, and Utensils.
Spoon and fork are part of utensils but spoon and fork both are different. Spoon and fork both are made up of metals but the main difference between spoon and fork is that the spoon is a utensil consisting of a small shallow bowl, oval, or round, at the end of a handle and fork is a piece of cutlery or kitchenware with two or more prongs and the part of the fork which we hold is called handle.
So, the best diagram which represents the relationship is

Hence, this is the correct answer.

SSC Selection Post Mock Test - 2 - Question 22

In the following question, select the related number from the given alternatives.

372 : 42 : : 456: ?

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 22

We can observe the following relation,
3 × 7 × 2 = 42
Therefore,
4 × 5 × 6 = 120 
Thus, 120 is the correct answer.

SSC Selection Post Mock Test - 2 - Question 23

In the following question, select the word which cannot be formed using the letters of the given word.

TRAMPOLINE

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 23

No, extra word should be used in the words formation.
PAID word cannot be formed from the as the letter ‘’D’’ is not present in the word TRAMPOLINE.
Else all other words can be formed.

SSC Selection Post Mock Test - 2 - Question 24

Study the given pattern carefully and select the number that can replace the question mark (?) in it.

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 24

As we can in the following image

3×6 = 18
3×9 = 27
In the same manner, the answer will be
9×6 = 54
Hence, the correct answer is 54.

SSC Selection Post Mock Test - 2 - Question 25

In a certain code language, STRANGE is written as HGIZMTV. How is FRAUD written in that code language?

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 25

The place values of all the alphabets are given below,

Given code,

So, the pattern followed here is that all the letters are replaced by their opposite letters to get the required code.
So, FRAUD will be coded as

Hence, the correct answer is UIZFW.

SSC Selection Post Mock Test - 2 - Question 26

It is given that ΔABC ~ ΔXYZ and Area ΔABC : Area ΔXYZ = 81 : 25. If AB = 18 cm, BC = 10 cm, CA = 15 cm, then what is the side XZ (in cm)?

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 26

Given:
ΔABC ~ ΔXYZ and Area ΔABC : Area ΔXYZ = 81 : 25. If AB = 18 cm, BC = 10 cm, CA = 15 cm,
Concept:
If two triangles are similar then, the ratio of the area of triangle is equal to the square of the ratio of any pair of the corresponding sides of the similar triangles.
Calculation:

Area Δ ABC/Area ΔXYZ = (AB/XY)2 = (BC/YZ)2 = (CA/XZ)2
81/25 = (15/XZ)2
⇒ 81/25 = (15 × 15)/(XZ)2
⇒ XZ2 = (15 × 15 × 25)/(81)
⇒ XZ2 = (5 × 5 × 25)/9
⇒ XZ = 25/3
∴ The side XZ is 25/3 cm.

SSC Selection Post Mock Test - 2 - Question 27

The initial ratio of sugar and flour in the dough was 4 : 7 With 22 kg of the dough Justine added more flour to make the sugar to flour ratio 2 : 5. How much flour did Justine later added?

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 27

Ratio of mixture of sugar and flour = 4 : 7
⇒ 4 + 7 = 11 unit
⇒ 11 unit = 22 kg
⇒ 1 unit = 2 kg
⇒ 4 unit = 2 × 4 = 8 kg
⇒ 7 unit = 2 × 7 = 14 kg
Quantity of sugar in the dough = 8 kg
Quantity of flour in the dough = 14 kg
Let quantity of flour added be x
According to the question
8/(14 + x) = 2/5
⇒ 40 = 28 + 2x
⇒ 2x = 40 – 28
⇒ x = 12/2
⇒ x = 6 kg
∴ Justine later on added 6 kg of flour.

SSC Selection Post Mock Test - 2 - Question 28

The wages of workers (W1, W2, W3, W4, W5, W6) for different tasks (T1, T2, T3) are given

Q. What is the difference in average wages per worker for task T1 and task T3?

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 28

Given:
Formula Used:
Average = Sum of Wages/Total workers
Calculations:
Sum of wages for T3 = W6 + W5 + W4 + W3 + W2 + W1 = 4 + 3 + 4 + 5 + 4 +3 = 23
Number of workers = 6
The average for T3 =  Sum of Wages/Total workers = 23/6
Sum of wages for T1 = W6 + W5 + W4 + W3 + W2 + W1 = 3 + 5 + 4 + 3 + 2 + 4 = 21
Number of workers = 6
The average for T1= Sum of Wages/Total workers = 21/6
Difference between them = Average for T3 - Average for T1 = 23/6 - 21/6 = 2/6 = 1/3
Hence, The Difference in average wages per worker for task T1 and task T3 is 1/3.

SSC Selection Post Mock Test - 2 - Question 29

A copper sphere of diameter 18 cm is drawn into a wire of diameter 6 mm. Find the length of the wire.

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 29

Given:
A copper sphere of diameter 18 cm is drawn into a wire of diameter 6 mm.
Concept used:
Volume of sphere = 4/3πr3
Volume of cylinder = πr2h
Calculation:
Radius of sphere = 9 cm
Radius of wire = 0.3 cm  [As 1 cm = 10 mm]
According to the question,
Volume of sphere = Volume of cylinder
⇒ 4/3π93 = π0.32x
⇒ 4/3 × 729 = 0.32x
⇒ 4 × 243 = 0.09x
⇒ x = 10800 cm = 108 m
∴ The length of the wire is 108 m.

SSC Selection Post Mock Test - 2 - Question 30

If HCF of the polynomials (x + 2) (3x2 - 2ax + 3) and (2x - 1) (5x2 - 3x + 2b) is (x + 2) (2x - 1), then find the value of (4a + 7b).

Detailed Solution for SSC Selection Post Mock Test - 2 - Question 30

Given:
The polynomials are (x + 2)(3x2 - 2ax + 3) and (2x - 1)(5x2 - 3x + 2b)
HCF is (x + 2)(2x - 1)
Concept used:
HCF or Highest Common Factor is the greatest number which divides each of the two or more numbers.
Calculation:
HCF of the two polynomials = (x + 2)(2x - 1)
So, roots of x are (-2), 1/2
Now,
(2x - 1) is one of the factors of (3x2 - 2ax + 3)
So,
f(x) = (3x2 - 2ax + 3)
For x = 1/2
f(1/2) = [3 × (1/2)2 - 2a × (1/2) + 3] = 0
⇒ [3 × (1/4) - a + 3] = 0
⇒ [3/4 - a + 3] = 0
⇒ (3 + 12)/4 = a
⇒ a = 15/4
Again,
(x + 2) is one of the factors of (5x2 - 3x + 2b)
So,
f(x) = (5x2 - 3x + 2b)
For x = - 2
f(-2) = [5 × (- 2)2 - 3 × - 2 + 2b] = 0
⇒ [5 × 4 + 6 + 2b] = 0
⇒ [20 + 6 + 2b] = 0
⇒ 26 = - 2b
⇒ b = - (26/2)
⇒ b = - 13
Now,
(4a + 7b) = [4 × (15/4) + 7 × (- 13)]
⇒ 15 - 91
⇒ - 76
∴ The value of (4a + 7b) is - 76.

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