Indian Air Force Agniveer Science & Other than Science Mock Test - 5 - Indian Air Force Agniveer Vayu MCQ

u = 0, t₁=10s, t₂ = 20s

Using the relation,

Acceleration being the same in two cases,

  S₂ = 4S₁

When the body is thrown upwards. its K.E is converted  into P.E. The loss of energy due to air friction is the difference of K.E and P.E.

 = 200 – 180 = 20 J

We know that the force of gravitation is inversely proportional to square of the distance between the two bodies,

i.e. F∝ r^-2

Hence, when the distance between them will be doubled, the force will be reduced by 4 times

So, the ratio will be 4:1

When liquid molecules are attracted strongly to themselves and weakly to those of solids, it costs lots of energy to create liquid-solid surface and liquid then does not wet the solid.

For Example: Mercury molecules (which make an obtuse angle with glass) have a strong force of attraction between themselves and a weak force of attraction toward solids. Hence, they tend to form drops.
On the other hand, water molecules make acute angles with glass. They have a weak force of attraction between themselves and a strong force of attraction toward solids. Hence, they tend to spread out.

A reversible process gives the maximum work.

∆ U = ∆ Q - ∆ W
In an adiabatic process ∆Q is zero, therefore
∆ U = - ∆ W

In a simple pendulum the restoring force is due to the tangential component of the gravitational force because on applying torque equation on the radial forces the effect is nullified due to it passing from centre & only tangential component remains.

Energy stored in capacitor

Maxwell’s Fourth Equation
It is based on Ampere’s circuital law. To understand Maxwell’s fourth equation it is crucial to understand Ampere’s circuital law,
Consider a wire of current-carrying conductor with the current I, since there is an electric field there has to be a magnetic field vector around it. Ampere’s circuit law states that “The closed line integral of magnetic field vector is always equal to the total amount of scalar electric field enclosed within the path of any shape” which means the current flowing along the wire(which is a scalar quantity) is equal to the magnetic field vector (which is a vector quantity)

We know that alpha particles are the nucleus of ionized helium atoms which contain two protons and two neutrons. These are emitted by the nuclei of certain radioactive substances. Streams of alpha particles, called α-rays, produce intense ionisation in gases through which they pass and are easily absorbed by matter.

Explanation:Materials that have the resistance levels between those of a conductor and an insulator are referred to as semiconductors.They are quite common, found in almost all electronic devices. Good examples of semiconductor materials are germanium, selenium, and silicon.Radium is a chemical element with symbol Ra and atomic number 88. It is the sixth element in group 2 of the periodic table, also known as the alkaline earth metals.

• n(A ∪ B) = n(A) + n(B) − n(A ∩ B) = 12 + 9 − 4 = 17
• Now, n((A ∪ B)^c) = n(U) − n(A ∪ B) = 20 − 17 = 3

 Radius of circle is given by -
r = √[(h-x1)² + (k-y1)²]
r = √[(2-3)² + (1+5)²]
r = √(-1² + 6²)
r = √(1 + 36)
r = √37
if centre (2,-]1) and radius=√26 are given,
(x-h)²+(y-k)²=r²
equation is (x-2)² + (y-1)² = (√37)²
x² + 4 - 4x + y² + 1 - 2y = 37
x² + y² - 4x - 2y - 32 = 0

lim(x → 0) (tanx-x)/x² tanx
As we know that tan x = sinx/cosx
lim(x → 0) (sinx/cosx - x)/x²(sinx/cosx)
lim(x → 0) (sinx - xcosx)/(x² sinx)
lim(x → 0) cosx - (-xsinx + cosx)/(x²cosx + sinx (2x))
lim(x → 0) (cosx + xsinx - cosx)/x²cosx + 2xsinx)
lim(x → 0) sinx/(xcosx + 2sinx)
Hence it is 0/0 form, apply L hospital rule
lim(x → 0) cosx/(-xsinx + cosx + 2cosx)
⇒ 1/(0+1+2)
= 1/3

For sin²(X), we will use the cos double angle formula:
cos(2X) = 1 - 2sin²(X)
The above formula can be rearranged to make sin²(X) the subject:
sin²(X) = 1/2(1 - cos(2X))
You can now rewrite the integration: 
∫sin²(X)dX = ∫1/2(1 - cos(2X))dX
Because 1/2 is a constant, we can remove it from the integration to make the calculation simpler. We are now integrating:
1/2 x ∫(1 - cos(2X)) dX 
= 1/2 x (X - 1/2sin(2X)) + C]-pi/4 to pi/4
∫sin2(X) dX = [1/2X - 1/4sin(2X)]-pi/4 to pi/4 + C
½[-pi/2] - 1/4sin(2(-pi/4)] - ½[pi/2] - 1/4sin(2(pi/4)] 
= π/2

Given:

If we divide both sides with 2 we get,

⇒ Mid pt. of AC = Mid. pt. of BD
∴ ABCD is a parallelogram.

This question has to do with parallel structure. The correct structure is ‘grow’, ‘become’ and ‘threaten’. Only B has this combination.

The context is about Russian attempt to expand their region. Sentence 4 is the leading sentence. It introduces Russia - 'as a growing empire'. The words 'begun their expansion' in 2 link with 'as a growing empire' in sentence 4. The word 'explorers' in 5 links with 'expedition' in 2. 'Fur-trading interests' in 3 refer to 'fur trade' in 5. So, 3 follows 5. The sequence becomes: 4-2-5-3. The explorers had excited the Russians for fur trade in Alaska but there was conflict of interest. Russians also found it difficult to produce food there (sentence 6) and the alternative is provided in sentence 1 (reasoned that ... California could serve both as a source of food). So, the final sequence becomes: 4-2-5-3-6-1.

The object of the active voice sentence ("the cat") becomes the subject in the passive voice sentence ("the cat was chased").

LCM of 12, 15, 25 and 30 is 300
least number of 4-digit divided by 300 is 1200

M x N → M is the father of N

N - C → N is the sister of C

and C + F → C is the brother of F.

Hence, M is the father of C or C is the son of M.

Fat-soluble vitamins are stored in the body in organs such as the liver. Most of the vitamin A that we consume goes to the liver to be stored until it is needed by another part of the body.

Thar Express is an international train that con-nects Karachi, Pakistan to Bhagat Ki Kothi, India. Six kilometres apart, Munabao and Khokhrapar are the two last railway stations of the India-Pakistan border. Jamrao, Mirpur Khas, Shadi Pali, Saeendad. Barmer, Pithoro, Dhoro Naro, and Chhore are some of the stations. Bhagat in Kothi is a train station 5km from Jodhpur Railway Station.

 Height of the cylinders = 42 cm
Radius of the outer cylinder = r₁ = 16/2 = 8 cm
Radius of the inner cylinder = r₂ = 14/2 = 7 cm
Therefore, volume of the cork dust required = Volume of the outer cylinder – Volume of the inner cylinder

= 1980 cm³

The NCC Integrated Software launched by Raksha Mantri Rajnath Singh aims to digitalize the entire process from the stage of cadet enrollment in NCC to exit registration as an alumni. The software simplifies the issuance of certificates and creates a comprehensive database of NCC cadets, aligning with the vision of digitization and the "Once a Cadet always a cadet" principle.