UP PGT Chemistry Mock Test - 7 - UPTET MCQ

Intramolecular Cannizaro reaction occur.

The formula that these isomers contain no rings or double bonds. The isomers must be alcohols and ethers.
For The alcohols
1. CH₃CH₂CH₂CH₂OH, butan 1-ol
2. CH3CH₂CH(OH)CH₃, butan-2-ol
3. (CH₃)₂CHCH₂OH, 2-methylpropan-1-ol 
4. (CH₃)₃COH, 2-methylpropan-2-ol.
Now for the ethers.
5. CH₃CH2CH₂OCH₃, 1-methoxypropane
6. CH₃CH2OCH₂CH₃ , ethoxyethane
7. (CH₃)₂CHOCH₃ , 2-methoxypropane.

The correct answer is Option A.

Isopropyl alcohol forms acetone on oxidation. 
 
The reaction is as follows:

• An enzyme inhibitor is a molecule that binds to an enzyme and decreases its activity.
• Since blocking an enzyme's activity can kill a pathogen or correct a metabolic imbalance, many drugs are enzyme inhibitors.
• They are also used in pesticides.

If we rotate one off the molecule in a plane perpendicular to molecule, then we will get the mirror image of others which are non superimposable. So, they are enantiomers.

The correct answer is option B.

The I.U.P.A.C. name for Fe(C₅H₅)₂ is bis(η⁵ -cyclopentadienyl) iron(II) 
The oxidation state of iron is +2 and is written in parenthesis in roman numerals. Two cyclopentadienyl ligands are coordinated to Fe. The prefix bis indicates 2. η⁵ indicates that the cyclopentadienyl ligands are penta coordinates.

50% ionised ⇒ [Salt] = [Acid]
⇒ pH = pKa = 4.5
⇒ pOH = 9.5

Sodium oxide is more basic than Magnesium oxide. A binary compound of an element with oxygen, in which Oxygen atom is electronegative is called an oxide. The oxides which react with water and produce alkali and can neutralise acids forming salt and water are called basic oxides. Na₂O, MgO are basic oxides.

3O2(g) → 2O3(g)
∆H = 3(B.E)_O2 - 2(B.E)_O3
= 3(498.8) - 2(302.3)
= 287.2 kJ ml-1

The correct answer is option c

Thus, a racemic mixture is obtained. A racemic mixture is one that has an equal amount of left and right handed enantiomers of a chiral molecule.

IV. Electrostatic force of attraction between  and
V. H₂O molecules joined together by dipole-dipole interaction.
VI. Outer H₂O molecule joined to by ion-dipole interaction.

(a) Octet of Cl expanded to (9).
(b) Octet Xe expanded to (10).
(c) Octet of P expanded to (10).
 

Microcosinic salt is used in microcosmicbed test

There are two elements in the 1^st period and eight elements in the 2^nd period., The third period starts with the element with Z = 11(sodium). Now, there are nine  elements in the third period. Thus, the 3^rd period ends with the element with Z = 18(argon) i.e., the element in the 18^th group of the third period has Z = 18. Hence, the element in the 17^th group of the third period has atomic number Z = 17 ,chlorine(Cl) with atomic mass 35.453, which is a p block element.

The given compound is superimposable on its mirror image, so it is achiral. Achiral molecules which have chirality centers are called meso compounds. Meso compounds are possible if two (or more) chirality centers in a molecule have the same set of four substituents.

Buna N is used in making oil seals , tank linings.

Zero overlap means that the orbitals don’t overlap at all. When there is no overlapping the bond formation doesn’t occur. As we all know that the extent of overlapping is dependent on the strength of the bond.

PBr does not split in the same fashion. The anion is not possible due to large size of Br-atoms. Hence, it splits differently.

Epoxidation is an example of electrophilic ad dition at olefin ic bonds. Therefore, greater the electron density at olefinic bond, greater its reactivity. Electron donating groups increases reactivity while electron withdrawing group s like — CF₃ decreases reactivity.

The correct answer is option C
ΔT = Kf​ × molality × (1+α)(HX ⇌ H+   + X−)
Given molality = 0.2;  degree of ionization is 0.3
=1.85×0.2×(1+0.3)
=0.481K
The freezing point of the solution will be 0.81 K.

The gaseous pollutants come down to the earth in form of rain forms acid rain.

The correct answer is Option B
Milk is an emulsified colloid of Liquid is dispersed in liquid where liquid butterfat globules dispersed within a water-based solution.

Here, Grignard reagent acts as base and acid base reaction occurs (as hydrogen of sp hybridized C atom acts as acid). So CH₃- takes H+ and forms CH₄.

SF₄ molecule has 1 lone pair of electrons, CF₄ has no lone pair of electrons and XeF₄ has 2 lone pair of electrons respectively.

Cesium is an alkali metal, like sodium; hence, it forms a salt, cesium chloride (CsCl) similar to table salt, sodium chloride.CsCl looks like most salts:It's worth noting that the formation of salts is highly exothermic, that is, if you were to get cesium metal and gaseous chlorine to combine to form this salt, the reaction would produce a lot of heat along the way!

As q = 0, we have adiabatic process.
V₁ = 100L and V₂ = 800L
T₁ = 300K and T₂ = not given
For NH₃, γ = 4/3
Applying TV^γ = constant
(300)(100)^4/3-1 = (T)(800)^4/3-1
T = 300/2 = 150K
W= nR(T₂-T₁)/γ-1
= 1×8.314×150/(4/3-1)
= 3714 J
= 900 cal