UP PGT Chemistry Mock Test - 6 - UPTET MCQ

Among the given molecules, N₂ has highest ionization enthalpy.The reason behind is the stability of half-filled orbitals which makes it more stable than other elements in the given option list.

Both elements are present in the same substance . Such reaction is called intramolecular redox reaction.

The elements of "s" and "p" blocks except "d" group elements are called as representative elements. Their outer shells are not completely filled with electrons. The elements get the nearest inert gas configuration by losing or gaining or sharing of electrons. 

Gadolinium (Gd) have [Xe] 4f⁷5d¹6s² configuration.

C-0/100-0 = F-32/180.
C/5= F-32/9.
C/5= 100-32/9.
C/5= 68/9.
C= 68×5/9.
C= 340/9.
C= 37.77.
C= 37.8

C₆H₆(l) + 15/2O₂(g) → 6CO₂(g) + 3H₂O(l)
∆H_r = (∆H_c)_C6H6 ⇒-3261  = ∑H_product - ∑H_reactant = 6(-393.5) -3(-283.83) - ∆_fH_C6H6
∆H_f = 48 kJ mol^-1

For H - atom , Z = 1

Reason behind it is that fluorine is more electronegative element than oxygen.

K_sp  = S (S–X) = 11 × 10^–6 × 10^–6
= 1.1 × 10–11

Multidentate ligand always act as chelating Ligand

The correct answer is Option B.
 Lecithin works as an emulsifier which stabilises the emulsion.

= 946 + 249 - 607 - 418 = 1195 - 1025 = 170 kJ mo^l-1 
Resonance energy = Observed heat of formation – calculated heat of formation 
= 82 -170 = 88 kJ mol^-1

Mg(OH)₂
Base or Antacid which distroys and as per neutralisation reaction

The correct answer is option A
2.03x 10^-4
The given equation is :-
 N2​(g)+3H2​(g) ⇌ 2NH_3​(g)
Initial moles : 1             3         0
At eqm ;       (1−x)    (3−3x)   (2x)               
(let)
Total moles of equation
 =1 − x + 3 − 3x + 2x = (4−2x)
Now, X(NH_3​) = 
⇒ 2x = 2 − x
⇒ 3x = 2 ⇒ x = 0.66 = 
32​
Now, at equation, moles of N₂​= 1/3, moles of NH_3​ = 4/3
             moles of H2 ​ =3 − 2 = 1

 

Product 1-Does not have any chiral carbon so only one product
Product 2-Two chiral centres so RR, RS and SR possible
Product 3-Two chiral centres so RR, RS and SR possible
Product 4-Two chiral centres but plane of symmetry exists, so only two isomers.

Even though each atom has more electrons as you move from left to right across the periodic table, the atomic radius decreases. The reason is that you're also adding more protons, which exert a stronger attractive force on the electrons, drawing them in a tiny bit closer. Ionic radius also decreases, although not for the exact same reason.

The correct answer is option C
The molar mass M₂​ of non-volatile substance can be calculated from the following formula.

Here, p⁰ vapour pressure of acetone and p is the vapour pressure of the solution.
M_1​ and W₁​ are the molar mass and mass of acetone.
M_2​ and W₂​ are the molar mass and mass of a non-volatile substance.
Substitute values in the above expression.

Hence, M2​=64.38g/mol.
Thus, the molar mass of the non-volatile substance is 64 g/mol (approximately).
 

Standard temperature and pressure (STP) is defined as 0 degrees Celsius and 1 atmosphere of pressure. At STP, 1 mole of any gas occupies 22.4 liters.
First, calculate the number of moles of hydrogen gas (H2) in 67.2 liters:
67.2 L / 22.4 L/mole = 3 moles of H2
Each molecule of H2 contains 2 atoms of hydrogen. Therefore, 3 moles of H2 contains:
3 moles * (6.022 x 10^23 molecules/mole) * 2 atoms/molecule = 3.6132 x 10^24 atoms of hydrogen.

The correct answer is Option A.

Out of the given four compounds only the first one has a chiral carbon. Hence compound A is optically active and it can rotate the plane polarised light.
 

Molarity = 2.772 M =2.772 mol L^-1  Thus, NaOH =2.772 mol

Selectivity is the ability to direct the reaction to get a particular product. Here we change the catalyst and we obtain different products with reactant remaining the same.

This alkaline earth hydride is a colourless solid that is insoluble in solvents that do not decompose it. Unlike the ionically bonded hydrides of the heavier Group 2 elements, beryllium hydride is covalently bonded (three-center two-electron bond).

Number of atoms = number of moles x N_A x atomicity

= 0.1 x 6.02 x 10²³ x 3

= 1.806 x 10²³

Hydrogen has some properties, resembling with IA group elements (alkali metals) and rest resembling with halogens (VII A group elements). Tendency to gain one electron is the property of halogens. Hence, hydrogen resembles with halogens in this respect.

 The two sulfur atoms of thiosulfate exist in the oxidation state of sulfate (+6) and sulfide (−2) and do not change their respective oxidation states upon disproportionation.  

So difference in the oxidation states of two types of sulphur atoms will be

= (+6)- (-2) 

= +8

ΔTb/Kb = ΔTf/Kf
0.186/18.6 = ΔTb/0.512
ΔTb = 0.1x0.512
= 0.0512.
Boiling point = boiling point (of water) + ΔTb
=> 100 + 0.0512
= 100.0512

Impure metal is made the anode and oxidation takes place

Cu²⁺ formed are reduced at cathode and thus, deposited there.

(c) Experrnent indicates that the applied voltage required is always greater than the voltage calculated from the standard E⁰_ox or E⁰_red. The additional voltage required is called overvoltage. Due to this, Cl₂ and not O₂ s formed. This, (c) 6 correct. 

Na₂[Fe(CN)₅NO] is Sodium nitroprusside.