HPSC TGT/PGT Exam  >  HPSC TGT/PGT Tests  >  HPSC PGT Mock Test Series 2025  >  HPSC PGT Physics Mock Test - 4 - HPSC TGT/PGT MCQ

HPSC PGT Physics Mock Test - 4 - HPSC TGT/PGT MCQ


Test Description

30 Questions MCQ Test HPSC PGT Mock Test Series 2025 - HPSC PGT Physics Mock Test - 4

HPSC PGT Physics Mock Test - 4 for HPSC TGT/PGT 2025 is part of HPSC PGT Mock Test Series 2025 preparation. The HPSC PGT Physics Mock Test - 4 questions and answers have been prepared according to the HPSC TGT/PGT exam syllabus.The HPSC PGT Physics Mock Test - 4 MCQs are made for HPSC TGT/PGT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HPSC PGT Physics Mock Test - 4 below.
Solutions of HPSC PGT Physics Mock Test - 4 questions in English are available as part of our HPSC PGT Mock Test Series 2025 for HPSC TGT/PGT & HPSC PGT Physics Mock Test - 4 solutions in Hindi for HPSC PGT Mock Test Series 2025 course. Download more important topics, notes, lectures and mock test series for HPSC TGT/PGT Exam by signing up for free. Attempt HPSC PGT Physics Mock Test - 4 | 100 questions in 120 minutes | Mock test for HPSC TGT/PGT preparation | Free important questions MCQ to study HPSC PGT Mock Test Series 2025 for HPSC TGT/PGT Exam | Download free PDF with solutions
HPSC PGT Physics Mock Test - 4 - Question 1

When is the World Earth Day celebrated?

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 1
HPSC PGT Physics Mock Test - 4 - Question 2

Who won double gold at the 65th National Shooting Championship on 2 December 2022?

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 2

The correct answer is Sarabjot Singh.

Key Points

  • Haryana’s Sarabjot Singh won double gold at the 65th National Shooting Championship on 2 December 2022.
  • Sarabjot defeated Gaurav Rana of the Air Force 16-4 in the gold medal match for the individual crown and also partnered with Sumit Raman and Anmol Jain to pick up the team gold in the event.
  • The championship is being held at the MP Shooting Academy range in Bhopal.

Additional Information

  • Other Sports News:
    • In Badminton, Satwiksairaj Rankireddy and Chirag Shetty bagged the biggest title of their career, claiming the French Open Super 750 crown.
    • In ISSF World Championship, Sagar Dangi bagged Gold and Silver in the Junior Men’s 10m Air Pistol team and individual events in Cairo, Egypt on 21 October 2022.
    • Indian javelin thrower DP Manu won Gold medal in the men’s competition with a best throw of 81.23m at the National Open Athletics Championships in Bengaluru on 18th Oct 2022.
HPSC PGT Physics Mock Test - 4 - Question 3

If the Young's double slit experiment is performed with white light, then which of the following is not true

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 3

The central fringe will be white because all the component color bands will superimpose there. The option (a) is true.
Since the fringes of different wavelengths of light have different fringe-widths, there will not be a completely dark fringe. Option (b) is true.
Since the wavelength of the violet light is nearly half of the red light, the fringe-width of the violet light is half of the red light. Since the central bright violet fringe combines with other fringes to form the white fringe, the next to it will be a minima for violet light. So violet will not be next to the central white fringe. Next will be a very thin band of white light minus violet light which will give a shade of off white. In this way, the components of indigo, blue, green, yellow and orange colors will be withdrawn respectively in the very thin consecutive bands. These will effect in different off white shades which cannot be clearly differentiated from the white band. The first color away from the center will be recognized as red when in these very thin bands yellow + orange + red, orange + red or red remains. Hence the option (d) is true.
https://cn.edurev.in/ApplicationImages/Temp/0_c2d814a7-e5a6-4115-9344-41d49f87e846_lg.png
Young's Double Slit Experiment with White light

HPSC PGT Physics Mock Test - 4 - Question 4

According to Carnot theorem no heat engine working between two given temperatures of source and sink can be more efficient than a perfectly ___________ engine working between the same two temperatures

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 4

According to Carnot theorem no heat engine working between two given temperatures of source and sink can be more efficient than a perfectly reversible engine working between the same two temperatures, by the statement of Carnot theorem.

HPSC PGT Physics Mock Test - 4 - Question 5

Energy of a photon of green light of wavelength 5500m  is (given: h = 6.62 ×10−34Js−1) approximately

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 5

Solution:

  • The energy of a photon can be calculated using the formula: E = hc / λ.
  • Here, h is Planck's constant, which is 6.63 × 10-34 J·s.
  • The speed of light (c) is 3 × 108 m/s.
  • The wavelength (λ) is given as 5500 × 10-10 m.

Substitute these values into the formula:

  • E = [6.63 × 10-34 J·s × 3 × 108 m/s] / 5500 × 10-10 m
  • Calculating gives: E = [0.36 × 10-26] / 10-8
  • This simplifies to: E = 3.6 × 10-19 J

Convert energy from joules to electronvolts:

  • 1 electronvolt (eV) = 1.6 × 10-19 J
  • Therefore, E = 3.6 × 10-19 J / 1.6 × 10-19 J/eV
  • The result is approximately 2.26 eV.
HPSC PGT Physics Mock Test - 4 - Question 6

The Earth always have both horizontal and vertical components everywhere.

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 6

No, this statement is false. The Earth always has a vertical component except at the equator. Similarly, the earth always has a horizontal component except at the poles.

HPSC PGT Physics Mock Test - 4 - Question 7

In Young's double slit experiment 62 fringes are visible in the field of view with sodium light (l = 5893Å). If green light (l = 5461Å) is used then the number of visible fringes will be _

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 7

Wavelength of light used is inversely proportional to number of fringes observed.

HPSC PGT Physics Mock Test - 4 - Question 8

Three masses of 1 kg, 6 kg and 3 kg are connected to each other with threads and are placed on a table a as shown in the figure. What is the acceleration with which the system is moving  (Take g = 10 m/s2)

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 8

HPSC PGT Physics Mock Test - 4 - Question 9

According to Avogadro’s law:

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 9

Explanation:Avogadro's law states that, "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules"For a given mass of an ideal gas, the volume and amount (moles) of the gas are directly proportional if the temperature and pressure are constant.

 

HPSC PGT Physics Mock Test - 4 - Question 10

When number of identical cells, in parallel combination are increased, the voltage of the circuit will

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 10

The voltage developed by the cells in parallel connection cannot be increased by increasing the number of cells present in the circuit. It is because they do not have the same circular path. In parallel connection the connection provides power based on one cell.
The voltage will remain the same.

HPSC PGT Physics Mock Test - 4 - Question 11

The diffraction of light is not easily noticed if:

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 11

Actually, diffraction occurs all the time. But when the aperture/wavelength ratio is large, the spacing between fringes becomes too small, and the diffractive effects are unnoticeable.

HPSC PGT Physics Mock Test - 4 - Question 12

As observed from earth, the sun appears to move in an approximate circular orbit. For the motion of another planet like mercury as observed from earth, this would

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 12

Concept:

Newton's law of gravitation: The force of attraction between any objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

  • The force acts along the line joining the two bodies.
  • The gravitational force is a central force that is It acts along the line joining the centers of two bodies.
  • It is a conservative force. This means that the work done by the gravitational force in displacing a body from one point to another is only dependent on the initial and final positions of the body and is independent of the path followed.

Explanation:

  • The gravitational force on mercury due to the sun is very large than that due to the earth.
  • As observed from the earth, the sun appears to move around the earth in a circular orbit though, in reality, the earth moves around the sun due to gravitational force between them
  • All planets move around the sun due to the huge gravitational force of the sun acting on them.
  • Since the gravitational force on mercury due to the earth is smaller as compared to that on it due to the sun therefore it revolves around the sun and not around the earth.

Hence, option (3) is the correct answer.

HPSC PGT Physics Mock Test - 4 - Question 13

A short bar magnet has a magnetic moment of 0.48 J/T .Magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on the axis has a direction and magnitude of .

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 13

Here M=0.48JT−1,d=10cm=0.1m
On axis,
B= (μ0​​/4π)(2M/d3)​=10−7×(2×0.48/0.13)​=0.96×10−4T

HPSC PGT Physics Mock Test - 4 - Question 14

Relation between torque and angular momentum is similar to the relation between

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 14

Torque is the rate of change of angular momentum. Force in linear motion corresponds to torque in rotary motion. Thus, just as Newton’s second law can be written as F = dP/dt (F for linear motion), it can be written as T = dL/dt for rotary motion.

HPSC PGT Physics Mock Test - 4 - Question 15

Relation between ray and wave front is

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 15

A wave front is a line representing all parts of a wave that are in phase and an equal number of wavelengths from the source of the wave. A ray is a line extending outward from the source and representing the direction of propagation of the wave at any point along it. Rays are perpendicular to wave fronts.

HPSC PGT Physics Mock Test - 4 - Question 16

The number of significant figures in the distance of one light year , 9.4605 × 1015 m is:

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 16

As the power of 10 is irrelevant in the determination of significant figures hence, the numbers of significant figures are 5 i.e. 9,4,6,0,5

HPSC PGT Physics Mock Test - 4 - Question 17

When a ball is thrown upwards, as it rises, the vertical component of its velocity

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 17

When a ball is thrown upwards, the vertical component of its velocity decreases as it rises because of the acceleration due to gravity (g), which acts downward.

  • Gravity opposes the upward motion, reducing the ball's vertical velocity until it becomes zero at the highest point.
  • After reaching the highest point, the ball starts descending, and the vertical velocity increases in the downward direction.

Thus, as the ball rises, the vertical component of its velocity decreases.

HPSC PGT Physics Mock Test - 4 - Question 18

A far- sighted person has lost his spectacles. He can read a book at usual distance by looking through a pin hole because while looking through the pin hole:

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 18

Long-sighted people who have lost their spectacles can still read a book by looking through a small (3-4 mm) hole in a sheet of paper because by doing so due to the diffraction at the hole the focal length of the eye lens is effectively decreased. Hence the correct option is C.
 

HPSC PGT Physics Mock Test - 4 - Question 19

The least count of any measuring equipment is:

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 19

The smallest value that can be measured by the measuring instrument is called its least count.

Measured values are good only up to this value. The least count error is the error associated with the resolution of the instrument.

HPSC PGT Physics Mock Test - 4 - Question 20

 The moment of inertia of a body depends upon -

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 20

I = mr2, therefore it depends on body mass and its mass distribution.
 

HPSC PGT Physics Mock Test - 4 - Question 21

A 14.5 kg mass, fastened to the end of a steel wire of unstretched length 1.0 m, is whirled in a vertical circle with an angular velocity of 2 rev/s at the bottom of the circle. The cross-sectional area of the wire is 0.065 cm2. Calculate the elongation of the wire when the mass is at the lowest point of its path.

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 21

Mass, m = 14.5 kg
Length of the steel wire, l = 1.0 m
Angular velocity, ω = 2 rev/s = 2 × 2π rad/s = 12.56 rad/s
Cross-sectional area of the wire, a = 0.065 cm2 = 0.065 × 10-4 m2
Let Δl be the elongation of the wire when the mass is at the lowest point of its path.
When the mass is placed at the position of the vertical circle, the total force on the mass is:
F = mg + mlω2
= 14.5 × 9.8 + 14.5 × 1 × (12.56)2
= 2429.53 N
Young’s modulus = Stress / Strain
Y = (F/A) / (∆l/l)
∴ ∆l = Fl / AY
Young’s modulus for steel = 2 × 1011 Pa
∆l = 2429.53 × 1 / (0.065 × 10-4 × 2 × 1011)   =   1.87 × 10-3 m
Hence, the elongation of the wire is 1.87 × 10–3 m
Hence 1.87 × 10–3 m

HPSC PGT Physics Mock Test - 4 - Question 22

A bar magnet of magnetic moment 1.5 J/T lies parallel to the direction of a uniform magnetic field of 0.22 T. What is the torque acting on it?

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 22

 Answer :- 

Solution :- torque when =180°

= 1.5 × 0.22 × sin 180°

= 0.33 × 0 = 0 Nm

HPSC PGT Physics Mock Test - 4 - Question 23

A sports car has a “lateral acceleration” of 0.96g = 9.4 m s−2. This is the maximum centripetal acceleration the car can sustain without skidding out of a curved path. If the car is traveling at a constant 40 m/s on level ground, what is the radius R of the tightest unbanked curve it can negotiate?

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 23

Explanation:

The car is in uniform circular motion because it’s moving at a constant speed along a curve that is a segment of a circle. Hence we know 

This is the minimum turning radius because arad is the maximum centripetal acceleration.

HPSC PGT Physics Mock Test - 4 - Question 24

A block takes twice as much time to slide down a 45o rough inclined plane as it takes to slide down a similar smooth plane. The coefficient of friction is   

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 24

HPSC PGT Physics Mock Test - 4 - Question 25

A ring has a total mass m but not uniformly distributed over its circumference. The radius of the ring is R. A point mass m is placed at the centre of the ring. Work done in taking away the point mass from centre to infinity is

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 25

W = increase in potential energy of system

=Uf - Ui

=m (Vf - Vi)

(V = gravitational potential)

Note: Even if mass is nonuniformly distributed potential at centre would be -GM/R

HPSC PGT Physics Mock Test - 4 - Question 26

Two different masses are dropped from same heights, then just before these strike the ground, the following is same :

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 26

Both the objects with different masses will attain the same v when striking the ground because acceleration and height is the same. 
As, K.E=(1​/2)mv2P.E=−GMm​p/r=mv
Thus K.E, P.E, and p will be different.
 

HPSC PGT Physics Mock Test - 4 - Question 27

The multiplication of 10.610 with 0.210 upto correct number of significant figure is:

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 27

The multiplication of the numbers:
10.610 × 0.210 = 2.2281

Since, the numbers 10.610 and 0.210 have 5 and 3 significant digits, respectively. So, the final result must also have 3 significant digits.

The final answer is 2.23 after rounding off 2.2281. 

HPSC PGT Physics Mock Test - 4 - Question 28

The electric current in a liquid is due to the flow of

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 28

In liquids the current is carried by ions. Ions are charged particles (atoms or groups of atoms). Ions can either be positive or negative, the positive ions being attracted to the negative plate and the negative ions to the positive plate. A positive ion is a particle with some negative charge taken away and a negative ion is a particle with some extra negative charge added.

HPSC PGT Physics Mock Test - 4 - Question 29

 A small particle of mass m is projected at an angle θ with the x-axis with an initial velocity v0 in the x-y plane as shown in the figure. At a time , the angular momentum of the particle is:

 [AIEEE 2010]

                           

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 29

HPSC PGT Physics Mock Test - 4 - Question 30

The current in a metallic conductor is plotted against voltage at two different temperatures T1 and T2. Which is correct

Detailed Solution for HPSC PGT Physics Mock Test - 4 - Question 30

According to Ohm's law R=V/I​ 
Where R= resistance, V= Voltage, I= Current
Also R  is directly proportional to temperature T and inversely proportional to the slope.
∴ from the above example
R1​∝T1​ and R2​∝T2
but from given figure R1​<R2
∴T1​<T2

View more questions
30 tests
Information about HPSC PGT Physics Mock Test - 4 Page
In this test you can find the Exam questions for HPSC PGT Physics Mock Test - 4 solved & explained in the simplest way possible. Besides giving Questions and answers for HPSC PGT Physics Mock Test - 4, EduRev gives you an ample number of Online tests for practice
Download as PDF