HPSC TGT/PGT Exam  >  HPSC TGT/PGT Tests  >  HPSC PGT Physics Mock Test - 6 - HPSC TGT/PGT MCQ

HPSC PGT Physics Mock Test - 6 - HPSC TGT/PGT MCQ


Test Description

30 Questions MCQ Test - HPSC PGT Physics Mock Test - 6

HPSC PGT Physics Mock Test - 6 for HPSC TGT/PGT 2025 is part of HPSC TGT/PGT preparation. The HPSC PGT Physics Mock Test - 6 questions and answers have been prepared according to the HPSC TGT/PGT exam syllabus.The HPSC PGT Physics Mock Test - 6 MCQs are made for HPSC TGT/PGT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HPSC PGT Physics Mock Test - 6 below.
Solutions of HPSC PGT Physics Mock Test - 6 questions in English are available as part of our course for HPSC TGT/PGT & HPSC PGT Physics Mock Test - 6 solutions in Hindi for HPSC TGT/PGT course. Download more important topics, notes, lectures and mock test series for HPSC TGT/PGT Exam by signing up for free. Attempt HPSC PGT Physics Mock Test - 6 | 100 questions in 120 minutes | Mock test for HPSC TGT/PGT preparation | Free important questions MCQ to study for HPSC TGT/PGT Exam | Download free PDF with solutions
HPSC PGT Physics Mock Test - 6 - Question 1

The stench due to leakage from LPG cylinder because of :

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 1

The correct answer is Ethyl mercaptan.

Key Points

  • The stench due to leakage from the LPG cylinder because of Ethyl mercaptan.
    • LPG gas is basically propane and butane.
    • It is odourless in its natural state.
    • The smell that you notice when there is a leak is actually the stench of an entirely different agent, called ethyl mercaptan​.
      • This substance is added to the gas when it leaves the main storage terminals.
  • Hence, option 4 is correct.
Additional Information
  • Methane :
    • Methane is a chemical compound with the chemical formula CH4.
    • Methane is a one-carbon compound in which the carbon is attached by single bonds to four hydrogen atoms
    • It is a group-14 hydride and the simplest alkane and is the main constituent of natural gas.
    • It is a colourless, odourless, non-toxic but flammable gas.
    • It has a role as a fossil fuel, a member of greenhouse gas, and a bacterial metabolite.
  • Butane :
    • Butane or n-butane is an alkane with the formula C4H10.
    • Butane is a gas at room temperature and atmospheric pressure.
    • Butane is a highly flammable, colourless, easily liquefied gas that quickly vaporizes at room temperature.
    • Butane is a hydrocarbon and a highly flammable, colourless, odourless, easily liquefied gas.
    • It is typically used as fuel for cigarette lighters and portable stoves, a propellant in aerosols, a heating fuel, a refrigerant.
  • Propane :
    • Propane is a three-carbon alkane with the molecular formula C3H8.
    • It is a gas at standard temperature and pressure, but compressible to a transportable liquid. 
    • Propane is a flammable hydrocarbon gas that is liquefied through pressurization and commonly used for fuel in heating, cooling, hot water, and vehicles.
    • Propane can also be used for refrigerants, aerosol propellants, and petrochemical feedstock.​ 
HPSC PGT Physics Mock Test - 6 - Question 2

Writings on hard surfaces such as stones or metals are called 

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 2

The correct answer is Inscriptions.

Key Points

  • Writings on hard surfaces like stone or metal are called Inscriptions.
  • Often kings got their orders inscribed so that people could see, read and obey them.
  • Other inscriptions have the activities done by men and women recorded on them.
  • Kings kept record of their victories in the form of inscriptions.

 Thus, we can say that writings on hard surfaces like stone and metals are called Inscriptions.

Additional Information

  •  Manuscripts were written on palm leaves or birch.
HPSC PGT Physics Mock Test - 6 - Question 3

Mahatma Gandhi was first arrested in which railway station of Haryana?

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 3

The correct answer is ​Palwal.

  • Mahatma Gandhi was arrested on April 10, 1919, when he was going to Punjab against the Rowlatt Act.

Key Points

  • Palwal Railway station is 29 km from Faridabad.
  • This was the place where Mahatma Gandhi was arrested for the first time.
  • In his remembrance, a building called ‘Gandhi Ashram’ is made.
  • Palwal is the 21st district of Haryana and Palwal city is the headquarters of this district.

Additional Information

  • Palwal got its name from a demon ‘Pulwasur’ who ruled this place during the time of Pandavas.
  • He was killed by Balram, the elder brother of Shri Krishna.
  • In memory of this incident ‘, the Baldev chat ka Mela festival is organized every year.
HPSC PGT Physics Mock Test - 6 - Question 4
During ancient times, Mahendragarh town of this state was known as
Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 4

The correct answer is Kandud.

Key Points

  • The old name of the Mahendragarh district of Haryana was Kanaud.
  • The previous name was derived from the Kanaudia group of Brahmins.
  • During the middle of the nineteenth century, it came to be known as Mahendragarh.

Additional Information

  • In 1861, ruler Maharaja Narendra Singh of Patiala principality named this fort in Mahendergarh in honor of his son Mohinder Singh.
  • This District has 3 Subdivisions: Narnaul, Mahendragarh, and Kanina.
  • Narnaul city is the administrative headquarters of the district and also the largest city in the district.
  • Mahendragarh district is divided into 5 tehsils, Narnaul, Nangal Chowdhary, Kanina Mahendragarh, and Ateli.
HPSC PGT Physics Mock Test - 6 - Question 5

A word with letters jumbled has been given. Choose the correct order of letters which are required to form the correct word.

Jumbled word: PTIOISCL

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 5

1) 8, 4, 3, 7, 1, 5, 2, 6

2) 5, 2, 7, 3, 4, 1, 8, 6

3) 3, 1, 6, 8, 4, 5, 2, 7

4) 1, 4, 8, 3, 2, 5, 7, 6

'POLITICS' is a meaningful English word.

Hence, '1, 4, 8, 3, 2, 5, 7, 6' is the correct answer.

HPSC PGT Physics Mock Test - 6 - Question 6

Which figure from the answer figures will replace the question mark (?) in the problem figures?

Problem Figures:

Answer Figures:

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 6

The logic followed here is:

The figure in image 2 is water image of the figure in image 1. The figure in image C of answer figure will be the water image of the figure in image 3.

Hence, image C of answer figure is the correct answer.

HPSC PGT Physics Mock Test - 6 - Question 7

A is father of C and D is son of B. E is brother of A. If C is sister of D, then how is B related to E?

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 7

The family chart is as follows:

i) A is father of C and D is son of B.

ii) E is brother of A.

iii) If C is sister of D

Drawing the family tree as per the given information:

Thus we can see B is the wife of A.

E is the brother of A.

Thus we can conclude B is the sister-in-law of E.

Hence, the correct answer is "Sister-in-law".

HPSC PGT Physics Mock Test - 6 - Question 8

How does NEP 2020 propose to promote experiential learning?

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 8

NEP 2020 recommends the incorporation of internships and projects to promote experiential learning.

HPSC PGT Physics Mock Test - 6 - Question 9

In a Young's double slit experiment, a small detector measures an intensity of illumination of I units at the centre of the fringe pattern. If one of the two (identical) slits is now covered, the measured intensity will be

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 9

If the intensity of central maxima is I, then intensity due to individual source must be I/4. So, if one of the slit is closed then due to remaining slit, intensity will be I/4.

HPSC PGT Physics Mock Test - 6 - Question 10

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Ω, L = 25.48 mH, and C = 796 μF. Power dissipated in the circuit; and the power factor are

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 10

Angular frequency of the ac signal w=2πν
∴ w=2π(50)=100π
Capacitive reactance Xc​=1/wC​
∴ Xc​=1/(100π×786×10−6)​=4Ω
Inductive reactance XL​=wL
∴ XL​=100π×(25.48×10−3)=8Ω
Impedance of the circuit Z=√[R2+(XL​−Xc​)2​]
∴ Z=√[32+(8−4)2​]=5Ω
 Phase difference ϕ=tan−1[(XL​−Xc​​)R]
Or ϕ=tan−1((8−4​)/3)=tan−1(4/3​)
⟹ ϕ=53.13o
Power factor cosϕ=cos53.13o=0.6
Power dissipated in the circuit
P=Iv2R
Now, Iv=I0/√2=E0/√2Z=283/(1.414×5)=40A
∴P=Iv2R=(40)2×3=4800 watt

HPSC PGT Physics Mock Test - 6 - Question 11

Two fixed frictionless inclined plane making an angle 30° and 60° with the vertical are shown in the figure. Two block A and B are placed on the two planes. What is the relative vertical acceleration of A with respect to B ?  

[AIEEE 2010]

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 11

HPSC PGT Physics Mock Test - 6 - Question 12

A particle of mass 1 Kg and charge 1/3 μC is projected towards a non conducting fixed spherical shell having the same charge uniformly distributed on its surface. The minimum intial velocity V0 of projection of particle required if the particle just grazes the shell is 

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 12

From conservation of angular momentum, 
mr0 = r/2 = mvr
⇒ v = v0/2
From conservation of energy,

HPSC PGT Physics Mock Test - 6 - Question 13

RMS value of ac i = i1 cos wt + i2 sin wt will be

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 13

I=(I1)cosωt+(I2)sinωt
(I2)mean=I12cos2ωt+I22sin2ωt+I1I2cosωtsinωt
I12×(1/2)×i22×(1/2)+2I1I2×0
Irms=√(i2)mean=√(I12+I22/2)=(1/√2)( I12+I22)1/2

HPSC PGT Physics Mock Test - 6 - Question 14

For a positively charged particle moving in a x-y plane initially along the x-axis, there is a sudden change in its path due to the presence of electric and/or magnetic fields beyond P.
The curved path is shown in the x-y plane and is found to be non-circular. Which one of the following combinations is possible?

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 14

The velocity at P is in the X-direction (given).

After P, the positively charged particle gets deflected in the x – y plane toward – y direction and the path is non-circular.

Since in option (b), electric field is also present therefore it will also exert a force in the + X direction.
The net result of the two forces will be a non-circular path.
Only option (b) fits for the above logic. For other option, we get some other results.

HPSC PGT Physics Mock Test - 6 - Question 15

If the coefficient of friction between an insect and bowl surface is μ and the radius of the bowl is r, the maximum height to which the insect can crawl in the bowl is  

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 15

HPSC PGT Physics Mock Test - 6 - Question 16

A conducting rod moves with constant velocity v perpendicular to the long, straight wire carrying a current I as shown compute that the emf generated between the ends of the rod.

                    

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 16

The magnetic field near the conducting rod due to long current carrying wire is 
B= μ0​I/2πr ​ (using Ampere's law, ∫B.dl=μ0​I)
Now, induced emf due to moving rod is e=Blv= (μ0​I/2πr) ​×lv= μ0​vIl/2πr

HPSC PGT Physics Mock Test - 6 - Question 17

If we have two coherent sources S1andS2 vibrating in phase, then for an arbitrary point P constructive interference is observed whenever the path difference is

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 17

Constructive interference occurs when the path differences (S1​P−S2​P) is an integral multiple of λ or (S1​P−S2​P)=nλ
Where n=0,1 ,2 3,….

HPSC PGT Physics Mock Test - 6 - Question 18

If the voltage across the electrodes of a cathode ray tube is 500 volts then energy gained by the electrons is

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 18

Voltage across the electrodes of a cathode ray gun, V=500V
Charge of the electron=1.6x10-19
Energy=eV
E= 1.6x10-19 x 500
E=800 x 10-19 J
E=8 x 10-17 J

HPSC PGT Physics Mock Test - 6 - Question 19

The speed of plane electromagnetic waves is maximum in

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 19

The speed of any electromagnetic waves in free space is the speed of light c = 3x108 m/s. Electromagnetic waves can have any wavelength λ or frequency f as long as λf = c.

HPSC PGT Physics Mock Test - 6 - Question 20

At the magnetic North Pole of the Earth, what is the value of the angle of dip?

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 20

Angle of dip is 90o at geographical North Pole because attraction on the North Pole of needle is very strong and the needle remains in vertical plane. At the magnetic equator, the needle will point horizontally, i.e. dip angle is 0o. As you move from the magnetic equator towards the magnetic pole, the angle increases in the northern hemisphere. So, the angle of dip is maximum.

*Multiple options can be correct
HPSC PGT Physics Mock Test - 6 - Question 21

The figure shows a circular loop of radius a with two long parallel wires (numbered 1 and 2) all in the plane of the paper. The distance of each wire from the centre of the loop is d. The loop and the wire are carrying the same current I.The current in the loop is in the counterclockwise direction if seen from above.

(q) The magnetic fields (B) at P due to the currents in the wires are in opposite directions.

(r) There is no magnetic field at P.

(s) The wires repel each other.

Q.5. Consider d >> a, and the loop is rotated about its diameter parallel to the wires by 30° from the position shown in the figure. If the currents in the wires are in the opposite directions, the torque on the loop at its new position will be (assume that the net field due to the wires is constant over the loop).

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 21

We know that torque

 

HPSC PGT Physics Mock Test - 6 - Question 22

The north pole of a magnet is brought near a coil. The induced current in the coil as seen by an observer on the side of magnet will be

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 22

The direction of the current will be anticlockwise.
 
According to Lenz's law, the current in the coil will be induced in the direction that'll oppose the external magnetic field .
As the flux due to the external magnet is increasing ( as the N-pole is brought close ) , the coil will have to induce current in the anticlockwise direction to oppose this increase in flux and not in clockwise direction as that'll end up supporting the external flux.

HPSC PGT Physics Mock Test - 6 - Question 23

At any instant if the velocity of point A is 10 m/s then calculate the velocity of point B?

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 23

HPSC PGT Physics Mock Test - 6 - Question 24

Nuclear mass M is found to be

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 24

The actual mass is always less than the sum of the individual masses of the constituent protons and neutrons because energy is removed when the nucleus is formed. This energy has mass, which is removed from the total mass of the original particles.

HPSC PGT Physics Mock Test - 6 - Question 25

Vapour is injected at a uniform rate in a closed vessel which was initially evacuated. The pressure in the vessel

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 25

HPSC PGT Physics Mock Test - 6 - Question 26

Two pendulums have time periods T and 5T/4. They are in phase at their mean positions at some instant of time. What will be their phase difference when the bigger pendulum completes one oscillation?

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 26

https://cn.edurev.in/ApplicationImages/Temp/540839_ead174e5-cd42-4612-ab3a-d5f431628c54_lg.png

*Multiple options can be correct
HPSC PGT Physics Mock Test - 6 - Question 27

A conducting rod PQ of length L = 1.0 m is moving with a uniform speed v = 20 m/s in a uniform magnetic field B = 4.0 T directed into the paper. A capacitor of capacity C = 10 mF is connected as shown in figure. Then

            

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 27

According to Fleming’s right-hand rule induced current flows from Q to P.
Hence P is at higher potential and Q is at lower potential. 
Therefore, A is positively charged and B is negatively charged.
Hence:
qA​=+800μC and qb​=−800μC

HPSC PGT Physics Mock Test - 6 - Question 28

The sum of the numbers 436.32, 227.2 and 0.301 in appropriate significant figures is

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 28

The result of an addition or subtraction in the number having different precisions should be reported to the same number of decimal places as present in the number having the least number of decimal places.

The final result should, therefore, be rounded off to one decimal place, i.e. 663.8

HPSC PGT Physics Mock Test - 6 - Question 29

Electric potential is a -

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 29

Electric potential is a pure Scalar quantity, The reason is as follows.
The Electric Potential is defined as the amount of work-done per unit positive charge to bring from infinity to that point under the influence of the primary charge only.
U=W/q
And work done is defined as the dot product of force and displacement which is a scalar quantity.
W=F.S
Thus Electric potential is a scalar quantity.

HPSC PGT Physics Mock Test - 6 - Question 30

Which of the following statements about magnetic field lines true?

Detailed Solution for HPSC PGT Physics Mock Test - 6 - Question 30

Magnetic poles exist in pairs. It is not possible to isolate a north pole or a south pole. Magnetic field lines start from the north pole and go to the south pole and return to the north pole. They form continuous closed loops unlike electric lines of force which do not as an electric monopole, a single charge does exist.

View more questions
Information about HPSC PGT Physics Mock Test - 6 Page
In this test you can find the Exam questions for HPSC PGT Physics Mock Test - 6 solved & explained in the simplest way possible. Besides giving Questions and answers for HPSC PGT Physics Mock Test - 6, EduRev gives you an ample number of Online tests for practice
Download as PDF