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Bihar STET Paper 1 Mathematics Mock Test - 10 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar STET Mock Test Series 2024 - Bihar STET Paper 1 Mathematics Mock Test - 10

Bihar STET Paper 1 Mathematics Mock Test - 10 for Bihar PGT/TGT/PRT 2024 is part of Bihar STET Mock Test Series 2024 preparation. The Bihar STET Paper 1 Mathematics Mock Test - 10 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 1 Mathematics Mock Test - 10 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 1 Mathematics Mock Test - 10 below.
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Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 1

If two positive integers a and b are written as a = x3y2 and b = xy3, where x, y are prime numbers, then LCM(a, b) is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 1

Here, a = x3y2 and b = xy3.
⇒ a = x * x * x * y * y and b = xy * y * y
∴ LCM(a, b) = x * y * y = x3 * y3 = x3y3
LCM = x3y3

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 2

For what values of k can the following numbers form an A.P:2k-1,k+2,2k​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 2

If  2k-1,k+2,2k are in AP, the difference of two consecutive terms will be same.
Therefore,

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Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 3

Evaluate: 303 + 203 – 503.​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 3

We have to find the value of

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 4

The probability of a sure event is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 4

The probability of a sure event is always 1.

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 5

Modal age of students in given distribution is​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 5

Mode is the most frequently occurring observation. Since it's not a grouped data the frequency is the occurrence of only one observation , So the highest no. of frequency is 7 . So the modal age is 13.

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 6

If one root of the equation 4x2−2x+(λ−4) = 0 be the reciprocal of the other, then the value of is 

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 6

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 7

If (2x + 5) is a factor of 2x2 – k, then the value of k is.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 7

Let p(x) = 2x2 − k
Since, (2x+5) is a factor of p(x), then by factor 
theorem,

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 8

Read the following text and answer the following question on the basis of the same:

Authority wants to construct a slide in a city park for children. The slide was to be constructed for children below the age of 12 years. Authority prefers the top of the slide at a height of 4 m above the ground and inclined at an angle of 30° to the ground.

Q. In the given figure, the value of (sin C × cos A) is:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 8

Since, AC ⊥ BC, then ∠C = 90°

sin 30 =AC/AB = 4/AB  
1/2=4/AB
AB=8

= 1 x 4 / 8

= 1 / 2

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 9

If the zeroes of the quadratic polynomial x2 + (a + 1) x + b are 2 and -3, then

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 9

p(x) = x2 + (a + 1)x + b
Given: zeros of polynomial is 2, -3
For x = 2
(2)2 + (a + 1)2 + b = 0
⇒ 4 + 2a + 2 + b = 0
⇒ 2a + b = -6 ...(i)

For x = -3
(-3)2 + (a + 1) (-3) + b = 0
⇒ 9 - 3a - 3 + b = 0
⇒ -3a + b = -6 ..(ii)

Solving (i) and (ii), we get 5a = 0
⇒ a = 0 and b = -6

Alternative method:

p(x) = x2 + (a + 1)x + b
Given: zeros of polynomial is 2, -3

Sum of zeros: -(a+1) = 2-3
⇒ a = 0
Product of zeros: b = 2.(-3) = -6 

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 10

What will be the nature of the graph lines of the equations 5x-2y+9 and 15x-6y+1?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 10

2. Coincident

  • Coincident Lines: Two lines are coincident if they are exactly the same line, meaning they have the same slope and y-intercept. In other words, they overlap completely.
  • For the given equations:

              

  •  Because the y-intercepts are different, the lines are not coincident.

3. Intersecting

  • Intersecting Lines: Two lines are intersecting if they cross each other at exactly one point. This happens when the lines have different slopes.

4. Perpendicular to Each Other

  • Perpendicular Lines: Two lines are perpendicular if the product of their slopes is −1-1−1. In other words, if the slopes are negative reciprocals of each other.

       

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 11

Root of the equation x2 - 0.09 = 0 is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 11

x2 - 0.09 = 0
x2 = 0.09
x = √0.09
x = 0.3

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 12

If angles A, B, C and D of the quadrilateral ABCD, taken in order, are in the ratio 3:7:6:4, then ABCD is 

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 12

 Given, ratio of angles of quadrilateral ABCD is 3 : 7 : 6 : 4.
Let angles of quadrilateral ABCD be 3x, 7x, 6x and 4x, respectively. We know that, sum of all angles of a quadrilateral is 360°.
3x + 7x + 6x + 4x = 360°
=> 20x = 360°
=> x=360°/20° = 18°

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 13

If one root of polynomial equation ax2 + bx + c = 0 be reciprocal of other, then

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 13

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 14

The angle of elevation of the top of a tower from a distance 100 m from its foot is 60°. The height of the tower is :

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 14

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 15

If x = a cos θ and y = b sin θ, then the value of b2x+ a2y2 is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 15


Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 16

Find the measure of angle marked e in the figure below:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 16
D+e=180(angles on linear pair),but d=30(vertically opposite angles),30+e=180,e=180-30,e=150
Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 17

X is a point on a circle with centre O. If X is equidistant from the two radii OP, OQ, then arc PX : arc PQ is equal to

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 17


Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 18

Which of the following equations has the sum of its roots as 3?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 18

sum of root = -b/a
for (3) option sum of roots will be -(3)/(-1) = 3

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 19

If x = 2 and x = 3 are zeros of the quadratic polynomial x2 + ax + b, the values of a and b respectively are :

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 19

Zeros of the polynomials are the values which gives zero when their value is substituted in the polynomial
When x=2,
x2+ax+b =(2)2+a*2+b=0
4+2a+b=0
b=-4-2a    ….1
When x=3,
(3)2+ 3a + b=0
9 + 3a + b=0
Substituting 
9 + 3a - 4 - 2a =0
5 + a =0
a = -5
b = 6

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 20

The mean of a data set with 12 observations is calculated as 19.25. If one more value is included in the data, then for the new data with 13 observations, mean becomes 20. Value of this 13th observation is​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 20

Suppose be all twelevth terms = x
Mean = Terms / Observation
19 . 25 = x / 12
x = 19.25 × 12
x = 231 .00

Now let thirteenth term will be y
Mean = 20
So, 20 = x + y / 13
20 = 231 + y / 13
20 × 13 = 231 + x
260 = 231 + x
260 - 231 = x
29 = x

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 21

If p(x) = x + 3, then p(x) + p(-x) is equal to

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 21
Given p(x) = x+3, put x = -x in the given equation, we get p(-x) = -x+3
Now, p(x)+ p(-x) = x+ 3+ (-x)+ 3=6
Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 22

Find the circumference of the circle, whose area is 144π cm2

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 22

The area should be 144π,
 ,Area of the circle= πr2
144π = πr2
r = 12cm
Circumference=2πr = 24πcm

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 23

Mode is not affected by

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 23

The mode of a set of data values is the value that appears most often.it is the value that is most likely to be sampled This means mode is the observations whose frequency is highest. So it does not pay attention to what is the maximum value or the minimum value . So it is not affected either by maximum or minimum values and its not affected by both as well.

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 24

The H.C.F of 441, 567 and 693 is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 24

693 = 3×3×7×7
567 = 3×3×3×3×7
441 = 3×3×7×11
Therefore H.C.F of 693, 567 and 441 is 63.

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 25

Which of the following communications has an emotional appeal?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 25

Interpersonal communication is the process by which people exchange information, feelings, and meaning through verbal and non-verbal messages: it is face-to-face communication. Emotions result from outside stimuli or physiological changes that influence our behaviors and communication.

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 26

Which is the best method to improve slow learning students?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 26

Slow learners learn the concepts at a lower pace than other students leading to delay in their work. One of the best methods that can help them is self exploring the things. This will lead them to understand things better.

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 27
A teacher believes that each child is unique and a special individual, and therefore actively involves them in their own education and development. The teacher is adopting:
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 27

If a teacher believes that each child is unique and a special individual, and therefore actively involves them in their own education and development.

The teacher is adopting a child-centric education. In this approach, the ‘learner’ or ‘child’ is the main focus of the educational programme. It emphasizes ‘learning’ rather than ‘teaching’.

Child-centric education advocates that-

  • accommodate the individual difference and unique character of each individual learner
  • each individual’s growth presents a different range of problems and requirements,
  • at every stage from the womb to tomb” implying that the child’s individuality and dignity should be respected and his/her needs, interests, aptitude. So that two individual provided opportunities to grow and realise their potentials in the same class.
  • Teacher adopts a variety of teaching-learning strategies to address the needs of all children at the same time.
  • Varieties of activities/opportunities are available in the classroom, which enables each child to learn at her/his own pace and in tune with her/his own learning style. 

Here it is clear that if a teacher believes that each child is unique and a special individual, and therefore actively involves them in their own education and development. The teacher is adopting a child-centric approach to learning. 

Additional Information

In a child-centred classroom-

  • The child is not a passive but an active participant in the classroom process.
  • Reflects planning of teaching-learning and its monitoring jointly by teacher and children
  • Evaluation of the child’s attainment is done to ensure the child’s progress and not as a means of passing judgement on the child’s abilities and achievement. it is diagnostic as well as remedial.
Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 28
Which of the following method is based on learning-central approach of Education?
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 28

A learner-centered approach places the learner at the center of the learning process, emphasizing active engagement and personalized learning.

Key Points

  • Activity-based scaffolding is an approach to teaching that involves breaking down complex tasks into smaller, more manageable parts and providing support as needed to help students develop the skills they need to complete those tasks independently.
  • Activity-based scaffolding is particularly effective for helping students develop complex skills and knowledge.

Thus, it is based on  is based on the learner-centered approach of Education.

Additional Information

  • Lecturing-demonstration is a teaching method in which the teacher presents information to the students, often using visual aids or hands-on demonstrations.
  • Joyful method is not a commonly used term in education, but it may refer to teaching methods that emphasize fun and engagement in the learning process.
  • Inductive method is a teaching method that involves presenting specific examples and then drawing general conclusions based on those examples.
Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 29
In which teaching method, does the learner practically work to achieve the goal?
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 29

Practice-based learning is more than 'learn the theory then go to work. ' With practice-based learning, students combine theory and work experience with a strategic, reflective process throughout the duration of your learning. Students don't just learn the theory first, then jump into the classroom and apply it afterward. Key Points

Advantages of practical teaching method

  • Practical-Learning assists students in identifying their real interests and choose a career accordingly.
  • Makes the learner practically work to achieve the goal.
  • Provides Basic Skills for Students. Practice and drills give students an opportunity to learn certain concepts quickly and effectively.

Hence, we can conclude that in practical teaching method does the learner practically work to achieve the goal.Additional Information

Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 30
Activity-Based Learning is essentially a form of _______.
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 10 - Question 30

Activity-based learning refers to learning through hands-on experience to develop an understanding of the environment around us. An activity is an action performed by the students to understand their environment and the environmental processes. 

Key Points

  •  Activity-based learning is a form of Learner-centered approach. It stimulates curiosity and independent thinking, develops problem-solving skills, promotes planning and execution of projects, and develops self-learning involving the acquisition of knowledge through observation of phenomena, and creative thinking abilities.
  • Tuition -Centric approach - This approach does not exist.
  • Teacher-Centric approach - It emphasizes the importance of a teacher and ignores the active involvement of the learner in the teaching-learning process.
  • Subject-Centric approach - It focuses on the subject matter and acquiring the subject knowledge through textbooks and resources available to be a master in the subject rather than the development of the child.

Hence, option 2 is the correct solution.

Important Points 

  • In a learner-centered approach, the Learner is at the center of all activities and the teacher plays the role of a facilitator of the learning process and an organizer of the learning situation.
  • The learner brings with him/her previous knowledge and experiences which influence the classroom learning process.
  • In this approach, the focus is given on developmental stages, maturity, learning strategies, prior knowledge and experiences, interests, social context, and culture of the learner.
  • The teacher must understand the learner and their learning styles to know in detail the characteristics of each and every learner in our classroom.       
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