Bihar STET Paper 2 Physics Mock Test - 7 - Bihar PGT/TGT/PRT MCQ

f=BA, area of square=(side)2
so, for case I.
loops is continuous,
so, flux should be added,
f=(L²+l²)B
for case II
loop is opposite,
so, flux should be subtracted
f=(L²-l²)B

The equivalent resistance of the group of resistances is R.
case 1:
a resistance r(say) is connected in parallel to the group, its new equivalent resistance R₁ is
R₁​=Rr/R+r​
hence, R₁​<R.
case 2:
a resistance r is connected in series to the group, its new equivalent resistance R₂ is
R₂​=R+r
hence, R₂​>R.

The beat frequency is always equal to the difference in frequency of the two notes that interfere to produce the beats. So if two sound waves with frequencies of 258 Hz and 256 Hz are played simultaneously, a beat frequency of 2 Hz will be detected.

KEY CONCEPT : Use Fleming's left hand rule. We find that a force is acting in the radially outward direction throughout the circumference of the conducting loop.

A reversible process gives the maximum work.

Argument of sin is dimensionless and using principle of dimensional homogeneity, we get
∣bt∣=∣cx∣=[M₀L₀T₀]
Thus, ∣b∣=T−1 and ∣c∣=[L⁻¹]
Thus, dimensions of b/c are [LT⁻¹], which is the same as the velocity of wave.

Stress is the force per unit area experienced by the body and strength is the ability to withstand the stress. When stress becomes greater than strength, accidents happen.

A conservative force is one for which the work done by the force in moving an object between two points is independent of the path taken. The gravitational force is an example of a conservative force since the work done by gravity in moving an object only depends on the initial and final positions, not the path taken. Frictional force, magnetic force, and tension force are non-conservative forces since the work done by these forces depends on the path taken.

In electrical engineering, admittance is a measure of how easily a circuit or device will allow a current to flow. It is defined as the reciprocal of impedance, analogous to how conductance & resistance are defined. The SI unit of admittance is the siemens (symbol S); the older, synonymous unit is mho, and its symbol is ℧ (an upside-down uppercase omega Ω). Oliver Heaviside coined the term admittance in December 1887. 
Admittance is defined as
Y=1/Z
where
Y is the admittance, measured in siemens
Z is the impedance, measured in ohms
 

Correct Answer :- d

Explanation : The load applied to a column would place the column in compression; conversely, a load hanging from a rod would place the rod in tension. Strain is the deformation of a structural member because of stress within the member.

Newton's law of cooling states that the heat released by a body with respect to time (or) the rate of heat released is directly proportional to the difference between the body's temperature and the surrounding temperature. 
dH/dt = k(T – Ts) where t = surrounding's temperature and T = temperature of the body 
Consider two bodies A and B, of equal surface areas, such that A's temperature is more that B's temperature and the surrounding temperature is less than both A and B. Then according to Newton's law of cooling A loses more heat to the surroundings when compared B during the same time interval. So, A will cool faster than B.

There is no force which can balance the weight of m₁.  

We know that magnitude of bulk modulus
K=[P/(dV/V)]
Now, percentage change in volume is. 10^-3 %
Therefore, (dV/V)x100=10^-3
So, dV/V=10^-5
Hence, k is,
K=40atm/10^-5=40x1.01x10⁵ /10^-5 =4.04x10¹¹ N/m² 

Energy in 1 revolution=2 x P x a x l=2 x 9 x104 x 0.2 x0.6 j=21600J
Energy in n revolutions= 21600nJ
Power=E/t=21600n/t=21600 x 5=18000 J/s= 108000/746 h.p=144.77 h.p.

y₁=Asin3 ωt
y₂=A₂cos(3ωt+p/6)
y₂=A₂cosd2
y₁=A sin(3ωt+p/2- p/2)
   =A sin(p/2+3ωt- p/2)
y₁=A cos(3ωt- p/2)  [sin(p/2+θ)=Cosθ]
y1=A1cosd1
d₂-d₁=(3ωt+p/6)- (3ωt- p/2)
=p/6+p/2=2p/3

 Suppose the angle between the transmission axes of the analyser and the polarizer is θ. The completely plane polarized light form the polarizer is incident on the analyser. If E₀ is the amplitude of the electric vector transmitted by the polarizer, then intensity I₀ of the light incident on the analyser is
I ∞ E₀²
 
The electric field vector E₀ can be resolved into two rectangular components i.e E₀ cosθ and E₀ sinθ. The analyzer will transmit only the component ( i.e E₀ cosθ ) which is parallel to its transmission axis. However, the component E₀sinθ will be absorbed by the analyser. Therefore, the intensity I of light transmitted by the analyzer is,
 
I ∞ ( E₀ x cosθ )²
 
I / I₀ = ( E₀ x cosθ )² / E₀² = cos2θ
 
I = I₀ x cos²θ
when light passes from polarizer it's intensity becomes half and when passed through analyser it becomes,
I = I₀ x cos²θ/2
 

white light is made up of seven colors VIBGYOR. All the seven colors will show interference, we can treat each color separately as a monochromatic light and study their interference separately. Each light will have their bright and dark fringes separately but at y=0 i.e for a center, each lights bright fringe will coincide. Two or more lights may have their bright and dark Fringe together or bright for one and dark for others may coincide depending upon the situation.

Gravitational Potential V = -GM/R for hollow spherical shell at the centre. If we replace R by R/2 then we get V = -2GM/R. Therefore it decreases.

Potential difference between two points is given by

V_a - V_b = W/q₀

Work, W = 2 J

Charge, q₀ = 20 C

Potential difference = 2/20 = 0.1 V

The correct option is C.

Balance the 2 opposite moments of inertia on the 2 sides
1 × 500 = F × 5
F = 100

On solving we get 3L/4
 

i=4sin(100πt+ π/6)
For I to be maximum
di/dt=0
therefore,4x100π(cos(100πt+π/6)=0
therefore, ωs(100πt+ π/6)=0
for the first time cosθ=0 at π/2
⇒ 100πt+ π/6= π/2
⇒ 100πt= π/3
⇒ πt= π/300
T=1/300

Lev Vygotsky is a Soviet psychologist who did plenty of research on children and came up with the sociocultural theory of cognitive development. His theory was based on the effects of social interactions on a child's cognitive development.

Objective questions are beneficial to assess the knowledge of the complete syllabus in short time. Maximum syllabus can be covered by making objective type questions. Hence, this is the ideal way to assess whether the child has prepared entire syllabus or not.

The National Mission on Foundational Literacy and Numeracy in NEP 2020 aims to enhance early literacy and numeracy skills.

The teacher should provide an overview of the main points before launching into the body of the speech. This tunes the mind of the students to capture information, which the teacher is about to provide to the students. The overview helps creating interest in the subject being taught, and the student anticipates things which he is about to learn, along with the combination of his previous knowledge and experience.

Continuous Comprehensive Evaluation is a school-based evaluation system. It promotes orderly learning and development. It includes regularity in assessment, diagnosis of learning gaps, retesting, etc. So, CCE emphasizes how learning can be observed, recorded, and improved upon. It is a 'continuous' process after each course over the entire session. 'Comprehensive' means the scheme follows both scholastic and co-scholastic aspects of students.
Hence, the correct answer is, 'How learning can be observed, recorded and improved upon.'

Different colours will make picture more attractive and easy to understand. This will leave an image on student's mind which will make the diagram easy to remember.

Gifted students have some advanced mental potential as compared with other children. Hence, they should be asked to spend more time on questions dealing with creating so that their extraordinary abilities can be channelled into discovering new ways to solve a problem.
Hence, this is the correct answer.