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AWES TGT Physics Mock Test - 10 - AWES TGT/PGT MCQ


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30 Questions MCQ Test - AWES TGT Physics Mock Test - 10

AWES TGT Physics Mock Test - 10 for AWES TGT/PGT 2025 is part of AWES TGT/PGT preparation. The AWES TGT Physics Mock Test - 10 questions and answers have been prepared according to the AWES TGT/PGT exam syllabus.The AWES TGT Physics Mock Test - 10 MCQs are made for AWES TGT/PGT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for AWES TGT Physics Mock Test - 10 below.
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AWES TGT Physics Mock Test - 10 - Question 1

Benisagar, which is in the news recently, is a place located in which state?

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 1
  • The Archaeological Survey of India (ASI) have stated excavations in Benisagar – which is a village in Jharkhand’s West Singhbhum district. The excavation has yielded hundreds of artifacts indicating continuous human habitation from the fifth century A.D. until the 16-17 century A.D.
  • Benisagar has been recognized by the ASI and listed among the top 100 significant archaeological monuments in the country.
AWES TGT Physics Mock Test - 10 - Question 2

Which country is currently on high alert due to unprecedented seismic activity and concerns of an imminent volcanic eruption in the Reykjanes peninsula?

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 2

Iceland is on high alert as an unprecedented seismic swarm, with 800 earthquakes in 14 hours, has raised concerns about a possible volcanic eruption in the Reykjanes peninsula. The Iceland Met Office has warned of a "considerable" likelihood of a volcanic eruption in the coming days, leading to the declaration of a state of emergency.

AWES TGT Physics Mock Test - 10 - Question 3

_________ is the study of cognitive development that is concerned with basic mechanics of learning.

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 3

The behavioristic approach focuses on the mechanics of learning.

  • Behaviorist approach is the study of cognitive development that is concerned with the basic mechanics of learning. Learning - changes in behavior because of experiences (excluding changes due to fatigue, injury, or drug effects), is at the center of this approach.
  • The central tenet of behaviorism is that an organism learns behavioral adaptation, whose learning is governed by the principles of association (forming connections between ideas and events).
  • Behaviorism stands apart from other approaches by its emphasis on the relationship between observable behavior (responses) and environmental events (stimuli).

Behaviorism or the behaviorist approach lays stress on the role of environmental stimuli in determining the way we act. Behaviorism is also referred to as behavioristic psychology.

AWES TGT Physics Mock Test - 10 - Question 4

Which of the following is an example of scaffolding?

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 4

One of the goals of education is to develop independent learning in students. However, at times, students might need a little push from the teacher in order to achieve that independence. Scaffolding is a technique that helps during such a scenario.

AWES TGT Physics Mock Test - 10 - Question 5

Which of the following tools/methods does National Education Policy 2020 propose for assessment of children?

(i) Role plays

(ii) Group work

(iii) Portfolios

(iv) Projects

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 5

Education Policy lays particular emphasis on the development of the creative potential of each individual. It is based on the principle that education must develop not only cognitive capacities - both the ‘foundational capacities ’of literacy and numeracy and ‘higher-order’ cognitive capacities, such as critical thinking and problem solving – but also social, ethical, and emotional capacities and dispositions.

National Education Policy 2020-

According to NEP 2020, A good educational institution is one in which every student feels welcomed and cared for, where a safe and stimulating learning environment exists, where a wide range of learning experiences are offered, and where good physical infrastructure and appropriate resources conducive to learning are available to all students.

Key Points Some important fundamental principles of the NEP 2020 are- 

  • Establishment of the linkage of the concepts with the environment or we can say that the linkage of the school with the home.
  • It includes the overall development of the leader, it covers all three aspects as Cognitive domain, affective domain, and psychomotor domain.
  • It will include Progress of the Child in Inquiry-Based Learning, Quiz, Projects Roleplay, Group Work, Portfolios, etc, as part of the assessment of the students.
  • Promoting self-assessment and the peer assessment done by the student in the classroom.
  • Making board examination low stake and less stressful by focusing on Logic and Core Competencies
  • It emphasizes group work as well as individual work, NEP 2020 links the study to the curriculum.
  • Hence we conclude that all the objectives given in the question are correct for the assessment of the student.

Important Points  There are many changes in the assessment of the child, proposed in NEP 2020:

  • Continuous Tracking Of Learning Outcome Of Each Child.
  • Board Examinations to be made more flexible with an assessment of essential skills.
  • Assessment to focus on core concepts, higher-order, and foundational skills 
  • AI-based soft wares to help track the progress of students to enable them to make optimal career choices.
  • National Assessment Centre (PARAKH) will bring greater synergy to board examinations.
  • Self Assessment & Peer Assessment.
  • National Testing Agency (NTA) will work to offer a Common Aptitude Test of high quality to eliminate the need for coaching for these exams. 
AWES TGT Physics Mock Test - 10 - Question 6
As per the NEP 2020, the Rajasthan government has decided to come up with a new syllabus that includes 3 languages, which are-
Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 6

National Education Policy (July 29, 2020) was finalized after reviewing the suggestions Kasturirangan committee, its vision is to develop a Bharat-centric knowledge society. A society that has its roots in eternal Bhartiya Sanskriti and looking forward to moving with the world. 

Key Points The NEP 2020 stipulated that the three-language formula would be maintained while keeping in mind the Constitution, the aspirations of the people, regions, and the Union, and the necessity to encourage multilingualism as well as national unity.

  • It stipulates that the three-language formula would be more flexible, that no language will be imposed on any state, and that one of its key priorities will be the promotion of regional languages.
  • In light of the foregoing, the Rajasthan State Council of Educational Research and Training (RSCERT) developed a new curriculum that includes three languages: Hindi, English, and the local dialect/ languages.
  • The central government recognizes 18 dialects from the state of Rajasthan, hence the state government has the authority to choose any of these 18 dialects in different regions.

Thus, it can be inferred that as per the NEP 2020, the Rajasthan government has decided to come up with a new syllabus that includes 3 languages, which are Hindi, English, and local languages.

AWES TGT Physics Mock Test - 10 - Question 7

In YDSE how many maxima can be obtained on the screen if wavelength of light used is 200nm and d = 700 nm.

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 7

Given that λ = 200nm, d=700nm
θ = λ/d
We know that maximum angle can be 900
No of rings that can be obtained say n,

If θ is so small then −

AWES TGT Physics Mock Test - 10 - Question 8

A man of mass m stands on a platform of equal mass m and pulls himself by two ropes passing over pulleys as shown in figure. If he pulls each rope with a force equal to half his weight, his upward acceleration would be 

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 8

AWES TGT Physics Mock Test - 10 - Question 9

According to Farady's law

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 9

Explanation:The induced electromotive force in any closed circuit is equal to the negative of the time rate of change of the magnetic flux enclosed by the circuit.

AWES TGT Physics Mock Test - 10 - Question 10

The resistance of a semi-conductors

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 10

The resistivity of a semiconductor decreases with temperature. This is because of increasing temperature, the electrons in the valence band gain sufficient thermal energies to jump to the conduction band. As the number of electrons in the conduction band increases, so conductivity increases and resistivity decreases.

AWES TGT Physics Mock Test - 10 - Question 11

Which of the given phenomenon is not related to convection?

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 11

Convection is the movement of surrounding medium according to density by which transfer of heat takes place. Whereas in option A it tells about the transfer of heat due to molecules inside conductor, which is conduction.

AWES TGT Physics Mock Test - 10 - Question 12

A force time graph for the motion of a body is as shown in figure. Change in linear momentum between 0 and 6 s is 

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 12

Area under F-t curve = change in momentum = 2 x (-2) + 1 x 4 = -4 + 4 = 0  

AWES TGT Physics Mock Test - 10 - Question 13

A battery is connected between two points A and B on the circumference of a uniform conducting ring of radius r and resistance R. One of the arcs AB of the ring subtends an angle q at the centre.The value of the magnetic induction at the centre due to the current in the ring is

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 13

Magnetic field at the centre due to current in arc ABC is

Magnetic field at the centre due to current in arc ADB is

Therefore net magnetic field at the centre

 

 

AWES TGT Physics Mock Test - 10 - Question 14

A new unit of length is chosen such that the speed of light in vacuum is unity. What is the distance between the Sun and the Earth in terms of the new unit if light takes 8 min and 20 s to cover this distance?

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 14

► Time can be converted as t = (8 x 60) + 20s = 500 seconds
► Now speed given= 1 unit
We know speed = Distance / Time
which implies distance = Speed x Time
Hence, the distance becomes 1 x 500 = 500 units.

AWES TGT Physics Mock Test - 10 - Question 15

7.5 MHz to 12 MHz band corresponds to wavelength band of

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 15

f​1=7.5×106 Hz
f2​=12×106 Hz
λ1​=c/f1​=40 m
λ2​=c/f2​=25 m
 
So, the range is 40m to 25m

AWES TGT Physics Mock Test - 10 - Question 16

An unpolarised beam of intensity Io is incident on a polarizer and analyser placed in contact. The angle between the transmission axes of the polarizer and the analyser is θ. What is the intensity of light emerging out of the analyser?​

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 16

 Suppose the angle between the transmission axes of the analyser and the polarizer is θ. The completely plane polarized light form the polarizer is incident on the analyser. If E0 is the amplitude of the electric vector transmitted by the polarizer, then intensity I0 of the light incident on the analyser is
I ∞ E02
 
The electric field vector E0 can be resolved into two rectangular components i.e E0 cosθ and E0 sinθ. The analyzer will transmit only the component ( i.e E0 cosθ ) which is parallel to its transmission axis. However, the component E0sinθ will be absorbed by the analyser. Therefore, the intensity I of light transmitted by the analyzer is,
 
I ∞ ( E0 x cosθ )2
 
I / I0 = ( E0 x cosθ )2 / E02 = cos2θ
 
I = I0 x cos2θ
when light passes from polarizer it's intensity becomes half and when passed through analyser it becomes,
I = I0 x cos2θ/2
 

AWES TGT Physics Mock Test - 10 - Question 17

A 14.5 kg mass, fastened to the end of a steel wire of unstretched length 1.0 m, is whirled in a vertical circle with an angular velocity of 2 rev/s at the bottom of the circle. The cross-sectional area of the wire is 0.065 cm2. Calculate the elongation of the wire when the mass is at the lowest point of its path.

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 17

Mass, m = 14.5 kg
Length of the steel wire, l = 1.0 m
Angular velocity, ω = 2 rev/s = 2 × 2π rad/s = 12.56 rad/s
Cross-sectional area of the wire, a = 0.065 cm2 = 0.065 × 10-4 m2
Let Δl be the elongation of the wire when the mass is at the lowest point of its path.
When the mass is placed at the position of the vertical circle, the total force on the mass is:
F = mg + mlω2
= 14.5 × 9.8 + 14.5 × 1 × (12.56)2
= 2429.53 N
Young’s modulus = Stress / Strain
Y = (F/A) / (∆l/l)
∴ ∆l = Fl / AY
Young’s modulus for steel = 2 × 1011 Pa
∆l = 2429.53 × 1 / (0.065 × 10-4 × 2 × 1011)   =   1.87 × 10-3 m
Hence, the elongation of the wire is 1.87 × 10–3 m
Hence 1.87 × 10–3 m

AWES TGT Physics Mock Test - 10 - Question 18

When a satellite moves around the earth in a certain orbit, the quantity which remains constant is

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 18

Kepler's Law states a principle relevant to planetary motion. The area swept out by a line connecting a planet to the Sun is constant over time. This principle ensures that the aerial velocity of a satellite, which is the rate of area swept out, remains constant.

This concept is mathematically represented as:

  • dA / dt = Constant

Where dA is the area swept out in time dt.

AWES TGT Physics Mock Test - 10 - Question 19

In the presence of an applied electric field in a metallic conductor.

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 19

Conduction of electrons in a conductor.
The motion of electrons is random but in presence of external electric field, they slowly drift opposite to  and cause a current
 

AWES TGT Physics Mock Test - 10 - Question 20

Which of the following statements about magnetic field lines true?

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 20

Magnetic poles exist in pairs. It is not possible to isolate a north pole or a south pole. Magnetic field lines start from the north pole and go to the south pole and return to the north pole. They form continuous closed loops unlike electric lines of force which do not as an electric monopole, a single charge does exist.

AWES TGT Physics Mock Test - 10 - Question 21

When a fluorescent tube is used in A.C. circuit:

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 21

In a.c. circuits, a choke coil is used to control the current in place of a resistance. If a resistance is used to control the current, the electrical energy will be wasted in the form of heat. Due to its inductive reactance, a choke coil decreases the current without wasting electrical energy in the form of heat.

AWES TGT Physics Mock Test - 10 - Question 22

The number of degrees of freedom a monatomic molecule is

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 22

Explanation:Degrees of freedom of a system refers to the possible independent motions a system can have.Monoatomic gas molecule can have 3 independent motion and hence have 3 degrees of freedom (all are translational).

AWES TGT Physics Mock Test - 10 - Question 23

which of the following features of atomic structure determine whether an element is diamagnetic or paramagnetic

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 23

Spin and Orbital angular momentum arise due to the presence of unpaired electrons. If there are unpaired electrons, these momenta will be there otherwise not.

AWES TGT Physics Mock Test - 10 - Question 24

If G is the universal gravitational constant and ρ is the uniform density of spherical planet.
Then shortest possible period of the planet can be

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 24

The fastest possible rate of rotation of a planet is that for which the gravitational force on material at the equator just barely provides the centripetal force needed for the rotation. Let M be the mass of the planet R its radius and m the mass of a particle on its surface. Then

AWES TGT Physics Mock Test - 10 - Question 25

A solid sphere and a hollow sphere of the same mass have the same moments of inertia about their respective diameters, the ratio of their radii is

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 25

We know moment of inertia of solid sphere Is​=2​/5ms​Rs2​ and 
moment of inertia of hollow sphere IH​=2/3​mH​RH2 ​As per question Is​=IH​
Now,
2/5​ms​Rs2​=2/3​mH​RH2​
as the masses are equal the ratio of their radii will be 
​Rs2 /RH2 ​​=2/3​/​2/5​=√5/3​​=(5)1/2: (3)1/2

AWES TGT Physics Mock Test - 10 - Question 26

Dimensional formula of ØE is​:

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 26

Flux = E. A
⇒ F = Eq
⇒ E= F/q= N/C
⇒ Flux= N/C × m²
= Nm2C-1

AWES TGT Physics Mock Test - 10 - Question 27

The amount of work done in moving a unit positive charge through distance of 10 cm on an equipotential surface is

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 27

Definition based

AWES TGT Physics Mock Test - 10 - Question 28

In a Young’s double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in the experiment

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 28

Distance between the slits, d=0.28×10−3 m

Distance between the slits and the screen, D=1.4m

Distance between the central fringe and the fourth (n=4) fringe, 

u=1.2×10−2 m

In case of a constructive interference, we have the relation for the distance between the two fringes as:

u=nλD/d

⇒λ=ud/nD=6×10−7m=600nm

AWES TGT Physics Mock Test - 10 - Question 29

In purely inductive circuits, the current:

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 29

Explanation:

- Inductive Circuits:
In purely inductive circuits, the current lags behind the voltage by π/2 (90 degrees). This is because in an inductive circuit, the voltage leads the current due to the phase shift caused by the presence of inductance.

- Phase Relationship:
When an alternating current passes through an inductor, a back EMF is induced in the coil which opposes the flow of current. This causes the current to lag behind the voltage in an inductive circuit.

- Mathematical Representation:
Mathematically, this phase shift can be represented as a phase angle of π/2 (90 degrees) between the current and voltage in a purely inductive circuit.

- Conclusion:
Therefore, in purely inductive circuits, the current lags behind the voltage by π/2 due to the inherent characteristics of inductors to oppose changes in current flow.

AWES TGT Physics Mock Test - 10 - Question 30

You have a 200.0 ΩΩ resistor, a 0.400-H inductor, 5.0 μF a capacitor, and a variable frequency ac source with an amplitude of 3.00 V. You connect all four elements together to form a series circuit. Current amplitude at an angular frequency of 400 rad/s is

Detailed Solution for AWES TGT Physics Mock Test - 10 - Question 30

Given,
The resistance is R=200ohm the inductor is L=0.4 H, the capacitance is C=5  µF and the amplitude voltage is V=CV
The frequency depends on the inductance and the capacitance and it is given by,
f0=1/ (2π√(LC))  (1)
So, plug the values of L and C into equation 1 to get f0
f0=1/ (2π√(LC))=2/(2π√[0.4H)(5x10-6)]=113Hz
 
The inductance reactance of the coil and could be calculated by,
XL=ωL
Plug the values for L and ω to get XL
XL= ωL=2π(113Hz)(0.4)=160ohm
 To get the capacitive reactance we use the formula,
XC=1/ωC
Now, we plus the values for ω and C to get XC
XC=1/ ωC=1/2π(113Hz)(5x10-6)=500ohm
We use the inductor, the resistor and the capacitor, so the impedance of the circuit is given by the equation,
Z=√(R2+(XL-XC)2 )  (2)
Now, we use the values for XR,XL and R into equation (2) to get Z
Z= √ (R2+(XL-XC)2 )
   =√ ((200Ω)2+(160Ω-500Ω)2 )
   =394.5Ω
The impedance represents the total resistance in the circuit, so we can use the value in Ohm’s law to get the current amplitude I in the circuit,
I=V/Z
So, plus the values of V and Z to get I,
I=V/Z=3V/394.5Ω=0.0076A=7.61mA

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