OSSSC TGT Science PCM Mock Test - 3 - OTET MCQ

Playing games along with studies in school is very important for the physical growth and balance of the children. It also develops in them qualities like cooperation and spirit of teamwork to work with each other.

The concrete operational stage is defined as the stage of child development in which a child starts performing mental operations and starts thinking logically. This stage occurs in children at the age of 7 – 11 years.

All India Council of Elementary Education was established by the government of India and was responsible for looking after the development and working of elementary education. In order to accelerate the pace of expansion of elementary education and to fulfill the directive of Article 45 of the Constitution, the Government of India decided that an All-India Council of Elementary Education should be established with effect from July 1, 1957.

From Ampere circuital law

The direction of field at the given point will be vertical up determined by the screw rule or right hand rule.

Plane (a small area on the surface of a large sphere is nearly planar). The portion of the wavefront of light from a distant star intercepted by the Earth is a plane.

The balance point will not change . For balancing of wheatstone bridge four arms of resistors are responsible. Interchange the position of galvanometer and cell does not affect balancing of wheatstone bridge.
 

Changes(if required):
Solution:
We can use the formula E1/E2=L1/L2
E1=2v,E2=?,l1=30,l2=60
2/E2=30/60
E2=120/30=4v

Magnification for convex lens,

Here, f = 10cm = 10 × 10⁻² m, u = 1.5 × 10¹¹ m

∴  Diameter of the image,
d = m × 1.39 × 10⁹
= 6.67 × 10⁻¹³ × 1.39 × 10⁹
= 9.27 × 10⁻⁴m

f​₁=7.5×10⁶ Hz
f₂​=12×10⁶ Hz
λ_1​=c/f₁​=40 m
λ₂​=c/f₂​=25 m
 
So, the range is 40m to 25m

Consider refraction of light from infinity at first surface,
(μ2/v)​​−( μ1/u​)​=(μ2​−μ1/R)​​
(1.5​/ v1​)-(1.75/−∞)​=1.5−1.75​/−R
Consider refraction of this image from second surface,
​(1.75​/ v2)−(​1.5/v1)​=(1.75−1.5​)/R
Hence, v2​=3.5R
This is the image of light coming from infinity, therefore the focal length.
It is converging since focal length is positive.
 

The typical range of resistivity for metals is from 10⁻⁸Ωm to 10⁻⁶Ωm

Chlorine is called Cl₂ because it is a diatomic molecule.
Diatomic means there are two atoms of the same elements in the molecules.
There are other diatomic molecules, such as hydrogen (H2), Nitrogen (N2), Oxygen (O2), Fluorine (F2), Chlorine (Cl2), Bromine (Br2), Iodine (I2).

Paraffins are also called Alkanes and have the general formula, C_nH_2n+2 , where n is the no. of carbon atoms in a given molecule. They are open - chain saturated hydrocarbons.

The general formula of monohydric alcohols is C_nH2_n+1OH where n = 1, 2, 3… etc.. or R-OH where R is any alkyl group.
Alcohols are formed by replacement of 1 hydrogen atom from hydrocarbons.

Cooking of vegetables is a chemical change because a new substance is formed having new properties and heat is used to change the state. Cooked vegetable cannot be reversed back as raw vegetable.

These are the only 6 possible outcomes:1,2,3,4,5,6.

μ = (22 + 26 + 28 + 20 + 24 + 30)/6
= 150/6 
= 25
x(i) = (xi - μ)²
x(22) = (22-25)² = 9
x(26) = (26-25)² = 1
x(28) = (28-25)² = 9
x(20) = (20-25)² = 25
x(24) = (24-25)² = 1
x(30) = (30-25)² = 25
​
(xi - μ)²  = 70
Standard deviation : [(xi - μ)²]/N
= (70/6)^½
= 3.42

f(x) = sinx + 1/2cos2x  
⇒ f'(x) = cos x – sin2x 
Now, f'(x) = 0 gives cosx – sin2x = 0 
⇒ cos x (1 – 2 sinx) = 0 
⇒ cos x = 0, (1 – 2 sinx) = 0 
⇒ cos x = 0, sinx = 1/2 
⇒ x = π/6 , π/2 
Now, f(0) = 1/2, 
f(π/6) = 1/2 + 1/4 = 3/4, 
f(π/2) = 1 – 1/2 = 1/2 
Therefore, the absolute max value = 3/4 and absolute min = 1/2

Given equation,

The area of an equilateral triangle

Hence, Option C is correct.

Required area is :

The diagonal elements of a skew-symmetric is zero.

On rationalizing,
 Lt x-->0 (1-Cosx)/[√(1+x) +1]
= lt x-->0 2sin²(x/2)[√(1+x)+1] /x
= lt x-->0 [2sin(x/2)/x].sinx/2 [√(1+x) +1 ]
= 2.1/2 .0[1+1]=0

A = {(2),(3)}      B = {-1,2,-2}
AB = {(-2,4,-4) (-3,6,-6)}

Let required radius be R. Then according to the question,

sin (45° + θ) - cos (45° - θ)
= sin {90° - (45° - θ)} - cos (45° - θ)
= cos (45° - θ) - cos (45° - θ) = 0