Find the unit digit of (7493^{263})x(151^{29})
Answer: c)7
Solution:
The given product is (7493^{263})x(151^{29})
Required unit digit = the unit digit of(3^{263})x(1^{29}) ...(1)
In the value of 3 to the power 4, we have the unit digit as 1.
so, we can rewrite (3^{263}) = [3^{(4x65 + 3)}] = [(3^{4})^{65}] x (3^{3})
Then from eqn(1),
The unit digit of(3^{263})x(1^{29}) = The unit digit of[(3^{4})^{65}] x (3^{3}) x 1^{29}
= The unit digit of[1^{65}] x 27 x 1
= The unit digit of 1 x 7 x 1 = 7
Hence, the answer is 7.
Find the unit digit of 634^{262} + 634^{263}
Given that 634^{262} + 634^{263}
= 634^{262}(1 + 634)
= (634^{262}) x 635
The unit digit of (634^{262}) x 635 = the unit digit of (4^{262} x 5)
We know that, the unit digit of 4 to the power of any odd number is 4 and the unit digit of 4 to the power of any even number is 6.
Then the unit digit of (4^{262} x 5) = unit digit of(6 x 5) = 0
The digit in the unit place of the number represented by (7^{95} * 3^{58}) is
What is the units digit of 57^{45}?
What is the units digit of 39^{61}?
Use Code STAYHOME200 and get INR 200 additional OFF

Use Coupon Code 







