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# Problem Solving Practice Quiz - 1

## 10 Questions MCQ Test Quantitative Aptitude for Banking Preparation | Problem Solving Practice Quiz - 1

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This mock test of Problem Solving Practice Quiz - 1 for UPSC helps you for every UPSC entrance exam. This contains 10 Multiple Choice Questions for UPSC Problem Solving Practice Quiz - 1 (mcq) to study with solutions a complete question bank. The solved questions answers in this Problem Solving Practice Quiz - 1 quiz give you a good mix of easy questions and tough questions. UPSC students definitely take this Problem Solving Practice Quiz - 1 exercise for a better result in the exam. You can find other Problem Solving Practice Quiz - 1 extra questions, long questions & short questions for UPSC on EduRev as well by searching above.
QUESTION: 1

### Of the following, which is greater than 1 / 2?

Solution:

2 / 5 = 0.4
4 / 7 = 0.571
4 / 9 = 0.444
5 / 11 = 0.45
6 / 13 = 0.46
and,
1 / 2 = 0.5
So, only 4 / 7 > 1 / 2

QUESTION: 2

### If an object travels at five feet per second, how many feet does it travel in one hour?

Solution:

If an object travels at 5 feet per second it covers 5 x 60 feet in one minute, and 5 x 60 x 60 feet in one hour. Answer = 18000 (E)

QUESTION: 3

### What is the average (arithmetic mean) of all the multiples of ten from 10 to 190 inclusive?

Solution:

Method 2:

Take the average of the outermost two numbers. This will be the same as the average of all 19 numbers, because the numbers in between are evenly spaced out, in a symmetrical pattern.

(10 + 20 + ... + 180 + 190) / 19

= 10 + 190 / 2

= 200 / 2

= 100

QUESTION: 4

A cubical block of metal weighs 6 pounds. How much will another cube of the same metal weigh if its sides are twice as long?

Solution:

If you double the sides of a cube, the ratio of the surface areas of the old and new cubes will be 1 : 4. The ratio of the volumes of the old and new cubes will be 1 : 8.
Weight is proportional to volume. So, If the first weighs 6 pounds, the second weighs 6 x 8 pounds = 48.

QUESTION: 5

In a class of 78 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course?

Solution:

You could solve this by drawing a Venn diagram. A simpler way is to realize that you can subtract the number of students taking both languages from the numbers taking French to find the number taking only French. Likewise find those taking only German. Then we have:Total = only French + only German + both + neither 78 = (41 - 9) + (22 - 9) + 9 + neither.

Not enrolled students = 24

QUESTION: 6

230 + 230 + 230 + 230 =

Solution:

4 (230) = 22 ×230 = 232

QUESTION: 7 Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip?

Solution:

Amy can travel clockwise or anticlockwise on the diagram.
Clockwise, she has no choice of route from A to B, a choice of one out of two routes from B to C, and a choice of one out of two routes from C back to A. This gives four possible routes.
Similarly, anticlockwise she has four different routes.
Total routes = 8

QUESTION: 8 In the figure above AD = 4, AB = 3 and CD = 9. What is the area of triangle AEC ?

Solution:

If we take AE as the base of triangle AEC, then the height is CD.
The height of the triangle is therefore, 9 (given).
To find the base we need to see that triangles AEB and CDE are similar. The ratio AB: CD, is therefore equal to the ratio AE: ED. The given information shows that the ratio is 3:9, or 1:3. Now dividing AD (4) in this ratio gives us AE as 1.
The area of AEC = ½ base x height
=1/2 x 9 = 4.5

QUESTION: 9 Which of the following could be a value of x, in the diagram above?

Solution:

The marked angle, ABC must be more than 90 degrees because it is the external angle of triangle BDC, and must be equal to the sum of angles BDC (90) and DCB.
Also ABC is not a straight line and must be less than 180.
Therefore 90 < 5x < 180
The only value of x which satisfies this relation is 20.

QUESTION: 10

Helpers are needed to prepare for the fete. Each helper can make either 2 large cakes per hour, or 35 small cakes per hour. The kitchen is available for 3 hours and 20 large cakes and 700 small cakes are needed. How many helpers are required?

Solution:

20 large cakes will require the equivalent of 10 helpers working for one hour. 700 small cakes will require the equivalent of 20 helpers working for one hour. This means if only one hour were available we would need 30 helpers. But since three hours are available we can use 10 helpers.