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This cycle is repeated.
∴ Last day of a century cannot be Tuesday or Thursday or Saturday.
Remember the leap year rule:
Hence, 800,1200 and 2000 are leap years.
If 10th May, 1997 was a Monday, what was the day on Oct 10, 2001?
In this question, the reference point is May 10, 1997 and we need to find the number of odd days from May 10, 1997 up to Oct 10, 2001.
► Now, from May 11, 1997  May 10, 1998 = 1 odd day
► May 11, 1998  May 10, 1999 = 1 odd day
► May 11, 1999  May 10, 2000 = 2 odd days (2000 was leap year)
► May 11, 2000  May 10, 2001 = 1 odd day
► Thus, the total number of odd days up to May 10, 2001 = 5.
► The remaining 21 days of May will give 0 odd days.
► In June, we have 2 odd days; in July, 3 odd days; in August, 3 odd days; in September,2 odd days and up to 10th October, we have 3 odd days. Hence, total number of odd days = 18 i.e. 4 odd days.
Since, May 10, 1997 was a Monday, and then 4 days after Monday would be Friday. So, Oct 10, 2001 was Friday.
For every 28 years, the calendars will same,
so the years 2008,2036 have the same calendar as 1980.
India got independence on 15th August 1947. What was the day on that date?
We shall first calculate the number of odd days till 31 December 1946:
Now, we shall calculate the number of odd days in 1947 till 15 August:
Month (Days):
Days = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 227 i.e. 32 weeks and 3 odd days
So, the total number of odd days till 15 August 1947 = 0 + 1 + 1 + 3 = 5
On counting five days from Monday, we get Friday.
Therefore, 15 August 1947 was a Friday.
Second & fourth Saturdays and every Sunday is a holiday. How many working days will be there in a month of 31 days beginning on a Friday ?
Given that the month begins on a Friday and has 31 days
The day of the 5th november is equal to the day of the date in the same year?
We will show that the number of odd days between the last day of February and the last day of October is zero.
Thus, 5th March of a year will be the same day as 5th November of that year.
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