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# Test: Calendars- 2

## 10 Questions MCQ Test Quantitative Aptitude for Banking Preparation | Test: Calendars- 2

Description
This mock test of Test: Calendars- 2 for LR helps you for every LR entrance exam. This contains 10 Multiple Choice Questions for LR Test: Calendars- 2 (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Calendars- 2 quiz give you a good mix of easy questions and tough questions. LR students definitely take this Test: Calendars- 2 exercise for a better result in the exam. You can find other Test: Calendars- 2 extra questions, long questions & short questions for LR on EduRev as well by searching above.
QUESTION: 1

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QUESTION: 2

Solution:
QUESTION: 3

### How many days are there in x weeks x days

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QUESTION: 4

15th July 1776,the day of the week was?

Solution:

16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776)

Counting of odd days :
1600 years have 0 odd day.
100 years have 5 odd days.

75 years = (18 leap years + 57 ordinary years) =  [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days
1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day.
Jan   Feb   Mar   Apr   May   Jun   Jul
31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 2 days)
Total number of odd days = (0 + 2) = 2.
Required day was 'Tuesday'.

QUESTION: 5

What will be the day of the week 15th August 2010?

Solution:
QUESTION: 6

It was Sunday on Jan 1, 2006. What was the day of the Week Jan 1, 2010

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QUESTION: 7

The last day of a Century cannot be

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QUESTION: 8

On 8th Feb,2005 it was Tuesday.What was the day of the Week on 8th Feb,2004?

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QUESTION: 9

Today is Monday. After 61 days, it will be:

Solution:

Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday. After 61 days, it will be Saturday.

QUESTION: 10

What was the day of the week on 28th May 2006?

Solution: