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How many twodigit numbers satisfy this property : The last digit (units digit) of the square of the twodigit number is 8 ?
A number ending in 8 can never be a perfect square.
1^{2} = 1
2^{2} = 4
3^{2} = 9
4^{2} = 16
5^{2} = 25
6^{2} = 36
7^{2} = 49
8^{2} = 64
9^{2} = 81
A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 59.29, the number of the member is the group is:
Money collected = (59.29 x 100) paise = 5929 paise.
∴ Number of members = √5929 = 77.
=
= 1.3225  3.78071 + 13.225
= 10.76679 ≈ 10.77
What is smallest number with which 5400 may be multiplied so that the product is perfect cube?
Find prime factors of 5400
5400=2×3×3×3×2×2×5×5
If we group them in the group of 3
5400=(2×2×2)×(3×3×3)×5×5
Here to make group of 3 for 5
We have to multiply 5400 by 5.
As we know that (a²b²) = (a+b) (ab)
Therefore 14²  2²x13 = 144.
So √144 = 12.
= [√248+√64]
= √248+8
= √256
= 16
√1 9/16
= √25/16
= 5/4
= 1 1/4.
√41√21+√19√9
= √41√21+√193
=√41√21+√16
=√41√21+4
=√41√25
=√415
=√36
=6
Cube root of (512)/125
= 8/5
Convert it into mixed fraction, we get
= 1 3/5
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