UPSSSC JE Civil Mock Test - 5 - Civil Engineering (CE) MCQ

Concept:

Retarding admixtures

• It slows down the rate of hydration of cement in its initial stage and increases the initial setting time of concrete.
• These are also called retarders and are used especially in high-temperature zones where concrete will set quickly.
• The quick setting in some situations may lead to discontinuities in structure, poor bond between the surfaces, creates unnecessary voids in concrete etc.

Air entraining admixtures

• These are one of the most important inventions in concrete technology.
• Their primary function is to increase the durability of concrete under freezing and thawing conditions.
• When added to the concrete mix, these admixtures will form millions of non-coalescing air bubbles throughout the mix and improve the properties of concrete.
• Air entrainment in concrete will also improve the workability of concrete, prevent segregation and bleeding, lower the unit weight and modulus of elasticity of concrete improve the chemical resistance of concrete and reduction of cement or sand or water content in concrete, etc.

Damp proofing admixtures-

• Damp-proofing or waterproofing admixtures are used to make the concrete structure impermeable against water and to prevent dampness on the concrete surface.
• In addition to the waterproof property, they also acts like accelerators in early stage of concrete hardening.
• Damp proofing admixtures are available in liquid form, powder form, paste form, etc.

​Pozzolanic admixtures

• These are used to prepare dense concrete mix which is bets suitable for water retaining structures like dams, reservoirs, etc.
• They also reduce the heat of hydration and thermal shrinkage.
• Best pozzolanic materials in optimum quantity give best results and prevents or reduce many risks such as alkali-aggregate reaction, leaching, sulfate attack etc.

Calculation:

R-log removal =

Where, N_t = percentage of removal after time T= 99

N_o = Original percentage = 100 %

=

= - Log (1 - 0.99)

= - Log (0.01)

R-Log removal = 2

Important Points As per Watson and Chicks law

Where,

K = Rate constant which depends on the type of microorganism, the type of disinfectant, and the temperature

n = Constant for a particular microorganism and type of disinfectant

C = Disinfectant concentration (weight/volume)

Nt = Number of microorganisms present at any time ‘t’

Classification of Mortar based on the nature of the application
Based on the nature of the application, mortar may be classified as follows:

1. Masonry mortar
2. Finishing mortar

Masonry mortar

• These mortars are used for the construction of masonry. Masonry mortars may be either lime mortar, cement mortar, and lime-cement mortar. Composite mortars (i.e. lime cement mortars) are preferred since they possess both plasticity as well as strength.

Finishing mortar

• Finishing mortars are those which are used for finishing works such as plastering, pointing, ornamental finishing, etc. Such a mortar should have strength, mobility, water retentivity, and resistance to atmospheric actions such as temperature, humidity, rain, wind, dust storm, etc.

Concept:
(δl)1 + (δl)2 + (δl)3 = 0

Calculation:
Draw the free body diagram of all the blocks

∵ R_A + R_B = 40.8 ............. (1)
(δl)1 + (δl)2 + (δl)3 = 0

100 RA + 200 RA – 2720 – 300 RB = 0
300 RA – 300 RB = 2720
RA - RB = 9.067 ----(2)
Solving equation (1) and (2),
∴ RA = 24.93 kN and RB = 15.86 kN

Similar triangle ABD and FDE
AB/AD = DF/FE
DF = AC and FC = CE - AD
AB/AD = AC/(CE-AD)
AB = AC × AD/ (CE-AD) = 40 × 40 /(75-40) = 45.71

Explanation:
Polar modulus is defined as the ratio of the polar moment of inertia to the radius of the shaft. It is also called as torsional section modulus. It is denoted by Zp.
Polar section modulus of a solid shaft is given by,

For Hollow solid shaft

Concept:

As per Terzaghi's theory, ultimate bearing capacity of strip footing is given by the equation

q_u = cN_c + γD_fN_q + 0.5BγN_γ

Modified equation of ultimate bearing capacity becomes for rectangular or raft footing:

Net ultimate bearing is given by, q_nu = q_u - γD_f

Calculation:

Given soil is cohesive, so for cohesive soil, ϕ = 0°

For ϕ = 0°, N_c = 5.7, N_q = 1 and N_γ = 0

B = 6 m, L = 9 m, Df = 3 m and c = 120 kN/m²

Ultimate bearing capacity is given by,

Net ultimate bearing capacity is given by

qnu = qu - γD_f

= 820.8 kN/m²

Concept:
The friction force is given by:
f = μN
where μ is the coefficient of friction between the surfaces in contact, N is the normal force perpendicular to friction force.
Calculation:
Given:
μ = 0.1, m = 1 kg, F = 0.8 N
Now, we know that
From the FBD as shown below

Normal reaction, N = mg = 1 × 9.81 = 9.81 N
Limiting friction force between the block and the surface, f = μN = 0.1 × 9.81 = 0.98 N
But the applied force is 0.8 N which is less than the limiting friction force.
∴ The friction force for the given case is 0.8 N.

Explanation:

Concrete Sleeper:

(i) Concrete sleeper is a kind of railway sleeper made of steel-reinforced concrete. With the characteristic of water-resistant, sun-resistant, and corrosion-resistant.

(ii) Concrete sleeper has been widely used all over the world since 1950.

Advantages of Concrete Sleepers:

• It is more durable having greater life (up to 50 years)
• It is economical as compared to wood and steel.
• Concrete sleepers can generally be mass-produced using local resources.
• Easy to manufacture.
• It is not susceptible to vermin attack
• It is not susceptible to fire
• Good for track circuited areas

Disadvantages of Concrete Sleepers

• It is brittle and cracks without warning.
• It cannot be repaired and required replacement.
• Fittings required are greater in number.
• No scrap value​

Other Related Points

Advantages of Wooden Sleepers:

• They are cheap and easy to manufacture
• They are easy to handle without damage
• They are more suitable for all types of ballast
• They absorb shocks and vibrations better than other types of sleepers.
• Ideal for track circuited sections
• Fittings are few and simple in design
• Good resilience
• Ease of handling
• Adaptability to non-standard situation
• Electrical insulation

Disadvantages of Wooden Sleepers:

• They are easily liable to attack by vermin and weather
• They are susceptible to fire
• It is difficult to maintain gauge in the case of wooden sleepers
• The scrap value is negligible
• Their useful life is short about 12 to 15 years.

Advantages of Steel Sleepers:

• It is more durable. Its life is about 35 years
• Lesser damage during handling and transport
• It is not susceptible to vermin attack
• It is not susceptible to fire
• Its scrap value is very good

Disadvantages of Steel Sleepers:

• It is liable to corrosion.
• Not suitable for track circuiting
• It can be used only for rails for which it is manufactured
• Cracks at rail seats develop during the service.
• Fittings required are greater in number

Advantages of Cast Iron Sleepers:

• Service life is very long
• Less liable to corrosion
• Form good track for light traffic up to 110 kmph as they form rigid track subjected to vibrations under moving loads without any damping
• Scrap value is high

Disadvantages of Cast Iron Sleepers:

• Gauge maintenance is difficult as tie bars get bent up
• Not suitable for circuited track
• Need a large number of fittings
• Suitable only for stone ballast
• Heavy traffic and high speeds (>110kmph) will cause loosening of keys and development of high creep

Permeability is defined as the property of a porous material which permits the passage or seepage of water through its interconnecting voids.

Usually, the finer the soil texture, the slower the permeability.

The decreasing order of permeability is:

Gravel > Coarse sand > Sand mixture > Clay

Concept:

Buoyancy:

• When a body is either wholly or partially immersed in a fluid, a lift is generated due to the net vertical component of hydrostatic pressure forces experienced by the body.
• This lift is called the buoyant force and the phenomenon is called buoyancy.

Archimedes principle:

• The Archimedes principle states that the buoyant force on a submerged body is equal to the weight of the liquid displaced by the body and acts vertically upward through the centroid of the displaced volume.
• Thus, the net weight of the submerged body, (the net vertical downward force experienced by it) is reduced from its actual weight by an amount that equals the buoyant force.

F_B = ρghA = ρgV

Loss in weight is due to the upward buoyancy force.

Buoyancy force = ρgV

where ρ is the density of the liquid, V is displaced volume.

Since ρ, g is constant for the same weight loss, the object must have an identical volume.

Concept-

Shear strength of soil is given by τ’ = C’ + σ’ tan φ

Where τ’ = Effective shear strength, C’ = Effective cohesion, σ’ = Effective stress, φ = Angle of internal friction

Here C’ and φ are the shear strength parameter of the soil.

Triaxial shear strength test on soil measures the mechanical properties of the soil.

In this test, soil sample is subjected to stress, such that the stress resulted in one direction will be different in perpendicular direction.

The material properties of the soil like shear resistance, cohesion and angle of internal friction are determined from this test. The test is most widely used and is suitable for all types of soils.

Vane shear test –

It is used to determine the undrained shear strength of soils especially soft clays.

This test can be done in laboratory or in the field directly on the ground. Vane shear test gives accurate results for soils of low shear strength (less than 0.3 kg/cm²).

Compaction test-

Compaction test of soil is carried out using Proctor’s test to understand compaction characteristics of different soils with change in moisture content.

Compaction of soil is the optimal moisture content at which a given soil type becomes most dense and achieve its maximum dry density by removal of air voids.

Concept:

From the figure
Tanθ = Ground slope = difference b/w lenght of staff and (HI)/Horizontal distance
Tanθ = 1/10 = 4 - 1.5/x
Calculations:
Given,
Height of instrument (HI) = 1.5 m
Length of staff = 4 m
Ground slope (down slope) = 1/10
Tanθ = 2.5/x = 1/10
x = 25 m.

Explain
A counterfort retaining wall is a cantilever wall with counterforts, or buttresses, attached to the inside face of the wall to further resist lateral thrust. The use of this counter fort is to reduce the shear force, and the bending moment in the vertical steam of the slab.

Design of counterfort retaining wall:
In a counterfort retaining wall, the vertical slab is designed as a continuous slab and the heel slab is designed as a continuous slab because this will reduce joint efficiency hence an extra margin is created. But this will increase the cost also.
Concept:
A counterfort retaining wall is a cantilever wall with counterforts, or buttresses, attached to the inside face of the wall to further resist lateral thrust.

• In the counterfort retaining wall, the stem and the base and the base slab are tied together by counterforts, at suitable intervals
• Because of the provision of counterforts, the vertical stem, as well as the heel slab, acts as a continuous slab, in contrast to the cantilevers of cantilever retaining wall
• Counterforts are firmly attached to the face slab as well as the base slab; The earth pressure acting on the face slab is transferred to the counter forts which deflect as vertical cantilevers
• The back of the rear counter forts comes in tension and their front face is under compression
• Hence the inclined (back) face of rear counter forts should be provided with main reinforcement and in front counterforts, the tension develops at the bottom face so it is provided with main reinforcement
• Counterfort retaining walls are economical for height over about 6m

∴ In a counterfort retaining wall, the main reinforcement is provided on the bottom face in front counterfort and inclined face in back counterfort.

Explanation:

Sight distance available from a point is the actual distance along the road surface, over which a driver from a specified height above the carriageway has visibility of stationary or moving objects. Three sight distance situations are considered for design:

• Stopping sight distance (SSD) or the absolute minimum sight distance
• Intermediate sight distance (ISD) is defined as twice SSD
• Overtaking sight distance (OSD) for safe overtaking operation
• Headlight sight distance is the distance visible to a driver during night driving under the illumination of headlights
• Safe sight distance to enter into an intersection

Bacteria: These are the microscopic unicellular plants or organisms. For the study of sanitary engineering, they are divided into three groups are as follows:

Aerobic bacteria: The aerobic bacteria require light and free oxygen for their existence and development.

Anaerobic bacteria: The anaerobic bacteria do not require light and free oxygen for their existence and development.

Explanation:

ϵv = ϵx + ϵy + ϵz
ε_x = (1/E) [σ_x - ν (σ_y + σ_z)]
ε_y = (1/E) [σ_y - ν (σ_x + σ_z)]
ε_z = (1/E) [σ_z - ν (σ_x + σ_y)]
Total strain or volumetric strain is given by:
ε_v = (1/E) [σ_x + σ_y + σ_z] (1 - 2ν)
There will be no change in volume if volumetric strain is zero.
ϵ_v = 0 ⇒ ν = 0.5

Concept:
Slope, temperature, and tension corrections are required in chain surveying, not in Tacheometric surveying.
In Method of Tacheometry

In this figure, the Line of sight is horizontal and staff is held truly vertical.
Tacheometric distance formula
D = (f/i)s + (f + d)
D = KS + C
Where,
K is (f/i) → called as multiplying constant
C is (f + d) → called as additive constantImportant PointsFor Annallatic Len
K = 100
C = 0

IRC(Indian Roads Congress) has classified the roads in the India in the following five categories:
(a) National Highways
(b) State Highways
(c) Major District Roads
(d) Other District Roads
(e) Village Roads

National Highways(NH):

• National highways are the major arterial roads spanning in the length and breadth of the country and connects the Capital to the various state capitals of the country or with the neighboring countries.

State Highways(SH):

• State highways are the roads which connect the state capital to other states and to the district headquarters in the state. They have design specifications similar to those of the National Highways because they carry enough traffic.

Major District Roads(MDR):

• These roads connect the district headquarters to the main town centers in the district, and to the headquarters of the other districts also. They also connect these major town centers to the other state highways of importance. They have lower design specifications as compared to the NH and SH.

Other district roads(ODR) :

• These roads connect the rural areas town centers to the major district roads of higher importance.They provide the facilities for the transportation of the raw materials or the goods mainly of agricultural products from the rural towns to the higher markets and vice-versa.

Village Roads(VR):

• These roads connect the rural villages with one another and to the nearest higher level road or to the nearest town center. They have lower design specifications and many of them are not even metaled.

Explanation:
Centrifugal or radial pumps are simple and versatile constructions with a wide range of impeller design. The motion of water in it is from the centre towards the periphery. The motion is caused by the centrifugal force created in the pump as a result of the revolving motion of the working wheel.

Water enters at the centre of the impeller. The water passes between the vanes and is pushed radically towards the casing and then onwards through the discharge nozzle. The vanes create an increase in both water velocity and pressure.
The housing that encloses the rotating element and seals the pressurized liquid inside commonly called as Casing. The casing is of spiral shape and it terminates in a delivery pipe.

The correct answer is B. Styles

Styles in word processing software, such as Microsoft Word, are essential for formatting text uniformly. They enable the creation of a table of contents by utilizing the document's heading styles. When headings are applied consistently, the software automatically generates the table of contents based on these styles, indicating the hierarchy of sections and subsections.

Details on Other Options:

• A: Hyperlinks are incorrect as they serve to connect different parts of the document or external websites, but do not contribute to the automatic generation of a table of contents.
• C: Spelling and grammar check is not relevant here, as it focuses on identifying and correcting language errors, rather than organizing document structure.
• D: Mail merge is unrelated to table of contents creation; it is a feature used for generating personalized documents like letters or emails.

Conclusion:

Option: B, as the most relevant option, is pivotal for organizing document content and facilitating navigation through headings. Thus, Styles is the correct choice.

The correct answer is i - correct, ii - incorrect

i. The keyboard shortcut to paste copied text in MS-Word365 is Ctrl + V.

• Explanation: In MS-Word365 and most other applications, the keyboard shortcut Ctrl + V is universally used to paste copied text.
• Verdict: Correct.

ii. The keyboard shortcut to undo an action in MS-Word365 is Ctrl + Y.

• Explanation: The keyboard shortcut Ctrl + Y is actually used to redo an action in MS-Word365. The correct shortcut to undo an action is Ctrl + Z.
• Verdict: Incorrect.

The correct answer is D. Ms. Shilpi Agarwal

Ms. Shilpi Agarwal secured the top position in the International Digital Teachers' Olympiad 2024, an event designed to showcase and improve digital teaching skills among educators worldwide. This prestigious competition is organized by upEducators and involved a significant number of participants, highlighting the importance of digital pedagogy in education.

Details on Other Options:

• A: This option is incorrect as Mr. Vijaya Kumar M did not achieve the top rank in the Olympiad, which was won by Ms. Shilpi Agarwal.
• B: This option is not correct because Ms. Neethu William did not secure the first position; the honor went to Ms. Shilpi Agarwal.
• C: This option is incorrect since Ms. Sonali Kumar did not rank first in the competition, which was topped by Ms. Shilpi Agarwal.

Conclusion:

Option: D, as the most accurate and relevant option, stands out due to Ms. Shilpi Agarwal's exceptional achievement in the Olympiad, clearly differentiating her from the other candidates. Thus, Ms. Shilpi Agarwal is the correct choice.

The correct answer is Uttar Pradesh.

Explanation

• Chikankari is a traditional embroidery style from Lucknow, Uttar Pradesh.
• It is renowned for its intricate and delicate handwork that involves sewing with a white cotton thread on fine white cotton fabric.
• Chikankari embroidery was introduced by the Mughals and has been passed down through generations.
• The art form has been recognized with a Geographical Indication (GI) tag, highlighting its uniqueness and cultural heritage.

The correct answer is Central.

Explanation

• The Nawabs of Farrukhabad ruled the Central Doab regions.
• After the death of Aurangzeb, five independent kingdoms were established in Uttar Pradesh.
• Pathan Sarda Najib Khan ruled Northern Regions of Uttar Pradesh: Bareily and Meerut.
• Rahmat Khan ruled Rohillakhand (Rohil Pradesh of Meerut and Doab).
• The Nawabs of Awadh ruled the regions of Faizabad and Lucknow.
• The Marathas ruled the Bundelkhand region.

The correct answer is 1991-1992.

Explanation

• Kalyan Singh served two terms as the Chief Minister of Uttar Pradesh, first from June 1991 to December 1992 and then from September 1997 to November 1999.
• His leadership period is notably remembered for the implementation of the party's core ideologies and development initiatives, despite being marked by controversies.
• Kalyan Singh is most prominently remembered for his role during the Ayodhya movement.
• Apart from his political career in Uttar Pradesh, Kalyan Singh also served as the Governor of Rajasthan from 2014 to 2019 and briefly served as the Governor of Himachal Pradesh in 2019.

The correct answer is B. Prayagraj

The Prayagraj Municipal Corporation (PMC) has taken action by issuing notices to nine departments, including the Prayagraj Development Authority (PDA), Public Works Department (PWD), North Central Railway (NCR), and Jal Nigam, due to their impact on air quality in Smart City Prayagraj. This initiative aims to address the rising air pollution linked to ongoing construction activities in the city.

Details on Other Options:

• A: This option is incorrect as Agra has not been reported to have issued notices regarding air quality by its municipal corporation.
• C: Lucknow is not the correct answer because there are no recent reports of similar notices being issued by its municipal corporation concerning air quality issues.
• D: Ghaziabad is also incorrect as it has not been highlighted in the context of notices related to air quality affecting departments.

Conclusion:

Option: B, stands out as the most accurate and relevant choice due to the direct actions taken by the Prayagraj Municipal Corporation in response to air quality concerns, clearly differentiating it from the other options. Thus, Prayagraj is the correct choice.

The correct answer is A. Sanjivani Jadhav

Sanjivani Jadhav won the women's 10,000m event at the 2024 Portland Track Festival, finishing with a time of 32:22.77. This victory highlights her impressive performance, showcasing her strength in long-distance running among a competitive field.

Details on Other Options:

• B: Dutee Chand is primarily known for her sprinting events, and her participation in the 10,000m event is not documented, making this option incorrect.
• C: Hima Das specializes in shorter distances, particularly the 400m, and did not compete in the 10,000m race, thus this option is not applicable.
• D: Parul Chaudhary finished third in the women's 3000m steeplechase at the festival, but she did not win the 10,000m event, which makes this option incorrect.

Conclusion:

Option: A, as the most accurate and relevant option, stands out for its representation of the actual winner of the women's 10,000m event, clearly differentiating it from the other options. Thus, Sanjivani Jadhav is the correct choice.

The correct answer is B. Panchala

Panchala was a prominent ancient kingdom in northern India, situated in the Ganges-Yamuna Doab region of the upper Gangetic plain. During the Late Vedic period, it emerged as one of the most powerful states in Ancient India, closely associated with the Kuru Kingdom. By the fifth century BCE, Panchala transformed into an oligarchic confederacy, becoming one of the sixteen Mahajanapadas of the Indian subcontinent. Eventually, it became part of the Mauryan Empire and was later incorporated into the Gupta Empire, marking its historical significance.

Details on Other Options:

• A: Hastinapur was the capital of the Kuru Empire, located in what is now Meerut district, Uttar Pradesh. While significant, it did not reach the same level of development as Panchala.
• C: Kannauj, previously known as Kanyakubja, served as the capital of the Amavasu kingdom. Although important, it was not as well developed as Panchala during the Vedic period.
• D: Kosala was an ancient kingdom in the Awadh region. It was smaller during the late Vedic era and is noted for being the birthplace of Jainism and Buddhism, but it did not match the development of Panchala.

Conclusion:

Option: B, as the most accurate and relevant choice, stands out for its historical prominence and political power during the Vedic period, clearly differentiating it from the other options. Thus, Panchala is the correct choice.