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HPCL Mechanical Engineer Mock Test - 8 - Mechanical Engineering MCQ


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30 Questions MCQ Test - HPCL Mechanical Engineer Mock Test - 8

HPCL Mechanical Engineer Mock Test - 8 for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The HPCL Mechanical Engineer Mock Test - 8 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The HPCL Mechanical Engineer Mock Test - 8 MCQs are made for Mechanical Engineering 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HPCL Mechanical Engineer Mock Test - 8 below.
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HPCL Mechanical Engineer Mock Test - 8 - Question 1

Find out the Synonym of the following word:

FORAY

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 1

The word maraud comes from a Middle French word that means "rascal or rogue."

 A marauder is someone who marauds and marauding describes people who raid and plunder. As a noun, a maraud is a quick, short foray

HPCL Mechanical Engineer Mock Test - 8 - Question 2

Direction: In the following question, the sentences have been given in Active/ Passive Voice. From the given alternatives, choose the one that best expresses the given sentence in Passive/ Active Voice.

Some people were helping the wounded woman.

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 2

Use structure “subject + auxiliary + past participle + by + object”
As per the given above sentence is given in Passive Voice.
The wounded woman was being helped by some people.
Therefore ,required answer will be option B .

HPCL Mechanical Engineer Mock Test - 8 - Question 3

Direction: In the following questions, choose the word opposite in meaning to the given word as your answer.

Hasten

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 3

The word Hasten (Verb) means : hurry; to say or do something without delay.
The word Dawdle (Verb) means : to take a long time to do something or go somewhere. 

HPCL Mechanical Engineer Mock Test - 8 - Question 4

Directions: In this question, you need to replace the underlined part of the sentence with the most suitable idiom/expression given as option.

He was not agreeing to back off, as if he was arguing just for the sake of it.

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 4

As per the meanings given below, the correct idiom will be ‘playing devil’s advocate’.
Take a rain check: postpone a plan.
Rain on someone’s parade: to spoil a moment.
Play devil’s advocate: to argue, just for the sake of it.
Play by the ear: to improvise.
Correct Sentence:
He was not agreeing to back off, as if he was playing devil’s advocate.
Hence, the correct answer is option C. 

HPCL Mechanical Engineer Mock Test - 8 - Question 5

Directions: In each of the following questions, a sentence has been given in Active (or Passive) Voice. Out of the four alternatives suggested, select the one that best expresses the same sentence in Passive/ Active Voice.

Do not disturb the patient.

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 5

The original sentence is in the active voice: "Do not disturb the patient."

The best expression of this sentence in the passive voice is: "The patient is not to be disturbed."

Therefore, the correct answer is indeed option B: "The patient is not to be disturbed."

HPCL Mechanical Engineer Mock Test - 8 - Question 6

The largest number which divides 70 and 125, leaving remainders 5 and 8 respectively, is      

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 6

Since, 5 and 8 are the remainders of 70 and 125, respectively. Thus, after subtracting these remainders from the numbers, we have the numbers 65 = (70-5),
117 = (125 – 8), which is divisible by the required number.
Now, required number = HCF of 65,117                                     [for the largest number]
For this, 117 = 65 × 1 + 52 [∵ dividend = divisior × quotient + remainder]
⇒ 65 = 52 × 1 + 13
⇒ 52 = 13 × 4 + 0
∴ HCF = 13 
Hence, 13 is the largest number which divides 70 and 125, leaving remainders 5 amnd 8.

HPCL Mechanical Engineer Mock Test - 8 - Question 7

A car travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. What is the average speed for the first 320 km of the tour?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 7

Total time taken = (160/64) + (160/80) = 9/2 hrs
∴ Average speed = 320 x (2/9) = 71.11 km/hr.

HPCL Mechanical Engineer Mock Test - 8 - Question 8

Find the volume of a cuboid whose length is 8 cm, width is 3 cm and height is 5 cm. 

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 8
Volume of cubiod =l×b×h
=8×3×5
=120cm3 .
HPCL Mechanical Engineer Mock Test - 8 - Question 9

In a big garden 40% of the trees are mango trees. The number of mango trees is 80% of the number of guava trees. The rest of the trees are Jambolan trees. If the number of Jambolan trees is 40, what is the total number of trees in the garden?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 9

Total Mango trees = 40%

Remaining trees = (100 – 40 – 50)% = 10%

Hence, Option B is correct.

HPCL Mechanical Engineer Mock Test - 8 - Question 10

Suraj can complete a work in 60 days. In how many days can he complete 80% of the work with 75% of his efficiency?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 10


Hence, Option B is correct.

HPCL Mechanical Engineer Mock Test - 8 - Question 11

Which of the following is the product of 7/8 and -4/21?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 11

To find the product of 7/8 and -4/21, follow these steps:

  • Multiply the numerators: 7 × -4 = -28.
  • Multiply the denominators: 8 × 21 = 168.
  • Combine the results: -28/168.
  • Simplify the fraction: -28/168 can be reduced to -1/6.

The final answer is -1/6.

HPCL Mechanical Engineer Mock Test - 8 - Question 12

An angle is equal to one-third of its supplement. Its measure is equal to :

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 12

Let the measured of the required angle be P degree.
Then, its supplement = 180 – P
Now use the formula,

3P + P180°
⇒ P = 45°

HPCL Mechanical Engineer Mock Test - 8 - Question 13

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

Computer : fqprxvht :: Language : ?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 13

HPCL Mechanical Engineer Mock Test - 8 - Question 14

Direction: Study the following question carefully and choose the right answer.

If ACNE can be coded as 3, 7, 29, 11 then BOIL will be coded as ….?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 14

In the given coding system, we have:

So, the code for BOIL is 5, 31, 19, 25.
Hence, option D is correct.

HPCL Mechanical Engineer Mock Test - 8 - Question 15

Direction: Study the following question carefully and choose the right answer.

If STAFF is coded as $2#55 and FOLD is coded as 5@3% then how is STOLL written in that code language?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 15



∴ STOLL → $2@33
Hence, option B is correct.

HPCL Mechanical Engineer Mock Test - 8 - Question 16

In a certain code, MONK is written as 53. How will TUTOR be written in that code?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 16

The logic follows here is :

Sum of place values of alphabets of the given word = Given number.

MONK → M + O + N + K = 13 + 15 + 14 + 11 = 53.

Similarly,

TUTOR → T + U + T + O + R = 20 + 21 + 20 + 15 + 18 = 94.

Hence, the correct answer is "94".

HPCL Mechanical Engineer Mock Test - 8 - Question 17

Some equations are based on the basis of a certain system. Using the same solve the unsolved equation.

If 10 - 3 = 12, 12 - 4 = 13, 14 - 5 = 14, what is 16 - 6 = ?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 17

The logic followed is:

Similarly,

Hence, the correct answer is "15".

HPCL Mechanical Engineer Mock Test - 8 - Question 18

What is the number of instantaneous centres of rotation for a 6-link mechanism?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 18

The number of instantaneous centres in a constrained kinematic chain is equal to the number of possible combinations of two links.

The number of instantaneous centres:

where n is the number of links.

HPCL Mechanical Engineer Mock Test - 8 - Question 19

Carburising heat treatment is used for

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 19
Case hardening produces a hard, wear-resistant surface or case over a strong, tough core. The principal forms of case hardening are carburizing, cyaniding, and nitriding. Only ferrous metals are case-hardened.

Carburization is a heat treatment process in which iron or steel absorbs carbon. In contrast, the metal is heated in the presence of a carbon-bearing material, such as charcoal or carbon monoxide. The intent is to make the metal surface harder.

HPCL Mechanical Engineer Mock Test - 8 - Question 20

In the pitot-tube the velocity of flow at a point is reduced to zero. That point is called as

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 20
The stagnation, the point is the point when a moving fluid is brought to rest. The point at which a vertical line through the heeler centre of buoyancy crosses the line through the original, vertical centre of buoyancy is the metacentre. The metacentre remains directly above the centre of buoyancy by definition.
HPCL Mechanical Engineer Mock Test - 8 - Question 21

Modulus of resilience for the below material is

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 21
Concept:

Proof resilience is defined as the maximum energy that can be absorbed within the elastic limit without creating a permanent distortion.

The modulus of resilience is defined as the maximum energy that can be absorbed per unit volume without creating a permanent distortion (i.e., The proof resilience per unit volume of a body is called the modulus of resilience). It can be calculated by integrating the stress-strain curve from zero to the elastic limit.

The area up to the Elastic limit is termed the modulus of resilience, and the total area up to fracture is termed the modulus of toughness.

Calculation:

Modulus of resilience = Area under stress-strain graph up to an elastic limit

= 1/2 × 2 × 10−3 × 350 = 0.35;MPa = 350;kPa

HPCL Mechanical Engineer Mock Test - 8 - Question 22

Thread angle of BSW thread in degree is

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 22
The principal features of the British Standard Whitworth (BSW) thread form are that the angle between the thread flanks is 55 degrees, and the thread has radii at both the roots and the crests of the thread.

P= Pitch

d= depth of thread

r= radius at crest and root

HPCL Mechanical Engineer Mock Test - 8 - Question 23

Stirling and Ericsson cycle are

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 23
Stirling cycle and Ericsson cycle are the modified forms of the Carnot cycle.

A Stirling cycle consists of two reversible isothermal and two reversible constant volume (isochoric) processes.

ηStirling = T3/T1/T3

Which is the same as Carnot’s efficiency.

Whereas an Ericsson cycle consists of two reversible isothermal and two reversible constant pressure (isobaric) processes.

ηericsson = 1−T1/T3which is the same as Carnot efficiency

HPCL Mechanical Engineer Mock Test - 8 - Question 24

Which of the following sand types is excellent for use in mortar and concrete work?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 24
Pit sand doesn’t contain any salts and has sharp, angular grains. These are the desired properties for sand to be used for mortar and concrete.

Hence, the correct option is (C).

HPCL Mechanical Engineer Mock Test - 8 - Question 25

Which iron ore is mainly used in the production of cast iron?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 25

Hematite

Hematite and magnetite are by far the most common types of ore. Pure magnetite contains 72.4 percent iron, hematite 69.9 percent, limonite 59.8 percent, and siderite 48.2 percent, but since these minerals never occur alone, the metal content of real ores is lower.

HPCL Mechanical Engineer Mock Test - 8 - Question 26

The energy loss inflow through a nozzle as compared to a venturi meter is

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 26
The flow nozzle is essentially a venturi meter with the divergent part omitted. Therefore the basic equations for the calculation of flow rate are the same as those for a venturi meter. The dissipation of energy downstream of the throat due to flow separation is greater than that for a venturi meter. But this disadvantage is often offset by the lower cost of the nozzle. Flow nozzle(top) and venturimeter(bottom) diagram is given below.

HPCL Mechanical Engineer Mock Test - 8 - Question 27

What is the ratio of displacement thickness to momentum thickness for linear velocity distribution over a flat plate?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 27

HPCL Mechanical Engineer Mock Test - 8 - Question 28

A cylindrical elastic body subjected to pure torsion about its axis develops

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 28

Pure torsion will be the case of pure shear in which principal normal stresses occur 45° to the axis.

Maximum and minimum principal stresses are equal in magnitude and opposite in direction.

1 = 90° ⇒ θ1 = 45°

HPCL Mechanical Engineer Mock Test - 8 - Question 29

Preheating before welding is done to

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 29

Correct Answer :- D

Explanation : The process of preheating involves heating the area around the weld joint or the entire part to a specified temperature before welding. This reduces the cooling rate of the weld and drives out moisture, which in turn helps prevent hydrogen buildup and the potential for cracking.

HPCL Mechanical Engineer Mock Test - 8 - Question 30

The critical pressure ratio for maximum discharge through a nozzle is given by

Detailed Solution for HPCL Mechanical Engineer Mock Test - 8 - Question 30

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