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MPPGCL JE Electronics Mock Test - 3 - Electronics and Communication Engineering (ECE) MCQ


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30 Questions MCQ Test MPPGCL JE Electronics Mock Test Series 2025 - MPPGCL JE Electronics Mock Test - 3

MPPGCL JE Electronics Mock Test - 3 for Electronics and Communication Engineering (ECE) 2024 is part of MPPGCL JE Electronics Mock Test Series 2025 preparation. The MPPGCL JE Electronics Mock Test - 3 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The MPPGCL JE Electronics Mock Test - 3 MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MPPGCL JE Electronics Mock Test - 3 below.
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MPPGCL JE Electronics Mock Test - 3 - Question 1

A series RL circuit has a resistance of 5 kΩ and inductive reactance of 5 kΩ. What is the magnitude and phase angle of the effective impedance?

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 1

Concept:

For a series RLC circuit, the net/effective impedance is given by:

XL = Inductive reactance 

XC = Capacitive reactance

The magnitude of the effective/net impedance is given by:

Also, the phase angle of the effective impedance is given by:

Calculation:

For a series RL circuit, XC = 0 Ω

Given, R = 5 kΩ and XL = 5 kΩ

The magnitude of the net/effective impedance will be:

Putting on the respective values, we get:

Z = 5√2 = 7.07 kΩ

The phase angle of the effective impedance will be:

ϕ = 45° 

MPPGCL JE Electronics Mock Test - 3 - Question 2

What is the frame rate of a TDM when the transmission rate is 32 kbps and each slot has 16 bits?

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 2

Concept:

Bitrate in the TDM system is given as:

Rb = bits per frame × frame rate

Units:

Calculation:

Given in a TDM system bitrate Rb = 32 kbps

Each slot has 16 bits i.e., each frame has 16 bits

The frame rate will be:

Frame rate = 2000 fps

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MPPGCL JE Electronics Mock Test - 3 - Question 3

The solid angle subtended by the sun as viewed from the earth is Ω = 4 × 10-5 steradian. A microwave antenna designed to be used for studying the microwave radiation from the sun has a very narrow beam whose equivalent solid angle is approximately equal to that subtended by the sun. What is the approximate directivity, D?

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 3

Calculation:

The given situation can be visualized as shown:-

The approximate directivity is given by:

MPPGCL JE Electronics Mock Test - 3 - Question 4

Which of the following statements are true -

I. Negative resists on exposure of light becomes more soluble.

II. Positive resists on exposure of light becomes more soluble.

III. Chrome glass is used as mask for pattern printing.

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 4
Key Points

A Negative Photoresist is the one which becomes less soluble in developer when exposed to light.

While the Positive Photoresist becomes more soluble when exposed to light.

Chrome glass is used as mask for Photolythography

MPPGCL JE Electronics Mock Test - 3 - Question 5

The contents to the register pair DE after the execution of the following Intel 8085 instructions, is

PUSH H; PUSH D; POP H; POP D

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 5

PUSH RP (Pre-decrement):

This instruction copies the contents of RP to stack.

For every PUSH:

  • Decrement SP and PUSH RPH
  • Decrement SP and PUSH RPL

POP RP (Pre-increment):

Used for retrieving the elements stored in the stack.

For every POP:

  • Get 1 byte from stack to RPL and increment.
  • Get 1 byte from stack to RPH and increment.

Let stack pointer (SP) = FFFF H and DE = 3025H ; HL = B315H

(a) PUSH H and

(b) PUSH D are as shown:

PUSH D: contents of DE register is copied to (FFFC and FFFB) H

PUSH H: contents of HL = B315 register, is copied to (FFFE & FFFD)H

Similarly,

c) POP J and

d) POP D are as shown:

POP H retrieves the contents to HL register

POP D: retrieves the contents to the DE register.

∴ After the execution of instructions, the contents of the DE register pair is DE = B315 H, which is

equal to HL before execution.

[H] → [D]

[L] → [E]

MPPGCL JE Electronics Mock Test - 3 - Question 6

Following constellation diagram represents:

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 6
  • PSK: It stands for phase shift keying.
  • In PSK, binary 1 is represented with the actual carrier, and 0 is represented with the 180o phase shift of carrier.
  • 1 is represented as  s(t) = Accos(2πfct)
  • 0 is represented as  s(t) = - Accos(2πfct)
  • As in PSK, one bit is transmitted in a specific time constant.
  • Similarly, in 16 PSK, log2(16) = 4 bits are transmitted in a specific time constant which is known as 16-ary PSK.

B.W. of PSK = 2Rb

Whereas for M-ary PSK,

Hence M-ary is preferred due to less bandwidth.

  • In 16 APSK, Amplitude and Phase both vary in a pattern as shown in the figure.
  • 16 QAM is a signal in which two carriers shifted in phase by 90 degrees are modulated and combined. As a result of their 90° phase difference, they are in quadrature.
  • Often one signal is called the In-phase or “I” signal, and the other is the quadrature or “Q” signal.

Hence the given figure is 16 QAM.

So the solution is option (2).

MPPGCL JE Electronics Mock Test - 3 - Question 7

The range of frequency generated by VHF oscillator is -

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 7

Explanation:

Very High Frequency:

It has a range of  30 MHz to 300 MHz and are used in television broadcast.

Some ultra high frequencies are also used in television broadcasting.

Additional Information

The frequency spectrum for the complete range is:


Hence option (3) is the correct answer.

MPPGCL JE Electronics Mock Test - 3 - Question 8

In a radar system, the term 'Rate-Race' is used in connection with 

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 8
  • The hybrid ring is used primarily in high-power radar and communications systems where it acts as a duplexer - allowing the same antenna to be used for transmitting and receiving functions.
  • The hybrid ring is also called as rat-race circuits.
  • It consists of an annular line of proper electrical length to sustain standing waves, to which four arms are connected at proper intervals by means of series or parallel junctions.

          

  • A duplexer is an electronic device that allows bi-directional (duplex) communication over a single path.
  • In radar and radio communications systems, it isolates the receiver from the transmitter while permitting them to share a common antenna.
  • Most radio repeater systems include a duplexer.
MPPGCL JE Electronics Mock Test - 3 - Question 9

A LTI system is described by the difference equation 3y[n] = 2y [n - 2] – 2x[n] + x[n - 1]

The system is

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 9

Since output of system for any value of n is only depends on values of input at n or previous values the system, it is causal system

3y[n] = 2y [n - 2] – 2x[n] + x [n - 1]

Taking z – transform

3y[z] = 2y (z) z - 2 – 2x[z] + x (z) z - 1

It has poles at

Since poles lie in unit circle |zp| < 1 the system is stable

MPPGCL JE Electronics Mock Test - 3 - Question 10

Which one of the following logic family comprises of BJTs?

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 10

Logic families are the logic circuits having identical electrical parameters.

  • It is a group of compatible ICs with the same logic levels and supply voltages for performing various logic functions.
  • They are fabricated using a specific circuit configuration which is referred to as a Logic family.
  • The logic family is designed by considering the basic electronic components such as resistors, diodes, transistors, and MOSFET; or combinations of any of these components.

Different logic families of digital ICs that have been introduced commercially are listed in the table.

TTL:

Important Point

The differences between different logic families are as follows:

MPPGCL JE Electronics Mock Test - 3 - Question 11

The condition for the low-loss transmission line is

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 11

Concept:

Propagation constant for the transmission line is given by:

For lossless line α = 0

If R ≪ ωL and a ≪ ωC, the propagation constant becomes:

   ---(1)

Comparing equation (1) with α + jβ:

α = 0. Hence the line is lossless.

Important points:

A transmission line is also lossless when:

R = 0 and G = 0.

Here also α = 0 and the line is lossless

∴ The conditions for lossless line includes:

1) R = 0; G = 0, or

2) ωL ≫ R & ωC ≫ G

MPPGCL JE Electronics Mock Test - 3 - Question 12

Overdamping will make instruments:

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 12

Concept:

Classification of instruments on the basis of damping:

1.) Overdamping:

  • The value of the damping ratio is greater than 1.
  • In case of overdamping, the instrument will become slow and lethargic and rise very slowly from its zero position to a steady state position.

​2.) Undamped:

  • The value of the damping ratio is equal to 0.
  • In this case, the instrument never settles down and always oscillates about its mean position.

3.) Under-damped:

  • The value of the damping ratio lies between 0 to 1.
  • In this case, the system initially oscillates about its mean position but settles down to a steady state.

4.) Critical-damping:

  • The value of the damping ratio is equal to 1.
  • This damping returns the system to equilibrium as fast as possible without any oscillations.

MPPGCL JE Electronics Mock Test - 3 - Question 13
The ALU uses ______ to store intermediate result.
Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 13

Concept:

ALU (Arithmetic logic unit) is a circuit to perform arithmetic and logic operations.

Explanation:

  • ALU uses accumulator (a register) for storing intermediate results of arithmetic and logic operations.
  • Control unit provides the data to the ALU and directs the ALU to perform specific operations.
  • ALU stores the result in accumulator which is a type of register. Accumulator is a kind of temporary storage device which stores the intermediate results and if some previous results are already stored on the accumulator then it automatically overwrites the new results and previous results are removed.
MPPGCL JE Electronics Mock Test - 3 - Question 14

The phenomenon of pulse spreading in optical fibre is known as:

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 14

Scattering:

  • Scattering is the loss of signal caused by the diffusion of a light beam, where the diffusion itself is caused by microscopic variations in the transmission medium
  • Scattering typically happens when a light signal hits an impurity in the fibre

Dispersion:

  • Dispersion is defined as pulse spreading in an optical fibre
  • As a pulse of light propagates through a fibre, elements such as numerical aperture, core diameter, refractive index profile, wavelength, and laser linewidth cause the pulse to broaden

Attenuation:

  • The attenuation of an optical fibre measures the amount of light lost between input and output
  • Total attenuation is the sum of all losses
  • For a given fibre, these losses are wavelength-dependent

Inter-symbol Interference:

  • This is the effect of dispersion on optical fibre
  • Intersymbol interference occurs when the pulse spreading caused by dispersion causes the output pulses of a system to overlap

 

MPPGCL JE Electronics Mock Test - 3 - Question 15
A _________stores such instructions that are required to start a computer.
Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 15

The correct answer is option 1 i.e ROM

The startup instructions are stored on ROM in a computer. It is a part of BIOS (Basic Input Output System)

MPPGCL JE Electronics Mock Test - 3 - Question 16
The stage used to eliminate the noise effects in a FM detector is called –
Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 16
  • At the transmitter the amplitude of the modulated signal is constant, noise and interfering stations produce amplitude changes on the modulated signal
  • The purpose of the limiter is to provide a constant level of the signal to the FM demodulator, thus reducing the effect of signal level changes in the output
MPPGCL JE Electronics Mock Test - 3 - Question 17
Find out even and odd part of signal x(t) = (2 + sin t)2
Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 17

Concept:

Any given signal x(t) can be written as the sum of its even part and odd part, i.e.

x(t) = xe(t) + xo(t)

xe(t) = Even part of g(t) calculated as:

xo(t) = Odd part of x(t) calculated as:

Calculation:

Given:

x(t) = (2 + sin t)2

x(t) = 4 + sin2t + 4 sin t

x(-t) = 4 + sin2t - 4 sin t

Even part of g(t) calculated as:

= 4 + sin2t

Odd part of x(t) calculated as:

= 4 sin t

MPPGCL JE Electronics Mock Test - 3 - Question 18

Directions: Study the following question carefully and choose the right answer.

In a certain code ‘TERMINAL’ is written as ‘SDQLJOBM’. How is CREDIBLE written in that code?

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 18


Hence, option A is correct.

MPPGCL JE Electronics Mock Test - 3 - Question 19

Sunny can complete a work in 15 days. If Bobby is 60% as efficient as Sunny, in how many days can Bobby complete the work?

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 19

MPPGCL JE Electronics Mock Test - 3 - Question 20

Direction: If a Paper (Transparent Sheet) is folded in a manner and a design or pattern is drawn. When unfolded this paper appears as given below in the answer figure. Choose the correct answer figure given below.

A round punched paper is given as shown in the question figure. Figure out from the four alternatives as to how it will appear when folded.
Question Figure

Answer figure

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 20

MPPGCL JE Electronics Mock Test - 3 - Question 21

The HCF of two numbers is 15 and their LCM is 300. If one of the number is 60, the other is :

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 21

Using Rule 1 :
1st number × 2nd number = L.C. M. × H.C.F,
First number × Second number = HCF × LCM

MPPGCL JE Electronics Mock Test - 3 - Question 22

Directions: Read the given information carefully and answer the questions given beside:

A certain number of people are sitting in a row watching F1 racing. All of them are facing towards the south direction. The distance between any two adjacent persons is the same. 
The number of people sitting between A and C is the same as the number of people sitting between X and C. At most 25 people are sitting in a row. X is an immediate neighbour of D, who sits on one of the ends. Two people are sitting between A and Z. The number of people sitting between D and C is the same as the number of people sitting between C and Y. C sits fourth to the right of Z. The number of people sitting to the right of A is the same as the number of people sitting to the left of Z.

Q. Who sits two places away from Y?

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 22

Following the common explanation, we get “C and Z sits two places away from Y”.
Hence, option D is correct.
Final Arrangement:

Common Explanation:
References:
1. Two people are sitting between A and Z.
2. C sits fourth to the right of Z.
3. The number of people sitting to the right of A is the same as the number of people sitting to the left of Z.
4. The number of people sitting between A and C is the same as the number of people sitting between X and C.
5. X is an immediate neighbour of D, who sits on one of the ends.
6. The number of people sitting between D and C is the same as the number of people sitting between C and Y.
7. At most 25 people are sitting in a row.
Inferences:
From reference 1, we get two possible cases.
From reference 7, case2 was eliminated.
Hence, Case 1 is the final arrangement.

MPPGCL JE Electronics Mock Test - 3 - Question 23

Which revolution in the world inspired the Indians to set up a socialist economy?

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 23

During that time Lenin introduced the idea of a socialist, cooperative economy and emphasized collectivisation .Hence, these values inspired Indians to set up a socialist economy.

MPPGCL JE Electronics Mock Test - 3 - Question 24
State animal of Haryana is:
Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 24

The correct answer is the Blackbuck.

Important Points

  • The Blackbuck is the state animal of Haryana. In India hunting of Blackbuck is ban under the Wildlife Protection Act of 1972, due to excessive hunting and habitat degradation of Blackbucks during the 20th century.
  • The Blackbuck or an Indian antelope are found in India, Nepal, and Pakistan. They have a lifespan of approximately 10 to 15 years.

Additional Information

  • Black Francolin of the pheasant family is the State bird of Haryana.
  • There are 2 National parks located in Haryana viz, Sultanpur National Park located in Gurugram and Kalesar National Park located in Yamunanagar.
  • Chinkara also known as Indian Gazelle is the state animal of Rajasthan.
MPPGCL JE Electronics Mock Test - 3 - Question 25

While working with 75% of its efficiency a pipe can fill a tank in 80 minutes. In how many minutes can the pipe fill the tank while working with 100% efficiency?

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 25


Hence, Option B is correct.

MPPGCL JE Electronics Mock Test - 3 - Question 26

Seven persons B, C, D, E, F, G and H are born on seven different months of a year starting from January, but not necessarily in the same order. Who was born in July?

Statement I: C was born just before D. Only two persons are born after H. Three persons are born between H and B. F was born two months after B.
Statement II: E was born in April. D was born after C. Two persons are born between E and B. B was not born in July. C was born one of the months after May.

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 26

Checking Statement I:

Using the above references, we get the following arrangement:


Clearly, D was born in July.

Hence data in statement I is sufficient to answer the question.

Checking Statement II:

Using the above references, we get the following arrangement:


Clearly, D was born in July.

Hence data in statement II is sufficient to answer the question.

Here, the data in either Statement I or II alone is sufficient to answer the question.

Hence, Option C is correct.

MPPGCL JE Electronics Mock Test - 3 - Question 27

Sambhu beats Kalu by 30 metres in 10 seconds. How much time was taken by Sambhu tocomplete a race 1200 meters.

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 27

Kalu’s speed = 3 m/s.
For 1200 m, Kalu would take 400 seconds and Sambhu would take 10 seconds less. Hence, 390
seconds.

MPPGCL JE Electronics Mock Test - 3 - Question 28

'Dogs' is related to 'Bark' in the same way as 'Goats' is related to:

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 28

As the cry of 'Dog' is called 'Bark' in the same way the cry of 'Goat' is called 'Bleat'.

MPPGCL JE Electronics Mock Test - 3 - Question 29

In a school 30% of the students play football and 50% of students play cricket. If 40% of the students play neither football nor cricket, what percentage of total students play both the games?

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 29

The number of students who play both the games = (30 + 50 + 40)% – 100% = 20%
Hence, Option D is correct.

MPPGCL JE Electronics Mock Test - 3 - Question 30

Directions: Each of the following consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question.

 A, B, C, D and E are sitting around a circle and facing away from the centre. Who sits second to the right of B?
Statement I: A sits to the immediate left of C. D sits second to the right of A.
Statement II: D sits immediately between E and B. B sits to the immediate left of A.

Detailed Solution for MPPGCL JE Electronics Mock Test - 3 - Question 30

From Statement 1:
A sits to the immediate left of C.
D sits second to the right of A.

From the statement, we cannot determine who sits second to the right of B.
From Statement 2:
D sits immediately between E and B.
B sits to the immediate left of A.

From the statement, C sits second to the right of B.
Hence option C is correct.

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