Punjab Police SI Paper 2 Mock Test - 6 - Punjab Police SI MCQ

The given series consists of squares of consecutive odd numbers

i.e. 1², 3², 5², 7²,.....

So, missing term = 9² = 81.

The given sequence is a combination of two series :

I. 625, 125, 25, 5 and II. 5, 25, ?

The pattern in I is ? 5, while that in II is x 5. So, missing term = 25 x 5 = 125.

Each term is divided by 2 to get the next term.
Hence missing term will be 50 / 2 = 25. 

Difference between consecutive terms are 1¹, 2², 3³, 4⁴.
Hence next term will be (289 + 5⁵) = 3414.

1st term = 5
2nd term = 5 + (4*1) = 5 + 4 = 9
3rd term = 9 + (4*2) = 9 + 8 = 17
4th term = 17 + (4*3) = 17 + 12 = 29
5th term = 29 + (4*4) = 29 + 16 = 45

Thus, the missing number is 6th term = 45 + (4*5) = 45 + 20 = 65

1st term = 95
2nd term = 95 + 20.5 = 115.5
3rd term = 115.5 + 22.5 = 138
4th term = 138 + 24.5 = 162.5
5th term = 162.5 + 26.5 = 189

Thus, the missing term is 4th term = 162.5

As it is given that C leaves the station before F leaves, but after D leaves, i.e. D > C > F.
So D C F can be the order of their departure.
E leaves the station before B leaves, who leaves before
F leaves, i.e. E > B > F.
So E B F can be the order of their departure.
A leaves the station after F and C leave the station,
i.e. C > F> A.
So A is the last person to leave as shown below.

The correct order is :

CrimePoliceJudgeJudgementPunishment31452

The correct order is :

MosquitoCatTigerElephantWhale32415

The correct order is :

RainSunRainbowChildHappy23154

Here , Shashikant was born on 29th September 1999.
∴ 15th August, 1999 was Sunday.
Days upto 29th September from 15 August
( i.e. 16 to 31 August month + 1 to 29 September month ) = 16 days + 29 days = 45 days = 6 weeks 3 old days
∴ Sunday + 3 days = Wednesday.
Hence , Shashikanth born was Wednesday.

According to the question,
Sunita is taller than Seema and Renu.
1. Sunita > Seema/Renu.
Renu is shorter than Radha and Gauri
2. Renu < Radha/Gauri.
Bina is taller than Radha.
3. Bina > Radha.
Bina shorter than Sunita.
4. Bina < Sunita.
Sunita is not the tallest and Renu is not the shortest.
5. Sunita (not tallest)
6. Renu (not Shortest)
On arranging the above data, we get
from 3 and 4,
7. Sunita > Bina > Radha
from 7 and 1,
8. Sunita > Bina > Radha > Renu/Seema.
from 8 , 5 and 6.
? Gauri > Sunita > Bina > Radha > Renu > Seema.
Bina occupies the third position from the top

According to given information as per height,
Eswer is taller than Debu.
E > D
Charu is taller than Anil but shorter than Bibek
C > A But C < B
Arrangement of heights in descending order
Bibek > Charu > Anil > Eswer > Debu
Arrangement of weights in descending order
Eswer is taller than Debu but not as fat as Debu.
1. D > E (Debu is fatter than Eswer)
Anil is fatter than Debu but not as fat as Bibek.
2. A > D But B > A
Eswer is thinner than Anil.
3. E < A
From 1 and 3
4. A or D > E
from 2 and 4,
5. B > A > D > E
Bibek > Anil > Debu > Charu > Eswer

Given that :- Today is Wednesday + 2 days = Friday
Therefore, Day after tomorrow will be Sunday.

(3 x 3) + (5 x 6) = 39

and (4 x 4) + (5 x 7) = 51

Therefore, (3 x 4) + (5 x 5) = 37.

93 - (27 + 3) = 63

79 - (38 + 4) = 37

Therefore, 67 - (16 + X) = 42

X = 9

(7 x 3) + 8 = 29

(4 x 3) + 7 = 19

(5 x ?) + 6 = 31

? = 5.

Column-wise relation:

Column 1: The missing number is 

From the information given in the question we get the following arrangement:

We can see that point J is in north-west direction with respect to K.
Hence, Option B is correct.

From hints given it is clear that he took two 90 degree turns in anticlockwise direction continuously, and then again took four 45 degree turns in clockwise direction continuously. So, the net turn is:
Anticlockwise 2(90) – clockwise 4(45) = 180 - 180 = 0 degree. Thus, after turning 0-degrees he is still facing east.

Hence option B is correct answer.

Checking → statement I:

References:

P is married to U.

V is married to R.

Q is the husband of W.

S is the daughter-in-law of W.

Inferences:

From the above references, we can conclude the following:

So, we can’t conclude the relation between X and S.

Thus, statement I alone is not sufficient to answer the question.

Checking → statement II

References:

V is the father of Q.

U is the mother-in-law of Q.

T is the sibling of X.

T is unmarried.

Inferences:

From the above reference, we can conclude the following:

So, we can’t conclude the relation between X and S.

Thus, statement II alone is not sufficient to answer the question.

Checking → statement I and II:

References:

P is married to U.

V is married to R.

Q is the husband of W.

S is the daughter-in-law of W.

V is the father of Q.

U is the mother-in-law of Q.

T is the sibling of X.

T is unmarried.

Inferences:

From the above references, we can conclude the following:

So, we can conclude that X is the husband of S.

Thus, statement I and II together is sufficient to answer the question.

Hence, option D is correct.

From Statement 1:
A’s rank is five ranks below H's rank, whose rank is 19^th from the bottom.

Here, A’s rank is 10^th from the top.
From Statement 2:
A’s rank is seven ranks above F's rank, whose rank is 11^th from the bottom.

Here, A’s rank is 6^th from the top.
Hence option C is correct.

From Statement I:

'Check is Mandatory' is written as '@wt ^yi *nr' and 'Corporate is expensive' is written as '$bl (ux *nr’.

Hence, Statement 1 alone is not sufficient to answer the question.

From Statement II:

‘Corporate Check Shipping' is written as '^yi (ux #jc' and 'Check praise expensive’ is written as '%hr ^yi $bl'.

Hence, Statement 2 alone is not sufficient to answer the question.

Checking both Statement, I and II together:

Clearly ‘is’ is repeated in statement 1 ('Check is Mandatory' is written as ‘@wt ^yi *nr’ and 'Corporate is expensive' is written as ‘$bl (ux *nr’) and statement 2 ('Check praise expensive’ is written as '%hr ^yi $bl’).

Thus, code for ‘Corporate’ is ‘(ux’.

Clearly, Statement I and Statement II together are necessary to answer the question.

Hence, option D is the correct answer.

(5 x 6 x 8) + (7 x 4 x 9) = 492

and (7 x 5 x 4) + (6 x 8 x 9) = 572

Therefore (4 x 3 x 5) + (7 x 2 x 5) = 130.

(6 + 5) - (7 + 4) = 0

and (7 + 6) - (8 + 4) = 1

Therefore (11 + 2) - (2 + 0) = 11.