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Class 9 Exam  >  Class 9 Tests  >  Subject-wise Mock Test for Class 9 2025  >  Maths Mock Test- 5 - Class 9 MCQ

Maths Mock Test- 5 - Class 9 MCQ


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30 Questions MCQ Test Subject-wise Mock Test for Class 9 2025 - Maths Mock Test- 5

Maths Mock Test- 5 for Class 9 2024 is part of Subject-wise Mock Test for Class 9 2025 preparation. The Maths Mock Test- 5 questions and answers have been prepared according to the Class 9 exam syllabus.The Maths Mock Test- 5 MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Maths Mock Test- 5 below.
Solutions of Maths Mock Test- 5 questions in English are available as part of our Subject-wise Mock Test for Class 9 2025 for Class 9 & Maths Mock Test- 5 solutions in Hindi for Subject-wise Mock Test for Class 9 2025 course. Download more important topics, notes, lectures and mock test series for Class 9 Exam by signing up for free. Attempt Maths Mock Test- 5 | 30 questions in 60 minutes | Mock test for Class 9 preparation | Free important questions MCQ to study Subject-wise Mock Test for Class 9 2025 for Class 9 Exam | Download free PDF with solutions
Maths Mock Test- 5 - Question 1
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The point A(3, 4) lies in

Detailed Solution for Maths Mock Test- 5 - Question 1

2. I Quadrant

Explanation:

The point A(3, 4) lies in the I Quadrant because:

  • In the I Quadrant, both the x-coordinate (abscissa) and the y-coordinate (ordinate) are positive.
  • Since 3 (x-coordinate) is positive and 4 (y-coordinate) is also positive, the point lies in the I Quadrant.
Maths Mock Test- 5 - Question 2
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A point both of whose co-ordinates are positive lies in

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Maths Mock Test- 5 - Question 3
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 The line drawn from the center of the circle to any point on its circumference is called:

Detailed Solution for Maths Mock Test- 5 - Question 3

Correct Option is A. Radius

Maths Mock Test- 5 - Question 4
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In the figure, O is the center of the circle. If ∠OAB = 40o, then ∠ACB is equal to :
Maths Mock Test- 5 - Question 5
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X is a point on a circle with centre O. If X is equidistant from the two radii OP, OQ, then arc PX : arc PQ is equal to
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Maths Mock Test- 5 - Question 6
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Two planes intersect each other to form a :
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Two non-parallel planes in space form a line upon intersection, as long as each plane is unique. Three non-parallel planes intersect at a point. The best and simplest example is to fold a piece of paper. Since the folded paper now represents two distinct planes, the crease itself is the intersection point, forming a line.
Maths Mock Test- 5 - Question 7
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In the adjoining figure, m ║ n, if ∠1 = 500, then ∠2 is equal to –

 
Maths Mock Test- 5 - Question 8
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Abscissa of a point is positive in
Maths Mock Test- 5 - Question 9
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The co-ordinates of the origin are
Maths Mock Test- 5 - Question 10
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The point (0, 9) lies
Maths Mock Test- 5 - Question 11
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If APB and CQD are 2 parallel lines, then the bisectors of the angles APQ, BPQ, CQP and PQD form, square only if
Detailed Solution for Maths Mock Test- 5 - Question 11
Line APB is parallel to CQD
when we join PQ it will be transversal
then angleBPQ=angleCQP    (alternate angles)
angleAPQ=anglePQD   
when we will draw bisectors 
then the figure formed will have opposite angles equal
which means that it is a parallelogram

Maths Mock Test- 5 - Question 12
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If bisectors of ∠A and ∠B of a quadrilateral ABCD intersect each other at P, of ∠B and ∠C at Q, of ∠C and ∠D at R and of ∠D and ∠A at S, then PQRS is a
Detailed Solution for Maths Mock Test- 5 - Question 12

To show: ∠PSR + ∠PQR = 180°
∠SPQ + ∠SRQ = 180°

In △DSA,

∠DAS + ∠ADS + ∠DSA = 180° (angle sum property)

+ ∠ SA = 180° (since RD and AP are bisectors of ∠D and ∠A)

∠DSA = 180°
∠PSR = 180°−

(∵ ∠DSA = ∠PSR are vertically opposite angles)

Similarly,

∠PQR = 180°− 


Adding (i) and (ii), we get, ∠PSR + ∠PQR = 180°
=360° − 1/2 ​× (∠A + ∠B + ∠C + ∠D)
 

=360°− 1/2​ × 360° = 180° ∴ ∠PSR + ∠PQR = 180°

In quadrilateral PQRS,

∠SPQ + ∠SRQ + ∠PSR + ∠PQR = 360°
=> ∠SPQ + ∠SRQ + 180° = 360°
=> ∠SPQ + ∠SRQ = 180°

Hence, showed that opposite angles of PQRS are supplementary.

Maths Mock Test- 5 - Question 13
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The Diagonals AC and BD of a Parallelogram ABCD intersect each other at the point O such that ∠DAC = 30∘ and ∠AOB = 70∘. Then, ∠DBC?
Maths Mock Test- 5 - Question 14
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In the given figure, ABCD is a Rhombus. Then, 
Maths Mock Test- 5 - Question 15
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D and E are the mid-points of the sides AB and AC. Of △ABC. If BC = 5.6cm, find DE.
Maths Mock Test- 5 - Question 16
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The simplest form of   is
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Maths Mock Test- 5 - Question 17
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(125/216) -1/3 =
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Maths Mock Test- 5 - Question 18
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8√15 ÷ 2√3
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Maths Mock Test- 5 - Question 19
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BC is a diameter of the circle and ∠BAO = 60o . Then ∠ADC is equal to
Maths Mock Test- 5 - Question 20
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What fraction of the whole circle is minor arc RP in the given figure ?
Maths Mock Test- 5 - Question 21
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AB is a chord of a circle with radius ‘r’. If P is any point on the circle such that ∠APB is a right angle , then AB is equal to
Maths Mock Test- 5 - Question 22
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In the given figure, AC is a diameter of the given circle and ∠BCD = 75o. Then, ∠EAF−∠ABC is equal to
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Maths Mock Test- 5 - Question 23
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Detailed Solution for Maths Mock Test- 5 - Question 23

ANSWER :- b

Solution :- (0.75 * 0.75 * 0.75 + 0.25 * 0.25 * 0.25)/(0.75 * 0.75 - 0.75 * 0.25 + 0.25 * 0.25)

= (0.421875 + 0.015625)/(0.5625 - 0.1875 + 0.0625)

= (0.4375)/(0.4375)

= 1

Maths Mock Test- 5 - Question 24
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If one of the factor of x2 + x – 20 is (x + 5). Find the other
Maths Mock Test- 5 - Question 25
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In quadrilateral ABCD, BM and DN are drawn perpendiculars to AC such that BM = DN. If BR = 8 cm. then BD is
Maths Mock Test- 5 - Question 26
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If the altitudes from two vertices of a triangle to the opposite sides are equal, then the triangles is
Detailed Solution for Maths Mock Test- 5 - Question 26

Given:

BE = CD

Concept Used:

When 2 sides of a triangle are equal, then it is isosceles.

When 2 angles and 1 side of 2 triangles is equal, then both the triangles are similar.

Calculations:

In △ABE and △ACD,

BE = CD (Given)

∠BEA = ∠CDA (90° each)

∠BAE = ∠CAD (Common Angle)

∠ABE = ∠ACE (By Sum angle property)

⇒ △ABE is similar to △ACD

⇒ AB = AC

∴ If the altitudes from two vertices of a triangle to the opposite sides are equal, then the triangle is isosceles.

Maths Mock Test- 5 - Question 27
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In △AOC and △XYZ, ∠A =∠X, AO = YZ, AC = XY, then by which congruence rule △AOC ≅ △XYZ
Detailed Solution for Maths Mock Test- 5 - Question 27

To determine the congruence rule for ΔAOC and ΔXYZ:


  • Given: ∠A = ∠X

  • AO = YZ (one pair of corresponding sides)

  • AC = XY (another pair of corresponding sides)

  • Two pairs of sides and the included angle are equal

    •  

Therefore, by the SAS (Side-Angle-Side) congruence rule, ΔAOC ≅ ΔXYZ.

Maths Mock Test- 5 - Question 28
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The graph of the line 5x + 3y = 4 cuts y-axis at the point :
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Maths Mock Test- 5 - Question 29
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A linear equation in two variables has maximum :
Maths Mock Test- 5 - Question 30
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The equation  =has
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