Semiconductor Diode NAT Level - 2 - Physics MCQ

The ratio of rms value to the average value is called form factor. Thus,
form factor 

The correct answer is: 1.57

and  
Now 130-60 = IR

Now, V_z = l_LR_L

I_z = 2mA
The correct answer is: 2

The correct answer is: 320

D₂ is reverse biased, hence, no current flow through it.
6 - iR_{2 -} iR₁=0

Now potential difference across R₁ 
= 2V
The correct answer is: 2

The correct answer is: 80

J = eDdn / dx
J = 1.6 * 10^-19 * 225 * (10¹⁸ - (7 * 10¹⁷)) / 0.1
= 108A/cm².

Peak inverse voltage (PIV) across each diode =when diode is conducting (during half cycle) the voltage across the diode is zero.
Hence, rms value of voltage across the diode =
The correct answer is: 339.4

The turn ratio of transform ation is 12:1. So if primary coil is connected to power mains o f 220V , then potential of secondary coil is Volts. In a half-wave rectifier,is the maximum voltage appearing across the transformer secondary coil. Now. peak inverse voltage, for half wave rectifier in given as V₀

= 25.9V
The correct answer is: 25 .9

 For maximum power dissipation, current through zener diode should be maximum which is maximum when total current in the circuit is maximum i.e. V_s = 15V.


The correct answer is: 0.5

Power of each diode = 10W
Potential = 10V 
⇒ current = 1A
⇒ Resistance of each zener diode R  
⇒ Equivalent resistance of three diodes connected in series

The correct answer is: 15