Practice Test: Mechanical Engineering (ME)- 9 - Mechanical Engineering MCQ

# Practice Test: Mechanical Engineering (ME)- 9 - Mechanical Engineering MCQ

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## 65 Questions MCQ Test GATE Mechanical (ME) 2024 Mock Test Series - Practice Test: Mechanical Engineering (ME)- 9

Practice Test: Mechanical Engineering (ME)- 9 for Mechanical Engineering 2024 is part of GATE Mechanical (ME) 2024 Mock Test Series preparation. The Practice Test: Mechanical Engineering (ME)- 9 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Practice Test: Mechanical Engineering (ME)- 9 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Practice Test: Mechanical Engineering (ME)- 9 below.
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Practice Test: Mechanical Engineering (ME)- 9 - Question 1

### Direction: Study the following pie-chart and tables carefully and answer the questions given below. Total Number of email received by the organization = 90000 Ratio of Read emails to Unread emails received by the organization What is the ratio of the number of emails read in January to those unread in the month of April in the organization?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 1

Number of read emails in the month of January = (90000*17/100*8/15)
Number of unread emails in the month of April = (90000* 8/100 * 5/12)
Ratio = 68:25

Practice Test: Mechanical Engineering (ME)- 9 - Question 2

### Direction: Two sentences with one blank in each, followed by five alternatives, are given. Choose that option as the answer which can fill both the blanks of both the sentences. I. Most of our employees get _____ abroad at some stage II. The aircraft and its crew were ______ missing.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 2

Post means to send somebody to a place for a period of time as part of their job and to announce something publicly or officially.
Hence, option D is correct.

Practice Test: Mechanical Engineering (ME)- 9 - Question 3

### In the following question, out of the given four alternatives, select the one which is opposite in the meaning of the given word. Scurrilous

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 3

The meanings of the given words are as follows:
Scurrilous— abusive
Coarse— rough or harsh in texture
Sophisticated— developed to a high degree of complexity.
Insolent— showing a rude and arrogant lack of respect
Complimentary— expressing a compliment; praising or approving
Clearly, option D is the antonym of the given word.

Practice Test: Mechanical Engineering (ME)- 9 - Question 4

Statements:
All pillows are beds.
No fruit is pillow.
Some foods are fruits.
Conclusions:
I. At least some foods are pillows.
II. Some beds are definitely fruits.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 4

Consider the following least possible Venn diagram,

Conclusions:
I. At least some foods are pillows → it’s possible but not definite, hence false.
II. Some beds are definitely fruits → it’s possible but not definite, hence false.

Practice Test: Mechanical Engineering (ME)- 9 - Question 5

Direction: Study the following information carefully and answer the questions given below:
P, Q, R, S, T, U, V and F are sitting around a circle facing the centre. U is third to the right of Q, who is third to the right of F. P is third to the left of F. R is fourth to the left of P. T is third to the right of S. S is not a neighbour of P.
Four of the following five are similar in a certain way based on their positions in the seating arrangement and so form a-group. Which of the following does not belong to that group?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 5

Option D does not belong the group.

Practice Test: Mechanical Engineering (ME)- 9 - Question 6

Following bar graphs shows time taken by different pipes to fill that particular percentage of tank which is described in tabular data. For Ex- Pipe 1 fills the 10 % of tank in 6 mins.

A Tank has three pipes; two of them are used to fil the tank while another one used to empty the tank namely: pipe 3, pipe 5 to fill the tank and a third pipe for making the tank empty. When all three pipes are open, 7/18th part of the tank is filled in 1 hours. How much time will the third pipe take to empty the completely filled tank 10 times the bigger than the previous one.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 6

part of work in one hour=
(P3+P5+Third pipE. X 1 = 7/18th part of work
⇒ 7/18th part of work = 1 hr
⇒ Total work done = 18/7 hr by all three pipes
Pipe 3 does 50% of work in 90 mins
100 % of work = 90/50 * 100 = 180 mins = 3 hr
Pipe 5 does 50% of work in 60 mins
100 % of work = 60/50 * 100 = 120 mins = 2 hr
Time Tw Efficiency
Pipe -3 = 3 hr Total work/3 = 6
Pipe-5 = 2 hr Total work/2 = 9
All three = 18/7 hr Total work/(18/7)= 7
For Total work = LCM of (3,2,18/7) = 18
Efficiency of pipe 3 + Efficiency of pipe 5 + Efficiency of third pipe = total efficiency
6+9+X= 7
X = 7-15 = -8 (Negative sign shows the negative work herE.
Efficiency X Time = Total work
8 X Time = 18 * 10 ( as tank is 10 times bigger than the previous onE.
Time = 180/8 = 22.5 hrs

Practice Test: Mechanical Engineering (ME)- 9 - Question 7

Directions: Rearrange the following six sentences (A), (B), (C), (D), (E) and (F) in the proper sequence to form a meaningful paragraph: then answer the questions given below them.

A). Indian Government remain concerned about potential spillover effects from the unconventional monetary policies of the advanced economies, which could cause disruptive volatility of exchange rates, asset prices and capital flows.
B). The challenges are related to high public debt and unemployment, poverty and inequality, lower investment and trade, negative real interest rates along with signs of prolonged low inflation in advanced economies.
C). In this context, emerging markets and developing countries (EMDCs) continue to be major drivers of global growth.
D). The global recovery continues, although growth remains fragile, with considerable divergences across countries and regions.
E). It is important to strengthen the framework of international financial cooperation, including through instruments such as swap-lines, to mitigate the negative impacts of monetary policy divergence in reserve currency issuing countries.
F). Structural reforms, domestic adjustment and promotion of innovation are important for sustainable growth and provide a strong and sustainable contribution to the world economy.
Which of the following will be the Second sentence?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 7

Refer to the last question of the series.

Practice Test: Mechanical Engineering (ME)- 9 - Question 8

In a school, 12th class consists of 30% male students of which 30% male students failed in the class. Total 82% students passed in 12th examination out of 900 students. Calculate the total number of female passed students?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 8

Short Trick:
Total students = 900
Boys : Girls = 30 % : 70% = 3 : 7
So, exactly Boys : Girls = 270 : 630
Total failed students = 18% of 900 = 162
Failed boys = 30% of 270 = 81
Failed girls = 162 - 81 = 81
Passed female students = 630 - 81 =549
Basic Method:

⇒ Let us consider total number of students be 100x
⇒ ∴ Males students = 30x , female students = 70x
⇒ According to condition given in the problem, of this 30x male students, 70 % male students pass the exam.

Practice Test: Mechanical Engineering (ME)- 9 - Question 9

Direction: In the following number series, only one number is wrong. Find out the wrong number.
17 25 34 98 121 339

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 9

The pattern followed here is,
⇒ 17 + 23 = 17 + 8 = 25
⇒ 25 + 32 = 25 + 9 = 34
⇒ 34 + 43 = 34 + 64 = 98
⇒ 98 + 52 = 98 + 25 = 123
⇒ 123 + 63 = 123 + 216 = 339

Practice Test: Mechanical Engineering (ME)- 9 - Question 10

There are 3 red balls and 5 green balls in a bag. If two balls are picked at random from the bag then find the probability of getting a red ball?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 10

Required probability
=3C1*5C1/8C2
= 3*5/28
= 15/28

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 11

In the parallel-plate configuration shown, steady-flow of an incompressible Newtonian fluid is established by moving the top plate with a constant speed, U0 = 1m/s. If the force required on the top plate to support this motion is 0.75 N per unit area (in m2 ) of the plate then the viscosity of the fluid between the plates is __________ N-s/m2

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 11

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 12

The figure shows reducing area conduit carrying water. The pressure p and velocity V are uniform across sections 1 and The density of water is 1000 kg/m3 . If the total loss of head due to friction is just equal to the loss of potential head between the inlet and the outlet, then V2 in m/s will be _____

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 12

Practice Test: Mechanical Engineering (ME)- 9 - Question 13

The stress-strain curve of an ideal elastic strain hardening material will be as

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 13

The figure d is the stress-strain curve of an ideal elastic strain hardening material

Practice Test: Mechanical Engineering (ME)- 9 - Question 14

The strain hardening exponent ‘n’ of stainless steel relates to
N →column-1)
P) Zero
Q) between zero and one
R) One
Column-2
1) Plastic deformation
2) elastic solid
3) Perfect moldable solid

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 14

For n = 0 → Perfect moldable solid

O < n< 1 → Plastic deformation

n = 1 → elastic solid

Practice Test: Mechanical Engineering (ME)- 9 - Question 15

Mohr’s circle for the state of stress defined by  MPa. is a circle with radius of

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 15

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Practice Test: Mechanical Engineering (ME)- 9 - Question 16

Water flows through a tube of diameter 25mm at an average velocity 1 m/sec. The properties of water ρ = 1000 kg/m3, μ = 6x 10-4 N-s/m2 , K= 0.625 W/mK, Pr= 4, Given Dittus – Boelter equation, Nu =0.023Re0.8 Prn and constant heat flux Nu = 3.66. What is Nusset number when fluid is cooling?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 16

Given, Pr = 4, fluid is cooling so, n= 0.3

So the flow is turbulent, we have to use Dittus- Boelter equation i.e

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 17

A machine tool company decides to make four sub-assemblies through three contractors differing in efficiency. Given below are the estimates of the time in hours) matrix. The minimum time in seconds is?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 17

Here, we have three contractors to make four sub-assemblies. The problem is unbalanced, we have to add dummy column to make it balanced.

Subtracting by the smallest element of each column.
S→ M1
S→ M3
S→ M2

The minimum time is = 7+4+18 = 29 hour = 1740 seconds

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 18

The average service rate at a Service Centre is 8 customer/hr, which varies exponentially. Customers arrive at random order with an average of 6 customer/hr. The probability of at least 3 customers in the system is____

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 18

At least 3 in system means 3 or more customers in system,

Practice Test: Mechanical Engineering (ME)- 9 - Question 19

In an Electrochemical machining process an iron( atomic weight=56 gm and valency=2) is used having cross section of 0.5x0.5 cm2. A current of 1000 A is passed through the electrolytic solution and the density of iron is given as 7.86gm/cm3. Find the feed rate of the electrode in cm/sec.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 19

Practice Test: Mechanical Engineering (ME)- 9 - Question 20

A mould has downsprue whose length is 15cm and cross-section area at the base of downsprue is 1.5 cm2. The downsprue feeds a horizontal runner leading into mould cavity of 1200 cm2. The time required to fill the mould cavity will be

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 20

Length of sprue h= 15 cm = 0.15 m

Practice Test: Mechanical Engineering (ME)- 9 - Question 21

Match the following:
a) Drop forging i-material is only upset
b) Machine forging ii-repeated hammer blows
c) Press forging iii-carried out manually
d) Upset forging iv-squeezing action
e) Smith forging v-metal gripped & pressure applied at heated end

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 21

In Drop forging repeated hammer blows, for machine forging material is only upset, in press forging squeezing action takes place.

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 22

The maximum reduction (upto 2 decimal points) in cross-sectional area per pass (R) of a cold wire drawing process is R = 1 - e -(n+1)
where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 22

Perfectly plastic material implies that strain hardening coefficient n is zero.
Hence

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 23

In spot welding of two stainless steel sheets, each of 5mm thickness, welding current 15000A is applied for 0.4sec, the heat dissipated to the base metal is 22000J . Assuming that the heat required for melting 2mm3 volume steel is 30J and contact resistance between sheets is 0.0004Ω. The volume (in mm3) of weld nugget is__________.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 23

Total heat generated = I2RT
= (15000)x 0.0004 x 0.4
=36000
Heat required to melt the nugget = 36000 -22000
=14000J
Volume of nugget = 14000/15 = 933.33 mm3

Practice Test: Mechanical Engineering (ME)- 9 - Question 24

Which of the following is false about comparator :

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 24

Comparators are more reliable as compare to other measuring method.

Practice Test: Mechanical Engineering (ME)- 9 - Question 25

Which types of stress strain relationship best describes the behaviour of brittle materials as ceramics and thermosetting plastics?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 25

Ceramics and thermosetting plastics does not undergo plastic strain since they are brittle materials. The stress strain curve reached to the elastic point and then material fails.

Practice Test: Mechanical Engineering (ME)- 9 - Question 26

Gyroscopic acceleration is due to

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 26

Gyroscopic acceleration is due to the change in the direction of angular velocity.
So, the correct option is (b).

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 27

A paddle wheel is rotated inside a sealed container containing 20kg of air. If the applied torque on paddle wheel is 80Nm and is rotated at 120rpm for 3 minutes. The temperature rise of air is ________ ℃

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 27

Using energy balance,

Practice Test: Mechanical Engineering (ME)- 9 - Question 28

According to second law of thermodynamics, the entropy change of the system for any process can be

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 28

We know that

is always a positive value and 0 for reversible process.
can be +ve or –ve depending upon heat addition and heat release respectively. So, the correct option is (d).

Practice Test: Mechanical Engineering (ME)- 9 - Question 29

The Mollier diagram of a pure substance is a

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 29

The Mollier diagram of a pure substance is a h-s diagram. So, the correct option is (a).

Practice Test: Mechanical Engineering (ME)- 9 - Question 30

Match List-1 (Refrigerant) with List-2 (Uses) and select the correct answer using the code given below the List

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 30

So, the correct option is (c).

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 31

In a Bell Coleman cycle, air enters the compressor at a pressure of 2.5 bar at a temperature of 100C. It is then compressed to a pressure of 6.25 bar and then cooled in a cooler to a temperature of 250C in the cooler before being expanded in the expansion cylinder upto a pressure of 2.5 bar. The COP will be ______ .

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 31

Bell Coleman cycle is also known as Reversed Brayton cycle

Practice Test: Mechanical Engineering (ME)- 9 - Question 32

Find the minimum number of stages required when air enters at 1 bar and 270C and delivers at 260 bar. The maximum temperature at the outlet of compressor is limited to 3270C . Take the perfect intercooling in between stages and γ = 1.3.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 32

In multistage compression, if there are N stages then pressure ratio in each stage will be equal for perfect intercooling.

From this we can write ,

Now, for perfect intercooling the inlet temperature for each compressor will be same. And as we know that pressure ratio will be same for each stage. So for perfect intercooling case we can write:

Solving , we get N = 1.85 ~ 2
So, the correct option is (a).

Practice Test: Mechanical Engineering (ME)- 9 - Question 33

The free body diagram of member AB is :-

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 33

Free body diagram of member DC, BC and AB is shown below :Therefore, correct option is (a).

Practice Test: Mechanical Engineering (ME)- 9 - Question 34

Consider the function f = |5-4x| and refer to the following options.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 34

Since the function is polynomial in both the cases, it is continuous.
Left Hand Derivative=-4
Right hand Derivative= +4
Since LHD≠RHD, the function is not differentiable at x=5/4.

Practice Test: Mechanical Engineering (ME)- 9 - Question 35

The value of integral

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 35

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 36

A small boat is floating in a small pool as shown in the figure, initially the valve is closed, find the time taken (in seconds) by water to spill out of the pool as soon as the valve is opened ?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 36

Apply continuity equation

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 37

A tank contains water up to a height of 1m and oil of specific gravity 0.9 is filled on the top of water up to 1 m height as shown in figure). Calculate the net force on the gate. (in kN)

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 37

Pressure at the top end of the gate.
= 0.9 × 9.81×1 =8.829 kPa.
Pressure at the lower end of the gate.
= 0.9 × 9.81×1 + 1 × 9.81 × 1 = 18.639 kPa.

Practice Test: Mechanical Engineering (ME)- 9 - Question 38

A lawn sprinkler has 0.6 cm diameter nozzle at the end of the rotating arm and discharges water at the rate of 10m/sec velocity. Determine the torque required to hold the rotating arm stationary

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 38

Rate of change for Angular momentum for arm ‘A’ =
Rate of change forAngular momentum for arm ‘B’ =
Net Rate of change of angular momentum = net Torque.

Practice Test: Mechanical Engineering (ME)- 9 - Question 39

Calculate the mean bucket speed(m/s) of a Pelton wheel working under a head of 52m and producing 320kW. The diameter of nozzle is 178mm and coefficient of velocity is 0.98. The jet is deflected by 165 °.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 39

Practice Test: Mechanical Engineering (ME)- 9 - Question 40

A rigid bar ABC is supported by three rods of same material and cross section, outer rods are of copper and inner rod is of steel →as shown in figure). Calculate the forces in the rod due to an applied load 400kN, If the ABC remain horizontal after the load has been applied →neglect wt. of rods)

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 40

2Pcu + Ps =400 kN …→1)
Since rods are fixed to rigid bar and bar remain horizontal after the load has been applied, so deformation in rod will be same.

⇒ from →1) and →2) Ps = 200kN Pcu = 100 kN

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 41

The circular shaft of constant cross- section carries four pulleys and belts which are vertical. Calculate and Un Known tension on the belt as shown in figure.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 41

Shaft is in equilibrium, Hence ∑T = 0
T1 + T2 +T3 + T4 = 0
T1 = →8-6) 0.1 = 0.4 kNm
T2 = →2P-3) 0.05 = →0.1P – 0.15) kNm
T3 = →2-P) 0.05 = →0.1 – 0.05P) kNm
T4 = →4-8) 0.1 = -0.4 kN-m
T2 = →2P-3) 0.05 = →0.1P – 0.15) kNm
⇒ 0.4 + 0.1P – 0.15 + 0.1 –0.05P – 0.4 =0 ⇒ P = 1 kN

Practice Test: Mechanical Engineering (ME)- 9 - Question 42

Find the vertical reaction at the point A as shown in figure.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 42

Given Beam

RA + RC = wL 1

Now from superposition we will break this beam into two i.e.

Practice Test: Mechanical Engineering (ME)- 9 - Question 43

The inlet temperature of hot water is 800K and outlet temperature is 400 K and the inlet temperature of cold water is 200 K, both are flowing at some mass flow rate. Taking counter flow heat exchanger the NTU and LMTD respectively are

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 43

Here, this is a case of balanced heat exchanger
MhCh =mcCc  = C [Both the fluids are water]

NTU = 2

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 44

Two products A & B are manufactured by two machines. Capacity of machines are limited to 18 hours and 40 hours per week. The requirement for product A & B on each machinery from the table

The profit from each unit of A & B is 30 Rs and 20 Rs per unit respectively. The optimum profit in Rs is?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 44

Z = 30A + 20B Maximize
Constraints
⇒3A + 2B ≤ 18 →1)
⇒4A + 8B ≤ 40 →2)

Zp= 30x0+ 20x0 = 0 Rs
ZQ = 30x0 + 20x5 = 100 Rs
ZR = 30x4 + 20x3 = 180 Rs
ZS = 30x6 + 20x0 = 180 Rs
Optimality occurs at R & S
Cost = 180 Rs

Practice Test: Mechanical Engineering (ME)- 9 - Question 45

Annual demand of a product A is 4000 units. Cost of order is Rupees 900 per order. Handling charge per year is 10% of the unit price. Item can be purchased in lot as shown below.

The feasible EOQ should be

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 45

Staring from the lowest cost available,

Since it is not feasible, moving to next

Again not feasible, moving to next

This lies in feasible range. Total cost at this EOQ,

It can be seen that minimum cost is obtained at Order Quantity of 1000 units hence our feasible EOQ is 1000 units.

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 46

Job A, B, C, D are done on two machines. The percentage utilization of machine 2 is?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 46

Optimum Sequence: - A-D-B-C
Make span time = 23 hours

Idle time = 2+1+6 = 9

= 60.8%

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 47

There is a rotating bar made up of steel (Sut = 650 MPA. which is subjected to a completely reversed bending stress. The corrected endurance limit of the bar is 300 MPa. The fatigue strength of the bar for a life of 1,00,000 cycles will be _____ MPa

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 47

Given:
Sut = 650 MPa
Corrected endurance limit , Se = 300 MPa
N = 1,00,000 cycles
We will draw the S-N diagram for it:
log10(0.9Sut) = log10(585) = 2.7672
log10(Se) = log10(300) = 2.4771
log10(N) = log10(100000) = 5

Fatigue strength for 1,00,000 cycles:
Equation of line AB:

Therefore the fatigue strength of the bar will be 468.274 MPa.

Practice Test: Mechanical Engineering (ME)- 9 - Question 48

Consider a single plate clutch, consisting of only one pair of connecting surfaces. It develops a maximum torque of 150 N-m. The permissible intensity of pressure is 400 kPa and the coefficient of friction is 0.3. Assume uniform wear theory and the ratio of inner to outer diameters of the friction lining is 0.577. The inner and outer radius of the friction lining will be:

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 48

Let the inner diameter be ‘d’ and outer diameter be ‘D’.
Given :
Mt = 150 N-m = 150000 N-mm
Permissible intensity of pressure i.e., Maximum
pressure, P = 400 kPa = 0.4 N/mm2
µ = 0.3

In uniform wear theory case Pressure is inversely proportional to radius, therefore maximum pressure will occur at inner radius.
For Uniform Wear Theory,

Putting all values in equation (i) we will get
D = 202.35 mm, so outer radius = 101.175 mm
d = 116.75 mm, so inner radius = 58.375 mm
Therefore, correct option is (c).

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 49

There is a riveted joint which consist of four identical rivets. It is subjected to an eccentric force of 50 kN as shown in figure. If the permissible shear stress of rivet is 60 MPa, then the minimum diameter of rivets will be _____ mm.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 49

Firstly we will locate the centre of gravity of the group of rivets.

Here ‘O’ is centre of gravity
Now, we will take 2 equal and opposite forces passing through centre of gravity (P1 and P2).

Here P1 = P2 = P = 50 kN
P1 will act equally on all rivets in the same direction of applied load and P2 and P causes a twisting couple in clockwise direction. Due to P1 there will be a primary shear force acting on each rivet and due to twisting couple there will be a secondary shear force acting on each rivet.
Primary shear force acting on each rivet

P2 and P causes a twisting couple of magnitude, T = P × e = 50 × 200 = 10000 kN-mm
And this twisting couple will lead to a secondary shear force  on rivet 1, 2 , 3 and 4 respectively as shown in figure:

Now,

And we know that

Now, Rivet 3 and Rivet 4 are critical rivets because when we will calculate the resultant shear force on each rivet then we will find it maximum for rivet 3 and 4. The angle between primary and secondary shear force is 450for rivet 3 and 4. The angle between rimary and secondary shear force is 1350 for rivet 1 and 2.

Putting A= 12.5 kN

B = 70.72 kN

And θ = 450

We will get Rmax = 80.05 kN

Now , for safe condition:

Therefore minimum diameter of rivet is 41.22 mm.

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 50

The length L key required to transmit 500 Nm torque for 60mm diameter shaft. The key has a cross section of 20x10mm (Syt=Syc=240 MPa, FOS=4) is?

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 50

Key Length → Shear design

So length of key should be 56mm

Practice Test: Mechanical Engineering (ME)- 9 - Question 51

In orthogonal turning of low carbon steel pipe, with shear strength of 300MPa, Following condition are taken.
Axial feed = 0.25 mm/rev
Radial depth of cut = 4mm
Chip thickness = 0.5mm
Cutting velocity = 150 m/min
Orthogonal rake angle 80
The shear force and MRR respectively are

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 51

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 52

There is a vertical engine, having piston at the top and crank at the bottom, running at 2400 rpm. The length of crank and connectivity rod is 50 mm and 300 mm respectively. The diameter of the pistons is 100 mm and the mass of the reciprocating parts is 1.5 kg. The crank has turned 300 from the top dead centre during the expansion stoke and the gas pressure is 600 kN/m2. The net force on the piston is _____ N.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 52

Given:
Length of crank, r = 50 mm = 0.05 m
Length of connecting rod, l = 300 mm = 0.3 m
N = 2400 rpm
Gas pressure, P = 600 kN/m2
Mass of reciprocating parts, m = 1.5 kg
Diameter of piston, d = 0.1 m
θ = 300

Now,
n = l/r = 0.3/0.05 = 6

Force due to gas pressure, Fp = Area x Pressure
= 4712.39 N

Net force on the piston, F
F = Fp – Fb + mg = 4712.39 – 4497.59 + 1.5 x 9.81 = 229.52 N

Practice Test: Mechanical Engineering (ME)- 9 - Question 53

For single degree of freedom, condition for getting peak (maxima) in "magnification factor" Vs "ω / ωn" curveThe damping factor should be less than

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 53

Frequency response curves
As we know

Now, for having maxima

So, we will yet the peak only it our damping is less than 0.707

Practice Test: Mechanical Engineering (ME)- 9 - Question 54

Air enters an insulated diffuser operating at steady state with a pressure of 0.65 bar, temperature of 670C and a velocity of 300 m/s. The inlet area is 0.5 m2. At the exit, the pressure is 1 bar and the area is 0.6 m2. Potential energy changes can be neglected. Assume ideal gas behavior for air. The mass flow rate and temperature of the air at exit is

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 54

P1 = 0.65 bar = 65 kPa
T1 = 670C = 340 K
V1 = 300 m/s

A1 = 0.5 m2
R = 0.287 kJ/kgK
Cp = 1.008 kJ/kgK
P2 = 1 bar = 100 kPa
A2 = 0.6 m2

Now applying steady flow energy equation between 1 and 2:

Putting the value of V2 in equation (i), we will get

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 55

There are two blocks connected by a light string placed on the inclined parts of a triangular structure as shown in the figure. The coefficients of static friction is 0.3 at each of the surfaces. The minimum value of ‘M’ for which the system remains at rest is ___ kg.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 55

The tendency of the mass ‘M’ will be to slide in the upward direction for its minimum value.
We will draw free body diagram for both object.

Practice Test: Mechanical Engineering (ME)- 9 - Question 56

Which one of the following is an eigen vector of the matrix:-

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 56

Firstly we will find its eigen values by solving its characteristics equation
|A - λI| = 0
Where A is given matrix and I is identity matrix[
now we will find the eigen vector corresponding to λ = -5

So, the correct option is (c).

Practice Test: Mechanical Engineering (ME)- 9 - Question 57

is a Partial differential equation whose solution is given by

The value of K is

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 57

The objective here is to find the Particular integral as Complementary function is already given in the solution.

Practice Test: Mechanical Engineering (ME)- 9 - Question 58

The Laurent series for f(z) = that is valid in the region |z| > 10 is

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 58

Practice Test: Mechanical Engineering (ME)- 9 - Question 59

In a batch of three students marks obtained in a certain test are 50, 60 and 70. The standard deviation of the marks obtained in test is

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 59

Standard Deviation,

where n= 3 in this case.

Practice Test: Mechanical Engineering (ME)- 9 - Question 60

The surface integral of N ds over the sphere given by x2 + y2 + z2 = 4

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 60

From Gauss – Divergence theorem, we can write:

= 33.51 (2a + 3b + 4c)
= 67a + 100.53b + 134.04c
So, the correct option is (a).

Practice Test: Mechanical Engineering (ME)- 9 - Question 61

Water flows over a flat plate at a free stream velocity of 0.15m/s. There is no pressure gradient and laminar boundary layer is 6mm thick. Assume velocity profile as for the flow conditions stated above, calculate the skin friction coefficient.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 61

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 62

A light bulb sphere shaped of diameter 80 mm is hanged inside a brick room of cube shaped of side as 0.4 m. The light bulb is at a temperature of 327 0C and the brick is at 270C. Take emissivity (Ԑ) of light bulb and cube brick as 1 and 0.8 respectively, Determine the rate of heat loss (in kW) by radiation _____________ (upto two decimal).

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 62

Given, d = 0.07 m , r = 0.035 m
T1 = 327 + 273 = 600 K, T2 = 300K

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 63

In a single-cylinder reciprocating engine, the mass of reciprocating parts is 55 kg and the mass of revolving parts is 30 kg. The speed of the engine is 200 rpm and the stroke length is 300 mm. If 65 % of the reciprocating parts and all the revolving parts are to be balanced then the required balance mass at a radius of 270 mm is ___ kg.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 63

Given,
Mass of reciprocating parts, m1 = 55 kg
Mass of revolving parts, m2 = 30 kg
Speed of engine, N = 200 rpm
Stoke length, l = 300 mm
% of reciprocating parts to be balanced, k = 65 %
Angular speed, ω = (2πN) / 60
= (2π × 200) / 60
Radius of crank, r = l / 2 = 300/2 = 150 mm
Total mass to be balanced, m = k × m1 + m2
= 0.65 × 55 + 30 = 65.75 kg
Let the required mass at radius (rp) 270 mm be mp.
So from balancing we can write,
mp × rp = m × r
mp = (m × r) / rp = (65.75 × 150) / 270 = 36.53 kg.

Practice Test: Mechanical Engineering (ME)- 9 - Question 64

Find the amount of work supplied by the engine (in kW) if fuel of Calorific Value 45 MJ burns at a rate of 3kg/min in an Air Standard Otto cycle of compression ratio 7.

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 64

*Answer can only contain numeric values
Practice Test: Mechanical Engineering (ME)- 9 - Question 65

A figure is shown below. The view factor F12 is

Detailed Solution for Practice Test: Mechanical Engineering (ME)- 9 - Question 65

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## GATE Mechanical (ME) 2024 Mock Test Series

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