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Test: Fluid Dynamics & Flow Through Pipes - 2 - Mechanical Engineering MCQ


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30 Questions MCQ Test GATE Mechanical (ME) Mock Test Series 2025 - Test: Fluid Dynamics & Flow Through Pipes - 2

Test: Fluid Dynamics & Flow Through Pipes - 2 for Mechanical Engineering 2024 is part of GATE Mechanical (ME) Mock Test Series 2025 preparation. The Test: Fluid Dynamics & Flow Through Pipes - 2 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Fluid Dynamics & Flow Through Pipes - 2 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Fluid Dynamics & Flow Through Pipes - 2 below.
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Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 1

Which combination of the following statements about steady incompressible forced vortex flow is correct?  
P: Shear stress is zero at all points in the flow.
Q: Vorticity is zero at all points in the flow
R: Velocity is directly proportional to the radius from the centre of thevortex.
S: Total mechanical energy per unit mass is constant in the entire flowfield.

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 1

Ans. (b)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 2

Bernoulli's equation represents the  

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 2

Ans. (b)

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Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 3

Assertion (A): Two table tennis balls hang parallelly maintaining asmall gap between them. If air is blown into the gap between the balls,the balls will move apart. 
Reason (R): Bernoulli's theorem is applicable in this case.

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 3

Ans. (c)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 4

Assertion (A): Bernoulli's equation is an energy equation.  
Reason (R): Starting from Euler's equation, one can arrive at Bernoulli's equation.

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 4

Ans. (b) Starting from Euler's equation, one can arrive at Bernoulli's equation. And
we know that Euler equation is a momentum equation and integrating Euler
equation we can arrive at Bernoulli’s equation.

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 5

Consider the following assumptions: 
1. The fluid is compressible
2. The fluid is inviscid.
3. The fluid is incompressible and homogeneous
4. The fluid is viscous and compressible.
The Euler's equation of motion requires assumptions indicated in :

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 5

Ans. (b)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 6

How is the velocity coefficient Cv, the discharge coefficient Cd, and thecontraction coefficient Cc of an orifice related?  

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 6

Ans. (c)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 7

Match List-I (Measuring Devices) with List-II (Measured Parameter) and select the correct answer using the codes given below: 

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 7

Ans. (b)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 8

Match List-I with List-II and select the correct answer using the codes given below the lists:  



Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 8

Ans. (b)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 9

Which one of the following conditions will linearize the Navier-Stokes equations to make it amenable for analytical solutions? 

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 9

Ans. (c)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 10

Assertion (A) : A cylinder, partly filled with a liquid is rotated about itsvertical axis. The rise of liquid level at the ends is equal to the fall ofliquid level at the axis.  
Reason (R) : Rotation creates forced vortex motion.

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 10

Ans. (b)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 11

Assertion (A): Head loss for sudden expansion is more than the head loss for a sudden contraction for the same diameter ratio.  
Reason (R): Head loss varies as the square of the upstream and downstream velocities in the pipe fitted with sudden expansion or sudden contraction.

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 11

Ans. (c)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 12

Which one of the following statements relates to expression ' ρ vc'?

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 12

Ans. (d)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 13

Velocity of pressure waves due to pressure disturbances imposed in aliquid is equal to: 

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 13

Ans. (a)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 14

For maximum transmission of power through a pipe line with totalhead H, the head lost due to friction hf is given by:  

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 14

Ans. (b)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 15

Point A of head 'HA' is at a higher elevation than point B of head 'HB'.The head loss between these points is HL. The flow will take place.  

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 15

Ans. (c) Flow may take place from lower elevation to higher elevation. Everyday
we are pumping water to our water tank.
If flow is from point 1 to point 2 then
Total head at point 1 = Total head at point 2 + loss of head between 1 and 2
If flow is from point A to point B then
Total head at point A (HA) = Total head at point B (HB) + Loss of head between
A and B (HL)
If flow is from point B to point A then
Total head at point B (HB) = Total head at point A (HA) + Loss of head between
B and A (HL)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 16

If energy grade and hydraulic grade lines are drawn for flow through an inclined pipeline the following 4 quantities can be directly observed:
1. Static head
2. Friction head  
3. Datum head
4. Velocity head
Starting from the arbitrary datum line, the above types of heads will:

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 16

Ans. (d) Starting from the arbitrary datum line, the heads in sequence be in the sequence will be 3-datum head, 1-static head 4-velocity head, and 2- friction head.

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 17

If coefficient of contraction at the vena contract is equal to 0.62, thenwhat will be the dynamic loss coefficient in sudden contraction in airconditioningduct?  

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 17

Ans. (b)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 18

Which one of the following statements is correct?  

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 18

Ans. (c)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 19

For a circular channel, the wetted parameter (where R = radius of circular channel, θ = half the angle subtended by the water surface atthe centre) is given by: 

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 19

Ans. (c)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 20

The pressure drop in a pipe flow is directly proportional to the meanvelocity. It can be deduced that the  

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 20

Ans. (a)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 21

How does the head loss in turbulent flow in pipe vary?  

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 21

Ans. (c) Head loss in the turbulent flow is Approximately proportional to square of
velocity. But Head loss in the Laminar flow is as proportional to velocity.

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 22

Aging of pipe implies  

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 22

Ans. (d)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 23

The frictional head loss in a turbulent flow through a pipe varies        

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 23

Ans. (b) Frictional head loss in turbulent flow varies directly as the square of average velocity.

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 24

Assertion (A): Nature of the fluid flow in a pipe does not dependentirely on average velocity but it actually a function of the Reynoldsnumber.  
Reason (R): Reynolds number depends not only on average velocity butalso on the diameter of the pipe and kinematic viscosity of the fluid.

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 24

Ans. (a) Reynold’s number decides the fluid flow is laminar or turbulent, i.e  Nature of fluid flow Re = 

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 25

Which one of the following statements is true of fully developed flowthrough pipes?

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 25

Ans. (a) For fully developed flow through pipes, the flow is parallel, has no inertia effect. The pressure gradient is of constant value and the pressure force is balanced by the viscous force.

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 26

A right circular cylinder is filled with a liquid upto its top level. It isrotated about its vertical axis at such a speed that halt the liquid spillsout then the pressure at the point of intersection of the axis and bottom surface is:  

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 26

Ans. (d)

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 27

Both free vortex and forced vortex can be expressed mathematically as functions of tangential velocity V at the corresponding radius r. Freevortex and forced vortex are definable through V and r as 
 

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 27

Ans. C. Free vortex can be expressed mathematically as Vx r = constant and the
forced votex as V = r x constant.

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 28

The Bernoulli’s equation refers to conservation of 

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 29

If the Reynolds number is less than 2000, the flow in a pipe is

Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 30

If a fluid jet discharging from a 50 mm diameter orifice has a 40 mm diameter at its vena contracta, then its coefficient of contraction willbe: 

Detailed Solution for Test: Fluid Dynamics & Flow Through Pipes - 2 - Question 30

Ans. (b)

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