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Gate Mock Test Civil Engineering (CE)- 11 - Civil Engineering (CE) MCQ


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30 Questions MCQ Test GATE Civil Engineering (CE) 2025 Mock Test Series - Gate Mock Test Civil Engineering (CE)- 11

Gate Mock Test Civil Engineering (CE)- 11 for Civil Engineering (CE) 2024 is part of GATE Civil Engineering (CE) 2025 Mock Test Series preparation. The Gate Mock Test Civil Engineering (CE)- 11 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Gate Mock Test Civil Engineering (CE)- 11 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Gate Mock Test Civil Engineering (CE)- 11 below.
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Gate Mock Test Civil Engineering (CE)- 11 - Question 1

Directions: Choose the appropriate option for the blank to make the sentence grammatically correct.

________________, it seems clear, he will continue to play for the country.

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 1
He is so great a player that the selectors cannot drop him. Since no negation precedes 'drop' here, the negation has to come in the form of negative 'too'.
Gate Mock Test Civil Engineering (CE)- 11 - Question 2

The mirror image of the above text about the x-axis is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 2

( ∴ Mirror image of any text about a line is symmetrical about the line)

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Gate Mock Test Civil Engineering (CE)- 11 - Question 3

Directions: Select the option that bears the same relationship as that of the given pair.

POLO : MALLET

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 3
Polo is a game played with help of a mallet (meaning a long handled hammer with flexible handle). Similarly, golf is a game played with the help of a club (meaning a heavy stick).
Gate Mock Test Civil Engineering (CE)- 11 - Question 4

If ⊕ and ⊙ are two operators on numbers p and q such that p ⊙ q = p - q, and p ⊕

q = p × q, then (9 ⊙(6 ⊕ 7)) ⊙ (7 ⊕ (6 ⊙ 5)) is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 4
(9 ⊙(6 ⊕ 7)) ⊙ (7 ⊕ (6 ⊙ 5))

= (9 - (6 × 9)) - (7 × (6 - 5))

= (9 - 42) - (7 × 1)

= -33 - 7

= -40

Gate Mock Test Civil Engineering (CE)- 11 - Question 5

What is the value of ?

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 5
The given fraction is equal to = (a + b + c)

Where a = 8/7, b = 7/8, c = 9/7

a + b + c = 8/7 + 7/8 + 9/7 = = 185/56

Gate Mock Test Civil Engineering (CE)- 11 - Question 6

On a planar field, you traveled 3 units East from point O. Next you traveled 4 units South to arrive at point P. Then you traveled from P in the North-East direction such that you arrived at a point that is 6 units East of point O. Next, you traveled in the North-West direction so that you arrive at point Q that is 8 units North of point P. The distance of point Q to point O, in the same units, should be ______.

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 6
From right angled triangle ORQ,

OQ2 = OR2 + RQ2

= 32 + 42

= 9 + 16 = 25

Gate Mock Test Civil Engineering (CE)- 11 - Question 7

A, B and C borrow Rs. 29,200 in all at 4% simple interest and pay back equal amounts in full settlement of their respective debts after 5, 10 and 15 years, respectively. Find the sum borrowed by C.

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 7
Suppose A, B and C borrow Rs. x, Rs. y and Rs. z, respectively.

x + y + z = 29,200 .........(i)

Amount paid back by A = Rs. x + x(4)(5/100) = Rs. 6x/5

Amount paid back by B = Rs. y + y(4)(10/100) = Rs. 7y/5

Amount paid back by C = Rs. z + z(4)(15/100) = Rs. 8z/5

6x/5 = 7y/5 = 8z/5

i.e. 6x = 7y = 8z .........(ii)

Solving (i) and (ii) simultaneously, we get

x = 11,200, y = 9,600, z = 8,400

Hence, A, B and C borrow Rs. 11,200, Rs. 9,600 and Rs. 8,400, respectively.

Gate Mock Test Civil Engineering (CE)- 11 - Question 8

1. Some football players play cricket.

2. All cricket players play hockey.

Among the options given below, the statement that logically follows from the two statements 1 and 2 above, is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 8
F → Football players

C → Cricket players

H → Hockey players

∴ Some football players play hockey

Gate Mock Test Civil Engineering (CE)- 11 - Question 9

Answer these questions based on the pipeline diagram given:

The following sketch shows the pipelines carrying material from one location to another. Each location has a demand for material. The demand at B is 800, at C is 800, at D is 1400, and at E is 400. Each arrow indicates the direction of material flow through the pipeline. The flow from B to C is 600. The quantity of material flow is such that the demands at all these location are exactly met. The capacity of each pipeline is 2000.

The quantity moved from A to E is _____.

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 9
The capacity of each pipeline is 2000.

According to the demand and the flow quantity, the block diagram is shown below:

We have, DB = 800, DC = 800, DD = 1400, DE = 400, fBC = 600

The flow quantity shown in figure.

Thus, quantity moved from A to E is 2000.

Gate Mock Test Civil Engineering (CE)- 11 - Question 10

In an equivalent triangle PQR, side PQ is divided into four equal parts, side QR is divided into six equal parts and side PR is divided into eight equal parts. The length of each subdivided part in cm is an integer.

The minimum possible area of the triangle PQR, in cm2, is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 10
Let the length of side of an equilateral triangle be 24 cm. (L.C.M of 4, 6, 8 = 24)

To have minimum area of triangle PQR, (length of each sub divided part is an integer)

Area of an equilateral triangle = √3/4 a2 (where a is the length of the side)

Gate Mock Test Civil Engineering (CE)- 11 - Question 11

For the differential equation with y(0) = 1, the general solution is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 11
D + 5 = 0

D = -5

The general solution is:

y = ce-5t

From y(0) = 1, we get

C = 1

The general solution is:

y = e-5t

Gate Mock Test Civil Engineering (CE)- 11 - Question 12

Which of the following statements are the advantages of surface vibrators?

Surface vibrators are best suited

1. for one way reinforced slabs and road surfaces

2. when depth of the concrete to be vibrated exceeds 250 mm

3. where immersion vibrations are impracticable

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 12
Surface vibrators are placed directly on the concrete mass. These are best suited for the compaction of shallow elements and should not be used when depth of concrete to be vibrated is more than 250 mm.
Gate Mock Test Civil Engineering (CE)- 11 - Question 13

is equal to

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 13
Let form.

By L' Hospital rule, I form.

Again apply L' Hospital rule.

Gate Mock Test Civil Engineering (CE)- 11 - Question 14

The main function of surge tanks is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 14
When the water is suddenly released in penstocks, there may be a problem of water hammer. To avoid this, surge tanks are employed, which decrease the pressure of water, thereby preventing water hammer.
Gate Mock Test Civil Engineering (CE)- 11 - Question 15

A point load of 800 kN is applied on the surface of thick layer of saturated clay. Using Boussin's elastic analysis, the estimated vertical stress at a depth of 2 m and a radial distance of 1.0 m from the point of application of the load is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 15

Gate Mock Test Civil Engineering (CE)- 11 - Question 16

For a B.G.(Broad Gauge) track, the value of maximum velocity is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 16
For a B.G. track, the value of maximum velocity is .

For an N.G.(Narrow Gauge) track, the value of maximum velocity is

Gate Mock Test Civil Engineering (CE)- 11 - Question 17

A long structural column (Length = L) with both ends hinged is acted upon by an axial compressive load P. The differential equation governing the bending of column is given by , where y is the structural lateral deflection and EI is the flexural rigidity. The first critical load on column responsible for its buckling is given by

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 17
Length of column = L

End condition: Both ends hinged

Compressive load = P

Flexural rigidity = EI

Critical load on column, Pc = π2EI/L2

Gate Mock Test Civil Engineering (CE)- 11 - Question 18

The correct expression for the modulus of elasticity for short-term loading is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 18
Correct expression for the modulus of elasticity for short-term loading is It is based on neglection of the effect of creep. Here, Ec is short-term static modulus of elasticity in N/mm2 and fck is the characteristic compressive strength of cubes in N/mm2. The above expression is updated as per IS : 456-2000.
Gate Mock Test Civil Engineering (CE)- 11 - Question 19

For linear elastic systems, the type of displacement function for the strain energy is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 19
For linear elastic system,

E∝ε2 which represents quadratic equation.

Gate Mock Test Civil Engineering (CE)- 11 - Question 20

The velocity components of a plane flow are x/k1 - y/k2 , 0 in the directions x, y, z, respectively. If k1 , k2 ≠ 0 are constant times, the correct expression for the flow to be incompressible is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 20
Consider the expression for the incompressible flow.

Gate Mock Test Civil Engineering (CE)- 11 - Question 21

In structural analysis, Muller Breslau principle is used for

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 21
In structural analysis, Muller Breslau principle is used for drawing influence line diagram for any force function by means of deflected diagram.
Gate Mock Test Civil Engineering (CE)- 11 - Question 22

To make certain that the backfill material is more previous than the soil to be drained, the relationship used is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 22
The filter material should be coarse enough to allow easy passage for percolating water which can move easily without any buildup of water pressure in the filter.

For the filter to provide full drainage,

kfilter ≥ 25kprotectedsoil

where k is the permeability and it is proportional to square of particles size.

So, D15filter ≥ D15protected soil

Gate Mock Test Civil Engineering (CE)- 11 - Question 23

Which of the following organisms exhibits very nearly the characteristics of an ideal pathogenic indicator?

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 23
Escherichia coli

it is the ideal pathogenic indicator used for the bacterial analysis of water is exhibited by the organism

Fecal indicator A group of organisms that indicates the presence of fecal contamination, such as the bacterial groups thermotolerant coliforms or E. coli.

Hence, it is a type of bacteria that normally lives in your intestines. It's also found in the gut of some animals. Most types of E. coli are harmless and even help keep your digestive tract healthy. But some strains can cause diarrhea if you eat contaminated food or drink fouled water.

Entamoeba histolytica:

it is an anaerobic parasitic amoebozoan, part of the genus Entamoeba. Predominantly infecting humans and other primates causing amoebiasis, E. histolytica is estimated to infect about 35-50 million people worldwide.

Salmonella Typhi (S. Typhi):

bacteria which infect the intestinal tract and the blood. The disease is referred to as typhoid fever. S. Paratyphi A, B, and C bacteria cause a similar illness which is included under the typhoid heading

Vibro comma(Vibrio cholera):

it is a species of Gram-negative, facultative anaerobe, and comma-shaped bacteria. The bacteria naturally live in brackish or saltwater where they attach themselves easily to the chitin-containing shells of crabs, shrimps, and other shellfish.

Gate Mock Test Civil Engineering (CE)- 11 - Question 24

Figure given below shows a smooth vertical-gravity retaining wall with cohesionless soil backfill having an angle of internal friction Φ. In the graphical representation of Rankine's active earth pressure for the retaining wall shown in figure, length OP represents

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 24
Rankine's active earth pressure method is graphical method to determine the active earth pressure of the soil.

OP does not cut the Mohr's circle tangential, so OP represents the vertical stress at the base.

Gate Mock Test Civil Engineering (CE)- 11 - Question 25

The results of analysis of a raw water sample are given below.

From the data given above, it can be inferred that water needs removal of

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 25
Fluoride should be less than 1.5 mg/L, hardness between 75 – 115 mg/L as CaCO3, iron 0.3 mg/L and MPN 1 per 100 mL (presence of pathogenic bacteria).

Hence, water needs removal of fluoride, harness iron and followed by disinfection to reduce MPN to 1 per 100 mL.

Gate Mock Test Civil Engineering (CE)- 11 - Question 26

Two identical concrete piles having the plane dimenstions 50 cm x 50 cm are driven into a homogeneous sandy layer as shown in the figures. Consider the bearing capacity factor Nq for Φ = 30o as 24.

If QP1 and QP2 represent the ultimate point bearing resistance of the piles under dry and submerged conditions, respectively, which one of the following statements is correct?

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 26

The point bearing resistance of piles in sandy soils

Qp = Ab .σv.Nq

As the area at base (Ab) and Nq are same for both the piles given,

Qp∞σv

For dry sand condition,

∴ QP2 ≈ 0.5QP1

(or) QP1 > QP2 by about 100%)

Gate Mock Test Civil Engineering (CE)- 11 - Question 27

The dispersion of pollutants in atmosphere is maximum when

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 27
Unstable environment means ELR > ALR.

(EIR = Environment Lapse Rate, ALR = Adiabatic Lapse Rate)

A rising air parcel will continue to go up and dispersion of pollutant will be rapid due to vertical mixing of air with pollutants

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 11 - Question 28

For the function f(x) = x2e-x, the maximum occurs when x is equal to ____.(Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 28

Now for the maxima and minima, f’(x) = 0

Now f”(0) = 2 and f”(2) = -2e-2 < 0.="" thus,="" x="2" is="" the="" point="" of="" />

Gate Mock Test Civil Engineering (CE)- 11 - Question 29

When a retaining wall moves away from the back-fill, the pressure exerted on the wall is termed as

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 29
When a retaining wall moves away from the backfill, the pressure exerted on the wall is termed as active earth pressure. When a retaining wall moves towards the backfill, the pressure exerted on the wall is termed as passive earth pressure.

Swelling pressure is the pressure exerted by the soil on the overlying structure if free swelling of the soil is restrained by the placement of a structure over the soil. Pore water pressure is the pressure exerted due to the pore water. It is equal to the product of the depth at which pore water pressure is required and unit weight of water.

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 11 - Question 30

In a circular tapering bar of length 120 mm, diameter varies from 20 mm to 45 mm. If a tensile load of 20 kN is applied axially, find the total deflection (in mm) of the bar. (Take E = 85 MPa) (Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 11 - Question 30

Here, D1 = 20 mm = 0.020 m, D2 = 45 mm = 0.045 m,

P = 20 kN = 20000 N and L = 120 mm = 0.120 m

Total deflection is

= 0.039 m

= 39 mm

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