Electronics and Communication Engineering (ECE) > GATE ECE (Electronics) 2023 Mock Test Series > Practice Test: Electronics Engineering (ECE)- 3
Download as PDF
Practice Test: Electronics Engineering (ECE)- 3
Test Description
65 Questions MCQ Test GATE ECE (Electronics) 2023 Mock Test Series | Practice Test: Electronics Engineering (ECE)- 3
Practice Test: Electronics Engineering (ECE)- 3 for Electronics and Communication Engineering (ECE) 2023 is part of GATE ECE (Electronics) 2023 Mock Test Series preparation. The Practice Test: Electronics Engineering (ECE)- 3 questions and answers have been
prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The Practice Test: Electronics Engineering (ECE)- 3 MCQs are made for Electronics and Communication Engineering (ECE) 2023 Exam. Find important
definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Practice Test: Electronics Engineering (ECE)- 3 below.
Solutions of Practice Test: Electronics Engineering (ECE)- 3 questions in English are available as part of our GATE ECE (Electronics) 2023 Mock Test Series for Electronics and Communication Engineering (ECE) & Practice Test: Electronics Engineering (ECE)- 3 solutions in
Hindi for GATE ECE (Electronics) 2023 Mock Test Series course. Download more important topics, notes, lectures and mock
test series for Electronics and Communication Engineering (ECE) Exam by signing up for free. Attempt Practice Test: Electronics Engineering (ECE)- 3 | 65 questions in 180 minutes | Mock test for Electronics and Communication Engineering (ECE) preparation | Free important questions MCQ to study GATE ECE (Electronics) 2023 Mock Test Series for Electronics and Communication Engineering (ECE) Exam | Download free PDF with solutions
| 1 Crore+ students have signed up on EduRev. Have you? |
Practice Test: Electronics Engineering (ECE)- 3 - Question 1
“Wanted a two bedroom flat in the court area for immediate possession” - An Advertisement.
Assumptions:
I. Flats are available in the court area
II. Some people will respond to the advertisement
III. It is a practice to give such an advertisement
Assumptions:
I. Flats are available in the court area
II. Some people will respond to the advertisement
III. It is a practice to give such an advertisement
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 1
The advertisement depicts only the requirement, not the availability of flats in court area. So, I is not implicit. Such advertisements are given with the expectation of a response which can make such a flat available. So, II is implicit. Assumption III does not follow from the statement and so is not implicit.
Practice Test: Electronics Engineering (ECE)- 3 - Question 2
Which of the following is most similar in meaning to the given word
DIRE
DIRE
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 2
DIRE means very serious
Alarming means something very serious.
So the correct answer is ALARMING
Practice Test: Electronics Engineering (ECE)- 3 - Question 3
In the question given below, the sentence has a part printed in bold. That part may contain a grammatical error. Replace that part with four choices given below:
The famous playwright has been in the sick bed from the last one week.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 3
We use the present perfect continuous tense to talk about an action that started in the past and is continuing now. This is often used with 'for' (showing period of time) or since (showing point of time).
As the given sentence is one, the prepositional phrase 'from the last' must be replaced with 'for the past' to make it a grammatically correct sentence.
Practice Test: Electronics Engineering (ECE)- 3 - Question 4
He always _________ you in his letters
Practice Test: Electronics Engineering (ECE)- 3 - Question 5
His health ____________ under the pressure of work.
Practice Test: Electronics Engineering (ECE)- 3 - Question 6
A, B and C shoots to hit a target. If A hits the target 4 times in 5 trials, B hits in 3 times in 4 trials and C hits it 2 times in 3 trials. What is the probability that the target is hit by at least 2 persons?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 6
Probability that A hits the target = 4/5
Probability that B hits the target = 3/4
Probability that C hits the target = 2/3
P (at least 2) = P(2) + P(3)
Probability that B hits the target = 3/4
Probability that C hits the target = 2/3
P (at least 2) = P(2) + P(3)
Practice Test: Electronics Engineering (ECE)- 3 - Question 7
Two liquids are mixed in the ratio 4:3 and the mixture is sold at Rs 20 with a profit of 
%. If the first liquid is costlier than the second by Rs 7. Find the sum of costs of both the liquids.
%. If the first liquid is costlier than the second by Rs 7. Find the sum of costs of both the liquids.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 7
Profit = 
%
Cost of 1 unit of liquid 1 = x+7
Cost of 1 unit of liquid 2 = x
(x+7)×4+3x = 15(4+3)
x = 11
x+7 = 18
Total value of the prices = 11+18 = 29
%Cost of 1 unit of liquid 1 = x+7
Cost of 1 unit of liquid 2 = x
(x+7)×4+3x = 15(4+3)
x = 11
x+7 = 18
Total value of the prices = 11+18 = 29
Practice Test: Electronics Engineering (ECE)- 3 - Question 8
Henry and Ford worked together to complete a task in 10 days. Had Henry worked with half of his efficiency and Ford at 5 times of his efficiency it would have taken them to finish the job in 50% of the scheduled time. In how many days can Ford complete the job working alone?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 8
Let henry’s one day work be x
Let ford’s one day work be y
Solving 2 equations we get, y = 1/30
Hence, Ford can complete the job working alone in 30 days
Let ford’s one day work be y
Solving 2 equations we get, y = 1/30
Hence, Ford can complete the job working alone in 30 days
Practice Test: Electronics Engineering (ECE)- 3 - Question 9
A new flag is to be designed with six vertical stripes using some or all of the colours- yellow, green, blue and red. Then the number of ways this can be done such that no two adjacent stripes have the same colour out is:
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 9
There are 6 stripes. The 
stripe can be coloured in 4ways, 
in 3, 
in 3 and so on.
Thus, total number of ways = 4×3×3×3×3×3=12×81
stripe can be coloured in 4ways, in 3, in 3 and so on.Thus, total number of ways = 4×3×3×3×3×3=12×81
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 10
y(y-3) = 0
y = 3
y(y-3) = 0
y = 3
Practice Test: Electronics Engineering (ECE)- 3 - Question 11
In the given circuit determine the value of current source
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 11
V = 4i
2i = 4–v
2i = 4 – 4i
6i = 4
i = 2/3
So, v = 8/3
2i = 4–v
2i = 4 – 4i
6i = 4
i = 2/3
So, v = 8/3
Practice Test: Electronics Engineering (ECE)- 3 - Question 12
If power of a signal x (t) is 6 units, then determine the power of g(t), where g (t) is given as,
g(t) = 4x (t)
g(t) = 4x (t)
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 12
Power of g(t),
= 48 + 108
= 156 units
= 48 + 108
= 156 units
Practice Test: Electronics Engineering (ECE)- 3 - Question 13
Which one of the following is non-periodic?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 13
For a signal to be periodic, the signal must be define from 
Practice Test: Electronics Engineering (ECE)- 3 - Question 14
The ROC of z-transform of the discrete time sequence, x(n) so that x(n) is absolutely summable 
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 14
Practice Test: Electronics Engineering (ECE)- 3 - Question 15
Consider two signals 
and 
in which 
is band limited to 3 kHZ and 
is band limited to 2KHz, determine the minimum sampling frequency of g(t) where 
and in which is band limited to 3 kHZ and is band limited to 2KHz, determine the minimum sampling frequency of g(t) where
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 15
Convolution in time domain results multiplication in frequency domain,
So resultant signal in frequency domain is limited upto 2 KHz, i.e.
= 2kHz
so,
= 2 × 2
= 4 KHz
So resultant signal in frequency domain is limited upto 2 KHz, i.e.
= 2kHzso,
= 2 × 2= 4 KHz
Practice Test: Electronics Engineering (ECE)- 3 - Question 16
A TDM link has 30 signal channels and each channel is sampled 9000 times/sec. Each sample is represented by seven binary bits and contains an additional bit for synchronization. The total bit rate for the TDM link is:
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 16
Bit rate = 30 × 9000 (7 + 1) bits/second
= 2160 kbps
= 2160 kbps
Practice Test: Electronics Engineering (ECE)- 3 - Question 17
The signal flow graph of a closed loop system is shown in the figure, where 
represents the disturbance in the forward path. The effect of the disturbance can be reduced by
represents the disturbance in the forward path. The effect of the disturbance can be reduced by
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 17
With feedback, the output due to disturbance
Without feedback output due to disturbance is
By comparing above two equations, feedback decreases the effect of noise
If
Increases, disturbance decreases, But gain also decreases. This is not desirable.
If
increases, disturbance increases, since noise links with 
If
increases, disturbance decreases, and gain also decreases. This is desirable.
Without feedback output due to disturbance is
By comparing above two equations, feedback decreases the effect of noise
If
Increases, disturbance decreases, But gain also decreases. This is not desirable.If
increases, disturbance increases, since noise links with If
increases, disturbance decreases, and gain also decreases. This is desirable.
Practice Test: Electronics Engineering (ECE)- 3 - Question 18
The energy of constant-amplitude complex valued exponential sequence is __________ (where A is the constant amplitude)
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 18
Practice Test: Electronics Engineering (ECE)- 3 - Question 19
Piecewise linear model of a diode shown in the figure
Determine the value of
in the given circuit
Determine the value of
in the given circuit
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 19
Practice Test: Electronics Engineering (ECE)- 3 - Question 20
Which of the following is a microwave power amplifier?
Practice Test: Electronics Engineering (ECE)- 3 - Question 21
A carrier signal 
is amplitude modulated by a message signal m (t) = 
.If the modulation index is 0.5, then the power in USB is given by
is amplitude modulated by a message signal m (t) = .If the modulation index is 0.5, then the power in USB is given by
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 21
Practice Test: Electronics Engineering (ECE)- 3 - Question 22
For the circuit shown in the figure assume ideal diodes with forward resistance and forward voltage drop are zero. The current through diode
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 22
In the given circuit both the diodes cannot be ON simultaneously.
In the above circuit only
is ON.
So current through diode
is Zero.
In the above circuit only
is ON.So current through diode
is Zero.
Practice Test: Electronics Engineering (ECE)- 3 - Question 23
Determine the value of 
in the given circuit given 
= 100
in the given circuit given = 100
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 23
Since
is negative, so Transistor is in cut-off mode, therefore, 
= 0
and
= 10V and 
=0
Therefore
= 10 volt
Since
is negative, so Transistor is in cut-off mode, therefore, = 0and
= 10V and =0Therefore
= 10 volt
Practice Test: Electronics Engineering (ECE)- 3 - Question 24
Determine the value of 
in the circuit, assume op-amp is ideal.
in the circuit, assume op-amp is ideal.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 24
= 11–10
= 1 volt
= 11–10
= 1 volt
Practice Test: Electronics Engineering (ECE)- 3 - Question 25
Assume the op-amp is ideal the transfer characteristics of the circuit is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 25
In the given circuit for positive half cycle of input voltage 
is at 
i.e. –10V and diode is off,and during negative half cycle 
is at 
i.e. +10V, so diode is ON and,virtual short-cirucit exist.
Therefore,
So transfer characteristic
is at i.e. –10V and diode is off,and during negative half cycle is at i.e. +10V, so diode is ON and,virtual short-cirucit exist.Therefore,
So transfer characteristic
Practice Test: Electronics Engineering (ECE)- 3 - Question 26
If cross-sectional area of base-emitter junction of transistor 
is 2 times of transistor 
then determine the value of 
Assume 
of both the transistors are very large
is 2 times of transistor then determine the value of Assume of both the transistors are very large
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 26
= 4.65 mA
As the area of base-emitter junction of transistor
is two times of 
So
= 4.65 mA
As the area of base-emitter junction of transistor
is two times of So
Practice Test: Electronics Engineering (ECE)- 3 - Question 27
7 EH and 5 FH are XORed. The output is multiplied by 10 H. The result is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 27
7EH - 01111110
5FH - 01011111
XORed 0010 0001 21H
5FH - 01011111
XORed 0010 0001 21H
Practice Test: Electronics Engineering (ECE)- 3 - Question 28
The minimal some of products form of 
is
is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 28
The K-map of the above function
So, the required minimal SoP of f is
f =
The K-map of the above function
So, the required minimal SoP of f is
f =
Practice Test: Electronics Engineering (ECE)- 3 - Question 29
In a twin-wire transmission line in air, the adjacent voltage maxima are at 12 cm and 18 cm. The operating frequency is.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 29
Adjacent maxima appear with a distance of 
f = 2.5 GHZ
f = 2.5 GHZ
Practice Test: Electronics Engineering (ECE)- 3 - Question 30
A system has receiver noise resistance of 50W. It is connected to an antenna with an input resistance of 50W The noise figure of the system is.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 30
The overall noise figure of the receiver is,
= 2
= 2
Practice Test: Electronics Engineering (ECE)- 3 - Question 31
For a parabolic reflector antenna with diameter of 3m, the far field pattern measurement at 10 GHz should be carried out at a distance of at least
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 31
Practice Test: Electronics Engineering (ECE)- 3 - Question 32
The dimension of the null space of the matrix A is, where 
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 32
Since order of matrix is 3 × 3 and rank of matrix is 2
So, dimension of null space = 3 – 2 = 1
So, dimension of null space = 3 – 2 = 1
Practice Test: Electronics Engineering (ECE)- 3 - Question 33
Given that x is a random variable in the range 
with a probability density function f(x)
the value of k is
with a probability density function f(x) the value of k is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 33
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 34
The limit is in the form of 
By L-hospitals rule,
Practice Test: Electronics Engineering (ECE)- 3 - Question 35
The value of 
where the contour is the unit circle traversed clockwise is
where the contour is the unit circle traversed clockwise is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 35
Practice Test: Electronics Engineering (ECE)- 3 - Question 36
The circuit shown in the figure is in series resonance at a frequency 
rad/sec. The value of 
in the volts is.
rad/sec. The value of in the volts is.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 36
Practice Test: Electronics Engineering (ECE)- 3 - Question 37
The circuit shown in the figure contains a dependent current source between A and B terminals. The thevenin’s equivalent resistance in kW between the terminals C and D is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 37
Thevenin’s equivalent circuit is made by connecting 1A current source at the output and short circuiting the battery.
At node A,
At node A,
Practice Test: Electronics Engineering (ECE)- 3 - Question 38
Determine the average power consume by the 4W resistor in the given circuit.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 38
Practice Test: Electronics Engineering (ECE)- 3 - Question 39
A discrete-time x[n] is obtained by sampling an analog signal at 10 kHz. The signal x[n] is filtered by a system with impulse response h(n) = 0.5 { d [n] +d (n – 1]}. The 3 dB cut off frequency of the filter is.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 39
Practice Test: Electronics Engineering (ECE)- 3 - Question 40
The transfer function of a digital system is given by 
Where 
is real.The transfer function is BIBO stable if the value of 
is
Where is real.The transfer function is BIBO stable if the value of is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 40
Transfer function of system,
The stability of a two-pole system can be investigated by stability criteria called “Scho-cohn” stability test In this approach there are two polynomials
and 
which are calculated from denominator polynomial of the transfer function. For the system to be stable,
|
These two conditions (1) and (2) are satisfied only if
= 0.5 among the given options.
The stability of a two-pole system can be investigated by stability criteria called “Scho-cohn” stability test In this approach there are two polynomials
and which are calculated from denominator polynomial of the transfer function. For the system to be stable,|
These two conditions (1) and (2) are satisfied only if
= 0.5 among the given options.
Practice Test: Electronics Engineering (ECE)- 3 - Question 41
The impulse response of a continuous time system is given by h (t) = d (t – 1) + d (t – 3).The value of the step response at t = 2 is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 41
Step response = integration of impulse response
Practice Test: Electronics Engineering (ECE)- 3 - Question 42
The impulse response of an LTI system is given as,
It represents a
It represents a
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 42
Since
for n < 0 or negative values of n. So, the system is non causal Also 
represents a rectangular function with the representation as
This represents the characteristics of ideal low-pass filter.
Since
for n < 0 or negative values of n. So, the system is non causal Also represents a rectangular function with the representation asThis represents the characteristics of ideal low-pass filter.
Practice Test: Electronics Engineering (ECE)- 3 - Question 43
In the circuit shown below current through the resistor is shown. Voltage across 4 Ω resistor is:
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 43
Voltage across 5 Ω = 10 V
Thus voltage across 7 Ω = 10 V (5 Ω || 7 Ω)
Practice Test: Electronics Engineering (ECE)- 3 - Question 44
Consider the control system shown in figure with feed forward action for rejection of a measurable disturbance d(t). The value of K, for which the disturbance response at the output y(t) is zero mean, is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 44
For r(t) = 1
For no disturbance effect
At steady state, s = 0
K = –2
For no disturbance effect
At steady state, s = 0
K = –2
Practice Test: Electronics Engineering (ECE)- 3 - Question 45
The open loop transfer function of a system is 
.The angles of arrival of its root loci are
.The angles of arrival of its root loci are
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 45
Angle of arrival
Practice Test: Electronics Engineering (ECE)- 3 - Question 46
Determine the maximum value of 
so that transistor remains in saturation region, Given b = 100 and 
=0 Volt
so that transistor remains in saturation region, Given b = 100 and =0 Volt
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 46
Small signal resistance,
Practice Test: Electronics Engineering (ECE)- 3 - Question 47
The small-signal resistance offered by the n-channel MOSPET M shown in the figure below, device transconductance parameter
threshold voltage
= 1 V.
threshold voltage= 1 V.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 47
Small signal resistance,
Practice Test: Electronics Engineering (ECE)- 3 - Question 48
Assuming op-amp is ideal, the magnitude of the transfer impedance in 
of the current to voltage converter in the given circui
of the current to voltage converter in the given circui
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 48
Apply KVL at node A,
Practice Test: Electronics Engineering (ECE)- 3 - Question 49
Assuming the op-amp is ideal, the input impedance that is seen by the voltage source in the given circuit is.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 49
Practice Test: Electronics Engineering (ECE)- 3 - Question 50
A 
n junction has a built-in potential of 0.6 V. The width of depletion layer at a reverse bias voltage of 1.4 V is 4µm. For a reverse bias of 17.4 V the depletion layer width will be
n junction has a built-in potential of 0.6 V. The width of depletion layer at a reverse bias voltage of 1.4 V is 4µm. For a reverse bias of 17.4 V the depletion layer width will be
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 50
Practice Test: Electronics Engineering (ECE)- 3 - Question 51
For the circuit shown below determine the ac voltage across the diode, given 
= 26 mV,
0.7 V and h = 1 and C is very large
= 26 mV,0.7 V and h = 1 and C is very large
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 51
and for ac analysis replace diode by its dynamic resistance
and for ac analysis replace diode by its dynamic resistance
Practice Test: Electronics Engineering (ECE)- 3 - Question 52
Integrated output waveform for the dual slope ADC is shown in the figure. The time 
for an 10 bit counter with 5 mHZ clock will be.
for an 10 bit counter with 5 mHZ clock will be.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 52
Practice Test: Electronics Engineering (ECE)- 3 - Question 53
In figure, if the input A = 0 and B = 0, the output F can be mode 0 by making
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 53
Given, A = 0, and B = 0
So only C = 1 and D = 1 will give output 0
Y = 0
Given, A = 0, and B = 0
So only C = 1 and D = 1 will give output 0
Y = 0
Practice Test: Electronics Engineering (ECE)- 3 - Question 54
The initial state of the counter in the circuit shown below is 01, and resolution of DAC is 0.5 volt. Determine the output of DAC after three clock pulses.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 54
The state diagram of counter
So, output of DAC = 0 volt
So, output of DAC = 0 volt
Practice Test: Electronics Engineering (ECE)- 3 - Question 55
A full duplex binary FSK transmission is made through a channel of bandwidth of 20 KHZ.In each direction of transmission the two carriers used for the two states are separated by 6KHZ. The maximum baud rate for this transmission is.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 55
Since the transmission is full duplex 10 KHz will be allocated for each direction
Bandwidth = Band Rate + (
)
Given
= 6 KHz
So, Band Rate = Band width - (
)
= 10 KHz – 6
= 4000 bps
Bandwidth = Band Rate + (
)Given
= 6 KHzSo, Band Rate = Band width - (
)= 10 KHz – 6
= 4000 bps
Practice Test: Electronics Engineering (ECE)- 3 - Question 56
The carrier signal 
is angle modulated by a message signal m(t) = 
.The deviation constant 
= 1.5 rad/V. Bandwidth of the modulated signal using Carson’s rule is.
is angle modulated by a message signal m(t) = .The deviation constant = 1.5 rad/V. Bandwidth of the modulated signal using Carson’s rule is.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 56
= 2(12 + 1) × 10 KHz
= 260 KHz
= 2(12 + 1) × 10 KHz
= 260 KHz
Practice Test: Electronics Engineering (ECE)- 3 - Question 57
The output signal of an AM transmitter is expressed as 
.The ratio of power of carrier signal to power contained in single sideband is
.The ratio of power of carrier signal to power contained in single sideband is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 57
= 450 W
= 450 W
Practice Test: Electronics Engineering (ECE)- 3 - Question 58
A frequency modulator has output 
. Where 
= 100 Hz/V and m (t) is shown in the figure. According Carson’s rule the bandwidth of s(t) is
. Where = 100 Hz/V and m (t) is shown in the figure. According Carson’s rule the bandwidth of s(t) is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 58
= 500 Hz,
So Bandwidth = 2
2(500 + 200)
= 1400 Hz
= 500 Hz,So Bandwidth = 2
2(500 + 200)
= 1400 Hz
Practice Test: Electronics Engineering (ECE)- 3 - Question 59
The magnetic field intensity vector of a plane wave is given by 
.where 
denotes the unit vector in Z direction.The wave is propagating with 0 phase velocity.
.where denotes the unit vector in Z direction.The wave is propagating with 0 phase velocity.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 59
Practice Test: Electronics Engineering (ECE)- 3 - Question 60
An air-filled rectangular waveguide has inner dimensions of 5cm × 4 cm. The wave impedance of the 
mode of propagation in the waveguide at a frequency of 18 GHZ is
mode of propagation in the waveguide at a frequency of 18 GHZ is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 60
Practice Test: Electronics Engineering (ECE)- 3 - Question 61
A load impedance 150 W is to be matched to a 600 W lossless transmission line by using a quarter wave line transformer. The characteristic impedance of the quarter wave transformer is required
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 61
Practice Test: Electronics Engineering (ECE)- 3 - Question 62
Consider a random variable x that takes values +1 and -1 with probability 0.5 each. The value of the cumulative distribution function F (x) at x = -1 and + 1 are
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 62
The PDF of the random variable is
The cumulative distribution function F(x) is the probability upto x as given below
The cumulative distribution function F(x) is the probability upto x as given below
Practice Test: Electronics Engineering (ECE)- 3 - Question 63
If the matrix A is such that A = 
then the determinant of A is equal to
then the determinant of A is equal to
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 63
Practice Test: Electronics Engineering (ECE)- 3 - Question 64
The maximum value of 
in the interval [1,6] is
in the interval [1,6] is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 64
= 21
= 41
So the maximum value of f(x) in interval [1, 6] is 41
= 21
= 41
So the maximum value of f(x) in interval [1, 6] is 41
Practice Test: Electronics Engineering (ECE)- 3 - Question 65
A rectangular waveguide, in dominant TE mode, has dimensions 10 cm x 15 cm. The cut off frequency is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 65
For TE10 mode
|
20 docs|263 tests
|
|
Use Code STAYHOME200 and get INR 200 additional OFF
|
Use Coupon Code |
Information about Practice Test: Electronics Engineering (ECE)- 3 Page
In this test you can find the Exam questions for Practice Test: Electronics Engineering (ECE)- 3 solved & explained in the simplest way possible.
Besides giving Questions and answers for Practice Test: Electronics Engineering (ECE)- 3, EduRev gives you an ample number of Online tests for practice
|
20 docs|263 tests
|
Download as PDF
Download free EduRev App
Track your progress, build streaks, highlight & save important lessons and more!
Related content with Practice Test: Electronics Engineering (ECE)- 3
|
Related tests with Practice Test: Electronics Engineering (ECE)- 3
|
|
|
|
|
|
© EduRev
|
Education Revolution
|
Follow Us
|
