# Test: Angle Modulation

## 10 Questions MCQ Test GATE ECE (Electronics) 2023 Mock Test Series | Test: Angle Modulation

Description
Attempt Test: Angle Modulation | 10 questions in 30 minutes | Mock test for GATE preparation | Free important questions MCQ to study GATE ECE (Electronics) 2023 Mock Test Series for GATE Exam | Download free PDF with solutions
QUESTION: 1

Solution:
QUESTION: 2

Solution:
QUESTION: 3

### The amount of frequency shift in FM is

Solution:

For FM, the frequency changes with the change in the amplitude of modulating signal value.

QUESTION: 4

Match List-l (Type of transmission) with List-l I (Applications) and select the correct answer using the codes given below the lists:
List-l
A. Wideband FM
B. AM
C. Narrowband FM
D. Vestigial sideband transmission
List-lI
2. Used for transmission of television signals
3. Used for high quality music transmission
4. Used for speech transmission (Police wireless, ambulance etc.)
Codes: Solution:
QUESTION: 5

According to Carson’s rule, the bandwidth of FM wave is given by (Aω is the frequency deviation and ωm the modulating frequency)

Solution:

According to Carson’s rule, the bandwidth of a single-tone wideband FM is
BW = 2(Δω + ωm)

QUESTION: 6

Consider the following statements associated with angle modulations:
1. In FM, the frequency deviation is proportional to modulating frequency.
2. In PM, the frequency deviation is independent of modulating signal.
3. Amplitude of both FM and PM are constant.
4. It is possible to receive FM on a PM receiver and vice-versa.
5. Signal to noise ratio of PM is better than that of FM.
Which of the statements given above are correct?

Solution:

• In FM, the frequency deviation is proportional only to the amplitude variation of the modulating signal and it is independent of modulating frequency fm. Hence, statement-1 is not correct.
• In PM, the frequency deviation increases with increase in modulating frequency fm and decreases with decrease in modulating frequency. Thus, frequency deviation in PM is proportional to modulating frequency. Hence, statement-2 is false.
• Statement-3 is correct.
• it is possible to receive FM on a PM receiver and PM on a FM receiver. Hence, statement-4 is correct.
• Signal to noise ratio of PM is inferior to that in FM. Hence, statement-5 is not correct.

QUESTION: 7

We can obtain PM from frequency modulator by passing the modulating signal through a

Solution:

A PM wave can be generated using a frequency modulator as shown in figure below: QUESTION: 8

Match List-l (Type of modulation) with List-II (Noise immunity) and select the correct answer using the codes given below the lists:  Solution:

The noise immunity of FM is better than AM and PM while the noise immunity of PM is better than AM but worse than FM.

QUESTION: 9

A FM wave is represented by the following equation:
v = 10 sin [5 x 10B t + 4 sin 1250 t]
Its maximum deviation is around.

Solution:

Given, v = 10sin [5 x 108t + 4 sin 1250 t]
Comparing the above equation with the standard for FM given by  we have modulating frequency, and modulation index,
mf = 4
∴ Maximum deviation, QUESTION: 10

In a FM system, the modulating frequency fm = 1 kHz, the modulating voltage Vm= 2 volt and the deviation is 6 kHz. If the modulating voltage is raised to 4 volt then what is the new deviation?

Solution:

Given, We know that, or, When, V'm = 4 V, the new deviation in frequency is  Use Code STAYHOME200 and get INR 200 additional OFF Use Coupon Code