Test: Basic Concepts of Network Theory
20 Questions MCQ Test GATE Electrical Engineering (EE) 2023 Mock Test Series | Test: Basic Concepts of Network Theory
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For the circuit given below.
What is the value of V2?
From Ohm’s law,
V2= -3i and V1=2i
Appling the KVL, -20 + V1 – V2=0 ———–(i)
Put the value on above equation and get i = 4A
Hence, V2 = -3 x 4 = -12 V
For the circuit given below.
What is the value of equivalent resistance?
The circuit given below.The Thevenin resistance across the diode in the circuit is?
The Thevenin resistance across the diode in the circuit is?
Diode is non-linear elements is removed.
After shorting the voltage source the redrawn circuit is
Thevenin resistance
= 11/3 ohm
Consider the following circuit.
What is the value of V24 / V13 of given circuit?
- Based on kirchoffs current law, we know that incoming currents at a node is equals to outgoing currents.
- So, based on this 4 and 3 will get canceled with 5 and 2.
- So, finally i = 1.
In the circuit given, a charge of 600 C is delivered to the 100 V source in a 1 minute. The value of v1 must be:
- In order for 600 C charge to be delivered to the 100 V source, the current must be anticlockwise.
- Applying KVL we get:
v1 + 60 - 100 = 10 x 20
v1 = 240 V
In the circuit of the fig the value of the voltage source E is:
Going from 10 V to 0 V:
- 10 + 5 + E + 1 = 0
- E = -16V
- Minus sign indicates that the polarity of battery should be reversed.
Consider the circuit graph shown in fig. Each branch of circuit graph represent a circuit element. The value of voltage v1 is:
- 100 = 65 + v2
⇒ v2 = 35 V
- v3 - 30 = v2
⇒ v3 = 65 V - 105 + v4 - v3 - 65 = 0
⇒ v4 = 25 V - v4 + 15 - 55 + v1 = 0
⇒ v1 = 15 V
What quantity of charge must be delivered by a battery with a Potential Difference of 110 V to do 660J of Work?
► V = W / Q
► Q = W / V = 660 / 110 = 6 C
- Voltage across 60 Ω resistor = 30 V
- Current = 30 / 60 = 0.5 A
- Voltage across R1 is = (70 - 20) V = 50 V
- R1 = 50 / 0.5 = 100 Ω
Twelve 6 Ω resistor are used as edge to form a cube.The resistance between two diagonally opposite corner of the cube is
The current i will be distributed in the cube branches symmetrically
If we go from +ve side of 1 kΩ through 7 V, 6 V and 5 V
We get, v1 = 7 + 6 - 5 = 8 V
From above figure
V – 4 – 5 = 0
or
V = 9 V
Hence alternative (D) is the correct choice.
In a AC circuit, resistive and total impedance are 10 and 20 ohms respectively. What is the phase angle difference between the voltage and current?
- Cosɸ = R/Z; where R= 10 ohms and Z = 20 ohms
- Cosɸ = 1/2 means phase angle is 60 degree.
The quantity of a charge that will be transferred by a current flow of 10 A over 1 hour period is _________ ?
We know that,
I=Q / t or Q = I x t = 10 x 1 hours
{since unit of current is Cs-1, therefore time should be in seconds}
∴ Q = 10 x 60 x 60
= 36000 C
= 3.6 x 104 C
A capacitor is charged by a constant current of 2 mA and results in a voltage increase of 12 V in a 10 sec interval. The value of capacitance is:
12 * C = 2 m x 10
C = 1.67 mF
Hence, Capacitance is equal to 1.67 mF.
The energy required to charge a 10 μF capacitor to 100 V is:
The current in a 100 μF capacitor is shown in fig. If capacitor is initially uncharged, then the waveform for the voltage across it is:
This 0.2 V increases linearly from 0 to 0.2 V. Then current is zero. So capacitor hold this voltage.
The voltage across a 100 μF capacitor is shown in fig. The waveform for the current in the capacitor is:
= 600 mA
For 1 ms < t < 2 ms,
The waveform for the current in a 200 μF capacitor is shown in fig. The waveform for the capacitor voltage is:
= 3125 t2
At t = 4 ms, vc = 0.05 V
It will be parabolic path at t = 0
t-axis will be tangent.
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22 docs|274 tests
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22 docs|274 tests
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