Test: Digital Electronics- 1 - Electrical Engineering (EE)


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15 Questions MCQ Test GATE Electrical Engineering (EE) 2023 Mock Test Series - Test: Digital Electronics- 1

Test: Digital Electronics- 1 for Electrical Engineering (EE) 2023 is part of GATE Electrical Engineering (EE) 2023 Mock Test Series preparation. The Test: Digital Electronics- 1 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Digital Electronics- 1 MCQs are made for Electrical Engineering (EE) 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Digital Electronics- 1 below.
Solutions of Test: Digital Electronics- 1 questions in English are available as part of our GATE Electrical Engineering (EE) 2023 Mock Test Series for Electrical Engineering (EE) & Test: Digital Electronics- 1 solutions in Hindi for GATE Electrical Engineering (EE) 2023 Mock Test Series course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Digital Electronics- 1 | 15 questions in 45 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study GATE Electrical Engineering (EE) 2023 Mock Test Series for Electrical Engineering (EE) Exam | Download free PDF with solutions
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Test: Digital Electronics- 1 - Question 1

What are the essential prime implicants of following Boolean function x'z + y`z + xz'

Detailed Solution for Test: Digital Electronics- 1 - Question 1

flx, y, z)= xlz + ylz + xzl These pairs are essential

Test: Digital Electronics- 1 - Question 2

Consider a multiplexer with X &Y as data inputs and z as a control pin. If Z = 0, selects input X and Z = I , selects input Y what are the connections required to realize the 2 - variable Boolean functions f T R

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Test: Digital Electronics- 1 - Question 3

A combinational circuit, using 8 x 1 MUX is shown in figure. The minimized expression for output Z is

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Test: Digital Electronics- 1 - Question 4

The Minimal Product of sums function described by k-Map, shown in figure is

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Test: Digital Electronics- 1 - Question 5

The output of an AND gate with three inputs, A, B, and C, is HIGH when ________.

Test: Digital Electronics- 1 - Question 6

The digital circuit using two inverters shown in figure will acts as

Detailed Solution for Test: Digital Electronics- 1 - Question 6

When 2 inverters are connected then it will become bi-stable.

Test: Digital Electronics- 1 - Question 7

Why is a demultiplexer called a data distributor? 

Detailed Solution for Test: Digital Electronics- 1 - Question 7

A demultiplexer sends a single input to multiple outputs, depending on the select lines. For one input, the demultiplexer gives several outputs. That is why it is called a data distributor.

*Answer can only contain numeric values
Test: Digital Electronics- 1 - Question 8

If 2's complement representation of a 16-bit number (one-sign bit and 15 Magnitude bits) is FFFFthen its magnitude in decimal representation is ____


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Test: Digital Electronics- 1 - Question 9

The initial state of MOD — 16, down counter is 0110. What state will be it be after 37 clock pulses??

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Test: Digital Electronics- 1 - Question 10

In the given figure shows a negative logic AND gate. If positive logic is used this gate is equivalent to

Detailed Solution for Test: Digital Electronics- 1 - Question 10

Y = A B = A + B .

Test: Digital Electronics- 1 - Question 11

An 8085 Microprocessor based system uses a 4 k x 8 bit RAM whose starting address is AAOOH. The address of last byte in this RAM is

Detailed Solution for Test: Digital Electronics- 1 - Question 11

4K x 8 = 212 x 8 bit it has 12 bits So address of last - byte will be AA 00 + 0 FFF = B9FF

Test: Digital Electronics- 1 - Question 12

What is F's complement of (2BFD)16

Detailed Solution for Test: Digital Electronics- 1 - Question 12

F'S complement of 2BFD is FFF F - 2BFD = D402

Test: Digital Electronics- 1 - Question 13

A. ROM is interfaced to an 8085 CPU as indicated in figure, shown, what is address range occupied by ROM is

Detailed Solution for Test: Digital Electronics- 1 - Question 13

A15 A 14 A 13 will be 000 So Range will be

Test: Digital Electronics- 1 - Question 14

112 4-bit 2's complement no's 1011 and 0110 are added, then result expressed in 2's complementnotation is

Test: Digital Electronics- 1 - Question 15

Which one of the following statement is correct?

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