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The natural response of an RLC circuit is described by the differential equation
The v(t) is
Find the current in the circuit which supplies an active power of 600 watts and reactive power of 800 VAR, if the voltage applied is 200 V (RMS value).
In the circuit of fig. v_{∞} = 0 for t > 0. The initial condition are v(0) = 6V and dv(0) /dt =3000 V s. The v(t) for t > 0 is
The circuit shown in fig. P1.6.5 has been open for a long time before closing at t = 0. The initial condition is v(0) = 2V. The v(t) for t > is
Circuit is shown in fig. Initial conditions are i_{1}(0) = i_{2}(0) =11A
i_{1} (1s) = ?
Circuit is shown in fig. P.1.6. Initial conditions are (0)i_{1=}i_{2}(0)=11A
i_{2} (1 s)= ?
The circuit shown in fig is in steady state with switch open. At t = 0 the switch is closed. Theoutput voltage v_{t} (c) for t > 0 is
The switch of the circuit shown in fig. is opened at t = 0 after long time. The v(t) , for t > 0 is
In the circuit of fig.the switch is opened at t = 0 after long time. The current i_{L}(t) for t > 0 is
In the circuit shown in fig.all initial condition are zero.
If i_{s} (t) = 1 A, then the inductor current i_{L}(t) is
In the circuit shown in fig. all initialcondition are zero
If i_{s}(t) = 0.5t A, then i_{L}(t) is
In the circuit of fig. switch is moved from position a to b at t = 0. The i_{L}(t) for t > 0 is
In the circuit shown in fig. a steady state has been established before switch closed. The i(t) for t > 0 is
The switch is closed after long time in the circuit of fig. The v(t) for t > 0 is
In the circuit of fig. i(0) = 1A and v(0) = 0. The current i(t) for t > 0 is
In the circuit of fig. a steady state has been established before switch closed. The v_{o} (t) for t >0 is
In the circuit of fig. a steady state has been established before switch closed. The i(t) for t > 0 is
Calculate the quality factor Q for an RLC circuit having R = 10 Ω, C = 30μF, and L = 27mH.
23 docs285 tests

23 docs285 tests
