Test: Quantitative Reasoning (February 14) - CAT MCQ

Required sum = (80 - 3 x 3) years = (80 - 9) years = 71 years.

Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.

Then, 2x + 3y = 77 ...(i) and

3x + 2y = 73 ...(ii)

Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.

Putting y = 17 in (i), we get: x = 13.

Ans is "Data inadequate".

Suppose ther are 18 students (10 girls, 8 boys).
1/5 of 10=2 (girls).
1/8 of 8=1 (boy).
Total participation=2+1=3.
Total students=10+8=18.
Answer = 3/18 = 1/6.
Answer cannot be determined until we have the "Ratio of girls to boys"
 

Clearly, we have :

B-3 = E ...(i)

B + 3 = D ...(ii)

A+B = D + E+10 ...(iii)

B = C + 2 ...(iv)

A+B + C + D + E= 133 ...(v)

From (i) and (ii), we have : 2 B = D + E ...(vi)

From (iii) and (vi), we have : A = B + 10 ...(vii)

Using (iv), (vi) and (vii) in (v), we get:

(B + 10) + B + (B - 2) + 2B = 133 5B = 125 B = 25.

Let x and y be the ten's and unit's digits respectively of the numeral denoting the woman's age.
Then, woman's age = (10x + y) years; husband's age = (10y + x) years.

Therefore (10y + x)- (10X + y) = (1/11) (10y + x + 10x + y)
⇒ (9y-9x) = (1/11)(11y + 11x) = (x + y)
⇒ 10x = 8y x = (4/5)y

Clearly, y should be a single-digit multiple of 5, which is 5.
So, x = 4, y = 5.
Hence, woman's age = 10x + y = 45 years.

Clearly, while counting, the numbers associated to the thumb will be : 1, 9,17, 25,.....

i.e. numbers of the form (8n + 1).

Since 1994 = 249 x 8 + 2, so 1993 shall correspond to the thumb and 1994 to the index finger.

Let number of notes of each denomination be x.

Then x + 5x + 10x = 480

⇒ 16x = 480

∴ x = 30.

Hence, total number of notes = 3x = 90.

Since one of the numbers on the dial of a telephone is zero, so the product of all the numbers on it is 0.