Test: Quantitative Reasoning (February 15) - CAT MCQ

Since B and D are twins, so B = D.
Now, A = B + 3 and A = C - 3.
Thus, B + 3 = C - 3
⇒ D + 3 = C-3
⇒ C - D = 6

Clearly, every member except one (i.e. the winner) must lose one game to decide the winner. Thus, minimum number of matches to be played = 30 - 1 = 29.

Each row contains 12 plants.

There are 11 gapes between the two corner trees (11 x 2) metres and 1 metre on each side is left.

Therefore Length = (22 + 2) m = 24 m.

Manick's present age = 12 years, Rahul's present age = 4 years.

Let Manick be twice as old as Rahul after x years from now.
Then, 12 + x = 2 (4 + x)
⇒ 12 + x = 8 + 2x
⇒ x = 4.

Hence, Manick's required age = 12 + x = 16 years.

Number of cuts made to cut a roll into 10 pieces = 9.

Therefore Required number of rolls = (45 x 24)/9 = 120.

Let the number of boys and girls participating in sports be 3x and 2x respectively.
Then, 3x = 15 or x = 5
⇒ Number of girls participating in sports = 2x = 10
⇒  Number of students not participating in sports = 60 - (15 + 10) = 35

Let number of boys not participating in sports be y.
Then, number of girls not participating in sports = (35 -y)

Therefore (35 - y) = y + 5
⇒  2y = 30
⇒  y = 15

So, number of girls not participating in sports = (35 - 15) = 20

Hence, total number of girls in the class = (10 + 20) = 30

Let x and y be the number of deer and peacocks in the zoo respectively. Then,

x + y = 80 ...(i) and

4x + 2y = 200 or 2x + y = 100 ...(ii)

Solving (i) and (ii), we get) x = 20, y = 60.

Since there are socks of only two colours, so two out of any three socks must always be of the same colour.

Total number of routes from Bristol to Carlisle = (4 x 3 x 2) = 24.

Let money with Ken = x. Then, money with Mac = x + £ 3.

Now, 3x = (x + x + £ 3) + £ 2 ⇒ x = £ 5.

Therefore Total money with Mac and Ken = 2x + £ 3 = £ 13.