Test: Data Interpretation- 5 - CLAT MCQ

# Test: Data Interpretation- 5 - CLAT MCQ

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## 20 Questions MCQ Test Quantitative Techniques for CLAT - Test: Data Interpretation- 5

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Test: Data Interpretation- 5 - Question 1

### Study the following graph carefully to answer the given questions Down Stream Distance = 200 km                      Up Stream Distance = 300 km A boatman rows down stream at 6kmph on Wednesday. Find the speed of upstream and Speed of current?

Detailed Solution for Test: Data Interpretation- 5 - Question 1

Downstream Speed = 6kmph
Upstream Speed = 8kmph – 6kmph = 2kmph
Speed of Current = (6-2)/2 = 2kmph

Test: Data Interpretation- 5 - Question 2

### Study the following graph carefully to answer the given questions Down Stream Distance = 200 km                      Up Stream Distance = 300 km A boatman rows up stream at 4kmph, 2 kmph and 8 kmph on Monday, Wednesday and Thursday respectively. Then find the ratio between the down stream speed of boat on Monday, Wednesday, and Thursday together and the rate of current on the same days together?

Detailed Solution for Test: Data Interpretation- 5 - Question 2

Downstream Speed of boat on Monday = 10 – 4 = 6kmph. similarly Downstream Speed of boat on Wednesday and Thursday = 6 kmph, 16kmph
Rate of current = 1kmph, 2kmph and 4kmph
Ratio = 28:7 = 4 : 1

Test: Data Interpretation- 5 - Question 3

### Study the following graph carefully to answer the given questions Down Stream Distance = 200 km                      Up Stream Distance = 300 km A boatman rows up stream at 16 kmph and 2 kmph on Tuesday and Friday. Then find the difference between the down stream speed of boat on Tuesday and Friday together and the speed of boat in still water on the same days together?

Detailed Solution for Test: Data Interpretation- 5 - Question 3

down stream speed of boat on Tuesday and Friday = 32 kmph
Still water speed = 25 kmph
Difference = 32 – 25 = 7 kmph

Test: Data Interpretation- 5 - Question 4

Study the following graph carefully to answer the given questions

Down Stream Distance = 200 km                      Up Stream Distance = 300 km

What time will be taken by a boat to cover a distance on Tuesday along the stream, if the up stream of boat is 3 kmph?

Detailed Solution for Test: Data Interpretation- 5 - Question 4

upstream of boat = 3 kmph
down stream of boat =15 kmph
Down Stream Distance = 15% of 200 = 30; Time = 30/15 = 2 hr

Test: Data Interpretation- 5 - Question 5

Study the following graph carefully to answer the given questions

Down Stream Distance = 200 km                      Up Stream Distance = 300 km

What is the sum of total distance travelled by the boat on Monday, Wednesday and Friday together?

Detailed Solution for Test: Data Interpretation- 5 - Question 5

Total distance travelled by the boat on Monday = 48 + 90 = 138
Similarly Total distance travelled by the boat on Wednesday and Friday = 102, 88
Total distance travelled by the boat on Monday, Wednesday and Friday = 138 + 102 + 88 = 328 km

Test: Data Interpretation- 5 - Question 6

Study the following graph carefully to answer the given questions

Down Stream Distance = 200 km                      Up Stream Distance = 300 km

Find the ratio between the down stream distance travelled by boat on Monday, Wednesday, Thursday and Friday together and the Up stream distance travelled by the boat on the same days together?

Detailed Solution for Test: Data Interpretation- 5 - Question 6

Down stream distance travelled by boat on Monday, Wednesday, Thursday and Friday together = 48 + 30 + 40 + 52 = 170
Up stream distance travelled by boat on Monday, Wednesday, Thursday and Friday together = 90 + 72 + 42 + 36 = 240
17 : 24.

Test: Data Interpretation- 5 - Question 7

Study the following graph carefully to answer the given questions

Down Stream Distance = 200 km                      Up Stream Distance = 300 km

Find the difference between the up stream distance travelled by boat on Tuesday and Friday together and the down stream distance travelled by boat on the same days together?

Detailed Solution for Test: Data Interpretation- 5 - Question 7

Difference  = 96 – 82 = 14

Test: Data Interpretation- 5 - Question 8

Study the following graph carefully to answer the given questions

Down Stream Distance = 200 km                      Up Stream Distance = 300 km

Total downstream distance travelled by boat on Monday, Tuesday and Wednesday together is what percentage of total upstream distance travelled by boat on the same days together?

Detailed Solution for Test: Data Interpretation- 5 - Question 8

Total downstream distance travelled by boat on Monday, Tuesday and Wednesday = 108
Total up stream distance travelled by boat on Monday, Tuesday and Wednesday = 222
% = 108/222 * 100 = 48.6%

Test: Data Interpretation- 5 - Question 9

Study the following graph carefully to answer the given questions

Down Stream Distance = 200 km                      Up Stream Distance = 300 km

A boatman rows down stream at 6kmph on Wednesday. Find the time taken by the boat to cover upsream distance on the same day?

Detailed Solution for Test: Data Interpretation- 5 - Question 9

Downstream Speed = 6kmph
Upstream Speed = 8kmph – 6kmph = 2kmph
Time taken by the boat to cover upstream distance = 72/2 = 36 hours

Test: Data Interpretation- 5 - Question 10

Study the following graph carefully to answer the given questions

Down Stream Distance = 200 km                      Up Stream Distance = 300 km

A boatman rows up stream at 16 kmph on Tuesday. Find the approximate time taken by the boat to cover downstream distance on the same day?

Detailed Solution for Test: Data Interpretation- 5 - Question 10

Downstream speed = 28 kmph; Time taken by the boat to cover downstream distance = 30/28 = 1 hr

Test: Data Interpretation- 5 - Question 11

(Q.no: 11-15). Refer to the table and answer the given questions.
NA refers the data which is not needed for a particular question. The number of working days of A, B, C, D is given below and some of them are missing. Take the data of the first row for the first question and the second row for the second question and so on.

A started a work alone and then B joined her 5 days before actual completion of the work. For how many days A worked alone?

Detailed Solution for Test: Data Interpretation- 5 - Question 11

Efficiency (A : B) = 5 : 4
Number of days(A : B) = 4x : 5x = 4x : 25
∴ Number of days required by A to finish the work alone = 4x
= 4 x 5 = 20.
A and B work together for last 5 days = 5 x 9 = 45%
Efficiency of A = 5% and B’s efficiency = 4%
∴ No. of days taken by A to complete 55% work = 55/5 = 11days

Test: Data Interpretation- 5 - Question 12

(Q.no: 11-15). Refer to the table and answer the given questions.
NA refers the data which is not needed for a particular question. The number of working days of A, B, C, D is given below and some of them are missing. Take the data of the first row for the first question and the second row for the second question and so on.

Working together B and C take 50% more number of days than A, B and C together take and A and B working together, take 8/3 more number of days than A, B and C take together. If A, B and C all have worked together till the completion of the work and B has received Rs.120 out of total earnings of Rs. 480 then in how many days did A, B and C together complete the whole work?

Detailed Solution for Test: Data Interpretation- 5 - Question 12

The days ratio of (A + B + C) : (B + C) = X:3X/2 = 2X:3x;
Efficiency ratio = 3X:2X
Efficiency of A = x.
(480/3X) = Rs.160
Amount received by B = Rs.120 & C = 200
160:120:200 =4:3:5
1/4:1/3:1/5= 15:20:12;
(1/15+1/12+1/20)*Y = 1
Y = 5 days

Test: Data Interpretation- 5 - Question 13

(Q.no: 11-15). Refer to the table and answer the given questions.
NA refers the data which is not needed for a particular question. The number of working days of A, B, C, D is given below and some of them are missing. Take the data of the first row for the first question and the second row for the second question and so on.

All of them started to work together but A leaves after 4 days. B leaves the job 3 days before the completion of the work. How long would the work last?

Detailed Solution for Test: Data Interpretation- 5 - Question 13

Let the work lasted for x days,
A’s 4 day’s work + B (x – 3) day’s work + C’s x day’s work = 1
⇒ (4/16) + (x – 3) / (64/5) + x/32 = 1
⇒ 5(x – 3)/64 + x/32 = 1 – 1/4
⇒ [5(x – 3) + 2x] / 64 = 3/4
⇒ 7x – 15 = 48
∴ x = (48 + 15)/7 = 63/7 = 9 days

Test: Data Interpretation- 5 - Question 14

(Q.no: 11-15). Refer to the table and answer the given questions.
NA refers the data which is not needed for a particular question. The number of working days of A, B, C, D is given below and some of them are missing. Take the data of the first row for the first question and the second row for the second question and so on.

C started the work and left after some days, when 25% work was done. After it D joined and completed it working for 25 days. In how many days C and D can do the complete work, working together?

Detailed Solution for Test: Data Interpretation- 5 - Question 14

Efficiency of C = (100/50) = 2%
Rest work = 75%
∴ Efficiency of D = 75/25 = 3%
∴ Combined efficiency of C and D = 5%
∴ Number of days required by C and D to work together = 100/5 = 20 days.

Test: Data Interpretation- 5 - Question 15

(Q.no: 11-15). Refer to the table and answer the given questions.
NA refers the data which is not needed for a particular question. The number of working days of A, B, C, D is given below and some of them are missing. Take the data of the first row for the first question and the second row for the second question and so on.

B and C started the work. After 3 days D joined them. What is the total number of days in which they had completed the work?

Detailed Solution for Test: Data Interpretation- 5 - Question 15

Efficiency of B and C = 11.11 + 5.55 = 16.66%
Work done in 3 days = 3 x 16.66 = 50%
Rest work done by B, C and D = 50/50 = 1 day
Work can be completed in 4 days.

Test: Data Interpretation- 5 - Question 16

(Q.no: 16 -20). Refer to the table and answer the given questions.

NA refers the data which is not needed for a particular question. The price details of 5 products are given below and some of them are missing. Take the data of the first row for the first question and the second row for the second question and so on.

Rahul purchased a mobile and sold it for a loss(loss % given in the table). From that money, he purchased another article and sold it for a gain of (Profit % given in the table). What is the overall gain or loss?

Detailed Solution for Test: Data Interpretation- 5 - Question 16

CP = 8400
SP = 8400 * 95/100 = 7980
CP = 7980
SP = 7980 * 105/100 = 8379
Difference = 8400 – 8379 = 21

Test: Data Interpretation- 5 - Question 17

(Q.no: 16 -20). Refer to the table and answer the given questions.

NA refers the data which is not needed for a particular question. The price details of 5 products are given below and some of them are missing. Take the data of the first row for the first question and the second row for the second question and so on.

A, B and C invests rupees 8000, 12000 and 10000 respectively in a business. At the end of the year the balance sheet shows a loss of initial investment. Find the share of loss of B.

Detailed Solution for Test: Data Interpretation- 5 - Question 17

Total loss after one year = 30000*40/100 = 12000
share of B = (40/10)*12000 = 4800

Test: Data Interpretation- 5 - Question 18

(Q.no: 16 -20). Refer to the table and answer the given questions.

NA refers the data which is not needed for a particular question. The price details of 5 products are given below and some of them are missing. Take the data of the first row for the first question and the second row for the second question and so on.

A Shop Keeper sells two bags for Rs. 500 each. On one, he gets % profit(as per the table) and on the other he gets % loss(as per the table). His profit or loss in the entire transaction was?

Detailed Solution for Test: Data Interpretation- 5 - Question 18

% = x
Loss % = x²/100 = 196/100 = 49/25%

Test: Data Interpretation- 5 - Question 19

(Q.no: 16 -20). Refer to the table and answer the given questions.

NA refers the data which is not needed for a particular question. The price details of 5 products are given below and some of them are missing. Take the data of the first row for the first question and the second row for the second question and so on.

The price of TV was marked up by %(as per the table).It was sold at a discount of 20% on the marked price. What was the profit percent of the cost price?

Detailed Solution for Test: Data Interpretation- 5 - Question 19

40 – 20 + [40 * (-20)/100] = 20 – 8 = 12%

Test: Data Interpretation- 5 - Question 20

(Q.no: 16 -20). Refer to the table and answer the given questions.

NA refers the data which is not needed for a particular question. The price details of 5 products are given below and some of them are missing. Take the data of the first row for the first question and the second row for the second question and so on.

Preethi sold a machine to Shalini at a profit of %(as per table). Shalini sold this machine to Arun at a loss of %(as per table). If Preethi paid Rs.5000 for this machine, then find the cost price of machine for Arun?

Detailed Solution for Test: Data Interpretation- 5 - Question 20

R1 = 30% R2 = 20%
5000 * 130/100 * 80/100 = Rs. 5200

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## Quantitative Techniques for CLAT

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