20 Questions MCQ Test Quantitative Techniques for CLAT - Test: Percentage- 1
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In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:
Detailed Solution for Test: Percentage- 1 - Question 4
Number of valid votes
= 80% of 7500
∴ Valid votes polled by other candidate
= 45% of 6000
= 45100×600045100×6000 = 2700
In an exam 80% of the students passed in Eng, 85% in Math and 75% in both. if 40 students failed in both subjects, the total number of students is?
Detailed Solution for Test: Percentage- 1 - Question 5
Let n(A) = no. of students pass in english
n(B) = no. of students pass in math
n(A U B) = no. of students pass in either math or english
n(A ∩ B) = no.of students pass in both math and english
let x are no. of students
⇒ n(A U B) = n(A) + n(B) - n(A ∩ B)
= 80x/100 + 85x/100 - 75x/100
no. of students fail in both either math or english = x - n(A U B)
In an examination, Summit got 30% marks and failed by 15 marks. In the same examination, Rohit got 40% marks, which is 35 marks more than the pass marks. Then what is the total marks in the examination?
Detailed Solution for Test: Percentage- 1 - Question 8
The correct option is A.
Let the total marks be x.
Sumit got = 30% of x
Passing marks = 0.3x+15
Rohit got = 40% of x
Passing marks = 0.4x - 35
Equating both passing marks , we get
0.3x+15 = 0.4x - 35
50 = 0.1x
x = 500
In Mathematics exam, a student scored 30% marks in the first paper, out of the total of 180. How much should he score in second paper out of a total of 150, if he is to get an overall average of at least 50%
Detailed Solution for Test: Percentage- 1 - Question 10
Firstly, marks he scored in first paper out of 180 will be
180 x 30÷100 = 54 marks
So he scored 54 marks out of 180 in the first paper.
Now total marks of the examination is 330 i.e 150+180.
50% of 330 is 165.
So in second paper he has to score 165–54=111 marks to get 50% marks over all.
Now the ans is asked in terms of percent so,
111÷150 x 100 = 74%
So he has to get 74 % in the second paper to get a overall percent of 50%.
On decreasing the price of TV set by 30%, its sale is increased by 20%. What is the effect on the revenue received by the shopkeeper?
Detailed Solution for Test: Percentage- 1 - Question 15
Lets take the orignal price as 100. Then on decreasing the price by 30% we get= 70. Now the sale is increased by 20%=84 (20% of 70 or 20/100*70= 14 now 70+14=84) So we can say that Cp=100 and Sp=84 Thats loss as cp is bigger. Loss=16 Loss%=16/100*100 =16%
The value of a machine depreciates 10% annually. If its present value is Rs. 4000, its value 2 years hence will be:
Detailed Solution for Test: Percentage- 1 - Question 16
The correct option is B.
Present value - 4000
Depreciation - 10% of present value annually
After one year value of machine will be = 4000 - 400(10% of 4000) = 3600
After 2nd year value of machine will be = 3600 - 360(10% of 3600) = 3240
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