20 Questions MCQ Test Quantitative Techniques for CLAT - Test: Time And Distance- 2
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A student walks from his house at 2 km/h and reaches school 5 minutes late and if his speed had been 3 km/h he would have reached the school 5 minutes earlier. How far is his school from house?
Detailed Solution for Test: Time And Distance- 2 - Question 3
Speed = Distance/Time
Let ideal time taken to reach school is t, distance to school = distance(d)
With a speed of 4km/hr or 4/60 km/min he reaches 5 mins late i.e.
60d = 4t + 20 ----- (1)
5/60 = d/(t-10)
60d = 5t - 50 ----- (2)
From eq 1 and 2
4t +20 = 5t - 50
t = 70 mins
60d = 4t + 20 = 280 + 20 = 300
distance(d) = 5 kms
A person walks from his house at the rate of 6 km/h and reaches office 12 minutes late and if his speed had been 8 km/h he would have reached the office 8 minutes earlier. How far is his office from house?
Two trains of 400 m and 350 m long are running on parallel tracks at the rate of 180 km/h and 120 km/h respectively. How long will they take to cross each other if they are running in opposite direction?
A train crosses a platform of length 350 m in 12 sec and a man standing on platform in 2 sec. Find the speed of train.
Detailed Solution for Test: Time And Distance- 2 - Question 12
The correct answer is B as
Let the length of train be x m.
Since the train crosses the man in 2 sec
Speed of train = x/2 m/s
Also it crosses the platform of length 350 m in 12 sec
So speed of train = (350+x)/12
Equating both the speeds of train ,we get
x/2 = (350+x)/12
x = (350+x)/6
6x = 350+x
5x = 350
x = 70
Thus length of train = 70 m
Now, speed of train = 70/2 = 35 m/s
= 35/1000*3600 = 35/5*18
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