KIITEE Mock Test - 8 - JEE MCQ

If F > μ_s mg, the block m will start moving on block M. It will, therefore, exert a force on block M due to kinetic friction m and M.
This force f_k = μ_k mg.
Thus, the acceleration of block

Hence, the correct choice is (1).

Magnitude of the Impulse received | ΔI| = 4mcu

V₁ and V₂ are velocities after collision.
Magnitude of impulse is the same on both A and B.
For body A:
2mv₁ - 6mu = -4mcu
2mv₁ = 6mu - 4cum
V₁ = 3u - 2cu(→)
For body B:
mv2 - (-mu) = 4mcu
mv2 = 4mcu - mu
v2 = 4cu - u(→) - speed of B

For the block with mass m, the force experienced is the spring force.
∴ Spring force = Mass × acceleration = ma
For block with mass M, forces are spring force and the external F

Since there is no friction between the sphere and the horizontal surface and also between the spheres themselves, there will be no transfer of angular momentum from sphere A to sphere B due to the collision. Since the collision is elastic and the spheres have the same mass, the sphere A only transfers its linear velocity v to sphere B. Sphere A will continue to rotate with the same angular speed ω at a fixed location. Hence the correct choice is (3).

We know that, p = 
% error in pressure = (% error in F) + 2(error in L)
= (4%) + 2(3%)
= 10%

In the expression, we have minimum three significant figures, hence answer should be up to three significant figures.

Rounding off the result 1.612979, we have

Solutions of alkali metals in liquid ammonia are blue coloured due to ammoniated electrons.

These ammoniated electrons absorb red colour from the visible light and so the transmitted light is blue.
Hence, option (4) is correct.

Option (1) is incorrect because the reducing power of the alkali metals increases from sodium to cesium. However, Li has the highest reducing power because of its highest heat of hydration.
Option (2) is incorrect because Li⁺, being highly hydrated, has the least ion mobility and the least value of ionic velocity.
Option (3) is incorrect because the metal ions are extensively hydrated in their aqueous solutions and the trend of the hydrated ionic radius is as follows.
Li⁺(aq) > Na⁺(aq) > K⁺(aq) > Rb⁺(aq) > Cs⁺(aq)
[Note: In solid ionic crystals, the trend of the radii of metal ions is the same as that for the atomic radii, which is Li⁺ < Na⁺ < K⁺ < Rb⁺ < Cs⁺]

The Newman projection formula using C₂ and C₃ is:

Hence, option (d) is correct.

Acid hydrolysis of an ester gives two different organic compounds.

For first order reaction,

Here, [A_o] = Initial concentration of reactant and [A] = Final concentration of reactant
When initial concentration drops to 3/4, then


But, t_1/4 = t_3/4 (given)
Therefore,


 = 

Yes, it is the correct answer.

(i) Enantiomers are the pairs of optical isomers which are non-superimposable mirror images of each other.
(ii) Diastereomers are stereoisomers that do not mirror one another and are non-superimposable on one another.
So, in the given compounds:
(A) and (B) are enantiomers. (See by rotating B at 180°.)
(A) and (C) are diastereomers.
(B) and (C) are also diastereomers.
Hence, the correct option is 4.

Flocculating value = Millimoles of effective ion (Ba²⁺) per litre

From the given equations, we have
K₁ = 
K₂ = 
K₃ = 
For the given reaction,
K = 

K = 

• This option is correct because both the statements A and B are incorrect.
• Trans-dichloro bis (ethylenediamine) rhodium(III) is symmetrical and therefore, is optically inactive.
• According to Werner's theory, secondary valency is directional, whereas primary valency is non-directional.
• Geometrical isomers are possible for [Co(en)₂Cl₂]⁺ and the cis isomer is optically active.

SN² mechanism means bimolecular nucleophilic substitution mechanism. In this, rate of reaction is determined by concentration of two molecules. It is characteristic of 1⁰ alkyl halides.
CH₃ -CH₂ -Cl
1⁰ alkyl halide

According to Gibb's equation:

The reaction becomes spontaneous at a temperature at which  is a negative value.
At 298K:

Since ΔGº is positive, the reaction is not spontaneous at this temperature.



Hence, the reaction is spontaneous above 1100 K or 827^oC.

This reaction is also called crossed Cannizzaro reaction. In this reaction, formaldehyde is oxidised to acid salt, while benzaldehyde is reduced to benzyl alcohol.

For a NaCl crystal, Cl- ions form the FCC lattice and Na+ ions lie in the octahedral voids.
The minimum value of radius ratio (radius of cation/radius of anion) in an octahedral void is 0.414.

Freundlich adsorption isotherm
x/m = kp^1/n
Here, x/m = Amount of gas adsorbed by adsorbent per gram
k and n = Constant
p = Pressure
Other forms are x = ^mkp1/n
x/m = kp^-n
All equations represent Freundlich adsorption isotherm.

The given equation can be written as

Hence, a² = 5, b² = 9 and the eccentricity is given by

Area of parallelogram = 
On comparing with given equations,
a = 1, b = 2, c = 3 and c' = 5/2
a₁ = 3, b₁ = 4, d = -10 and d' = - 5
Thus, area of parallelogram =  sq. units
=  sq. units = 5/4 sq. units

According to question:

Given that probability that a teacher will give an unannounced test during any class meeting is 1/5.
The probability of not missing the test = 1 - 1/5 = 4/5
The probability of not missing both the tests = (4/5) × (4/5) = 16/25
Hence, probability that he will miss at least one test = 1 - 16/25 = 9/25

From question, we get the slope of the given line is -3/4.
The slope of line perpendicular to the given line must be 4/3.
Only equation that satisfies the given condition is 4x − 3y + k = 0 (Option 2)