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AP EAMCET Mock Test - 5 - JEE MCQ


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30 Questions MCQ Test AP EAMCET Mock Test Series - AP EAMCET Mock Test - 5

AP EAMCET Mock Test - 5 for JEE 2024 is part of AP EAMCET Mock Test Series preparation. The AP EAMCET Mock Test - 5 questions and answers have been prepared according to the JEE exam syllabus.The AP EAMCET Mock Test - 5 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for AP EAMCET Mock Test - 5 below.
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AP EAMCET Mock Test - 5 - Question 1

Ultra-violet rays are detected by

AP EAMCET Mock Test - 5 - Question 2

When the current in a coil is changed from 10 A in one direction to 10 A in opposite direction in 0.5 s, an e.m.f. of 1 V is induced in it. Self-inductance of the coil is

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AP EAMCET Mock Test - 5 - Question 3

The temperature coefficient of resistance for a wire is 0.00125/ oC. At 300 K its resistance is 1 ohm. The temperature at which the resistance becomes 2 ohm is

AP EAMCET Mock Test - 5 - Question 4

A 5 cm long solenoid having 10 cm resistance and 5 mH inductance is joined to a 10 V battery. At steady state, current through solenoid is

Detailed Solution for AP EAMCET Mock Test - 5 - Question 4

At steady state, inductance is ineffective
I = V/R = 10/10 = 1A

AP EAMCET Mock Test - 5 - Question 5

Two equal charges q of opposite sign separated by a distance 2a constitute an electric dipole of dipole moment p. If P is a point at a distance r from the centre of the dipole and the line joining centre to this point makes an angle θ with the axis of the dipole, then potential at the point P is given by

AP EAMCET Mock Test - 5 - Question 6

Two moles of an ideal gas is expanded isothermally and reversibly at 300 K from 1L to 10 L. The enthalpy change in kJ is

Detailed Solution for AP EAMCET Mock Test - 5 - Question 6
The enthalpy change at constant pressure is given as

ΔH = CpΔT

For isothermal expansion

ΔT = 0

∴ ΔH = 0

AP EAMCET Mock Test - 5 - Question 7

For a chemical reaction rate law is, rate = k[A]2[B]. If [A] is doubled at constant [B], the rate of reaction

Detailed Solution for AP EAMCET Mock Test - 5 - Question 7
Given,

Initial rate = k[A]2 [B]

Rate k = [2A]2 [B] = 4k[A]2 [B]

Thus if the concentration of A, [A] is doubled and that of [B] is constant, then initial rate increases by a factor of 4.

AP EAMCET Mock Test - 5 - Question 8

An antiseptic Dettol is a mixture of two compounds 'A' and 'B' where A has 6π electrons and B has 2π electrons. What is 'B'?

Detailed Solution for AP EAMCET Mock Test - 5 - Question 8

Dettol is mixture of

Hence compound ‘B’ is Terpineol.

AP EAMCET Mock Test - 5 - Question 9

How many isomers are possible for an akane having molecular formula C5H12?

Detailed Solution for AP EAMCET Mock Test - 5 - Question 9
There can be 3 possible isomers (or an alkane having formula C5H12. These are as follows

AP EAMCET Mock Test - 5 - Question 10

Which among the following statements is true about the Schottky defect?

Detailed Solution for AP EAMCET Mock Test - 5 - Question 10
In Schottky defect, cation and anion are lacking in stoichiometric proportion. It is basically a vacancy defect in ionic solids. In order to maintain electrical neutrality, the number of missing cations and anions are equal. This defect can easily be illustrated by the following figure.

AP EAMCET Mock Test - 5 - Question 11

Propene when treated with a cold cone. H2SO4 forms a compound which on heating with water gives

Detailed Solution for AP EAMCET Mock Test - 5 - Question 11
Propone when treated with cold cone. H2SO4 forms a compound, isopropyl* hydrogen sulphate on heating with water gives propan-2-ol.

AP EAMCET Mock Test - 5 - Question 12

The bond angle H—O —O in H2O2 in gaseous phase is

Detailed Solution for AP EAMCET Mock Test - 5 - Question 12

The molecular dimensions of H2O2 in the gaseous phase is shown in the following figure.

Thus, the bond angle H — O — O in H2O2 in gaseous phase is 94.8º

AP EAMCET Mock Test - 5 - Question 13

According to Werner’s theory the geometry of the complex is determined by

Detailed Solution for AP EAMCET Mock Test - 5 - Question 13

Werner’s theory was used to describe the structure and formation of complex compounds or coordination compounds. According to this theory the primary valency gives the oxidation number and the secondary valency gives the coordination number. Also, the geometry of the complex is determined by the number and position of secondary valences in space as the ligand satisfying secondary valences are always Greeted towards the fixed position in space.

AP EAMCET Mock Test - 5 - Question 14

The integrated rate equation for first order reaction, A product is

Detailed Solution for AP EAMCET Mock Test - 5 - Question 14
The integrated rate equation for first order reaction, A → product is k =

For 1st order reactions, R → P

Rate = -d(R)/dt = k[R]

On integrating this elation, we get

In [R] = -kt + l …(i)

At t = 0, R = [R]0, In[R]0 = -k x 0 + l

In[R]0 = l

Substituting the value of I in (i) and on rearrangement, we get

In[R] = -kt + InR0And, k = 1/t in [R0]/[R]

AP EAMCET Mock Test - 5 - Question 15

Which among the following is correct for electrolysis of brine solution?

Detailed Solution for AP EAMCET Mock Test - 5 - Question 15
In electrolysis of brine solution, H2 gas is liberated at cathode. The solution contains four ions Na+, Cl+ , H+ and OH ions. There occurs a race amongst them for their discharge at their respective electrodes.

Following electrode reactions are possible:

In this electrolysis, H2 at cathode and Cl2, at anode are given off.

AP EAMCET Mock Test - 5 - Question 16

The oxidation state of sulphur in H2S2O7 is

Detailed Solution for AP EAMCET Mock Test - 5 - Question 16
Let, the oxidation state of sulphur in H2S2O7 be x.

∴ 2(+1) + 2(x) + 7(-2) = 0

2 + 2x - 14 = 0

2x = 12 x = +6

AP EAMCET Mock Test - 5 - Question 17

Choose the correct value of  x + y in the following equation from the given options:

Detailed Solution for AP EAMCET Mock Test - 5 - Question 17

The given equation is

⇒ 2x + 3 = 7; 2y − 4 = 14

⇒  2x = 4; y = 9

⇒ x = 2; y = 9

∴ x + y = 2 + 9 = 11

AP EAMCET Mock Test - 5 - Question 18

If one root of the equation x2 + px + q = 0  is the square of the other, then

Detailed Solution for AP EAMCET Mock Test - 5 - Question 18

x2 + px + q = 0
Let, α, α2 are the roots of the given equation.
⇒ α + α2 = −p
and α⋅α2 = q
⇒ α3 = q
∵ α + α2 = −p
⇒ (α + α2)3 = −p3
⇒ α6 + α3 + 3α.α2(α + α2) = −p3
⇒ q2 + q + 3α3(α + α2) = −p3
⇒ q2 + q + 3q(−p) = −p3
⇒ p3 + q2 + q − 3pq = 0
⇒ p3 + q2 + q(1 − 3p) = 0

AP EAMCET Mock Test - 5 - Question 19

The range of the function f(x) = [x] − x, where [x] denotes the greatest integer ≤ x, is

Detailed Solution for AP EAMCET Mock Test - 5 - Question 19

f(x) = [x] - x
= x - {x} - x
= -{x}
Range of {x} = [0, 1)
Range of -{x} = (-1, 0]

AP EAMCET Mock Test - 5 - Question 20

The ratio of the area enclosed by the locus of the midpoint of PS and area of the ellipse is (P be any point on the ellipse and S is its focus)

Detailed Solution for AP EAMCET Mock Test - 5 - Question 20

Any parametric point on the ellipse can be taken as P(acosθ, bsinθ).

Now if midpoint of PS is (h, k) then

Now, to find the locus we need to eliminate θ,

Using sin2θ + cos2θ = 1

Which is also an ellipse 
Now,
Area of the ellipse 
Therefore, ratio = 1/4

AP EAMCET Mock Test - 5 - Question 21

In L.P.P., the constraints 5x+4y≥20, x≤6, y≤4 and x,y ≥ 0 form

Detailed Solution for AP EAMCET Mock Test - 5 - Question 21

Let

Feasible solutions are

Clearly, the solution region is the quadrilateral.

AP EAMCET Mock Test - 5 - Question 22

The probability that a man will die in another 10 years is 1/4 and the probability that his wife will die in another 10 years is 1/3. Then, the probability that both of them will be alive in 10 years is

Detailed Solution for AP EAMCET Mock Test - 5 - Question 22

Let P(A) and P(B) be the probabilities that a man and a woman live for another 10 years respectively.

AP EAMCET Mock Test - 5 - Question 23

The probability that at least one of the events A and B occurs is 0.6. If A and B occur simultaneously with probability 0.2, then is equal to

Detailed Solution for AP EAMCET Mock Test - 5 - Question 23

It is given that
P(AUB)=0.6 and P(AB) = 0.2
Therefore

AP EAMCET Mock Test - 5 - Question 24

The smallest positive integer n for which , is

Detailed Solution for AP EAMCET Mock Test - 5 - Question 24

AP EAMCET Mock Test - 5 - Question 25

The false statement in the following is

Detailed Solution for AP EAMCET Mock Test - 5 - Question 25

A tautology is a compound statement which always results in truth value.

p ⇒ q is logically equivalent to ~q ⇒ ~p~.

∴ (p ⇒ q) ⇔ (~q ⇒ ~p) is a tautology but not a contradiction.

AP EAMCET Mock Test - 5 - Question 26

If the position vectors of A,B and C are respectively  and  then cos2A is equal to

Detailed Solution for AP EAMCET Mock Test - 5 - Question 26

Given:

then,

AP EAMCET Mock Test - 5 - Question 27

If the differential equation of all the straight lines which are at a fixed distance of 10 units from the origin is given by (y − xy1)2 = A(1 + y12) then the value of A is equal to

Detailed Solution for AP EAMCET Mock Test - 5 - Question 27

The given family of lines can be represented by the equation,
xcosα + ysin α = 10               ...(1)
where ​α is an arbitrary constant.
Differentiating we have,
cosα + sinαy1 = 0                  ...(2)
Multiplying (2) by x and subtracting it from (1),

⇒ (y − xy1)sinα = 10          ...(3)
Multiplying (1) by y1 and (2) by y and subtracting,
xy1cosα − ycosα = 10y1
⇒ (xy1 − y)cosα = 10y1...(4)
Squaring and adding (3) and (4) we get, (y − xy1)2 = 100(1 + y12)
Now on comparing, we get A = 100.

AP EAMCET Mock Test - 5 - Question 28

If a variable takes the values 0, 1, 2 ____, n with frequencies proportional to the binomial coefficients C(n, 0), C(n, 1) ___, C(n, n), respectively, then the variance of the distribution is

Detailed Solution for AP EAMCET Mock Test - 5 - Question 28

AP EAMCET Mock Test - 5 - Question 29

 is equal to

Detailed Solution for AP EAMCET Mock Test - 5 - Question 29

AP EAMCET Mock Test - 5 - Question 30

If the tangent to the curve 2y3 = ax2 + x3 at the point (a, a) cuts off intercepts α and β on the coordinate axes, where α2 + β2 = 61, then the value of |a| is

Detailed Solution for AP EAMCET Mock Test - 5 - Question 30

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