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MHT CET Mock Test - 5 - JEE MCQ


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30 Questions MCQ Test MHT CET Mock Test Series - MHT CET Mock Test - 5

MHT CET Mock Test - 5 for JEE 2024 is part of MHT CET Mock Test Series preparation. The MHT CET Mock Test - 5 questions and answers have been prepared according to the JEE exam syllabus.The MHT CET Mock Test - 5 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MHT CET Mock Test - 5 below.
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MHT CET Mock Test - 5 - Question 1

Escape velocity is:

Detailed Solution for MHT CET Mock Test - 5 - Question 1

Escape velocity is the minimum velocity with which the body has to be projected vertically upwards from the surface of the earth so that it crosses the gravitational field of earth and never returns back on its own.

MHT CET Mock Test - 5 - Question 2

The mechanism of transfer of heat between two adjacent parts of a body because of their temperature difference is known as

Detailed Solution for MHT CET Mock Test - 5 - Question 2

The mechanism of transfer of heat between two adjacent parts of a body because of their temperature difference is known as conduction. This is the definition of conduction.

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MHT CET Mock Test - 5 - Question 3

An oscillator is nothing but an amplifier with:

Detailed Solution for MHT CET Mock Test - 5 - Question 3

An oscillator is an electronic circuit that converts DC from a power supply to an AC signal. An oscillator produces a periodic and oscillating signal. An oscillator is like an amplifier that gives positive feedback to the circuit. Positive feedback means that a portion of output is combined in phase with the input.

MHT CET Mock Test - 5 - Question 4

In order to determine the e.m.f of a storage battery it was connected in series with a standard cell in a certain circuit and a current I1 was obtained. When the battery is connected to the same circuit opposite to the standard cell a current I2 flow in the external circuit from the positive pole of the storage battery was obtained. What is the e.m.f e1 of the storage battery? The e.m.f of the standard cell is e2.

Detailed Solution for MHT CET Mock Test - 5 - Question 4

ε12=I1R,ε1−ε2=I2R
Dividing ε1=( I1+I2/I1-I22

MHT CET Mock Test - 5 - Question 5

What is the voltage gain in a common emitter, where input resistance is 3Ω and the load resistance is 24Ω, β = 0.6​

Detailed Solution for MHT CET Mock Test - 5 - Question 5

Voltage gain   =β× (Rc​​/Rb​)
Or,   Voltage gain =0.6×(24/3)​=4.8

MHT CET Mock Test - 5 - Question 6

The terminal voltage across a battery of emf E can be

Detailed Solution for MHT CET Mock Test - 5 - Question 6

Potential difference(V) across the terminals of a cell
i. Discharging of cell when cell is supplying current,
Therefore, V=VP+VQ=E-Ir, i,r., V<E
ii. charging of cell when cell is taking current,
V=VP-VQ=E+Ir, i.e., V>E
iii. When the cell is short circuited i.e., external resistance is zero,
=> I=E/r
=>  V=VP-VQ=E-Ir=0 i.e., V=0

MHT CET Mock Test - 5 - Question 7

A dipole is said to be in stable equilibrium when angle between electric field and dipole moment is:​

Detailed Solution for MHT CET Mock Test - 5 - Question 7

Stable equilibrium is attained when potential energy of the dipole system is minimum which is possible at an inclination of 0°.

MHT CET Mock Test - 5 - Question 8

The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4eV. The stopping potential is Volts is

Detailed Solution for MHT CET Mock Test - 5 - Question 8

Given, the maximum kinetic energy: Kmax​=4eV
If V0​ be the stopping potential, then Kmax​=eV0​
⇒eV0​=4eV 
⇒V0​=4V

MHT CET Mock Test - 5 - Question 9

Diamagnetic substances are

Detailed Solution for MHT CET Mock Test - 5 - Question 9

When a diamagnetic material is placed in an external magnetic field the spin motion of electrons is so modified that the electrons which produce the moments in the direction of the external field show down while the electrons which produce magnetic moments in opposite directions get accelerated.
Thus, a net magnetic moment is induced in the opposite direction of the applied magnetic field. Hence the substance is magnetized opposite of the external field. Thus, it moves from stronger. Weaker parts of the magnetic.
 

MHT CET Mock Test - 5 - Question 10

A geminal dichloride is formed in all of the following reactions except

Detailed Solution for MHT CET Mock Test - 5 - Question 10

MHT CET Mock Test - 5 - Question 11

Which one of the following soaps are soft to the skin?

Detailed Solution for MHT CET Mock Test - 5 - Question 11

The correct answer is Option B.
Potassium soaps are softer to the skin than sodium soaps. These can be prepared by using potassium hydroxide solution in place of sodium hydroxide.
Potassium soaps are used in shampoo, shaving cream and bathing soaps etc sodium soaps are toilet soaps used for washing purposes.
 

MHT CET Mock Test - 5 - Question 12

The atom which defines the structure of a family of organic compounds and their properties is called ___________

Detailed Solution for MHT CET Mock Test - 5 - Question 12

Explanation: The atom which defines the structure of a family of organic compounds and their properties is called a functional group. Functional groups are specific groups of atoms or bonds within molecules that are responsible for the characteristic chemical reactions of those molecules.

MHT CET Mock Test - 5 - Question 13

Propanamide on treatment with bromine in an aqueous solution of sodium hydroxide gives:

Detailed Solution for MHT CET Mock Test - 5 - Question 13

MHT CET Mock Test - 5 - Question 14

What is aggregation of colloidal particles into insoluble precipitate by addition of some suitable electrolyte called?

Detailed Solution for MHT CET Mock Test - 5 - Question 14

Aggregation of colloidal particles into insoluble precipitate by addition of some suitable electrolyte is called coagulation.

MHT CET Mock Test - 5 - Question 15

Which of the following polymers have tetrafluoroethene monomer units?

Detailed Solution for MHT CET Mock Test - 5 - Question 15

Teflon has CF2=CF2 as monomer unit.

MHT CET Mock Test - 5 - Question 16

An alkene on treatment with meta chloro perbenzoic acid undergoes epoxidation reaction to give oxirane. What is the correct order of increasing reactivity of the following in the above mentioned epoxidation reaction?

Detailed Solution for MHT CET Mock Test - 5 - Question 16

Epoxidation is an example of electrophilic ad dition at olefin ic bonds. Therefore, greater the electron density at olefinic bond, greater its reactivity. Electron donating groups increases reactivity while electron withdrawing group s like — CF3 decreases reactivity.

MHT CET Mock Test - 5 - Question 17

Which compound given below has the highest solubility in water ?

Detailed Solution for MHT CET Mock Test - 5 - Question 17

Greater the number of hydroxy groups , greater its a bility to form H-bonds with water, hence greater solubility.

MHT CET Mock Test - 5 - Question 18

Antioxidants are added to food:

Detailed Solution for MHT CET Mock Test - 5 - Question 18

Antioxidants are additives capable of delaying or preventing rancidity of food due to oxidation, and therefore, lengthen the shelf life of products. They are very important in the food industry because they allow foods to conserve their nutritional properties and their quality levels. Antioxidants do not improve the quality of food, but it does help them to keep for a longer period of time. There is a wide variety of antioxidants from natural and synthetic origin, which are usually used in food. The most common uses of antioxidants are oils, margarines, confectionery, baked goods, pastries, snacks, cereals and sauces. Some natural antioxidants used in the food industry are Tocopherols, Ascorbic Acid or Rosemary Extract.

MHT CET Mock Test - 5 - Question 19

In SN1 reaction, racemisation occurs if the reaction occurs at a stereogenic centre, however, 50:50 mixture of enantiomers are rarely obtained, why?

Detailed Solution for MHT CET Mock Test - 5 - Question 19

In SN1 reaction, some of the substrate, even after ionisation, remains associated as an intimate ion pair preventing nucleophilic attacks from front side and gives inverted product.


Due to partial reaction of nucleophile with intimate ion pair, net inversion of configuration is observed although predominant reaction occurs at planar carbocation giving racemic products.

MHT CET Mock Test - 5 - Question 20

Which of the following compound gives more than one oxirane upon epoxidation with Ag2O/heat? 

Detailed Solution for MHT CET Mock Test - 5 - Question 20

It gives racemic mixture of oxiranes.

MHT CET Mock Test - 5 - Question 21

Comprehension Type
This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).

Potassium crystallises in a bcc lattice as shown

Q.

Distance between the two nearest neighbours and between next nearest neighbour respectively, is

Detailed Solution for MHT CET Mock Test - 5 - Question 21

(a)

Nearest neighbours are along the diagonal at the half distance apart, Diagonal AB = √3a

∴ Distance of the nearest neighbour

Next nearest neighbours are along the cell edge = 520 pm

K-atom at the centre is surrounded by eight K-atoms as nearest neighbours.

In bcc, coordination number is six as next nearest neighbours

MHT CET Mock Test - 5 - Question 22

Name the RNA molecules which is used to carry genetic information copied from DNA?

Detailed Solution for MHT CET Mock Test - 5 - Question 22

Each type of RNA functions differently, among them mRNA which is also known as messenger RNA carries genetic information from DNA in the form of series of a three-base codon, which specifies the amino acid.

MHT CET Mock Test - 5 - Question 23

The % by volume of C4H10 in a gaseous mixture of C4H10, CH4 and CO is 40. When 200 ml of the mixture is burnt in excess of O2. Find volume (in ml) of CO2 produced.

Detailed Solution for MHT CET Mock Test - 5 - Question 23

C4H10 = 80 ml
CH4 = xml  CO = y ml
x + y = 120 ml

total CO2 volume
= 320 + x + y ml
= 320 + 120
= 440 ml

MHT CET Mock Test - 5 - Question 24

We can obtain ethylamine by Hoffmann bromamide reaction. The amide used in this reaction is:

Detailed Solution for MHT CET Mock Test - 5 - Question 24

The correct answer is option C
CH3​CH2​CONH2​ (A)⟶ CH3​ − CH2 ​− NH2​ (B)⟶ ​CH3​ − CH2 ​− OH
In the above sequence A & B respectively are Br2​/KOH and HNO2
The first step is Hoffmann bromamide degradation reaction in which an amide (propanamide) is converted to an amine  (ethylamine) containing one carbon atom less. The reagent A is bromine in presence of KOH. In the second step, aliphatic primary amine (ethyl amine) reacts with nitrous acid (reagent B) to form aliphatic primary alcohol (ethyl alcohol).
 

MHT CET Mock Test - 5 - Question 25

Two integers are selected at random from integers 1 to 11. If the sum is even, find the probability that both the numbers are odd.

Detailed Solution for MHT CET Mock Test - 5 - Question 25

Out of integers from 1 to 11, there are 5 even and 6 odd integers.
Let A – both the numbers chosen are odd
B –sum of the numbers chosen is even. 

MHT CET Mock Test - 5 - Question 26

For which of the following values of m , is the area of the region bounded by the curve y = x - x2 and the line y = mx equal to 9/2 ?

Detailed Solution for MHT CET Mock Test - 5 - Question 26


MHT CET Mock Test - 5 - Question 27

Find the value of x for which x  is a unit vector

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MHT CET Mock Test - 5 - Question 28

The area enclosed between the curves y = x3 ,x- axis and two ordinates x = 1 to x = 2 is [in square units]

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MHT CET Mock Test - 5 - Question 29

The area bounded by the curves y2 = x and y = x2 is

Detailed Solution for MHT CET Mock Test - 5 - Question 29

The two curves meet in (0 , 0) and (1, 1).The required area lies above the curve y = x2 and below x = y2 and is equal to ;

MHT CET Mock Test - 5 - Question 30

Equation of the tangent to the curve  at the point (a, b) is

Detailed Solution for MHT CET Mock Test - 5 - Question 30


Hence ,slope of tangent at (a , b) = -b/a . Therefore , the equation of tangent at (a , b ) is ; 

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