Test: Geometry - 2 - CTET & State TET MCQ

An obtuse angle is an angle whose measure is greater than 90 degrees but less than 180 degrees.

The first letter is M. It is made of 4 lines intersecting at 3 points. We can see that none of the angles are right angles. So M don’t have any perpendicular lines.
The next letter is A. It has 3 lines intersecting at 3 points and no lines are perpendicular. So don't have any perpendicular lines.
Let us consider T. It has 2 lines which meet at one point. From the letter we can say that the 2 lines are perpendicular. So T has perpendicular lines.
Now we have H. It has 2 parallel lines intersected by a line. From the figure we can say that the intersected line is perpendicular to the parallel lines. So H also has perpendicular lines.
The last letter is S. It doesn’t have a straight line or any intersection. So it doesn’t have any perpendicular lines.
So only the letters T and H have perpendicular lines.
So only 2 of the given letters have perpendicular lines.

Measure of angle Q is more thaan 90o but less than 180o.

Hence the ∠Q is an obtuse angle.

Any angle which is larger than 180o but smaller than 360o is called as a reflex angle.

Here, the angle shown is larger than 180o but smaller than 360o. 

Hence, it is a reflex angle.

Therefore, option C is correct.

Figure A, Figure B and Figure C are the angles that are greater than the right angle.

Hence the correct answer is option C

The question asks us to mark the correct option in which the angle formed by the two lines is greater than a right angle which means greater than 90∘90∘. To solve the question we need to move anticlockwise from the horizontal line to the other line and check whether the angle is greater than 90∘90∘ or not.
So on analysing option A we see that the angle formed between the two lines is 90∘90∘, as the lines are perpendicular. The image shows that the two lines are horizontal and vertical.
On analysing the second option we see that when we move anticlockwise along the line we see that the angle formed is less than 90∘90∘.
Moving to option C, since the angle is measured anticlockwise so on measuring the angle we see that the angle is present in the 3rd3rd quadrant. The angle formed is less than 90∘90∘as we move anticlockwise along the horizontal line given in the image.
In the fourth option we see that the angle formed on moving your hand anti-clockwise along the horizontal line we get an angle which is greater than 90∘90∘also called obtuse angle.

So, the correct answer is “Option D”.

Here, 6 pairs of perpendicular lines are CB⊥ AB, BC ⊥ CD, ED ⊥ CD, DE⊥ EF, FG⊥ EF and FG ⊥ HG.

Hence Jyoti made the correct statement..

As shown in above figures, figure 2, figure 4 and figure 5 are the figures which has  the pair of parallel lines

Hence the correct answer is option B 

Pair of parallel lines in above figure  1 pair of parallel lines.

The given angle is a acute angle, so option D and option C is not correct

The approximate value of above angle is 45o, as the angle of 20o would be very small than the given angle

Hence the correct answer is option B.

an angle which measures more than 0 degree and less than 90 degree is called an acute angle..

5 angles are less than a right angle.

According to the given figure line IJ and line AB meet each other at right angle

∴ Line IJ is perpendicular to line AB
Hence the correct answer is option B

Except line segment CD, ray BD, line AD and ∠B is clearly seen in the diagram.

Hence the correct answer is option D.

Measure of angle drawn by Danish = 40^∘
∴Measure of angle drawn by Manish = 2×40^∘=80^∘

There are 3 acute angles in the given figures. 

Here the angle between any two consecutive numbers in a clock is 30^∘.
Now we know that when time is 30 minutes, then the minute clock will be at 6.
And when time is 10:30, the hour clock will be between 10 and 11. Let us draw a clock here for better understanding.

Now the number of parts (number) between 6 to 10 are 4. So an angle between 6 and 10 will be 4×30^∘=120^∘4×30^∘=120^∘. Similarly, there are 5 parts between 6 to 11. So the angle between 6 and 11 will be 5×30^∘=150^∘5×30^∘=150^∘.
Hence our angle will be between 120^∘ and 150^∘120^∘ and 150∘ and it will be exactly in middle of 10 and 11, so angle will be equal to 120^∘+150^∘2=270^∘2=135^∘120^∘+150^∘2=270^∘2=135^∘.
Hence our required angle between the hands of a clock as 10:30 is 135^∘.
Since 135^∘ is greater than 90^∘ so it is an obtuse angle.

4

All the figures as shown in above have perpendicular lines
Hence the correct answer is option D.

(A)
(B)
(C) 
(D)