The solution of dy/dx = y2 with initial value y(0) = 1 is bounded in the interval
Solve the following equation:
yexydx + (xexy + 2y)dy = 0
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Consider the differential equationThe general solution with constant C is
The solutions of the equation 3yy’ + 4x = 0 represents a:
The solution of differential equation dx – (x + y + 1) dy = 0 is
The solution of the differential equation (dy/dx) = ky, y(0) = c is
What is the solution of the differential equation dy/dx = x/y, with the initial condition, x = 0, y = 1?
Given the value of y at x = 2 is ________ (round off to nearest integer) (Important - Enter only the numerical value in the answer)
Which of the following equations cannot be solved by using the method of separation of variables?
65 videos|120 docs|94 tests
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65 videos|120 docs|94 tests
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