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If the principal part of the Laurent’s series vanishes, then the Laurent’s series reduces to
In the neighbourhood of z = 1, the function f(z) has a power series expansion of the form
f(z) = 1 + (1 − z) + (1 − z)2 + ....... ∞
Then f(z) is
The value of y at x = 0.1 to five places of decimals, by Taylor's series method, given that dy/dx = x2y−1, y(0) = 1, is
65 videos|120 docs|94 tests
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65 videos|120 docs|94 tests
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